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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？% F5 }8 Q d) ~6 H; f* Y" i
注：
! @% p$ D6 Q& |4 ?Machine: G2 " N) {8 _4 U t0 e8 F$ Y# r
Nominal: 100 MVA 10.5 kV rms
) r4 s% l" c5 L# u4 g. Z2 bBus Type: Swing bus
% K3 f7 Z3 |+ q- X# P' j: [- P: JUan phase: -40.27° , {+ z1 B8 M$ N- ^$ ]8 R8 W' l
Uab: 52029 Vrms [4.955 pu] -10.27°
- q6 j! W( d6 AUbc: 48895 Vrms [4.657 pu] 157.70°
) ^/ W% c2 ^0 P4 I& K) |Uca: 11025 Vrms [1.05 pu] -122.71°
/ Z% r/ i |' q% G& G. u) JIa: 16777 Arms [3.051 pu] -9.91° $ W/ I% X9 L9 O# e/ S% Y- `; A
Ib: 16777 Arms [3.051 pu] -129.91° % F4 G: _6 ?# t6 s5 N% [; _$ d
Ic: 16777 Arms [3.051 pu] 110.09° ) `/ K: B) e" l) @2 \: b- m0 g
P: 1.3046e+009 W [13.05 pu] + z1 z9 m I& G
Q: -7.6415e+008 Vars [-7.642 pu] " d0 S# D. ~9 W( [$ W& |. g
Pmec: 1.3079e+009 W [13.08 pu] 2 M) s, w. P) V, N: f$ B7 l4 K
Torque: 8.3264e+006 N.m [13.08 pu]
( I& b1 O. P4 W+ N" CVf: 6.067 pu
# k2 j! V: s2 G
0 _7 @* V9 u, C C$ SMachine: G1
9 U( H# Q) |6 dNominal: 100 MVA 10.5 kV rms % }0 Y7 g$ x2 l) I* j
Bus Type: P & V generator
# V" _- M, F3 Y$ `! e$ KUan phase: -40.45°
9 a- @; W3 \! E) v2 R5 i& }2 YUab: 55176 Vrms [5.255 pu] -10.45°
% y8 r' ~( {! Y; x8 t1 N: PUbc: 50638 Vrms [4.823 pu] 158.65°
* t1 P8 m; j3 ]# U5 N; V& yUca: 11025 Vrms [1.05 pu] -130.09°
: p8 I ]* v0 G% xIa: 17338 Arms [3.153 pu] -21.32° ! v, A8 n u) q* Z- u- w
Ib: 17338 Arms [3.153 pu] -141.32° % e; J0 v# l+ E: L) }/ ?
Ic: 17338 Arms [3.153 pu] 98.68°
( B) v j) `7 f; s! aP: 1.5654e+009 W [15.65 pu]
2 ~+ ]" r7 \) c, L. \) pQ: -5.4297e+008 Vars [-5.43 pu]
# V, c) @' w5 r4 o+ A2 l$ CPmec: 1.569e+009 W [15.69 pu] p. P' I. B. O) ]
Torque: 9.9887e+006 N.m [15.69 pu] 2 p3 D% h) U/ `$ S! h# M
Vf: 6.7898 pu
O# W. r% I) @& k% p1 p
- }, d6 O) t( z- s" i$ _Machine: Load3
4 B4 ^, F( u, o; E, INominal: 115 kV rms
' Q2 m0 [" |+ c4 n g0 l, w+ G, A* LBus Type: P & Q load * s3 T8 {0 h' J/ H
Uan phase: -46.14° ' T; u. e1 M4 z
Uab: 6.2602e+005 Vrms [5.444 pu] -16.14° 8 q6 r/ `/ v! W0 X$ F
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43°
5 s) k. g+ V/ J9 NUca: 30061 Vrms [0.2614 pu] -136.62° 9 H) S5 ]! y! W) a! s9 A1 @/ |6 |( l' A
Ia: 300.16 Arms -102.68°
5 z2 \7 T! n9 q2 NIb: 300.16 Arms 137.32°
7 p: u% g( R9 r" HIc: 300.16 Arms 17.32° 4 e ~+ J ]6 \! ~
P: 1.7944e+008 W
6 p& h" M1 N5 Y# S/ f% @Q: 2.7153e+008 Vars
3 V* \( X8 E) D1 r3 c ; C& O, q; m3 T/ S* s
Machine: Load2 ) Y% t4 N$ G2 t' s A
Nominal: 115 kV rms 4 j& h& i7 Q4 [1 |9 V8 b
Bus Type: P & Q load 6 y+ p7 H. D+ ~- v0 ]$ {/ A
Uan phase: -41.18° ( U2 ~+ w* H% i% s- u
Uab: 6.0512e+005 Vrms [5.262 pu] -11.18° 3 U$ g: {5 {8 V) g2 Y4 U
Ubc: 5.7431e+005 Vrms [4.994 pu] 157.92°
0 F) W8 x! ]6 E6 [ t8 v9 B2 vUca: 1.1609e+005 Vrms [1.009 pu] -121.95°
4 Q3 K, _1 A; Y# d$ A8 F2 d8 P$ w q7 M) PIa: 798.9 Arms -92.72°
2 i3 u3 b- t& F0 A! |Ib: 798.9 Arms 147.28°
" |) t& i0 R/ w; x% PIc: 798.9 Arms 27.28° ' |( q2 E% t9 M( W3 a
P: 5.2087e+008 W 2 ]# V Y8 O0 t @! F, m
Q: 6.5561e+008 Vars
8 x R. N% K |$ J% C# V' V* m
$ u2 W/ s }# v# M; [2 ^Machine: Load1 " ?( P. ]1 p- {7 F: O+ J) F
Nominal: 115 kV rms
& I. }! I0 r, J! RBus Type: P & Q load + }3 z# F; P9 F! E2 O
Uan phase: -40.94°
3 g# `/ b% L! N' m4 ]/ |1 uUab: 6.3759e+005 Vrms [5.544 pu] -10.94° * E# y9 b" B! i3 T/ F
Ubc: 5.8926e+005 Vrms [5.124 pu] 158.63° 8 F; p- a: e; H6 [2 x1 B
Uca: 1.2147e+005 Vrms [1.056 pu] -129.49°$ u$ Y! ^1 R/ ^+ a" F `
Ia: 433.21 Arms -97.84°
' | M5 [3 q1 Q. A9 X; IIb: 433.21 Arms 142.16°
: E8 z8 c. a: rIc: 433.21 Arms 22.16° , J+ s' L. U4 A# \% V4 }" k4 z
P: 2.6123e+008 W / ^$ z, @9 G3 ^8 V5 d0 _: L: f
Q: 4.0079e+008 Vars |
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