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例如这些结果是什么意思?
+ n3 K" c0 l% h6 u2 \0 u* ePWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-11- M0 ~6 J4 R6 b: D" }
5 |* r4 E: V* V0 E! e% j) d
A COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN ' t/ s% R: u& g+ U3 S
bus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S
& _# e9 |9 ?+ A1 F. x4 d bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9 / P! W8 O e; m0 M- k# }: G0 U0 i5 [
3556.1PNET 622.2QNET -0.9 SLACK ADJ
3 V5 p& Q ~0 V& ubus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE 8 L1 d1 O/ ^3 {8 V+ k
bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5 * ?& X! F( i" s8 l( D! @
-3000.0PNET 0.0QNET
' ~8 C- C, T( u% G0 r1 U& Vbus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE
/ G* A4 Q5 T' n1 X' J bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0 1 J5 t+ O g' c2 \( x1 y
bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0 - r2 O5 h- Q" D! b3 l) s
0.0PNET 0.0QNET
3 A2 V) K. Y- m0 z3 J' L/ sbus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q # }( r9 I# s' k' J
bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9
' q" ~7 Z4 K# I I3 R& q9 v 1500.0PNET 16.2QNET
) c6 [' ^2 k2 i, C6 k% j1 W& |bus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE
0 ~9 c/ i- y- r. l) U bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC
4 n' S5 k7 F% k U+ e* O& K* r bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0 0 y: \6 v9 O3 o0 p5 T& p5 [
bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4 2 L& z# E1 ]7 C6 E/ W
bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4 1 a, l* Z9 S% M
bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4
- \( {3 |" T$ F' V2 W N) b bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4 " \* T4 a- x7 o$ r: ]
bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4 4 M' i# w( m8 ?, e9 V0 d
0.0PNET 0.0QNET
+ w. U9 R' O$ c; R9 l' ^5 Dbus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE ; Q0 Z, V; u |0 `" t
bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC 5 K7 R P4 a6 k( U5 `5 k$ `
bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7 8 G1 _5 T9 H/ A0 j" S
bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7
8 i0 d! ^5 t7 G4 \) q. L5 Q3 W bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7
) R' G' m: u5 s- u0 A bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7 9 H0 v: p4 y: n
bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0 # X6 p" Y$ a1 ]
bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0
% @, x+ D. d+ }) I. U! K bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0 ; a8 Q% D3 {8 M* M
1011.7QUSED 1011.7QCAP SCHEDULED
: J$ Y( `! C4 ^! D& Z. L' z4 ~ 0.0PNET 1011.7QNET
. R4 {7 r ]1 I% ~# @. xbus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q / N1 O4 \7 D$ h1 d/ a
bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8
* a- e- _' k+ ]2 _, ~! s 1094.0PNET -1.0QNET
5 F9 K/ ?, c5 u ~. Sbus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE
) n: Y1 k1 K @9 g. c bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6 \, y1 k9 n; k5 W0 k7 i6 @
1497.4QUSED 1497.4QCAP SCHEDULED
! T% q/ ?5 B/ L+ p& I+ ~$ N) j -3000.0PNET -302.6QNET
, n, ^& O7 j0 B, Kbus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE 4 s7 f+ h: H8 n/ i
bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0
' k1 c) Q8 v' p4 c. R7 @ bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0
7 e$ L: K( g) } 307.4QUSED 307.4QCAP SCHEDULED . ]1 o9 Y3 O3 D6 O3 B
0.0PNET 307.4QNET
9 U5 Z8 X0 |' x7 z, O6 {1 W7 e xbus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE
5 U; _8 z& S# M bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0
% G9 `5 W$ G. x1 S; x/ @0 z5 { bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0
5 u& q; \& I+ V& p+ G4 C, ^ 0.0PNET 0.0QNET 8 x" e, p6 s. o, j7 t) z! w
' S2 ?3 U8 Q5 J
5 o% w6 ~1 V' z
实在不太懂,还请会BPA的网友教教我怎么看这些信息。 |
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