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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？5 r9 @) m! g. g2 x2 ~
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Machine: G2 # e& Z2 Y8 R8 {0 a& I6 d4 F" y
Nominal: 100 MVA 10.5 kV rms * P0 B7 L1 T0 J5 J4 G
Bus Type: Swing bus
6 \; o. Q: R; d* Q F2 }0 v1 WUan phase: -40.27° # E2 o+ P. F, h, T2 i' L* p5 V* C
Uab: 52029 Vrms [4.955 pu] -10.27° 5 e! Z8 a& V" i, G. u; q
Ubc: 48895 Vrms [4.657 pu] 157.70° p% N% i: h9 R( L, G G) O
Uca: 11025 Vrms [1.05 pu] -122.71° 1 r* y, Q/ j$ w7 P
Ia: 16777 Arms [3.051 pu] -9.91°
- {2 [" H" C; z0 F' L- d3 WIb: 16777 Arms [3.051 pu] -129.91° 2 A# P9 i8 E; I+ ?% s. H7 i1 U7 J
Ic: 16777 Arms [3.051 pu] 110.09° C3 F1 |8 t, _" S, |0 y+ r
P: 1.3046e+009 W [13.05 pu]
+ N$ q" k7 l7 K# c; FQ: -7.6415e+008 Vars [-7.642 pu] 9 h/ K: P; b7 V8 a: X2 i7 u, ?8 f
Pmec: 1.3079e+009 W [13.08 pu]
" r8 [1 Q( s( H( W+ c$ u; a, BTorque: 8.3264e+006 N.m [13.08 pu]
* r# d4 `1 P7 b y/ `8 X& X/ G# I6 PVf: 6.067 pu : K, j* f( U2 f ` k
, t% R3 W4 Z$ P! B9 I2 _
Machine: G1
' [/ `6 q' p) x; }- K+ d* d. \Nominal: 100 MVA 10.5 kV rms / _. P) s3 ]! K4 ^1 \
Bus Type: P & V generator
& A7 I+ e8 y" C2 |5 w+ }- SUan phase: -40.45°
2 [* m, D2 u9 ~! u; t6 VUab: 55176 Vrms [5.255 pu] -10.45°
2 X4 K( }* T$ m7 ?$ qUbc: 50638 Vrms [4.823 pu] 158.65° , s+ p# c4 F/ \! q- U6 X$ S9 i! s4 h0 m
Uca: 11025 Vrms [1.05 pu] -130.09° 3 B n4 a; T/ _ l0 P' t
Ia: 17338 Arms [3.153 pu] -21.32°
5 d* [' J: n) N4 Q7 O3 g5 WIb: 17338 Arms [3.153 pu] -141.32°
, c, }7 n7 S7 B1 e( CIc: 17338 Arms [3.153 pu] 98.68° 2 l9 m: x0 A8 V1 `: ~+ R
P: 1.5654e+009 W [15.65 pu] / u5 ~/ O4 \0 e/ |
Q: -5.4297e+008 Vars [-5.43 pu] 6 C: x; D v3 F1 L0 b% C
Pmec: 1.569e+009 W [15.69 pu]
0 m" M' v* r! j9 JTorque: 9.9887e+006 N.m [15.69 pu] ) X- A( o5 t6 h! k% L
Vf: 6.7898 pu % m0 z+ E! J# A0 K7 X
) |$ {! S( g" N h z& u5 gMachine: Load3 4 p0 i& c+ H F1 {5 @5 X: O
Nominal: 115 kV rms
* ~+ o4 w3 B: h/ T, ~! C0 ^! V0 SBus Type: P & Q load # Q# [4 X4 r* m1 Y( Q. p
Uan phase: -46.14° 6 L* j9 v9 O1 z. W U- U/ N6 Q
Uab: 6.2602e+005 Vrms [5.444 pu] -16.14°
: z9 o Q5 n. CUbc: 6.1132e+005 Vrms [5.316 pu] 161.43°
8 I6 I9 T5 H+ h8 @7 @Uca: 30061 Vrms [0.2614 pu] -136.62°
% j& |* s; T$ {9 X! u$ HIa: 300.16 Arms -102.68°
) q ~; n& i6 W3 w, r0 R+ ]; UIb: 300.16 Arms 137.32°
- c! T2 O1 e. h1 F5 l9 y: W3 K- T0 H$ GIc: 300.16 Arms 17.32°
" I" M, ^( H) M& R* dP: 1.7944e+008 W ; f. G, e, w1 j- a6 m) g
Q: 2.7153e+008 Vars $ [0 e7 V" {9 D+ Y: f4 x5 M
6 ^# V1 _! n0 @' l9 P
Machine: Load2
: j! w1 k2 q/ N& L) h# f3 C4 VNominal: 115 kV rms
; b# u8 e1 p0 n2 tBus Type: P & Q load % @2 F+ R7 K1 f q5 v* c* P
Uan phase: -41.18° 0 t. a! M+ |$ Z& t. r# a
Uab: 6.0512e+005 Vrms [5.262 pu] -11.18°
$ I5 H2 v5 q8 Z+ x; K4 Z1 `' LUbc: 5.7431e+005 Vrms [4.994 pu] 157.92°
9 w1 p! c8 {7 ]! Q; e" sUca: 1.1609e+005 Vrms [1.009 pu] -121.95°
" M1 d- W0 K$ [0 rIa: 798.9 Arms -92.72° 4 l! c8 V+ v) L/ k0 \
Ib: 798.9 Arms 147.28° 4 X. ^4 _8 B. J
Ic: 798.9 Arms 27.28°
% x4 ^; d! H7 o& V. a- e$ IP: 5.2087e+008 W
" E/ m5 W% ~* f. t0 @" |4 cQ: 6.5561e+008 Vars
& L" }- c5 q' U, ~6 a" U9 n 6 U1 ~$ u7 M7 Q, E1 V3 O4 ?! S. Z: N
Machine: Load1
; h( |% D4 @3 ]8 A3 INominal: 115 kV rms & B X2 k' F. |' H' _; T/ u5 _
Bus Type: P & Q load
& Z( v6 S* q) c8 R) ?) @Uan phase: -40.94°
- {9 X7 y* H0 |Uab: 6.3759e+005 Vrms [5.544 pu] -10.94° , B; q# w3 ~/ Q+ r1 ^+ b9 l
Ubc: 5.8926e+005 Vrms [5.124 pu] 158.63° / q8 @7 m( u& ?6 a) {3 M- Z' F' ^: B
Uca: 1.2147e+005 Vrms [1.056 pu] -129.49°
M- u+ F9 I5 r+ j! C9 aIa: 433.21 Arms -97.84° 1 U2 ?2 X, R9 I% l
Ib: 433.21 Arms 142.16° , D& x o o d
Ic: 433.21 Arms 22.16° ( u; k7 v* z8 A. b
P: 2.6123e+008 W . d: q" q& p+ J6 I. i; M' K
Q: 4.0079e+008 Vars |
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发表于 2012-4-29 16:29:59
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