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ATPDraw运行时的error. log 如下:0 p' F5 N1 Z$ l8 P
* a8 i; M7 }8 {/ }" a
% y* l; n1 @- g: s% ]5 v+++/// Caution. Disconnected subnetwork. During the Y-matrix elimination for phasor voltages, a near-zero diagonal element; O- Q$ y$ x7 o! d" I5 ?1 _
for node "XX0013" exists just prior to reciprocation. Statistics follow: Original ABS(Ykk) = 0.00000000E+00,
. Z1 Z! }; d; A4 b questionable value = 0.00000000E+00, tolerance ratio TOLMAT = 1.00000000E-08 . The node in question might be
4 x' k6 ~( i& z' @/ K connected to other nodes, forming a subnetwork, but that subnetwork has no, or only very weak, paths to ground or* l6 N1 E4 k" Y: ~* `7 E
to any other known voltage node of the steady-state network. The solution voltages for this isolated subnetwork! N. j6 A/ E; v
will now be set to zero, as the solution continues.6 Q& V. R4 ?9 a- C
+++/// Caution. Disconnected subnetwork. During the Y-matrix elimination for phasor voltages, a near-zero diagonal element) T+ e" i# S8 ]( G* }, _
for node "XX0003" exists just prior to reciprocation. Statistics follow: Original ABS(Ykk) = 0.00000000E+00,
2 m$ H" E( v2 a& @7 S& K questionable value = 0.00000000E+00, tolerance ratio TOLMAT = 1.00000000E-08 . The node in question might be2 s+ e5 r9 S! M, m% X% }8 M" y
connected to other nodes, forming a subnetwork, but that subnetwork has no, or only very weak, paths to ground or/ u. F" D6 J/ T: y/ Q2 F- J3 n
to any other known voltage node of the steady-state network. The solution voltages for this isolated subnetwork( Q7 H6 w' U7 ^, \' V) X0 K
will now be set to zero, as the solution continues., r: G' _2 v8 O/ Z
/ |- g" C; \* h L0 `
2 n5 a7 h/ k5 N0 f* F
( V/ c/ X' H7 C0 d8 D有没有高手遇见过这样的问题呀 这里我仿真的是电弧模型 |