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按照ATP的rule book中RB—19E的DATA BASE MODULE部分的例子填了卡片,但不知道为何不产生.pch的打孔文件,请教各位达人可知原因,不胜感激
9 b: g! y0 _, h% H! KBEGIN NEW DATA CASE ---- NOSORT ----
0 D# O j. I+ x. `8 O& NDATA BASE MODULE6 q9 m* D3 Q4 w0 [ O0 ^0 t
$ERASE/ `; \# x+ A8 w" L5 ] \8 ~
ARG, _NODE, _MINUS, __PLUS, _FIRE,RESIS,CAPACI; s9 G6 ^+ @0 e) J# r
NUM,RESIS,CAPACI5 B [; q1 y' ?: `! l$ L9 X* V5 j8 Z
DUM,__MID1,__MID2,__MID3,__MID4,__MID5,__MID6- b& E) E* j. r8 Y# E
/BRANCH
% d* ^; p- K! A# S- F* s- S: x7 ZC3 Begin with anode reactors and parallel resistors (6 pairs):
2 e( Z# b& h% Y# w4 R# H2 J& G _NODEA__MID1 RESIS CAPACI
7 j n1 S) j& J _NODEA__MID1 1.0
/ g% W" X4 {$ D/ _5 t6 G _NODEB__MID3 RESIS! K0 }" d; y: w+ V, u% S k6 y
_NODEB__MID3 1.0
3 x! A5 I3 e, n: ^( V- e _NODEC__MID5 RESIS
2 ^' l( n3 z* b4 E3 }+ t) X5 y _NODEC__MID5 1.07 W$ X. a- j, p( e5 s
__PLUS__MID4 RESIS
9 c/ c/ R t8 g" t$ l. { __PLUS__MID4 1.0+ C2 J0 Q6 F+ n0 B; @7 x
__PLUS__MID6 RESIS/ X* r% d3 j, n3 u. n& }* F2 T
__PLUS__MID6 1.0
+ z1 }/ S( O9 o3 A* { __PLUS__MID2 RESIS % F! S# D. Y M% Z' b
__PLUS__MID2 1.0, J5 x; ~7 t& q6 f
C3 Next come the snubber circuits, across valves and anode reactors:
* v& Z; w4 T3 {+ W+ t3 p9 u _NODEA_MINUS 1200. 0.1
; ~+ l1 `- G/ P0 } _NODEB_MINUS 1200. 0.1
0 L7 d" K8 v; c2 B, w _NODEC_MINUS 1200. 0.19 v9 L+ e9 Z% v9 l; c
_NODEA__PLUS 1200. 0.17 f% M1 P/ R3 b N) h" Y
_NODEB__PLUS 1200. 0.1
* O- J' T7 o) v* j; T: [ _NODEC__PLUS 1200. 0.1
; j2 o/ |$ Q+ fC3 Next come the valves:
1 [7 r6 @6 p7 I- @ p% w2 S: q/SWITCH
9 J$ j' ^( ^0 l0 [" {4 Y" c. V' G11__MID1_MINUS _FIRE25 x% X) Z9 M' a) s
11__MID3_MINUS _FIRE4" f6 t* @) q# i; O
11__MID5_MINUS _FIRE6
C( S9 Z* r9 M" _- w11__MID4_NODEA _FIRE57 e* a! u& K( ` C
11__MID6_NODEB _FIRE10 ^# |, o8 V0 k% y. U* N3 V1 H
11__MID2_NODEC _FIRE3
2 T1 @: S2 \' H; }+ E5 }8 H0 [BEGIN NEW DATA CASE
4 G8 X5 o t; a* j, hC Just a comment card$ D# O( y0 J. R \
$PUNCH { Flush critical portion of answers from preceding first subcase
! R1 o# a3 B3 J8 h/ aBEGIN NEW DATA CASE
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