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function SGrey
! E0 d9 K0 g2 ~4 ~5 \0 b* v7 Z6 ?: b# L: V( I
X0 = input('请输入原始负荷数据:'); %输入原始数据' K/ v( e: ?$ Y5 d# v% f, M
n = length(X0); %原始n年数据
. Y7 ?2 @/ |. Q4 d! B0 i1 Z+ ]8 n k2 y# u3 g
%累加生成
, ?- a0 Y8 F# v" A' ~2 i4 yX1 = zeros(1,n);
$ O$ z# w+ j4 M* vfor i = 1:n
/ ~* F- x9 n8 @ if i == 1& w/ P+ N: z, \
X1(1,i) = X0(1,i);: }5 P* M4 Q8 ]0 g- ]7 p# n6 |% p
else; m$ J" y! I5 N+ \7 \* F3 H
X1(1,i) = X0(1,i) + X1(1,i-1);
. W* q; N- _3 r5 c" a1 \# P. Z end
$ N$ _0 Q/ d2 r' i2 fend
! Z; ^5 O+ j& s! N1 x. ~X14 ?* ]) r5 O& A! P( X
" c$ n% @* Y5 T* N" S- K%计算数据矩阵B和数据向量Y1 L8 Y w) Z. H9 k/ R B
B = zeros(n-1,2);+ \* i0 }9 E. U" u& X3 ^+ w
Y = zeros(n-1,1);
& \9 T; [* R8 f4 Bfor i = 1:n-1( V& ]2 z) Q" F& e% R3 c
B(i,1) = -0.5*(X1(1,i) + X1(1,i+1));9 z/ ]/ d @# W* f8 ?3 b" x) i
B(i,2) = 1;4 _1 z4 i/ |5 p
Y(i,1) = X0(1,i+1); }$ Z% d8 G) K( n) Y. \/ o7 L
end1 _3 |6 B% g {; g) F& b" e9 q
B,Y
8 q' `8 f2 @+ ~& A5 c6 |' J/ n" W6 K/ D
%计算GM(1,1)微分方程的参数a和u, {: t4 y( D6 ~/ g/ O
A = zeros(2,1);0 E( F4 ]/ P+ {
A = inv(B'*B)*B'*Y;1 B1 Q8 V, _: x4 r3 s
a = A(1,1);
I/ @; B6 V9 y/ R- Z5 z, Au = A(2,1);
! y* E, L4 l: i+ P- \+ e1 D1 h# ^, }a,u) O* @! X% ~+ I
; a* |# ^6 P0 x%建立灰色预测模型, m% @+ ~4 r% S/ N2 C' I
XX0(1,1) = X0(1,1);
/ I- g$ I* f# w( e9 Afor i = 2:n
+ K2 x" @* S$ [9 q, } XX0(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i-1));! G' h. u0 i+ |$ b
end! l) {/ |* ]+ z+ `
XX0
$ Q1 h% A" k# P8 J" G%模型精度的后验差检验
5 e9 ? i, v, w2 ]/ C! ?e = 0; %求残差平均值/ {8 r, y8 Z( P& J d+ @
for i =1:n
s1 t$ D/ M) Q2 K# j$ r: I e = e + (X0(1,i) - XX0(1,i));% d4 L0 X: n4 d$ C- t1 o
end
+ Q$ l# @1 y4 j6 H, M0 xe = e/n;
* Y; D4 O4 M+ R$ S/ H$ D2 i2 S( be6 d; Q/ t# j4 [
aver = 0; %求历史数据平均值
! F' W) v/ \ Efor i = 1:n% R* [: x- Q; K
aver = aver + X0(1,i);
% z2 d% M0 S1 A3 @# D, g+ q' i+ rend* J. @7 U7 w, U- [
aver = aver / n;
' W, L0 l/ o( p0 y3 [7 m; A& l) Xaver7 ?* g. R' l( |# L- Q) v
s12 = 0; %求历史数据方差
: I, Z" w0 ?0 O) n; D! [for i = 1:n9 c0 P* n8 ~0 v8 J* O8 m1 X
s12 = s12 + (X0(1,i)-aver)^2;
1 f5 M) q0 g9 k) Vend
7 b0 \( u! O/ m8 Us12 = s12 / n;) J! T) l' P9 z0 {
s12- |; q# i7 v6 Z2 [! I+ D
s22 = 0; %求残差方差
" Z+ y2 L- e- B& pfor i = 1:n1 R* S; X# m' k' X
s22 = s22 + ((X0(1,i) - XX0(1,i)) - e)^2;
3 ~1 ~0 \$ h3 Dend8 `5 \+ M' F0 C- n- }
s22 = s22 / n;
: A& @2 `7 l4 R7 ~) ^7 `, C6 Bs22
2 e) F% o) R6 Z9 OC = s22 / s12; %求后验差比值" T5 k3 @! p( ]& G
C
1 ]! `( g1 D) D" i2 V8 wcout = 0; %求小误差概率% J6 k L# x: r7 H, h2 x4 _
for i = 1:n0 a) o* [; d8 I' R3 Y% h" A
if abs((X0(1,i) - XX0(1,i)) - e) < 0.6754*sqrt(s12)
' D5 r n9 }# s) C0 O4 G2 V" @ cout = cout+1;
% g: {' G& _1 d% r8 [8 B" G else
$ G4 c& g. k( \1 R3 c* [0 C$ m8 v cout = cout;
+ {' }' m. H" h end
+ q; Z* S5 _. A' @end
& p$ `' w: {8 r! I+ tP = cout / n;
5 x6 C, x. J0 u H6 ?9 F0 d, H* E* `; kP
$ b F( S) a5 Q( G1 C% }9 g% Iif (C < 0.35 & P > 0.95): J9 K( s* [& ~, m$ R9 M1 K+ c
disp('预测精度为一级');
1 W m1 V0 n: l- d9 s) @! Z m = input('请输入需要预测的年数: m = '); %预测往后各年的负荷
`2 c& y- V3 J( ]% c8 @: p# v disp('往后m各年负荷为:');
7 U; x9 j7 ^2 H+ Q) e7 b f = zeros(1,m);) m/ u6 |7 \ S& [1 z
for i = 1:m
3 C8 T4 ^1 R f$ d f(1,i) = (X0(1,1) - u/a)*(1-exp(a))*exp(-a*(i+n-1));, @ H. K1 x0 N' F# t: f
end
q. H1 I+ K m$ L f5 @! y6 l3 U% \; v3 x
else
2 z8 r" B0 j3 [! d! z, k& l disp('灰色预测法不适用');
' ^1 J8 o8 p) T* `end |