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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？0 Z# H4 ]* Y1 D( A
注：
8 x3 Z- m4 t% AMachine: G2 2 Z, h- V: \! U4 F4 ]
Nominal: 100 MVA 10.5 kV rms ; ~( }5 ~6 F; k6 [: L* A6 u
Bus Type: Swing bus 2 o; ^5 G: u5 b5 V/ e# M
Uan phase: -40.27° " O6 ?, o. t) T- v' R+ @
Uab: 52029 Vrms [4.955 pu] -10.27° $ `: q+ {% n' a( I$ p8 K' D: ]2 B
Ubc: 48895 Vrms [4.657 pu] 157.70°
- `1 E C; V0 F; r* cUca: 11025 Vrms [1.05 pu] -122.71° " j; R6 l' D1 c/ u$ z4 c
Ia: 16777 Arms [3.051 pu] -9.91°
+ u% U+ f( ~2 S0 S9 G8 ]Ib: 16777 Arms [3.051 pu] -129.91°
& k0 s" ~) X2 T% AIc: 16777 Arms [3.051 pu] 110.09° * j' N* }) z, g7 z
P: 1.3046e+009 W [13.05 pu] " O8 }! E" E& ^: U" N& N( Q6 U% Y0 O5 S# }
Q: -7.6415e+008 Vars [-7.642 pu]
; Y* I. s$ ~0 Y. jPmec: 1.3079e+009 W [13.08 pu] , v5 M0 k5 J5 k: j- _8 }* H
Torque: 8.3264e+006 N.m [13.08 pu] 2 H" i! P0 q m: K% h
Vf: 6.067 pu : F& B; V- G7 Z8 @* _" @ E! b
/ J* h. N! e8 n# Y/ j' c: ]$ M5 ^Machine: G1
+ a! ]+ [% L$ t' r( Y: N& ]! R9 hNominal: 100 MVA 10.5 kV rms
/ v. J( |8 t0 |9 C T3 rBus Type: P & V generator
5 e- W3 h3 S% C( v e# x- }Uan phase: -40.45°
% n' O2 v5 m- `. vUab: 55176 Vrms [5.255 pu] -10.45° 9 X. f+ S; ?9 ]0 L
Ubc: 50638 Vrms [4.823 pu] 158.65° 3 }0 K" l) A( y! v9 s9 a
Uca: 11025 Vrms [1.05 pu] -130.09°
) ]* t: n2 i% j4 f! O7 s5 @( XIa: 17338 Arms [3.153 pu] -21.32°
$ `! X4 ^; e& j8 F5 z/ eIb: 17338 Arms [3.153 pu] -141.32°
7 m' j' Y5 }$ P" xIc: 17338 Arms [3.153 pu] 98.68° 1 U/ R6 r8 }" v1 W( ]; t# x1 ` {
P: 1.5654e+009 W [15.65 pu] # |- E% K% m" n- ]
Q: -5.4297e+008 Vars [-5.43 pu] " n0 m6 R1 g$ L2 m( V1 R8 M
Pmec: 1.569e+009 W [15.69 pu] 2 u! j+ Y/ G# f' l3 n6 d9 O
Torque: 9.9887e+006 N.m [15.69 pu] 3 j n2 u5 w9 W! l
Vf: 6.7898 pu 4 y1 g; N# a! G& j3 L0 `
^5 ?& O5 g) K0 V% T: \/ BMachine: Load3
- ?5 U3 Z- U/ [! F$ v# b7 p8 {, S" xNominal: 115 kV rms 4 Q0 ~# A J3 m h8 P1 g3 ~9 M: U
Bus Type: P & Q load . c; O/ b, u% L6 o$ G A
Uan phase: -46.14° 9 ]. s, R7 g8 }" n6 Q% i7 c, u8 Y
Uab: 6.2602e+005 Vrms [5.444 pu] -16.14° $ ~ j% ]/ ^; j2 V
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43°
& n- Q6 h3 \) Y# `Uca: 30061 Vrms [0.2614 pu] -136.62° 6 ^# |. Z) H! |7 U+ v& n3 w9 G
Ia: 300.16 Arms -102.68°
) e! O* ~1 n# A# U" s0 A& SIb: 300.16 Arms 137.32°
* {& G7 Q3 Y1 T' p* ~, jIc: 300.16 Arms 17.32°
4 Q, F; a* ^1 v5 }" K- O9 |P: 1.7944e+008 W 7 Y% g# l& G- {3 f- U6 w
Q: 2.7153e+008 Vars & [( T. ?' t7 g, A% @) c3 F
3 }, z3 J! E) t! b
Machine: Load2 ( s4 N: p" v* k Q! T5 P% M F
Nominal: 115 kV rms
5 t+ _1 Q+ c: ]9 \& ~4 cBus Type: P & Q load
, `0 J4 {0 x9 ]8 U3 Y7 D x8 J, [6 q9 k) eUan phase: -41.18°
0 m) x1 U; L! i: B7 N$ c( ^2 _Uab: 6.0512e+005 Vrms [5.262 pu] -11.18°
2 Y( }' k5 Z& K5 S3 i3 PUbc: 5.7431e+005 Vrms [4.994 pu] 157.92°
Z7 k7 P: F2 VUca: 1.1609e+005 Vrms [1.009 pu] -121.95°% L d, O6 E( z7 V! X" Q
Ia: 798.9 Arms -92.72°
5 \! [$ m6 c% F YIb: 798.9 Arms 147.28° 3 {9 P6 d- T6 @# \
Ic: 798.9 Arms 27.28°
3 N6 G- P( L+ v' N: H- F; gP: 5.2087e+008 W ) S2 G" [+ W! E# C
Q: 6.5561e+008 Vars
" m; W1 S. ?* T; I
5 U- w1 t3 s; j E: D) dMachine: Load1
# [5 q& }+ `" x) f5 K/ j0 a" FNominal: 115 kV rms
1 `. E; s: r! J2 U& VBus Type: P & Q load ) \# @) Z+ d8 C' j0 W
Uan phase: -40.94° 1 U6 k! i8 v" t# e' @; E) H
Uab: 6.3759e+005 Vrms [5.544 pu] -10.94°
6 w7 E* x! X7 e2 `5 n! |Ubc: 5.8926e+005 Vrms [5.124 pu] 158.63° + w; J3 Z/ N8 M8 d; Y2 J7 U
Uca: 1.2147e+005 Vrms [1.056 pu] -129.49°
& `5 L" @" O& r7 MIa: 433.21 Arms -97.84°
/ Q+ P* B, J( F y( SIb: 433.21 Arms 142.16°
7 O4 M* N9 K' ~; Y9 CIc: 433.21 Arms 22.16° - d f% Q2 ^+ T5 k9 `9 w$ w8 x
P: 2.6123e+008 W 3 d2 X' |' w/ i) K# m* B* Z( h
Q: 4.0079e+008 Vars |
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发表于 2012-4-29 16:29:59
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