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例如这些结果是什么意思?
7 Z3 a3 y8 o7 M+ T) IPWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-118 q6 N e" E3 }3 G8 F9 ~* j' w
+ J: P. p% n. g3 hA COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN
: l2 `# y; ^9 D8 j |% xbus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S - |* R; c: d B- r' j+ D
bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9 # n# n: D( s3 T7 m; Y: l
3556.1PNET 622.2QNET -0.9 SLACK ADJ
: V# Z: S) B& n1 N9 X& Vbus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE " \, R- L4 e; e5 f/ R" v
bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5
2 k6 ?, d" c* m2 v" [( F -3000.0PNET 0.0QNET
( D; ^4 z, r1 Lbus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE
4 B7 l' r+ Z7 Z2 S; `2 d bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0
: `) v. f# `# _6 q bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0 , T0 j* p5 R6 s/ X2 Z
0.0PNET 0.0QNET
; R# A) P- i) m1 t/ Y+ bbus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q
0 R3 n3 B/ o6 S9 A+ S) E bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9 : | L9 i- w: m0 w
1500.0PNET 16.2QNET
( t$ i; c U' c% u4 d" l/ zbus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE 5 V3 i! ^2 b6 x% A
bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC
$ {( Q% V4 X+ c7 {3 E bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0
" A o, s: R8 \ bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4 ' _( g1 g3 F- N* u4 o# s j
bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4 6 Q2 U5 Q0 y$ r& x
bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4 $ D: f" b. R1 g* Q2 u
bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4 6 H% K; I5 W/ `; c( e3 F
bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4 , K$ m( X- x7 g+ \) D% t
0.0PNET 0.0QNET
' D. J- U+ H4 d7 c' N3 R3 A: F+ Q* sbus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE
7 u+ |9 P; u8 F, l1 {1 L bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC ' h( c+ {0 J( |/ s
bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7
D, x- |6 _+ t. ?6 o/ S bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7
: K. H7 d; @0 D: c1 q2 H1 ~ bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7
9 C7 G* d4 I3 _/ h& w5 `* f; V! T bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7
6 a7 A3 s6 J( L bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0 5 M" e7 F% c/ U* a! H
bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0 1 V# W! ~8 ~ H
bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0
' B& q2 v' k7 r) |% c! Q6 d 1011.7QUSED 1011.7QCAP SCHEDULED ) ~/ r$ s6 F! K" {% h* U1 o: k
0.0PNET 1011.7QNET ) ?3 M- U8 v" J3 C
bus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q
" U7 Z3 K2 {. M) ?7 I( i5 q, R3 u- x bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8 ' r! a4 g# p( M9 S6 K
1094.0PNET -1.0QNET
5 d: T9 R) ?/ ~8 o. a' gbus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE
" ~& ?) t& H" m3 C l- E" u! T) y# Z9 H bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6 1 N1 t4 y; `0 R5 {
1497.4QUSED 1497.4QCAP SCHEDULED # S9 f" z G$ Z; Z
-3000.0PNET -302.6QNET 1 M; D7 S% @ U$ V" ]& K
bus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE 4 @/ s$ _0 G+ {0 l; N4 Y
bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0
0 M7 p" S% W. J) X2 r* Z bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0
3 C' E/ H g2 f* a3 k% [ 307.4QUSED 307.4QCAP SCHEDULED . N! `7 Q+ _2 n: j; K
0.0PNET 307.4QNET
3 Y8 Y- X& J1 Y: ~4 b+ mbus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE
7 e* L6 |5 n4 g9 s$ ]( W2 O bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0 1 y$ t' e" z( W) B
bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0 4 g$ f1 Q8 V: n- u2 L; u8 a1 c
0.0PNET 0.0QNET
' Q7 j( D/ _+ `! t% s B- ~( }" D: W& h' t d* B* v
6 C U6 T- c" @: F9 S5 P实在不太懂,还请会BPA的网友教教我怎么看这些信息。 |
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