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用Jmarti模型的Lcc建立了一个输电线路模型，我想通过生成的LIS文件读出线路的电气参量R，L，C等，不知道可行否？或者怎么从LIS文件读取自己想获取的信息？谢谢各位高人，不胜感激！！！- e. m% a, [4 A- i
====================================贴一段LIS文件，高手看看=============================5 {: @, W' c& s% s) m7 A9 [0 P
Comment card. NUMDCD = 1. |C data:C:\ATP5\ATP\TEST_LCC1.ATP
/ r4 T8 W$ g7 X7 i7 G$ |1 sMarker card preceding new EMTP data case. |BEGIN NEW DATA CASE! D8 M; G* z4 l0 ~5 j# C0 a
Comment card. NUMDCD = 3. |C --------------------------------------------------------
5 j6 J8 X4 V1 C" _( B8 ~) l" B, ]9 oComment card. NUMDCD = 4. |C Generated by ATPDRAW 十二月, 星期二 22, 20097 y9 }' W1 B! }% E$ t8 U! T: C
Comment card. NUMDCD = 5. |C A Bonneville Power Administration program3 q( C! n0 y+ f3 G! M% F4 [* _
Comment card. NUMDCD = 6. |C by H. K. H鴌dalen at SEfAS/NTNU - NORWAY 1994-2008
6 O+ }. Q( l2 f) y' L- c- u; gComment card. NUMDCD = 7. |C --------------------------------------------------------4 H, S0 O9 x* U6 x
Comment card. NUMDCD = 8. |C $DUMMY, XYZ000
- x% A. ]& m2 R$ aComment card. NUMDCD = 9. |C dT >< Tmax >< Xopt >< Copt >
8 C/ ~0 A1 M5 Q! U3 N }8 W% K, W1 ]Misc. data. 1.000E-06 7.500E-02 0.000E+00 | 1.E-6 .075, s% S: N+ f$ |3 `" v
Misc. data. 500 1 1 1 1 0 0 1 0 0 | 500 1 1 1 1 0 0 1 0# S9 h2 L3 A. Y& |7 Z+ |$ `
Comment card. NUMDCD = 12. |C 1 2 3 4 5 6 7 8
: J7 k" p: j. r) B4 `- v# b( eComment card. NUMDCD = 13. |C 345678901234567890123456789012345678901234567890123456789012345678901234567890/ }2 z/ k, {% _" q. \
Comment card. NUMDCD = 14. |C < n1 >< n2 ><ref1><ref2>< R >< L >< C >6 X; o+ O E& F
Comment card. NUMDCD = 15. |C < n1 >< n2 ><ref1><ref2>< R >< A >< B ><Leng><><>06 ^% E5 g# X; x+ F
Series R-L-C. 1.000E+00 3.000E-01 0.000E+00 | XX0001 1. 300. 01 w# ?. p9 W4 p% A$ A% s
Series R-L-C. 5.000E+00 3.000E-01 0.000E+00 | X0004AX0002A 5. 300. 0# Q+ x- h7 p4 V% v1 b
Series R-L-C. 5.000E+00 3.000E-01 0.000E+00 | X0004BX0002B 5. 300. 02 S& E7 a) z: S
Series R-L-C. 5.000E+00 3.000E-01 0.000E+00 | X0004CX0002C 5. 300. 05 R0 m' ~$ w2 ]/ c. P2 E2 g8 g: \
Series R-L-C. 2.000E+01 0.000E+00 0.000E+00 | XX0005 20. 0
! m. w0 ?; _' tSeries R-L-C. 5.000E+00 1.800E-01 0.000E+00 | X0003AX0010A 5. 180. 0% c8 R% b) d) V$ L3 b
Series R-L-C. 5.000E+00 1.800E-01 0.000E+00 | X0003BX0010B 5. 180. 08 }3 {9 b5 U5 v% G
Series R-L-C. 5.000E+00 1.800E-01 0.000E+00 | X0003CX0010C 5. 180. 0
2 P( i2 q7 J# |" nSeries R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0003AX0010A 150. 0
, r, t1 }! M' {& SSeries R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0003BX0010B 150. 0
. G) X; S( }3 P D' \Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0003CX0010C 150. 0
5 k' Y) ~* J# {4 G0 hSeries R-L-C. 1.000E+01 3.000E+00 0.000E+00 | NA XX0015 10. 3.E3 0
7 E- B6 q+ s* D2 M( TSeries R-L-C. 1.000E+01 3.000E+00 0.000E+00 | NB XX0015 10. 3.E3 0& c( T8 j; i. b
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | NC XX0015 10. 3.E3 0
3 B0 q5 G8 k. r% G6 y" j) ?/ ^. V0 qSeries R-L-C. 1.000E+00 3.000E-01 0.000E+00 | XX0015 1. 300. 08 R6 s; t$ E# f: K7 y+ l
Series R-L-C. 2.000E+00 2.000E-01 0.000E+00 | X0010AX0014A 2. 200. 0' Z; Y; G' k+ Y
Series R-L-C. 2.000E+00 2.000E-01 0.000E+00 | X0010BX0014B 2. 200. 0) u2 Y! @$ o5 i2 ~3 r
Series R-L-C. 2.000E+00 2.000E-01 0.000E+00 | X0010CX0014C 2. 200. 0$ q( s* e, v/ g; |( i4 v! U
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | MA XX0001 10. 3.E3 0
! b: P+ |& h0 F! a9 ~Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | MB XX0001 10. 3.E3 0
. ?. {: ?% p0 X! t' v/ n* H* M/ c* TSeries R-L-C. 1.000E+01 3.000E+00 0.000E+00 | MC XX0001 10. 3.E3 0
6 j( h% |5 r; X1 }# [/ kSeries R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0004AX0002A 150. 0) [- e% c9 G9 R H7 P, j, e7 d
Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0004BX0002B 150. 0; d" m9 u8 B9 Z0 ~* A
Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0004CX0002C 150. 04 R. e2 l6 O6 p1 r" M3 M- J0 q: S
Comment card. NUMDCD = 40. |C $INCLUDE, C:\ATP5\Atp\LIN750_1.lib, X0013A, X0013B, X0013C, X0006A, X0006B $$/ P/ G3 L) F7 ?
Comment card. NUMDCD = 41. |C , X0006C
7 D. t2 E, _* t5 K P; dJ. Marti line, mode 1 parameters begin. |-1X0013AX0006A 2. 0.00 -2 3
% Y' e" k* H; b V% PJ. Marti line, mode 2 parameters begin. |-2X0013BX0006B 2. 0.00 -2 3
% f/ t$ K3 G. x( NJ. Marti line, mode 3 parameters begin. |-3X0013CX0006C 2. 0.00 -2 3
( p/ C+ `% i' p, X3 k. yTR(1,1 )... 0.584-0.707-0.421 | 0.58387433 -0.70710678 -0.42133648
( M4 u7 H% c+ \9 r8 m6 j: kTI(1,1 )... 0.000 0.000 0.000 | 0.00000000 0.00000000 0.00000000% z% n, L, v0 ~" C
TR(2,1 )... 0.564 0.000 0.803 | 0.56407583 0.00000000 0.80308851
6 s. k4 g" Q# [: v6 @6 H! F- TTI(2,1 )... 0.000 0.000 0.000 | 0.00000000 0.00000000 0.000000005 w4 J7 @4 O9 W, X4 R4 z: {
TR(3,1 )... 0.584 0.707-0.421 | 0.58387433 0.70710678 -0.42133648
% s! n. m2 C! n" }TI(3,1 )... 0.000 0.000 0.000 | 0.00000000 0.00000000 0.000000006 ]4 F s0 _) u: h) \2 E
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发表于 2009-12-30 17:38:22
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