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例如这些结果是什么意思？9 B0 F8 ~3 H& Y( |/ E( ?
PWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-11
/ {4 O! z% m+ c% w! s, ]" g! t" E4 f0 Q4 ?
A COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN . l% Z3 j+ A6 C! {: P1 i9 c
bus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S 3 P4 X4 |9 r8 ~) K2 ~2 S
bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9 2 B9 [1 J7 {" x1 W
3556.1PNET 622.2QNET -0.9 SLACK ADJ
2 D* M9 ?2 w# q- ~. Hbus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE
! a: K& v1 q; r6 |1 V bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5
& j# M- \% ^, `% A, x, @, M* s -3000.0PNET 0.0QNET
1 {7 K' f0 Y- @bus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE ' [" u" K C8 R) P$ S
bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0 ; V( M* |/ X- o1 r9 u
bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0 8 r% V5 v; A# T! q2 K4 D$ X
0.0PNET 0.0QNET - K8 r* W7 C7 x! u( T0 f8 }; w
bus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q ( f2 Y4 @( P( v% G1 @
bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9 : ?2 J1 i5 X; `' y) ]: M/ {
1500.0PNET 16.2QNET 6 e4 x7 v5 ~ ?3 S
bus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE , o8 }7 c8 `% o6 X; r( X
bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC # r+ q2 \6 K& J6 w" J8 E3 A
bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0
$ e1 {" v8 V" Z1 h) d7 s bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4
) x1 `( R' D' U6 H E, u, k( h bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4
4 Y: _9 F2 h1 V, G! x, w* E bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4 + f( n( |* U5 v' {+ l, H) O
bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4 7 L: `3 N1 L1 }
bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4 . m5 ?4 P) u9 C N4 Z
0.0PNET 0.0QNET ) Y3 d+ |1 Y" ?" d( P0 ^& m
bus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE & B, T8 y5 i0 X: d( i
bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC 6 Z0 q+ T0 [( M8 q1 p) u! Q# C
bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7
5 E4 Q9 F5 d7 a bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7 $ F5 p/ p" G& |7 }
bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7 9 U5 a2 b( A/ T& S* P3 n1 ]5 @# w
bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7
8 O7 `2 k" _2 _+ m5 d; N" u6 G bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0 + M* B0 w" m( B+ w
bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0
* ?6 ~6 b+ \! v" ^ bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0 1 w0 I0 P! u/ q. g7 W. F
1011.7QUSED 1011.7QCAP SCHEDULED
6 M2 N5 @5 b- F# T6 U 0.0PNET 1011.7QNET 6 E- z4 f2 V: t) Z) ^! F! v X* J
bus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q
0 ? e. b1 H2 \5 U+ C$ q' m! N bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8
& w* ]% V' t% Q. Q+ w, P 1094.0PNET -1.0QNET
- p4 a+ T7 }, T$ Sbus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE
1 m$ L/ B, V" A# m% x2 X; x bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6
. Y) d o# [* b 1497.4QUSED 1497.4QCAP SCHEDULED
. ~% D& p ~3 E& ] -3000.0PNET -302.6QNET * `, W, Z- ~$ S# k! J4 l' ~/ Q
bus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE 6 m3 D2 \- M& H7 a8 O0 q
bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0
; g: `' l! `# d, _& B( J bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0
* f* Y; H, B" K9 a3 i 307.4QUSED 307.4QCAP SCHEDULED
! h5 r, D9 _2 t; X' x 0.0PNET 307.4QNET
/ v9 B- ]* l' h! Xbus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE 7 Z9 s6 U& l% P
bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0
" a3 P. v9 a2 _" A Q1 l. l bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0 0 V4 ]3 ?6 a8 b: h: k
0.0PNET 0.0QNET 8 j' d" i: I: e d5 u) W
. ~% h6 ? x- m: G8 N( c- q
5 {/ Q/ y4 C3 q7 h9 l! }实在不太懂，还请会BPA的网友教教我怎么看这些信息。 |
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