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例如这些结果是什么意思？0 Y& H: U; F! O. H( ?
PWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-11
8 k2 @0 L, J" s' a- V) n: B
- Z8 y3 x. l( [% p& X5 VA COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN 1 m% J' g9 i8 Z; q/ n
bus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S . L% D% y( Q" m6 m# C
bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9 & x! e5 c8 Q" K. e
3556.1PNET 622.2QNET -0.9 SLACK ADJ
0 T, b! X- J3 `9 Xbus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE
; Y1 }9 D: J& a- ~) S bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5 " v# _! ~- }/ e. ^2 z, A
-3000.0PNET 0.0QNET / C+ m' t ]6 h) t
bus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE
9 Z% |" F; R+ z1 D- { bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0 / }" {1 h! `0 X
bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0 5 H3 n5 `% M' c. y% c4 O; `
0.0PNET 0.0QNET 2 m) P1 G6 m$ {0 h
bus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q
( ~1 s( Y0 e+ \! J: n bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9
# d1 G/ X9 O+ u+ ?7 ]# Y 1500.0PNET 16.2QNET 6 t8 B8 h% j g; n
bus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE % g5 g$ J" Q6 e; ~2 d# o- C1 d
bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC 0 x# V" a7 u3 n+ d2 q/ t
bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0 & D" a3 p# N1 C: Y) K
bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4 / |6 x. b3 H2 J# {+ E8 e' Z
bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4 ( U5 I) a% Z+ d4 [7 c/ Y
bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4
% o/ `0 b3 o# p3 V' P. a; {0 s bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4 6 n- k3 X: X- i9 y4 u; i
bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4 - m7 r7 S( ~' @- e8 I$ e
0.0PNET 0.0QNET 4 ^& V J( T5 z5 h. t! N
bus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE * W, A' D, [& H- \1 V
bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC , O# A! j* ~6 ?9 ^6 p! Q
bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7
+ @! M0 T! J8 J4 \+ O bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7 ' N( u: F2 P, B
bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7
& y, F3 d' Q1 D0 ^' d bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7 " e [' [( n: V$ O P/ C* j' ]
bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0
! ]/ i9 d4 [- ^* P) w& w8 \" Z, M bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0
0 Q* U& T+ P' E) u+ E8 o7 @ bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0
, W- K* ]% j" W8 f: Z) @. `6 u 1011.7QUSED 1011.7QCAP SCHEDULED
% }- }* A2 t& ?$ M, ?) W 0.0PNET 1011.7QNET ; W$ [7 S0 |4 I. V( B) O4 A
bus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q 7 `4 m- c+ F8 _; A
bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8
: @$ H" B! U8 p' j$ w9 t, Y 1094.0PNET -1.0QNET 9 e6 f$ S* ~: p, r
bus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE , |5 z+ n. u) S. v1 e
bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6 & ~/ |% w( N, i! X6 Q, G+ E
1497.4QUSED 1497.4QCAP SCHEDULED
7 r, Y+ V$ Z3 v, c -3000.0PNET -302.6QNET
$ w; t, ]- J: \) H6 l7 J5 `) L. Nbus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE + p# G* N4 E; ~& Q. G' K0 Y
bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0
9 X n; x/ D6 W% r1 W0 U* B, x& Z bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0
- u; s+ q' b- M+ t 307.4QUSED 307.4QCAP SCHEDULED 2 L3 G( O- X0 V% }- ^& B1 y
0.0PNET 307.4QNET 0 e1 d7 h8 c% j9 v9 X
bus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE
7 {: R' ?) x' V; [ bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0
_5 a1 Z- E6 w3 \/ o bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0 3 R5 P, z; b4 D% Y2 p
0.0PNET 0.0QNET
0 o: G+ T9 o+ c% X% L
5 t K' N" z- S9 I5 V; g( W$ z3 c2 L7 R2 @' \( D$ J' a" Z
实在不太懂，还请会BPA的网友教教我怎么看这些信息。 |
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