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function SGrey' I, ]( \" E& O
( p8 [$ Z% k# U( U" ^0 f8 e+ v9 z6 ^
X0 = input('请输入原始负荷数据:'); %输入原始数据' P% O/ h4 v5 y: Y& k1 W
n = length(X0); %原始n年数据
) j& H% c% b( I
4 W+ y' q8 R3 O7 M7 S1 `/ I' q; P%累加生成
" K( s R5 M3 ^, z6 I0 W) o# T4 IX1 = zeros(1,n);% @, O6 I5 V9 e, v0 o) B W
for i = 1:n5 q: Z5 c J- O5 S- l( _5 W
if i == 1
0 {8 W' ?5 a0 o f) `: U/ u X1(1,i) = X0(1,i);
7 M8 c% K$ e: b, |; d) W else
+ w0 a- L0 `) Y0 f4 O X1(1,i) = X0(1,i) + X1(1,i-1);
0 A# _, s* m) Z end2 @* R- o0 K0 l$ Z6 o/ B# G
end8 X& T% N$ W2 s. t0 q; j9 M/ w
X1! v; q; H E2 q$ ^( ] W/ Q
( `% I7 V" i, c
%计算数据矩阵B和数据向量Y
: \* I: Z$ o% V2 m3 VB = zeros(n-1,2);
8 ~) U( g' Y, ~ f% \7 U' mY = zeros(n-1,1);
9 B7 ?$ i) ^) A8 N- tfor i = 1:n-1
! B8 L5 Q" n |6 z3 G6 w B(i,1) = -0.5*(X1(1,i) + X1(1,i+1)); g+ R( {/ U# t4 l4 w4 q& X
B(i,2) = 1;! Q o/ Z k1 r5 y6 g& k
Y(i,1) = X0(1,i+1);4 v% Y) o( \6 X# S1 F, x) |
end4 W8 o" l/ F1 j9 L
B,Y. t' u1 U* l; Q5 B
, l- f& D! S0 X%计算GM(1,1)微分方程的参数a和u9 [. d6 r1 P. B; ^* i
A = zeros(2,1);
% k! _- Z, h1 b& S& f' f9 XA = inv(B'*B)*B'*Y;
- z$ N0 Z5 l: i. f& w b6 Va = A(1,1);$ _% o) N8 U' G% s( d, F7 j
u = A(2,1);0 H: d0 q( S1 v0 v* o
a,u x; a' C8 ^2 E @* h3 n2 y3 m
7 O) V+ X8 \( y, m h" a \& T
%建立灰色预测模型! m3 P4 g; c+ w3 o* E9 N
XX0(1,1) = X0(1,1);) c: B7 L6 y- t' a
for i = 2:n
( `1 L# I4 E) o$ _3 m0 g1 Q& b XX0(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i-1));; u% \: ~7 K& C8 K% v$ C
end1 _5 C$ @5 k! F. b) U
XX0
$ O8 h: j8 S0 S0 l% F a' l. `%模型精度的后验差检验* ?1 l" {1 k6 R
e = 0; %求残差平均值 b: o/ T/ |& z/ P0 h; y
for i =1:n
) q! y. k0 l' j( ~+ ~. T W+ ~. o e = e + (X0(1,i) - XX0(1,i));
6 w8 L3 o! }7 u* [" _1 Send8 |. T% ?. a% m/ [
e = e/n;
' G; s3 k( \: H" x* x& F( Xe
7 k( K3 d2 U2 B, m6 f, U. ?aver = 0; %求历史数据平均值$ o% A6 [& i. C, s- L8 [0 F8 \
for i = 1:n& Q. m) R7 U$ W3 m. |' M/ v7 O P" f
aver = aver + X0(1,i);
3 c ?+ j/ p# }( cend
" |/ t9 Y& y) w8 A- [ z3 naver = aver / n;4 y. t& T: w, [
aver
0 s8 F# C1 j$ | s" u) D2 c5 U4 es12 = 0; %求历史数据方差
6 d, j* b( g/ ]' o) T1 z2 `for i = 1:n
, m2 \- v3 n8 G! C0 G s12 = s12 + (X0(1,i)-aver)^2;1 E' a" S& i, b
end
2 x, `5 {: w) ks12 = s12 / n;; _2 F; M# o4 G6 N( ]
s12
1 v& h3 ]6 j+ e( [) ks22 = 0; %求残差方差
( `/ {: d7 t7 n; l" afor i = 1:n
/ m" `' h5 f; F. x' x+ s s22 = s22 + ((X0(1,i) - XX0(1,i)) - e)^2;
4 s' @( C. P1 Q- `% G/ \* tend
q, G' }) X: a' @$ _- Y; Rs22 = s22 / n;
8 l# n4 }8 m; y! U) ps22
. _: g6 N V2 l+ B& GC = s22 / s12; %求后验差比值
* n. g4 W5 _9 l: F0 I2 X" JC3 b4 ]9 y; ^/ q& ?7 v$ t) {) `/ ]
cout = 0; %求小误差概率$ U* [5 T. l+ E7 y& A( Q! E
for i = 1:n/ H$ ]5 i: C4 G1 C2 e! s
if abs((X0(1,i) - XX0(1,i)) - e) < 0.6754*sqrt(s12)" d" {5 I" _0 e/ l. L- ^2 f
cout = cout+1;0 n1 R* Z5 M8 ]$ a! t0 Y8 d1 p
else
) i0 z4 C8 r* a, e cout = cout;5 e* D0 t q0 x: d7 o
end3 c* M! J! W3 ]" W" A1 @
end5 x* \$ f/ n! c3 M; N9 M7 {- Y4 p
P = cout / n;' F9 l" v+ h% ?$ M
P/ X3 M7 X6 m" a. B6 b- V8 U
if (C < 0.35 & P > 0.95)' E- y5 U+ h5 N( W
disp('预测精度为一级');
1 a% a7 S/ E9 X) P2 C9 @+ Z m = input('请输入需要预测的年数: m = '); %预测往后各年的负荷
! K' ]9 d) O! G+ J( E disp('往后m各年负荷为:');7 D5 c; _9 r* S: s
f = zeros(1,m);0 r) i. |( S# I: }0 n
for i = 1:m) x0 ?, s5 \8 Y$ t, Y; l6 A, w
f(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i+n-1));! \ s( q/ y" t
end
: M6 [2 n& `) O' M f: H7 [. x' I. {" {% _
else, h9 b. {: t2 X% r
disp('灰色预测法不适用');
" x {7 }0 h: P' X& I: tend |