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例如这些结果是什么意思?
4 d$ i N, R8 F) F5 Q9 MPWRFLO case: EMS proj: TEST * * * * DETAILED OUTPUT LISTING * * * * Date: 06-MAR-11/ b- b5 ^+ b: }
5 Q) i1 n2 q' C9 Z+ X" nA COMPLETE OUTPUT LISTING OF ALL BUSSES WILL BE GIVEN
9 K, C" Y+ S6 v% b, ]8 f' ibus-1 100.0 98.0KV/ 0.0 ZONE 1 3556.1PGE 622.2QCOND 0.0PLOAD 0.0QLOAD 0.980PU KV BUS TYPE S 6 T3 Z6 l' X7 x; d
bus-2 100.0 1 1 3556.1PIN 622.2QIN 0.0000PLOSS 246.98QLOSS 100.0/112.9 {5 y( B; K# Z
3556.1PNET 622.2QNET -0.9 SLACK ADJ 5 L9 b1 E2 h+ v
bus-10 100.0 100.3KV/-37.1 ZONE 1 3000.0PLOAD 0.0QLOAD 1.003PU KV BUS TYPE
/ p+ N+ u# ?# u& | bus-9 100.0 1 -3000.0PIN 0.0QIN 0.0005PLOSS 85.02QLOSS 100.0/ 97.5
$ R& Q) q8 O: ?' O! N: a -3000.0PNET 0.0QNET
1 e n( H0 k4 B: g9 H' ^7 hbus-2 100.0 109.6KV/ -3.9 ZONE 1 0.0PLOAD 0.0QLOAD 1.096PU KV BUS TYPE 3 V3 C9 q% ^: [+ y7 M- a( w: p h' s
bus-1 100.0 1 1 -3556.1PIN -375.3QIN 0.0000PLOSS 246.98QLOSS 112.9/100.0
4 N1 ^0 t4 {% a bus-4 100.0 1 1 3556.1 375.3 0.0000 425.79 0.0 * i5 U, r4 e! \9 y- I: e
0.0PNET 0.0QNET + A0 o' U# K& j+ k
bus-3 100.0 96.4KV/ -6.9 ZONE 1 1500.0PGE 16.2QCOND 0.0PLOAD 0.0QLOAD 0.964PU KV BUS TYPE Q " t! b/ S7 N: S8 v3 d2 L
bus-4 100.0 1 1 1500.0PIN 16.2QIN 0.0001PLOSS 99.52QLOSS 100.0/112.9 3 C+ m3 g5 i( _6 d+ f" q
1500.0PNET 16.2QNET / u, _4 ^) c$ O7 J! C$ A
bus-4 100.0 109.0KV/-10.7 ZONE 1 0.0PLOAD 0.0QLOAD 1.090PU KV BUS TYPE
: A& W) Y# D/ m# w# O: t1 h+ h bus-2 100.0 1 1 -3556.1PIN 50.5QIN 0.0000PLOSS 425.79QLOSS 0.0QC 3 x: g8 A7 J* |, b
bus-3 100.0 1 1 -1500.0 83.3 -0.0006 99.52 112.9/100.0
' H4 q5 R* G0 ]6 Q' w bus-5 100.0 1 1 1011.2 -26.8 13.0686 -25.18 139.4
1 W" J& }8 H) A! l v) Z: I bus-5 100.0 2 1 1011.2 -26.8 13.0686 -25.18 139.4 - }1 l2 m1 F8 }# x1 c3 N$ H1 G% @
bus-5 100.0 3 1 1011.2 -26.8 13.0686 -25.18 139.4 , q0 L& E9 s/ o9 K0 O4 M
bus-5 100.0 4 1 1011.2 -26.8 13.0686 -25.18 139.4 z* ^* d6 ]' A& P" p6 o+ f
bus-5 100.0 5 1 1011.2 -26.8 13.0686 -25.18 139.4 ) F2 f* l2 Z1 z8 t
0.0PNET 0.0QNET - c7 a) \! F ]
bus-5 100.0 108.0KV/-25.0 ZONE 1 0.0PLOAD 0.0QLOAD 1.080PU KV BUS TYPE # F+ @- M0 ~; Z! {3 j
bus-4 100.0 1 1 -998.2PIN 1.6QIN 13.0687PLOSS -25.18QLOSS 136.7QC
3 C5 ^- Q1 |! v1 v9 z5 ^8 M bus-4 100.0 2 1 -998.2 1.6 13.0687 -25.18 136.7 + L8 I* k: ^; d
bus-4 100.0 3 1 -998.2 1.6 13.0687 -25.18 136.7 " i% K0 s' z M3 C7 ~' A
bus-4 100.0 4 1 -998.2 1.6 13.0687 -25.18 136.7 " h D; H# f. E" c0 A
bus-4 100.0 5 1 -998.2 1.6 13.0687 -25.18 136.7
1 y& C: ?$ |* g0 I bus-6 100.0 1 1 -1094.0 73.3 0.0007 72.33 110.8/100.0
6 @- {+ f9 K$ q% [ bus-7 100.0 1 3000.0 584.0 0.0002 281.42 106.6/100.0
! X" A7 s7 p3 p% ~- E K- W bus-8 100.0 1 3084.8 346.3 0.0007 283.32 106.0/100.0 ! L# V7 u- Q# p& e
1011.7QUSED 1011.7QCAP SCHEDULED $ L+ p6 h# t/ X P8 `
0.0PNET 1011.7QNET . n6 `: ~: P- B8 A4 H6 C
bus-6 100.0 97.2KV/-21.2 ZONE 1 1094.0PGE -1.0QCOND 0.0PLOAD 0.0QLOAD 0.972PU KV BUS TYPE Q
5 N0 \( Z! l9 c& n. F* w. u bus-5 100.0 1 1 1094.0PIN -1.0QIN -0.0004PLOSS 72.33QLOSS 100.0/110.8 9 Y% ?5 V7 D2 S) a" t/ Y" y* w' ~
1094.0PNET -1.0QNET
7 e4 R& }' h2 N& |, P! dbus-7 100.0 99.9KV/-30.2 ZONE 1 3000.0PLOAD 1800.0QLOAD 0.999PU KV BUS TYPE
! L+ e2 k& ^2 F) t bus-5 100.0 1 -3000.0PIN -302.6QIN 0.0010PLOSS 281.42QLOSS 100.0/106.6
# _, u, D9 a% K$ l" [ 1497.4QUSED 1497.4QCAP SCHEDULED
/ d4 t7 E" b4 }3 l0 c -3000.0PNET -302.6QNET 2 n- U# K! @. f8 Z4 E: G1 Y2 a
bus-8 100.0 101.2KV/-30.2 ZONE 1 0.0PLOAD 0.0QLOAD 1.012PU KV BUS TYPE
/ w2 O: ^# ]2 Z) \1 d/ r. d bus-5 100.0 1 -3084.8PIN -63.0QIN -0.0002PLOSS 283.32QLOSS 100.0/106.0
6 p) I, p+ ?; I3 U4 v, J3 A bus-9 100.0 1 1 3084.8 370.4 84.7737 285.40 0.0 9 W7 X" d% G* T& T8 J; a
307.4QUSED 307.4QCAP SCHEDULED
4 T: D' g8 e1 Y) c0 O7 E 0.0PNET 307.4QNET
+ D1 b- @8 ~) x% K( |; w2 Xbus-9 100.0 97.8KV/-35.4 ZONE 1 0.0PLOAD 0.0QLOAD 0.978PU KV BUS TYPE , W4 q# A" J3 i$ e3 }2 R3 N$ v
bus-10 100.0 1 3000.0PIN 85.0QIN 0.0032PLOSS 85.02QLOSS 97.5/100.0 1 J: g7 ]! Y$ ~/ O i
bus-8 100.0 1 1 -3000.0 -85.0 84.7734 285.40 0.0 5 _0 {7 F8 L8 `- ^( w5 ^
0.0PNET 0.0QNET 1 x7 j4 R8 X; E% ^% R7 g H
9 [% Q7 r. o5 x
$ k( U& l( N# T& v. T6 [8 E5 H: ^1 Q实在不太懂,还请会BPA的网友教教我怎么看这些信息。 |
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