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例如这些结果是什么意思?$ i* j A; a7 w& M, T0 l
PWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-11% ~& L/ o; l% c4 }0 C# W0 R
k' z2 I( j7 a: g, w) a2 l! `( RA COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN ' n, ?2 a r& O9 M1 e4 I9 f' Y
bus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S + @% H7 {* P+ p7 ?6 W9 [
bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9 " g& {& C: g8 g+ G3 D0 L
3556.1PNET 622.2QNET -0.9 SLACK ADJ + v0 U* w n, J1 C
bus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE
1 E* j* y5 ]' u/ ]: Q" b0 U bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5
* B. I6 N# }7 ?7 G -3000.0PNET 0.0QNET
9 a( X9 P4 `% N1 P' `bus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE
( e( Q K8 J" D" G4 i bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0 3 N: `0 w" s: R: G* S* _3 v3 y
bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0
! G! a! h1 {$ @: D7 V 0.0PNET 0.0QNET
0 b% H/ u( y9 i# L: `3 bbus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q
! }$ z0 F* I$ [9 C bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9
- D& A& l; p7 h- \% H2 d/ Y 1500.0PNET 16.2QNET
8 q& r. x% [8 \, f$ T, y# R1 Mbus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE . B( p& w- L0 E( [
bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC , k0 w! J" q/ C [
bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0 * n9 x1 L; w8 @ G: e7 {& M
bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4
0 d+ H! V2 H% \1 ] bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4
4 t3 \6 e" v4 @0 [ \+ v bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4
+ E; t1 P- j$ U bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4
' \; _+ T1 ^6 F3 ?0 i5 [ bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4
8 \, ^9 [4 Q4 v4 Y0 u) x 0.0PNET 0.0QNET ! f& A) o* W( O, I0 ] g
bus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE
# a% N: v& i6 X' { bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC ! A: Q( \9 o# N! q$ C3 j
bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7 & T& f, N/ U; |: k) [. \
bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7 " g" w7 {$ Q3 \( k
bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7 . x) |! z" a5 w( T! \
bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7
) g; Q/ q0 `3 u; ~/ {- C. i6 T8 y bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0
" e0 t- ~4 ~% i. |& d: s- G bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0 5 E; F! O5 ]6 W3 A0 Q& ~
bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0 , ?+ B0 r2 l) \/ e' p
1011.7QUSED 1011.7QCAP SCHEDULED
" _, S6 v0 m1 l6 ~ 0.0PNET 1011.7QNET
( ^8 }2 Z: ]4 q' X( }) l6 Ibus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q
$ O* z. p4 p8 I5 P( u bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8
% Y4 K8 }$ O2 z, Y( D 1094.0PNET -1.0QNET
7 m, `: s. p- _) W: Q+ ~9 I9 {3 zbus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE / U8 b! T# f! @9 Y p0 B
bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6 t( j8 F% s( P5 ?# |. u
1497.4QUSED 1497.4QCAP SCHEDULED
# c9 r G; g8 P# B# { -3000.0PNET -302.6QNET
8 K" u0 \( ]- f& C, zbus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE
/ v. h- Y, k5 q bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0
0 {* ]5 g$ o6 ]+ R bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0 $ ]& _. F0 W# U% T4 \ D; [! ]
307.4QUSED 307.4QCAP SCHEDULED / `$ b6 F2 k+ t! U+ @4 {" [9 P
0.0PNET 307.4QNET ' u+ k5 U0 ~+ ^4 e9 d% H6 F% X- N
bus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE
1 @7 G/ _, e# c+ a5 g bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0 - k, G# w* d& M* D% E7 R
bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0
5 C, \, k: e8 ~ I 0.0PNET 0.0QNET 0 L) y' O% j- D C4 Z
/ Q/ c. r8 l" L; C4 k3 Q, c8 \
% G: ~, X6 O6 n' J' M( l9 U实在不太懂,还请会BPA的网友教教我怎么看这些信息。 |
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