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function SGrey7 K( z. Z5 T) t! {' N) `% x
% K S: F. H4 W2 P% ]
X0 = input('请输入原始负荷数据:'); %输入原始数据
5 o! U0 R) y5 `n = length(X0); %原始n年数据
, x9 |! l0 s$ ?1 n/ ]4 l2 _- C" c6 R, m% u! g N
%累加生成5 ~+ G% {; z& |1 k& E. z
X1 = zeros(1,n);) l, U. i4 @. }! Z" F( P- ^; L$ U
for i = 1:n8 q; E7 X: h) M% x9 O1 q
if i == 1 W( _% R% d6 {: h
X1(1,i) = X0(1,i);5 p5 W% Z A( D5 J% p
else8 p/ A8 D0 }0 |5 e
X1(1,i) = X0(1,i) + X1(1,i-1);: L/ ^( ?1 X4 p6 ?0 C/ R+ l ~
end
6 ~/ _3 i( i& i6 e6 s& tend
3 L& G' ~3 b) B' NX1
: x+ h7 Q- j7 _
! V4 O: \3 T% j& ]9 e%计算数据矩阵B和数据向量Y
/ c* [3 T( r6 H4 f- q3 j. EB = zeros(n-1,2);/ g3 U/ J6 `% J# H% o& H
Y = zeros(n-1,1);
8 F2 L; c* S4 Mfor i = 1:n-1
9 n! Z: S- k2 W B(i,1) = -0.5*(X1(1,i) + X1(1,i+1));
$ G) n$ c, n' {1 H7 \9 h- C B(i,2) = 1;
( o- V9 M" E( {8 I Y(i,1) = X0(1,i+1);
9 ^( H q# V% aend
0 _' K) C& a) }; l/ q, {$ FB,Y4 i1 }3 p0 r" k0 f
# R2 T3 B7 p, B T%计算GM(1,1)微分方程的参数a和u
' s, {3 o' m5 e8 G) {/ u8 w0 }7 V0 G9 KA = zeros(2,1);, w* e8 n1 W, s
A = inv(B'*B)*B'*Y;! b; H' y) f, K. \ |7 }
a = A(1,1);& W; U( [ b0 V6 i6 D8 P
u = A(2,1);
. L @, Z, M; P4 H. `a,u# q, V4 a" a: ?" C$ p$ F
6 d/ G1 V( m3 S2 F) x. ^* M
%建立灰色预测模型
0 {) }! E) r1 XXX0(1,1) = X0(1,1);
2 r$ u1 S( }5 o5 f2 n8 Ufor i = 2:n0 j# e1 l, F! [- l% ^
XX0(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i-1));5 n8 U& W* [1 K& x4 K9 W& a
end* ` |$ }: Z6 l' N; X8 S
XX0% D2 Y; Q( Q+ y$ N$ l4 b" c
%模型精度的后验差检验
5 C1 T; l" t- g" r' R0 ze = 0; %求残差平均值/ R* i0 V4 O" I( i! p
for i =1:n0 A/ Q+ u5 l5 F5 n" ~
e = e + (X0(1,i) - XX0(1,i));
3 m* t3 y c: U% O& Oend
" b3 S, t! Q. I; e% {/ se = e/n;
7 e0 Q3 r' V J) G) g7 M% z# U* r! ^e
: h+ {$ f* N* t0 t naver = 0; %求历史数据平均值
1 `) r k# I" l! gfor i = 1:n( v# E5 M% d' i/ C
aver = aver + X0(1,i);
( w& h$ o+ }( [end6 U W0 B8 Q) l& V( o, `
aver = aver / n;$ b3 N: z1 [6 F B( I' V9 W
aver! V6 p3 z. p o% A1 }: F' f! J7 @
s12 = 0; %求历史数据方差
0 U) ?7 R' R3 gfor i = 1:n
/ U5 w0 {" S# f; Y, q( s& a8 I s12 = s12 + (X0(1,i)-aver)^2;
( G" C0 N+ E" u3 l$ Aend, e, h4 }+ Z& h' e
s12 = s12 / n;
" N! m3 o, m1 [+ u6 }s12" C* L- K% ^5 v% \8 q
s22 = 0; %求残差方差
" Y2 m! |# d1 K8 z0 E( }4 [" K0 ]for i = 1:n
# r+ _% W/ h+ J+ ~% \ s22 = s22 + ((X0(1,i) - XX0(1,i)) - e)^2;
' W; j$ T' r6 Z- B9 L7 n! fend
5 P1 g5 K& U! G" U. N) X* \s22 = s22 / n;
4 g1 h/ t6 W# M; b& o" @+ K+ d5 j os22
; J$ \1 {3 Q/ w: W4 M/ |# Z/ Z0 NC = s22 / s12; %求后验差比值
/ }5 [- c% f- _; D ~" _1 t* R, vC
H) u$ P5 N5 Scout = 0; %求小误差概率' W/ S" f1 }" l# @/ X1 {2 A
for i = 1:n; b7 c& h3 F* U# Y! E
if abs((X0(1,i) - XX0(1,i)) - e) < 0.6754*sqrt(s12)* Y" k, ^- Y$ N$ D5 l( J, ]
cout = cout+1; m, \! {6 ]+ n+ `% g! C* ^
else. Y. k5 d! Z3 }1 w/ a4 j+ B& P
cout = cout;
" P% P! n4 x; j" L end
( ~4 h1 k6 P* ]9 n6 p! kend
3 X. M4 ^/ J: A; d; m# AP = cout / n;9 e0 h; \, n/ v$ x. w
P3 x1 [( c/ f! ^4 ?
if (C < 0.35 & P > 0.95)
+ N5 I0 k5 _/ Y( d. A disp('预测精度为一级');* {% d$ a7 Z& B5 I4 ?' {
m = input('请输入需要预测的年数: m = '); %预测往后各年的负荷
" a1 Z9 f! z0 l/ T7 f4 s disp('往后m各年负荷为:');$ v# z* u! ]- E- S, r2 K
f = zeros(1,m);
5 f) ?2 G. K, n# C+ K( x& M for i = 1:m
& r: K/ ] C0 @, M f(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i+n-1));7 _/ L+ i0 Y- L. L
end3 S* n# y! q: K5 _4 w9 x
f4 K7 j8 D! p* p1 e" k8 t* f
else! _ a3 c/ `1 G- g4 s
disp('灰色预测法不适用');
5 F) Z( l8 r0 eend |