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例如这些结果是什么意思?& Q3 j) K& v8 d+ n: x
PWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-11
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0 F; s& W- N- x* o9 kA COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN
8 H7 y8 L, {& ?! gbus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S g! N! I! {' @- R! q& R
bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9
# F( j) g& R1 ]+ p& K$ k% M 3556.1PNET 622.2QNET -0.9 SLACK ADJ
9 q+ [ o2 o, j- A! \3 j/ lbus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE
* G/ Y/ y6 _3 g6 ]: z8 V bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5
- t B0 E0 [3 m. M, T -3000.0PNET 0.0QNET
1 K% j- F v$ T) j, q2 i1 ?( kbus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE . z6 m1 A0 _0 M: ?6 h/ s
bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0 8 |5 z; j9 B2 p& d( V$ Z
bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0
2 }& Y& W& E! Q1 D: L9 X+ v 0.0PNET 0.0QNET " G4 _7 S9 p% J: k! b# e- M
bus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q
# r- ~3 Z$ ?$ f& q8 Y$ j* w bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9 6 r/ P9 [' Y4 m% ~& E2 J
1500.0PNET 16.2QNET + u2 v9 \# P0 D1 }2 E4 t" Y! z/ r
bus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE
$ J2 i- M4 @! H/ Z bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC 3 {: L; f: Y& F% q! j3 Z0 o& `: P
bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0
2 R% |4 f5 V* o+ M6 x+ `7 b bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4
9 j \0 E o4 h6 c; Y5 p, [% Q1 K bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4 ' Y/ d$ x' u8 d$ q
bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4 - e6 p: `5 z9 W+ E$ @" {& W% X
bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4
) t$ y1 b& ?0 q8 M! L) _ bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4
6 R- S- v. T! G, G6 k 0.0PNET 0.0QNET 4 d2 W' _( F+ f0 Y3 _* X$ ?' D
bus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE & R( K# e" O) E( ~" ?" D3 H* c% C1 e
bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC
- d) V/ f1 h, ?6 Y7 h! p0 s. x bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7
R$ Y$ x+ K, u. D+ @$ M bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7 . s6 L% ?8 O( ~, h, |4 q( v4 C
bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7
6 ?0 u' t4 z( l" t" h% x7 ]3 ? bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7 & [( v; t) `$ v5 d8 A
bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0 - X* D+ D$ m$ P O
bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0
$ U$ P4 M- Z" O; M bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0
4 o1 Z/ u& b5 D3 a 1011.7QUSED 1011.7QCAP SCHEDULED
d" \8 p0 `0 p4 y4 B 0.0PNET 1011.7QNET - v! \9 L; ?9 n% G/ A
bus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q 5 Q0 C C2 g4 K4 S6 g( `
bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8
+ p, y3 W) p' B2 }6 H 1094.0PNET -1.0QNET ! |. V, s" @6 B. |- ?
bus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE % V0 c6 z1 a$ }/ Y+ C3 {
bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6 0 l/ m3 r/ e1 f/ `9 e' r
1497.4QUSED 1497.4QCAP SCHEDULED 0 Z! [7 R9 V* J! D0 i
-3000.0PNET -302.6QNET ; B! u2 O! U9 F% h6 \0 Z& L3 |
bus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE " T. F4 P! i5 \, B' y- Y A
bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0 $ r) l9 B; M- H$ ? D$ ?
bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0 $ y, t& |, U& E$ U# [' O
307.4QUSED 307.4QCAP SCHEDULED ' |- ]* x7 @+ Y/ J: o: }9 T
0.0PNET 307.4QNET
4 Z" T) q6 }2 ^+ r8 u8 C& U, mbus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE + N, P. C6 x% { O6 r
bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0
8 t2 @' T( J$ k8 M( w) b bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0
* `( d# e3 w) U/ W# s5 T+ C 0.0PNET 0.0QNET
/ h1 B% y h. ]. X: H( C. A0 ^3 G" N" f/ e0 q
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实在不太懂,还请会BPA的网友教教我怎么看这些信息。 |
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