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例如这些结果是什么意思?
$ x& i/ _- h2 m& u, pPWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-11 T+ X0 v2 \( W9 o" D
2 t; M8 @! c/ C& x: C
A COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN
0 u( G6 w; w2 y, Rbus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S
3 X- G9 u8 r. w- l1 m bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9 0 Z/ i5 \/ b' L" K
3556.1PNET 622.2QNET -0.9 SLACK ADJ : E2 U3 a/ f- `/ }/ n0 w3 Y
bus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE
* U+ G ~% V5 L; \ z5 }6 i bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5
# z$ P+ ~2 Y* c* d" H1 J$ N" K8 _ -3000.0PNET 0.0QNET ' o5 f. j( e |1 A
bus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE " a) \8 V% e+ `% A$ q
bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0 0 E- o* Z$ R2 l: S
bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0 : ?+ H( I2 t" n: ^ H2 {( G" Q
0.0PNET 0.0QNET
* }( W3 Y8 l6 \! `0 a; |bus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q
) W* {/ U& y! X* X0 c7 ~ bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9 " ]/ {3 F1 }6 A' v
1500.0PNET 16.2QNET
& r G6 I- Q& q0 \; c% nbus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE 2 m0 E/ F, M3 M; ?& n
bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC
W; c: }$ n7 S- A5 V bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0
w9 W, l& S$ c- e) T bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4 2 n1 Y' c/ V0 S8 A( x2 h! G
bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4
- m% z5 y2 V+ a bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4
7 C p% R% {) b O; ^+ Y3 e bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4
. \4 {- X, ^6 {' E9 B9 M$ b bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4
& {% c2 E2 M1 w" j+ [6 U# C/ A 0.0PNET 0.0QNET
% ?$ ]3 ~" g, |& g# ]( Bbus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE & Y9 ~& n9 D4 i2 e
bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC ' h( ` q" h5 N
bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7 / p4 Y3 Z& G# U% t$ w& ~* C
bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7 4 b, ]. T6 y% z2 O4 N @
bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7
5 d- p9 l6 ^- ~ bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7 + G/ R- j6 F0 t
bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0
% i' v2 g' b; v: |# b5 s; J bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0
8 i# b( ]; S0 Z! Y# v! r1 }* A bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0 + H3 _) v+ |1 N7 |' W0 g8 o& v
1011.7QUSED 1011.7QCAP SCHEDULED 0 _* H. g1 M; m: ^. j: p
0.0PNET 1011.7QNET
! w$ b; _9 v) f0 }6 ~) _9 V/ obus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q
' `- y' v. ^4 c bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8 2 Z" V% F) |/ H0 w- b; G
1094.0PNET -1.0QNET
9 |0 v0 g1 P2 ^' O3 h0 ~* [/ ]1 ibus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE
' u: E" C. m+ p1 o1 h g' X7 N7 M9 _% g bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6
# L& p' V' b& f 1497.4QUSED 1497.4QCAP SCHEDULED
* [: y; y; ~) h! s$ g -3000.0PNET -302.6QNET $ g2 G* w: h q
bus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE " h) C- p7 p3 L& o- { w1 R- n+ B
bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0
) c8 \( e4 V l! d9 r3 P2 B9 O bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0
" e8 x' ^& e6 h- y3 \ 307.4QUSED 307.4QCAP SCHEDULED 9 }2 X2 |) i& B* x6 Q
0.0PNET 307.4QNET ) C! W) \$ q/ o' K& d
bus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE * @2 s& i4 n5 x
bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0 5 Z2 Z2 K f3 t0 S, v
bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0
) G: _& `6 a* T0 L: Z, Y* Y 0.0PNET 0.0QNET
$ `# b u S* m& k% x* T+ M# b( @: A
8 ]* o, o+ r1 S5 Z) Y6 d. ^
5 z. v$ c. z2 H0 g1 n1 D3 Z实在不太懂,还请会bpa的网友教教我怎么看这些信息。 |
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