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例如这些结果是什么意思？
9 M# h" g" m. w; b J* k& fPWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-11
) l9 i# ~( J# A* a
- u- h8 L m3 gA COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN
8 a! V# H6 d! _1 q ~/ G2 W8 T5 @; Wbus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S + A6 W8 b d9 M8 ?- u
bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9 - \( }+ I4 F- d" G* c
3556.1PNET 622.2QNET -0.9 SLACK ADJ 7 l' B6 z5 s% g: o/ G7 z7 a
bus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE ( }$ x9 A# S/ ?2 I' i0 ?
bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5 2 r* I, P0 s5 x: h' m7 X
-3000.0PNET 0.0QNET
/ C7 ]1 C3 i8 hbus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE
5 `& ` {0 ^6 u n bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0
; S8 M( F& b+ L; E/ j bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0 4 ]8 J0 s& K- \0 K/ G
0.0PNET 0.0QNET 2 B$ ^, Z1 r3 i- X
bus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q
& ^6 [6 k% C3 C( g z bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9
: R# o; q3 z* w3 [1 I+ { 1500.0PNET 16.2QNET 8 a" g( z8 g* K7 p# @
bus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE 4 t& L' b# @. x; _4 W w
bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC 7 {, |/ G0 \* n! m
bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0 2 ]% r$ w) q' K7 V M8 i
bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4
$ T3 U; Q; o. E bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4 - i0 f4 i, i/ E3 i( `
bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4
4 P( R% N% r2 m2 N) ^$ o T+ L A bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4
& R {- v; x9 O8 c1 Z bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4
8 M5 `( R& Q/ \- ~+ v 0.0PNET 0.0QNET , d) {6 U4 j# _3 T( g0 @
bus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE $ N! ~* U+ n6 b: Y
bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC 7 _: H: E" G3 i! ~ E
bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7 7 Z. U* T0 B O% x& r `* `
bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7
; `) w: T$ ^$ P3 B9 @+ \* C) L4 I: R bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7 0 o* c8 p1 ?) y5 p1 L
bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7
# g1 w0 s3 n# U bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0
+ E1 D! Y2 j$ \/ v bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0 7 {# ?3 u$ i4 m# L9 v5 X; m0 S. ?) D
bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0
0 j' K* J* b; G4 n 1011.7QUSED 1011.7QCAP SCHEDULED
1 \3 w; @9 Q. N0 z 0.0PNET 1011.7QNET
1 {- l8 A5 p1 j/ k' mbus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q ! {8 r/ [3 i" h; s$ O6 U9 w/ x
bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8 : K& X# G' w% A1 G8 i+ l
1094.0PNET -1.0QNET 1 I8 Z) S* s! P! @8 ?% a2 G! c
bus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE $ N6 y0 N3 E+ S0 |
bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6
3 ? w6 Q$ M# e0 O( p+ h 1497.4QUSED 1497.4QCAP SCHEDULED
# p5 J" X: z: ~( n7 s -3000.0PNET -302.6QNET
6 k! k9 B. M& j/ f% x/ Ybus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE
) {" }9 d+ J7 E, E$ {( e bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0
$ I ~8 S; v1 b) I6 @ bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0 ) V9 m& N" ^; F2 G% U5 Q
307.4QUSED 307.4QCAP SCHEDULED
7 ?+ y& h! D. _9 T# Z' u S% [* {+ N+ K 0.0PNET 307.4QNET
7 c( A& I/ f, ` F {' G, H7 I) sbus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE : V2 E( h, Z/ `. {3 c( Q
bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0
! L) n) c0 r/ _8 | bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0 # F0 {( B# k+ k; u" B. J
0.0PNET 0.0QNET
5 R0 g0 T7 D- W$ ]2 ~7 p6 ]7 ]! P* D* D2 O
2 m& f; U: a0 [ b; h
实在不太懂，还请会BPA的网友教教我怎么看这些信息。 |
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狗仔卡
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