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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？
0 P% t/ ~% W- L" B注：
6 g0 t0 [& _* N4 y. E2 P* eMachine: G2 % K3 l! `5 [! M2 E" B) P! s
Nominal: 100 MVA 10.5 kV rms $ S! r8 H# h' n" _7 j2 y
Bus Type: Swing bus & k6 B- \' E- D; S
Uan phase: -40.27° " `6 Y0 J& F1 Q2 }0 ?( D( n4 [, l
Uab: 52029 Vrms [4.955 pu] -10.27° - Z6 i5 U) `- |6 X. J5 q% w
Ubc: 48895 Vrms [4.657 pu] 157.70° 0 w, H+ j# J* f' A* \- A9 i4 C
Uca: 11025 Vrms [1.05 pu] -122.71° 8 X) K5 _1 f x5 j0 T, _8 n* ^# z3 U
Ia: 16777 Arms [3.051 pu] -9.91° 7 @3 C$ z' Z+ j, H) e% Y9 [2 C' ?
Ib: 16777 Arms [3.051 pu] -129.91° % [3 x& E% I4 i8 g* `8 @2 k. F. M# l
Ic: 16777 Arms [3.051 pu] 110.09°
7 R5 p, O* Y; ~3 p% NP: 1.3046e+009 W [13.05 pu] . [% m! ~+ z3 p3 [& w) x
Q: -7.6415e+008 Vars [-7.642 pu]
1 h3 R! A3 B4 j& k I) xPmec: 1.3079e+009 W [13.08 pu]
; ^( J) y5 V: J7 H3 D. u. aTorque: 8.3264e+006 N.m [13.08 pu]
4 C% f+ i; g& S3 KVf: 6.067 pu 6 I! _- o. k0 S2 d2 r+ v( e2 ^! J
4 ]) z7 ~, k) P3 t0 d( `2 H6 j. c
Machine: G1
9 q$ I2 Q/ a/ ?- d! FNominal: 100 MVA 10.5 kV rms ' F( D- K: f f+ I3 e: u$ C! Q
Bus Type: P & V generator # d/ B$ S) P: `& H9 C' c
Uan phase: -40.45°
4 b7 s' `4 `: j4 \# A* WUab: 55176 Vrms [5.255 pu] -10.45° : ^/ ~, b9 _- c# Y" J% N' n
Ubc: 50638 Vrms [4.823 pu] 158.65° . J. o, }) u8 V/ O; F0 p; K
Uca: 11025 Vrms [1.05 pu] -130.09° 4 ?) e6 e' |* o0 C6 s
Ia: 17338 Arms [3.153 pu] -21.32°
. c1 e" R! D1 ?7 T$ iIb: 17338 Arms [3.153 pu] -141.32° 4 `- W4 H0 G& G4 k
Ic: 17338 Arms [3.153 pu] 98.68° - J! l3 Y+ |+ z' Y8 }
P: 1.5654e+009 W [15.65 pu] 0 A/ e \( o4 f0 l7 g% q: L8 p M! D
Q: -5.4297e+008 Vars [-5.43 pu]
9 ?- j; b' V9 K( s, tPmec: 1.569e+009 W [15.69 pu] ! v- e' s5 O0 S9 c' D
Torque: 9.9887e+006 N.m [15.69 pu] + S. x5 ^& K; S! [
Vf: 6.7898 pu
% C I, U0 M. D; A9 O ' z/ f9 ~5 L% \, t- C' |
Machine: Load3
5 W0 ~9 g8 d9 s6 D6 L% T- U: DNominal: 115 kV rms
/ d5 _* x T2 Q$ m' FBus Type: P & Q load
5 f: Q3 ~# T, i2 L2 R2 `( Y- ]4 d6 DUan phase: -46.14° : C" U, T9 y) }2 {
Uab: 6.2602e+005 Vrms [5.444 pu] -16.14° 6 h8 b0 `( U& J
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43°
) b$ C9 P, Q4 @: q& g& MUca: 30061 Vrms [0.2614 pu] -136.62° ! l+ l& I& S; ]! B k2 ?
Ia: 300.16 Arms -102.68°
+ L) E' Z2 [, `" J8 g+ U* Y& t- p6 qIb: 300.16 Arms 137.32° 0 Z# Z- v( G% [$ b, [* g+ h" Q
Ic: 300.16 Arms 17.32°
7 q$ L# |7 B; R1 N' W+ A' A+ ZP: 1.7944e+008 W , p4 ^( t# l$ O
Q: 2.7153e+008 Vars
8 s8 n/ G) l6 G$ Z9 W ) ?7 J3 f& y$ ^* P1 V
Machine: Load2 * J/ n p1 e! F
Nominal: 115 kV rms
. ]0 u4 b# _6 k6 v- D5 f( H6 sBus Type: P & Q load % G# O/ Y6 ?* b( j9 Z
Uan phase: -41.18°
1 v# W5 q1 |1 EUab: 6.0512e+005 Vrms [5.262 pu] -11.18°
0 \) ^! v% ~0 |+ J- v* GUbc: 5.7431e+005 Vrms [4.994 pu] 157.92°
+ @& L( w; _3 q" xUca: 1.1609e+005 Vrms [1.009 pu] -121.95°! [4 j h& r. G* |4 G
Ia: 798.9 Arms -92.72°
4 r6 S# `7 @% g8 z# `Ib: 798.9 Arms 147.28°
6 J: q' R2 c, L1 {Ic: 798.9 Arms 27.28° # M' m) o( u# |/ p& ^
P: 5.2087e+008 W
4 l' M( a$ f2 l% o* X- m# @, R9 EQ: 6.5561e+008 Vars 3 }& |, I3 p6 v) ^6 E
; x) r* n( X$ E, m
Machine: Load1 ' |& x$ n+ p4 R4 q! P" G
Nominal: 115 kV rms - k9 {; V n. Y |) e: f6 Z
Bus Type: P & Q load
& s" f2 I8 Q t7 iUan phase: -40.94° 5 G* @" E+ D5 o/ p5 }& \' k
Uab: 6.3759e+005 Vrms [5.544 pu] -10.94°
! s3 n: s/ Q5 e6 T; X. OUbc: 5.8926e+005 Vrms [5.124 pu] 158.63°
) ?* Q. C D# q5 ^3 v, RUca: 1.2147e+005 Vrms [1.056 pu] -129.49°
4 \' N0 T, q: j. GIa: 433.21 Arms -97.84°
; {0 ` M) a, |2 h! Q, LIb: 433.21 Arms 142.16° 2 H3 |' n5 V8 W, o
Ic: 433.21 Arms 22.16°
4 }- p9 |" P/ G" t q& ^- pP: 2.6123e+008 W 0 w. G2 [/ {' c" a l9 D' o
Q: 4.0079e+008 Vars |
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发表于 2012-4-29 16:29:59
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