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用Jmarti模型的Lcc建立了一个输电线路模型，我想通过生成的LIS文件读出线路的电气参量R，L，C等，不知道可行否？或者怎么从LIS文件读取自己想获取的信息？谢谢各位高人，不胜感激！！！8 r( c E4 G5 c% N5 |" u/ X* G0 J
====================================贴一段LIS文件，高手看看=============================
* h4 P. d7 j3 K+ e5 U; m xComment card. NUMDCD = 1. |C data:C:\ATP5\ATP\TEST_LCC1.ATP1 V6 H" q7 Z7 f/ |- o
Marker card preceding new EMTP data case. |BEGIN NEW DATA CASE
1 T. P3 _( d$ X I- ]( Q# UComment card. NUMDCD = 3. |C --------------------------------------------------------( ], S, p. g$ }% Y# v
Comment card. NUMDCD = 4. |C Generated by ATPDRAW 十二月, 星期二 22, 2009
! p, f+ {! _8 G/ f5 YComment card. NUMDCD = 5. |C A Bonneville Power Administration program# a" q% I& c/ i$ Q
Comment card. NUMDCD = 6. |C by H. K. H鴌dalen at SEfAS/NTNU - NORWAY 1994-2008
) K: G; |+ f4 D5 X& LComment card. NUMDCD = 7. |C --------------------------------------------------------1 Y4 [# `& M1 s, m' d3 O! m$ m
Comment card. NUMDCD = 8. |C $DUMMY, XYZ000
0 p: b: Y, c0 Y$ H1 [Comment card. NUMDCD = 9. |C dT >< Tmax >< Xopt >< Copt >
) [- \7 H/ N, c, rMisc. data. 1.000E-06 7.500E-02 0.000E+00 | 1.E-6 .075
; p8 l+ ~$ o" m" kMisc. data. 500 1 1 1 1 0 0 1 0 0 | 500 1 1 1 1 0 0 1 0
]3 }3 \8 E, f! ?& V# IComment card. NUMDCD = 12. |C 1 2 3 4 5 6 7 8
0 D$ w. }$ Z2 k$ GComment card. NUMDCD = 13. |C 345678901234567890123456789012345678901234567890123456789012345678901234567890( {" f( m! _ W& Y. S3 n; ~
Comment card. NUMDCD = 14. |C < n1 >< n2 ><ref1><ref2>< R >< L >< C >
% H+ g9 S9 r. Z& H& U. G- @! uComment card. NUMDCD = 15. |C < n1 >< n2 ><ref1><ref2>< R >< A >< B ><Leng><><>0
) ]5 y) q2 z- t5 b |Series R-L-C. 1.000E+00 3.000E-01 0.000E+00 | XX0001 1. 300. 0
$ f/ B# @+ ?. |5 x2 FSeries R-L-C. 5.000E+00 3.000E-01 0.000E+00 | X0004AX0002A 5. 300. 0
7 G! n) e Z1 I gSeries R-L-C. 5.000E+00 3.000E-01 0.000E+00 | X0004BX0002B 5. 300. 0) d9 g& ^. y8 g( r {8 u2 G' L. y
Series R-L-C. 5.000E+00 3.000E-01 0.000E+00 | X0004CX0002C 5. 300. 0
/ c$ h6 w9 Y9 ^8 Z2 G, |Series R-L-C. 2.000E+01 0.000E+00 0.000E+00 | XX0005 20. 0
U4 b' v3 P P- j ^/ ~1 J4 gSeries R-L-C. 5.000E+00 1.800E-01 0.000E+00 | X0003AX0010A 5. 180. 0
! V- q* w" J+ ESeries R-L-C. 5.000E+00 1.800E-01 0.000E+00 | X0003BX0010B 5. 180. 0
; t1 D" z" ~. ^Series R-L-C. 5.000E+00 1.800E-01 0.000E+00 | X0003CX0010C 5. 180. 0
5 S5 u8 w* ~7 b$ M7 WSeries R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0003AX0010A 150. 09 c' s0 b/ T) r$ Y- \. ~6 A& V& ~
Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0003BX0010B 150. 0
. W7 G4 O3 }/ }' l$ v( K# G1 fSeries R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0003CX0010C 150. 0( P& V: A9 G# o; h0 q$ K
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | NA XX0015 10. 3.E3 09 Q& i4 r' W3 [
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | NB XX0015 10. 3.E3 09 X; k2 Z3 k7 G5 V2 \' [
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | NC XX0015 10. 3.E3 00 j$ h4 {5 |, Q: Q7 E5 c
Series R-L-C. 1.000E+00 3.000E-01 0.000E+00 | XX0015 1. 300. 0" @& e; C- P; a" e$ v, G
Series R-L-C. 2.000E+00 2.000E-01 0.000E+00 | X0010AX0014A 2. 200. 07 I: w A! ?* \' U8 e: V* B
Series R-L-C. 2.000E+00 2.000E-01 0.000E+00 | X0010BX0014B 2. 200. 09 f% N" Q5 g0 A
Series R-L-C. 2.000E+00 2.000E-01 0.000E+00 | X0010CX0014C 2. 200. 0
m( T4 l: t; Z* OSeries R-L-C. 1.000E+01 3.000E+00 0.000E+00 | MA XX0001 10. 3.E3 0
1 M3 [" i' L* I. V6 d* g1 h4 ]Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | MB XX0001 10. 3.E3 0! u% C; ~& h" Y0 o y$ \7 v/ e
Series R-L-C. 1.000E+01 3.000E+00 0.000E+00 | MC XX0001 10. 3.E3 0
" S" n4 z |: k# B: PSeries R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0004AX0002A 150. 0
& e! C z2 B- J* ?Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0004BX0002B 150. 0; ]4 a2 @# v7 A4 x5 X! v' G1 u
Series R-L-C. 1.500E+02 0.000E+00 0.000E+00 | X0004CX0002C 150. 0* z1 j, a" b4 T7 n% b# u
Comment card. NUMDCD = 40. |C $INCLUDE, C:\ATP5\Atp\LIN750_1.lib, X0013A, X0013B, X0013C, X0006A, X0006B $$# B! }3 Z6 m( h; e) B
Comment card. NUMDCD = 41. |C , X0006C* o" P; G0 K& p$ J; m; X/ P
J. Marti line, mode 1 parameters begin. |-1X0013AX0006A 2. 0.00 -2 36 T: i5 G6 ~) S Y& D7 R; d
J. Marti line, mode 2 parameters begin. |-2X0013BX0006B 2. 0.00 -2 32 `8 Q% A& a2 h& J! X
J. Marti line, mode 3 parameters begin. |-3X0013CX0006C 2. 0.00 -2 3
$ P$ t ]. s) STR(1,1 )... 0.584-0.707-0.421 | 0.58387433 -0.70710678 -0.42133648
& Y: y3 ?* M4 G& k6 xTI(1,1 )... 0.000 0.000 0.000 | 0.00000000 0.00000000 0.00000000
0 D$ J7 z- y4 z, L+ P% F% {' JTR(2,1 )... 0.564 0.000 0.803 | 0.56407583 0.00000000 0.80308851
* n _9 o: `$ ~. _3 V# V' ITI(2,1 )... 0.000 0.000 0.000 | 0.00000000 0.00000000 0.000000002 Y( {# Q1 P$ M: x! i: ?% t( ^
TR(3,1 )... 0.584 0.707-0.421 | 0.58387433 0.70710678 -0.421336487 d' e" I. j0 r3 C1 f) i
TI(3,1 )... 0.000 0.000 0.000 | 0.00000000 0.00000000 0.00000000
' {$ h8 j' L( s9 O$ |7 w* vComment |
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发表于 2009-12-30 17:38:22
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