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function SGrey3 {. I% R- c: |1 L Z' w/ L: `
7 R2 [' R% l; Q8 u
X0 = input('请输入原始负荷数据:'); %输入原始数据6 |: f/ ~9 {+ R7 G5 Z3 W# a: I
n = length(X0); %原始n年数据
- F. r3 e3 I0 z" |! V
. g; o' ]# t4 v7 }) v( p%累加生成
, A \" c, ~% F# h/ p$ c* aX1 = zeros(1,n);
+ v n$ y0 y9 ^9 u- m6 f( m' w2 sfor i = 1:n) C/ W5 e' x6 o8 L% t6 K
if i == 10 E% j" V: E! t' v
X1(1,i) = X0(1,i);
7 j. ~' m# U. L5 l" p- F6 T else
- |6 j* X9 D1 x% X$ _% e" d X1(1,i) = X0(1,i) + X1(1,i-1); @& y* o. ~6 F- R# \, E- [
end* W# j, t4 j; n3 J5 m' L& l
end, ~1 m3 C. k+ e8 a, f9 i
X18 w; L! V& H6 l& F( B. Q
8 b. ]' S0 r+ T* {( j p
%计算数据矩阵B和数据向量Y$ E2 D7 \4 j6 X% l, e; P* S
B = zeros(n-1,2);/ @4 F5 g j; p) J
Y = zeros(n-1,1);& t% J6 f- q- q+ n+ V, u( r
for i = 1:n-1
7 x! Y7 _# g- Y, I- G2 Q4 `6 K B(i,1) = -0.5*(X1(1,i) + X1(1,i+1));
! h2 o* Y3 W/ r! [1 q4 F B(i,2) = 1;) E( ]5 F: h2 c* p( n3 }( \$ o+ m
Y(i,1) = X0(1,i+1);8 F, p6 P7 {+ w; v$ r
end2 D6 a9 B0 G0 P. o
B,Y/ B9 N7 j/ L/ y+ U" K: a* }1 q
) Q6 u0 _0 d1 f) w1 K8 \, W
%计算GM(1,1)微分方程的参数a和u
* d, O, B$ G( p7 P5 b# E. x% G6 Z/ eA = zeros(2,1);
* v' m9 W# ^/ v0 b$ |A = inv(B'*B)*B'*Y;! R) i" H+ w) M4 O
a = A(1,1);
- b4 ?8 t! n9 C9 O( x" Tu = A(2,1);) P7 R* h! c+ B( E
a,u
( Z+ {/ x* n7 d& G+ O* e- x
1 b: e# b$ g7 E& v6 a2 l%建立灰色预测模型
2 F$ }" _6 Q7 P: C1 x7 _% ]9 X2 zXX0(1,1) = X0(1,1);
6 R2 ~! C" y) R$ j! l' Rfor i = 2:n
% w& r" f3 o# c7 @9 t0 Z; H" A9 A XX0(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i-1));
+ P0 J1 W) b, U Qend5 _: V% q6 o6 a
XX0/ P! v" h. [: X+ _6 G. J4 ]
%模型精度的后验差检验$ g+ S- `' m1 V2 v9 \' |7 T! W1 g
e = 0; %求残差平均值4 \' q! ~3 e, Z, d9 s- M
for i =1:n
6 J& n1 ~" \3 G9 O1 H" a e = e + (X0(1,i) - XX0(1,i));
2 C9 E# O* C; w& y/ {* ]5 E- Iend! Y. R3 Q( `) _3 g
e = e/n;
4 V5 s" q- N/ d( \e
% G' U# P8 r* F+ W: F6 @aver = 0; %求历史数据平均值0 ^0 l2 ]/ r$ ^) O. Y2 j
for i = 1:n, Q# I* b9 o& R( A
aver = aver + X0(1,i);
9 K) F. W& w! [# fend
* o% D+ W' [* G* b! s8 kaver = aver / n;- |# A. E: z4 {, L
aver
; ?4 Y6 {2 u) j" Z5 H) \# h* Q' ys12 = 0; %求历史数据方差9 X" ?+ W" f- f
for i = 1:n7 h [1 l% e& j* t
s12 = s12 + (X0(1,i)-aver)^2;0 ^5 ^4 G5 M g. H
end0 L- a/ p% z. C
s12 = s12 / n;
+ G4 P0 @. Q# S) fs12
4 i! A! w9 ?! P4 Z9 P: Rs22 = 0; %求残差方差
/ A& P. ^" T! z! a, J, Mfor i = 1:n
3 E; i( V0 O" |; R$ `) z5 O( u s22 = s22 + ((X0(1,i) - XX0(1,i)) - e)^2;# v; L: M& } W: p. r- S. a' b9 ?
end" l- R; _: ^4 K
s22 = s22 / n;
7 U* l/ T: p. l# P/ t; Qs22) _8 P& ^3 J4 Y; z# E& b; j
C = s22 / s12; %求后验差比值
1 B8 {1 {! C" c! D7 MC
2 c, N. b5 F! m- b4 n& A* y# m$ n \cout = 0; %求小误差概率
1 H6 K$ W4 \3 f8 q9 c2 ~for i = 1:n" r! |1 v. _5 E* i0 _
if abs((X0(1,i) - XX0(1,i)) - e) < 0.6754*sqrt(s12)
; E3 ~/ O9 f9 _6 \2 ?1 h cout = cout+1;# a8 O. n: j ^8 O; u5 ~7 O' E0 K% f
else0 G& g+ I4 V- ?9 K. |9 }
cout = cout;: L, z- S% X! K! {* K3 K$ c- v
end
+ }3 ~- A- q5 I6 W. Send
. Z5 c3 `0 }$ X& nP = cout / n;
% X! |& |! ^: D! aP
5 @; p5 s* S( v% ?7 V/ g. hif (C < 0.35 & P > 0.95)/ v* j7 U" J4 M/ H
disp('预测精度为一级');0 |) \$ B5 w6 y6 {2 I
m = input('请输入需要预测的年数: m = '); %预测往后各年的负荷3 X3 C& h9 p0 `. L+ v! h
disp('往后m各年负荷为:');; t* x1 S/ X& h/ t( g! Z0 S7 f$ U
f = zeros(1,m);. L, ~$ G5 ?# W& Q
for i = 1:m
, h4 I8 i5 @/ T: z f(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i+n-1));
+ @9 W& Q6 ?; `# y7 f; \+ h# Q( R1 @% t end. R4 \/ d8 j) a
f# |8 m4 O3 @1 p; K
else, A' Q+ k/ `5 A- x" v* h
disp('灰色预测法不适用');
/ e6 o; I& A7 e2 Z1 Send |