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ATPDraw运行时的error. log 如下:- v7 S4 K$ o# s* b; ^
8 K- A& a) l& `0 r
7 L1 _5 G; C8 x% d8 o* L, W+++/// Caution. Disconnected subnetwork. During the Y-matrix elimination for phasor voltages, a near-zero diagonal element6 |7 g/ [$ i- T# X$ J2 g$ Q
for node "XX0013" exists just prior to reciprocation. Statistics follow: Original ABS(Ykk) = 0.00000000E+00,* p x( m1 a* j
questionable value = 0.00000000E+00, tolerance ratio TOLMAT = 1.00000000E-08 . The node in question might be/ V% t- r4 I* P- q
connected to other nodes, forming a subnetwork, but that subnetwork has no, or only very weak, paths to ground or: H7 n. e" D- ~6 @
to any other known voltage node of the steady-state network. The solution voltages for this isolated subnetwork
3 j0 T% e( x/ p9 G1 y will now be set to zero, as the solution continues., o, `+ Z# o3 ~# H9 I
+++/// Caution. Disconnected subnetwork. During the Y-matrix elimination for phasor voltages, a near-zero diagonal element
% g( D# w/ A) c% W" n0 }8 ` for node "XX0003" exists just prior to reciprocation. Statistics follow: Original ABS(Ykk) = 0.00000000E+00,, f0 N" q0 g" }- n
questionable value = 0.00000000E+00, tolerance ratio TOLMAT = 1.00000000E-08 . The node in question might be
* ^5 d9 f* a7 Y- ]3 |# d connected to other nodes, forming a subnetwork, but that subnetwork has no, or only very weak, paths to ground or9 H" C4 R3 [1 _5 T" N2 v l1 p3 v
to any other known voltage node of the steady-state network. The solution voltages for this isolated subnetwork
8 U2 `8 w8 `+ M" i& ~3 P will now be set to zero, as the solution continues.. ?8 I5 ]6 j. P" o7 n& q
' M4 z7 h4 `8 ]# ?1 O/ \, K. O7 a( u1 l
5 h- n& v Q/ i1 z _
有没有高手遇见过这样的问题呀 这里我仿真的是电弧模型 |