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例如这些结果是什么意思?
. e- M1 w6 H. n" l; LPWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-11
, x- e/ N1 U9 H! B; W7 `1 M$ K" P ~& l
A COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN 9 |. z% P: g1 |" R1 L4 G, e g
bus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S
4 G4 @6 F" C5 u* C bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9 ) ~# s9 I( F' }2 T& [. s
3556.1PNET 622.2QNET -0.9 SLACK ADJ
% J/ \% |0 \( A$ ?bus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE : H6 B1 I' d3 d& C S: l
bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5 3 S y. _; a5 w& x' B
-3000.0PNET 0.0QNET 7 P9 i3 P/ y' u
bus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE
# S" y% q9 N- [: [- Q bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0
8 E4 U/ ^6 F! T- S bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0
9 _' W$ g! R. X* z 0.0PNET 0.0QNET
; c3 @) G" V8 h, {: h1 g& u+ Nbus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q
$ `( b" g0 b9 g! J& ~$ Q bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9
3 v; O3 p4 J$ H+ q: A* m 1500.0PNET 16.2QNET # n- |6 u6 P" u' w
bus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE
" K/ [. K/ o/ P( ~* b bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC ' V" r3 n5 @1 r# R! J
bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0 ' M5 p2 p4 C9 e* ]8 o( K% M' ~! m
bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4
* N( g. U1 ^4 o bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4 6 R* t' D8 q7 ]$ o
bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4 , l, F, c; L, r& `+ X; j
bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4
# j, x; l8 u8 V. N1 b$ ~; Y bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4
9 X O _$ X+ @0 ~! B6 f/ P; z 0.0PNET 0.0QNET 6 J( H/ i) B# P( _ X) d& N
bus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE , ~4 o1 b6 I$ y1 G: D5 q
bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC $ L# @2 @: J! Z+ }1 D5 I
bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7 3 [! B4 M# v$ y! k
bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7 . F8 a4 _1 F( C0 t W
bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7
2 ~4 b' F# f& N0 Y3 ^' l$ ^ bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7 & a' i5 L. ?: i9 D4 i# B+ |! J' Z
bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0 7 i5 O9 X% n" n
bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0 ! [$ _% p) `, S% N+ [, V m
bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0
& j' B! G; [8 [3 m+ R 1011.7QUSED 1011.7QCAP SCHEDULED
. X3 }, U2 a5 V! \6 l- W- Q; l 0.0PNET 1011.7QNET " C0 l4 I4 L) M6 j' e
bus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q C1 Z7 x) w+ Y8 i' D9 L+ H
bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8
. U" }( D( |( I) S7 i% p6 i 1094.0PNET -1.0QNET
( K. X. V9 |- x8 bbus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE : Z! ~8 k$ Q, v+ E1 Y/ u+ c |2 Q
bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6 + S$ k1 U" e H( H3 E1 w3 I& V: o3 T# z( x
1497.4QUSED 1497.4QCAP SCHEDULED
$ N; D$ G0 s- l ?1 v) y3 T -3000.0PNET -302.6QNET ! s2 U/ @5 {- |& C
bus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE , R$ p. i: |3 _& j8 }' _/ S! u
bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0
5 V4 I$ S: }. l s2 E bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0 ' ~: Y6 }+ E9 g" _5 r
307.4QUSED 307.4QCAP SCHEDULED
6 A1 U; D% B% {" B$ u A1 y' S 0.0PNET 307.4QNET 5 e O6 o1 j" w
bus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE
+ r( j- M- e1 K* ^! x- l bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0 4 ]( p9 Q/ Y2 l4 }, ?* C" q
bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0
& i9 t. @' C( W5 O7 X+ R 0.0PNET 0.0QNET : K" t: K8 p& U0 U7 F0 w* |
8 L, l$ w# J2 ~, r
\# V# n3 w( N2 L实在不太懂,还请会BPA的网友教教我怎么看这些信息。 |
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