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function SGrey' T4 v% q9 ?- h" U
4 F H0 F. U0 P% \8 Q9 ]
X0 = input('请输入原始负荷数据:'); %输入原始数据
: A) H5 G. L! D N3 \1 s/ h: yn = length(X0); %原始n年数据& ]' J$ c# E8 u- N" }& N4 o0 B
) y, B" n, z o. p) \$ S" y" R
%累加生成
4 S0 P2 T8 p1 v$ K7 ^1 KX1 = zeros(1,n);+ e( {. C# k2 W
for i = 1:n
) i. S; [$ ^3 C+ q if i == 12 ?" I: _ P$ D5 B) ~$ u
X1(1,i) = X0(1,i);
& o3 a. G _* e else
0 E. Z% a- H4 y7 C6 G. Z/ m( Y X1(1,i) = X0(1,i) + X1(1,i-1);
, d- o) B* e5 j3 Q0 H4 \ end
7 a4 p3 M3 a1 l; z+ zend
. C2 U( Q2 _% v- t3 X% eX1
* U. _7 E& v; L* T. b" c; P+ n
2 g8 C5 ]5 z2 d6 h* m9 M- r%计算数据矩阵B和数据向量Y7 K# v8 |7 v- R2 {% b! W7 P. x
B = zeros(n-1,2);% b- K' G7 k4 O! K
Y = zeros(n-1,1);
0 @( n" k/ }5 p, q% M. f& }for i = 1:n-1* w+ W5 U0 i! P; s+ R1 t! Q$ }
B(i,1) = -0.5*(X1(1,i) + X1(1,i+1));
8 g F5 f" }. D! R6 t4 } B(i,2) = 1;
* H8 c2 D3 k5 D Y(i,1) = X0(1,i+1);
; `7 x5 O" w( hend8 g& t+ m* e* S$ _5 m) v
B,Y
0 B5 ^0 S( e! h n) u4 p4 P8 f& {9 Z8 y, h" @& O
%计算GM(1,1)微分方程的参数a和u7 \2 f4 M" Y% \3 j- q% C v
A = zeros(2,1);
( h5 V! p2 y U& PA = inv(B'*B)*B'*Y;) H1 b* ^5 U6 z0 y. h& j
a = A(1,1);
6 [- `% \( _( g' i% Q1 hu = A(2,1);
) K) e Y" z# n. u# q2 Ra,u
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%建立灰色预测模型" x( J5 ~* S7 W4 ~, h2 J# V
XX0(1,1) = X0(1,1);
, B k; Y& c. S. g; Sfor i = 2:n/ Q6 {: I; B/ S
XX0(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i-1));
s% q; e0 m! R% t" D6 F; m) W% Qend
n, U% N" M1 W( e# P7 DXX09 N) y2 p* e" o3 I
%模型精度的后验差检验# l& ^, b% C& ?& _5 K) q
e = 0; %求残差平均值
, ?5 U- [1 {! S3 c9 mfor i =1:n
/ M+ A# T+ m9 C$ n6 e4 L e = e + (X0(1,i) - XX0(1,i));
1 S8 h# T7 x% A, `6 T. Y; F' C; q$ |end
G: X6 b( q- }e = e/n;; n! |+ ^: w" Q5 J
e
+ o6 G+ C! B8 D$ U" \aver = 0; %求历史数据平均值
8 j2 M- H4 K. o. gfor i = 1:n, K: i- q, J9 e8 W. R* w
aver = aver + X0(1,i);; d( n0 f7 d/ d6 i
end. c' \; Z' c+ R4 D
aver = aver / n;* @ [6 C4 o- j
aver# _; [, E+ s5 }! {* i; x
s12 = 0; %求历史数据方差. V1 L1 k: A0 a! o; c
for i = 1:n. N! |6 k, x$ G H
s12 = s12 + (X0(1,i)-aver)^2;$ t9 t) O) x9 g" H
end
: n6 T0 w2 j: V/ N4 E- n! D as12 = s12 / n;
. ^: A; L- s4 C, L; `7 O) t, vs12
- }" a$ N: E4 M+ c7 W% m. f" k+ ds22 = 0; %求残差方差
6 p( O- X0 |5 O a! [* E# j! ufor i = 1:n
7 |8 K, n$ b3 b/ K6 ~- j& r+ j8 @ s22 = s22 + ((X0(1,i) - XX0(1,i)) - e)^2;+ y" [ l6 i) b3 n
end
6 O! i, |& T4 R! [4 q( v: fs22 = s22 / n;
O. J/ e2 s3 R( as22
$ g- ~6 s! G+ b( F, @& L" m; [C = s22 / s12; %求后验差比值) r$ [5 _, E# o6 d8 _# a4 U
C' A" c: I2 D4 S! x2 E! w' z$ @
cout = 0; %求小误差概率
~5 k- v8 K4 M2 S) p2 S0 h" jfor i = 1:n
. Z% { u. x% J: f, A if abs((X0(1,i) - XX0(1,i)) - e) < 0.6754*sqrt(s12) _" k$ p+ A( ?- _# L/ G
cout = cout+1;
4 `/ _; t# p" C; R# O else& o G3 }) ?7 A+ Q
cout = cout;2 A; i0 k9 P# e; i7 ]
end# t# {( L! b* i% i
end
+ ?3 P0 E6 A Z% n& lP = cout / n;! }, m; Q& C7 t3 @; k
P
% O9 z1 m: @+ q( [- i" Z* cif (C < 0.35 & P > 0.95)
7 H J0 p5 |; D) g a% M [ disp('预测精度为一级');! n) D' O1 L) K
m = input('请输入需要预测的年数: m = '); %预测往后各年的负荷
! S3 q X( S0 C. Q) G( C0 w. v* W1 K disp('往后m各年负荷为:');0 o# P' k( W. @9 z2 S M
f = zeros(1,m);$ ~7 }! a/ ?0 ~/ o
for i = 1:m5 l* a5 A4 t1 u
f(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i+n-1));; t* M# f7 [+ q; A( s
end
3 q/ _$ U: \; t6 }! j. u+ L' O f
5 O, e% i5 y% G! w9 Welse
# c5 D( C# I; @2 y7 P/ B4 \ disp('灰色预测法不适用');
7 D' ?! N5 G" i: s* _+ ?end |