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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？* W8 n! K& E) s# h; |) j+ }: S0 k# N
注：
& N9 R+ v0 l# u& v+ G: rMachine: G2
! S- V! ~) d6 tNominal: 100 MVA 10.5 kV rms
5 m, E0 n5 R& Q5 y8 ZBus Type: Swing bus ) S) L- N9 Q% h5 |" _" \" A# M
Uan phase: -40.27° $ J7 a( N* x9 |* k) y! r
Uab: 52029 Vrms [4.955 pu] -10.27° ' T4 m+ C7 h$ e: A7 C
Ubc: 48895 Vrms [4.657 pu] 157.70° * `2 u3 ~ T! O# }5 W
Uca: 11025 Vrms [1.05 pu] -122.71° 1 s3 M+ ^* u0 c5 H/ T' c4 u
Ia: 16777 Arms [3.051 pu] -9.91° - j* y2 O$ a4 k. H' y
Ib: 16777 Arms [3.051 pu] -129.91° ( b& p2 h: s* n0 a' J
Ic: 16777 Arms [3.051 pu] 110.09° ! m) m9 L% I% P& c
P: 1.3046e+009 W [13.05 pu] 8 N' f" c: ], {- \. M* J6 u
Q: -7.6415e+008 Vars [-7.642 pu]
u, K$ h7 v6 R4 [9 j& Y( ^" [3 m- }Pmec: 1.3079e+009 W [13.08 pu] 3 v C% m0 O; l; d# G
Torque: 8.3264e+006 N.m [13.08 pu]
( C4 A9 E$ W2 F9 M( z' @Vf: 6.067 pu
0 v# W4 ?9 U# O% g : `. U! P8 Z, a7 C/ B' q. B
Machine: G1 ( w* c$ w5 n0 U0 Y
Nominal: 100 MVA 10.5 kV rms
6 o! p. M. p# N0 yBus Type: P & V generator
5 s2 I! k+ r: g9 @( hUan phase: -40.45° ) c. A9 _+ Q2 v7 M! }
Uab: 55176 Vrms [5.255 pu] -10.45°
5 h+ w1 y) l6 [0 W% ?* l( |8 @7 |0 cUbc: 50638 Vrms [4.823 pu] 158.65°
9 [) g. Y7 B/ c' N" Z2 EUca: 11025 Vrms [1.05 pu] -130.09°
/ ^6 S1 O- p! _; d8 xIa: 17338 Arms [3.153 pu] -21.32° 2 G, H7 e) q0 Q f6 G
Ib: 17338 Arms [3.153 pu] -141.32°
% q4 U2 j! T1 G# v% ?9 c* S* {Ic: 17338 Arms [3.153 pu] 98.68° 6 I( o% d9 S) `) R6 m/ V7 _
P: 1.5654e+009 W [15.65 pu] * w# O( i7 K! m! i
Q: -5.4297e+008 Vars [-5.43 pu] 7 R( K% u3 c9 l& x+ n4 J
Pmec: 1.569e+009 W [15.69 pu]
$ T6 C. r( g/ `7 [* TTorque: 9.9887e+006 N.m [15.69 pu]
\( z/ {4 H0 n+ b! d" A k @. NVf: 6.7898 pu
i8 q8 G1 g2 p% }* Q
( Y+ |" [4 I1 _6 \2 f( f" E- g/ KMachine: Load3
g0 h' O& `' ]7 |+ ENominal: 115 kV rms 9 ~4 _8 j7 X% ?1 @9 {" O9 Z9 h( j
Bus Type: P & Q load ( x; P% O# ?' K/ Y5 ?) c* T7 ] m6 A
Uan phase: -46.14° 3 v) d( W6 |9 L, r
Uab: 6.2602e+005 Vrms [5.444 pu] -16.14° ) s% R. ?1 v2 Z% C: i* _$ f% L
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43° ) q+ |. e: _$ Y l& x
Uca: 30061 Vrms [0.2614 pu] -136.62° ( ~' a9 G4 I9 \# X8 Q5 c. `
Ia: 300.16 Arms -102.68° 7 j" m! ^- j( U
Ib: 300.16 Arms 137.32° , X: Y9 i T$ ?0 D; A
Ic: 300.16 Arms 17.32°
4 t4 p" [! L' z& q- M8 j8 tP: 1.7944e+008 W 1 o: q) ~: U; }5 X/ i) K
Q: 2.7153e+008 Vars + {7 K0 n) v) C( |* F2 \4 ?
6 g! U6 C ?& n0 r
Machine: Load2
) W# Q" X( m, I9 F Z. b- L) oNominal: 115 kV rms 8 b7 c' g) f8 e4 ^% O
Bus Type: P & Q load
% `2 T3 R9 M0 f, g' [Uan phase: -41.18° 1 c5 v) G7 `0 U. `8 ?; n7 n
Uab: 6.0512e+005 Vrms [5.262 pu] -11.18° # h( W& d7 Y/ B+ C H! b9 r
Ubc: 5.7431e+005 Vrms [4.994 pu] 157.92°
$ w" T) k& X: U& s4 MUca: 1.1609e+005 Vrms [1.009 pu] -121.95°3 T' H6 T$ }" F1 T& m( m
Ia: 798.9 Arms -92.72° V! w0 b1 a b' K) A6 M, Z
Ib: 798.9 Arms 147.28°
( f' {! _0 c7 E# p! Z7 kIc: 798.9 Arms 27.28°
) y' P t- c9 eP: 5.2087e+008 W
. Z+ m% ^6 Y! v! U' k. S$ _Q: 6.5561e+008 Vars ' q e8 _6 a% `$ S. e- B, R" R& V2 p
2 c& Z) I1 d$ K6 W
Machine: Load1
: R. ^, z4 K) _4 e- M2 H" o9 BNominal: 115 kV rms 3 Y) X! w+ Z& n, _) P! r% `* u
Bus Type: P & Q load
( x7 e k: B1 _* D# m9 PUan phase: -40.94°
, E" K* x: }; `. W, w: cUab: 6.3759e+005 Vrms [5.544 pu] -10.94° # @, y/ I% E7 ]4 E
Ubc: 5.8926e+005 Vrms [5.124 pu] 158.63° 7 H: {. V6 b6 d! }/ U
Uca: 1.2147e+005 Vrms [1.056 pu] -129.49°# [( X S- v4 H+ W7 |; w' r
Ia: 433.21 Arms -97.84°
2 {( m Y3 w7 ~Ib: 433.21 Arms 142.16°
. L- A, Z9 W! s/ B" k4 bIc: 433.21 Arms 22.16° . B# c3 {% o3 j+ Y! k# M) B
P: 2.6123e+008 W 8 q2 s, Y! Z$ j3 G0 X
Q: 4.0079e+008 Vars |
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发表于 2012-4-29 16:29:59
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