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ATPDraw运行时的error. log 如下:
& @0 ^: u: i9 ?. G% m. c1 s" g, r* x( ~1 Q& Q
% P" ?2 X) x2 T! U+++/// Caution. Disconnected subnetwork. During the Y-matrix elimination for phasor voltages, a near-zero diagonal element. {1 t& P0 q, z8 i5 y
for node "XX0013" exists just prior to reciprocation. Statistics follow: Original ABS(Ykk) = 0.00000000E+00,6 p; s$ x" k, P4 ]4 m5 g3 ]( `
questionable value = 0.00000000E+00, tolerance ratio TOLMAT = 1.00000000E-08 . The node in question might be
8 z, O0 f& {, \; q% v0 X' c4 j connected to other nodes, forming a subnetwork, but that subnetwork has no, or only very weak, paths to ground or; k' Z+ r/ A3 L0 i
to any other known voltage node of the steady-state network. The solution voltages for this isolated subnetwork+ A9 l: O, c- X( Y& k
will now be set to zero, as the solution continues. R# m6 ~1 w( R* V
+++/// Caution. Disconnected subnetwork. During the Y-matrix elimination for phasor voltages, a near-zero diagonal element
5 C- s( n+ r" x' S0 z for node "XX0003" exists just prior to reciprocation. Statistics follow: Original ABS(Ykk) = 0.00000000E+00,
8 P& _, ~* _' D4 k! N& R- | questionable value = 0.00000000E+00, tolerance ratio TOLMAT = 1.00000000E-08 . The node in question might be
2 ?6 f/ j4 d) y$ Y$ g connected to other nodes, forming a subnetwork, but that subnetwork has no, or only very weak, paths to ground or4 M2 ~7 E1 S) d$ K- u" i
to any other known voltage node of the steady-state network. The solution voltages for this isolated subnetwork+ w! e3 k" O0 [. H! D) Q- f
will now be set to zero, as the solution continues.
3 d& N& l* ]5 L& f, K2 ?9 o+ Q5 z/ Y9 e4 ^/ {' J
4 H+ K, ?" v; @" K( [+ @7 P) y
( m/ E- w8 }' ~6 Y" I
有没有高手遇见过这样的问题呀 这里我仿真的是电弧模型 |