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用Jmarti模型的Lcc建立了一个输电线路模型，我想通过生成的LIS文件读出线路的电气参量R，L，C等，不知道可行否？或者怎么从LIS文件读取自己想获取的信息？谢谢各位高人，不胜感激！！！8 P: ?0 t+ E1 B. k- R% R* ]
====================================贴一段LIS文件，高手看看=============================/ E& {7 s" Q3 W( R j* M+ A
Comment card. NUMDCD = 1. |C data:C:\ATP5\ATP\TEST_LCC1.ATP
; B U6 [* W# G0 l$ F) H9 C# Z+ X* KMarker card preceding new EMTP data case. |BEGIN NEW DATA CASE
. q* \+ T/ H7 A' LComment card. NUMDCD = 3. |C -------------------------------------------------------- q8 E/ \$ S. |) o# D/ S! R$ j! [! T! v
Comment card. NUMDCD = 4. |C Generated by ATPDRAW 十二月, 星期二 22, 20097 Q8 x# f5 l* g& [
Comment card. NUMDCD = 5. |C A Bonneville Power Administration program
/ L2 b' n: u' fComment card. NUMDCD = 6. |C by H. K. H鴌dalen at SEfAS/NTNU - NORWAY 1994-2008, l3 y' a& n- E6 b/ |3 Y9 P, z& d
Comment card. NUMDCD = 7. |C --------------------------------------------------------
8 p) O9 c, p+ t2 ~6 lComment card. NUMDCD = 8. |C $DUMMY, XYZ000
, u, I# `/ b7 W) E0 _8 E' f9 YComment card. NUMDCD = 9. |C dT >< Tmax >< Xopt >< Copt >% d: G" r4 Z& Q/ \1 e6 l! {
Misc. data. 1.000E-06 7.500E-02 0.000E+00 | 1.E-6 .075
. l8 ~0 q6 r& r3 v6 }! ZMisc. data. 500 1 1 1 1 0 0 1 0 0 | 500 1 1 1 1 0 0 1 0
: T9 B/ B' S1 Z/ Q9 j* ]7 eComment card. NUMDCD = 12. |C 1 2 3 4 5 6 7 8
! k4 b" f4 k6 j rComment card. NUMDCD = 13. |C 345678901234567890123456789012345678901234567890123456789012345678901234567890
: U* }8 j0 g8 NComment card. NUMDCD = 14. |C < n1 >< n2 ><ref1><ref2>< R >< L >< C >
- n$ U5 j) r# [& i0 Q) E- N3 Z Q4 KComment card. NUMDCD = 15. |C < n1 >< n2 ><ref1><ref2>< R >< A >< B ><Leng><><>0& J v& G/ h6 w/ T
Series R-L-C. 1.000E+00 3.000E-01 0.000E+00 | XX0001 1. 300. 0
: A! b, C0 ~" \- LSeries R-L-C. 5.000E+00 3.000E-01 0.000E+00 | X0004AX0002A 5. 300. 0; |. f }: _/ T2 W0 X
Series R-L-C. 5.000E+00 3.000E-01 0.000E+00 | X0004BX0002B 5. 300. 06 c6 H' a2 h) g
Series R-L-C. 5.000E+00 3.000E-01 0.000E+00 | X0004CX0002C 5. 300. 0
, g( c$ i: k1 V; iSeries R-L-C. 2.000E+01 0.000E+00 0.000E+00 | XX0005 20. 0+ M4 N4 b% P! s! L o) y
Series R-L-C. 5.000E+00 1.800E-01 0.000E+00 | X0003AX0010A 5. 180. 0
8 F# \5 i; v9 x8 NSeries R-L-C. 5.000E+00 1.800E-01 0.000E+00 | X0003BX0010B 5. 180. 07 K$ C3 R" D+ s: J" x* ~6 B
Series R-L-C. 5.000E+00 1.800E-01 0.000E+00 | X0003CX0010C 5. 180. 0$ ?. T* r! t; i! M) K
Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0003AX0010A 150. 0
5 m$ O- c* J. p, p# S# E4 u/ [Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0003BX0010B 150. 0
" f3 D( C3 H/ _2 @; }0 wSeries R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0003CX0010C 150. 0 |& k2 v% F8 z% T) a" W: Y
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | NA XX0015 10. 3.E3 0. R/ l( q$ n# `: s L
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | NB XX0015 10. 3.E3 0
9 S( }9 J1 p5 w' I9 [Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | NC XX0015 10. 3.E3 02 T6 l( r% L8 W$ u$ @1 r" R
Series R-L-C. 1.000E+00 3.000E-01 0.000E+00 | XX0015 1. 300. 0
{ f& g3 K8 y" E, uSeries R-L-C. 2.000E+00 2.000E-01 0.000E+00 | X0010AX0014A 2. 200. 0
9 K; L" \' o. U7 }* l' s/ }Series R-L-C. 2.000E+00 2.000E-01 0.000E+00 | X0010BX0014B 2. 200. 0
. F( B0 J6 K: l5 r1 R4 |( }Series R-L-C. 2.000E+00 2.000E-01 0.000E+00 | X0010CX0014C 2. 200. 0
5 j [7 X$ s* ?" M3 E! Z/ B5 WSeries R-L-C. 1.000E+01 3.000E+00 0.000E+00 | MA XX0001 10. 3.E3 03 j; H3 {" X- p: J e' U
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | MB XX0001 10. 3.E3 0% h+ L: P! D; Y) I% a2 ]# @ n
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | MC XX0001 10. 3.E3 0
$ D9 H" }! y0 _ H$ wSeries R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0004AX0002A 150. 07 F; V3 V, y8 s" O1 i
Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0004BX0002B 150. 0
[# K! Z; M" M* ^8 _Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0004CX0002C 150. 0
. ]1 A& [, B- d i1 e' C# HComment card. NUMDCD = 40. |C $INCLUDE, C:\ATP5\Atp\LIN750_1.lib, X0013A, X0013B, X0013C, X0006A, X0006B $$
- |- f/ q( p0 E8 i0 r2 {Comment card. NUMDCD = 41. |C , X0006C# x5 M) z5 X( A/ l) B0 P* e
J. Marti line, mode 1 parameters begin. |-1X0013AX0006A 2. 0.00 -2 3. L" ? M9 V" }2 n5 i
J. Marti line, mode 2 parameters begin. |-2X0013BX0006B 2. 0.00 -2 3
! o% I* T. f7 O$ D5 rJ. Marti line, mode 3 parameters begin. |-3X0013CX0006C 2. 0.00 -2 3& E( k. q, A( k; r! T
TR(1,1 )... 0.584-0.707-0.421 | 0.58387433 -0.70710678 -0.42133648' P) v9 `; C. F( v
TI(1,1 )... 0.000 0.000 0.000 | 0.00000000 0.00000000 0.00000000* w: q! W' V# T
TR(2,1 )... 0.564 0.000 0.803 | 0.56407583 0.00000000 0.80308851( ?1 c; t: A" }7 v1 z/ J- M! `
TI(2,1 )... 0.000 0.000 0.000 | 0.00000000 0.00000000 0.00000000
+ A4 S+ i% {0 W2 TTR(3,1 )... 0.584 0.707-0.421 | 0.58387433 0.70710678 -0.421336481 \( R1 R) X+ d: t n: J
TI(3,1 )... 0.000 0.000 0.000 | 0.00000000 0.00000000 0.000000002 P3 b q! }, B
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发表于 2009-12-30 17:38:22
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