ATPDraw运行时的error. log 如下: 4 i9 v# G6 @6 I( ]* c Y; W3 h! h* z+ o
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+++/// Caution. Disconnected subnetwork. During the Y-matrix elimination for phasor voltages, a near-zero diagonal element : ^2 D& E# t- U* s for node "XX0013" exists just prior to reciprocation. Statistics follow: Original ABS(Ykk) = 0.00000000E+00, ?* U# a9 n& i% x2 i; I8 q$ e questionable value = 0.00000000E+00, tolerance ratio TOLMAT = 1.00000000E-08 . The node in question might be5 Q* s7 S3 g& {: F4 Q4 _0 N
connected to other nodes, forming a subnetwork, but that subnetwork has no, or only very weak, paths to ground or& ~3 p; f7 C& `
to any other known voltage node of the steady-state network. The solution voltages for this isolated subnetwork ; w: n; j: P' X# @1 q will now be set to zero, as the solution continues., o( U, B( U8 m+ E* u
+++/// Caution. Disconnected subnetwork. During the Y-matrix elimination for phasor voltages, a near-zero diagonal element6 c3 K% w# v r1 \
for node "XX0003" exists just prior to reciprocation. Statistics follow: Original ABS(Ykk) = 0.00000000E+00,$ A6 E! ?4 P- r# r" f' S2 ?
questionable value = 0.00000000E+00, tolerance ratio TOLMAT = 1.00000000E-08 . The node in question might be 4 n, n+ Z% m2 l$ W- y' J connected to other nodes, forming a subnetwork, but that subnetwork has no, or only very weak, paths to ground or 2 S& O" s7 I' d. t' p/ I* z to any other known voltage node of the steady-state network. The solution voltages for this isolated subnetwork4 ^6 n" ~7 s) O7 [
will now be set to zero, as the solution continues. 0 R5 |" @* o& T4 l1 @1 N8 L( {7 M8 ? T; b. K) {: A& E
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有没有高手遇见过这样的问题呀 这里我仿真的是电弧模型