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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真,我参数完全按照书中设置,但调试有问题,Update Load Flow之后,得出发电机的三相电压不对称,数据如注释所示。哪位高手知道为啥?
! Q9 X& v8 ^# Z. x- V注:& J$ x% D- U K: k- {
Machine: G2
: @% M X6 j `, dNominal: 100 MVA 10.5 kV rms
# O; y$ } l9 l/ M- UBus Type: Swing bus # y9 i+ e% f2 g( V5 x5 f
Uan phase: -40.27°
1 m0 g) g% g! o: g) tUab: 52029 Vrms [4.955 pu] -10.27° / _' V' x y7 r" J; I3 C4 F8 C P
Ubc: 48895 Vrms [4.657 pu] 157.70° * h1 j: J9 a# t6 T4 z
Uca: 11025 Vrms [1.05 pu] -122.71°
0 T2 f: T5 b2 k8 ZIa: 16777 Arms [3.051 pu] -9.91° - B" q- Z4 S) y
Ib: 16777 Arms [3.051 pu] -129.91°
% B: H z6 C8 C4 f/ A: y KIc: 16777 Arms [3.051 pu] 110.09°
( @2 G+ }8 V- x& gP: 1.3046e+009 W [13.05 pu] 8 \0 j1 f9 n2 A7 U+ Z* L
Q: -7.6415e+008 Vars [-7.642 pu] ( s( s- f9 J& _; D
Pmec: 1.3079e+009 W [13.08 pu] 4 m# p4 @9 n' S
Torque: 8.3264e+006 N.m [13.08 pu]
' k2 w$ m3 v7 ?/ [) ?+ CVf: 6.067 pu & z; g; d. E1 e, ?/ p" W' s
8 ~ u4 A7 N$ |
Machine: G1 ' e+ n$ b9 t3 w
Nominal: 100 MVA 10.5 kV rms 9 d0 Q4 u& v2 }4 H
Bus Type: P & V generator , M2 Y# {; r' c9 v3 Q3 s
Uan phase: -40.45°
& s- ~# ]* L; b" W$ RUab: 55176 Vrms [5.255 pu] -10.45° * W- @" b( b2 t: D$ ~- c
Ubc: 50638 Vrms [4.823 pu] 158.65°
8 g# z) U, K( v" e& PUca: 11025 Vrms [1.05 pu] -130.09°
/ r( l* h1 m, rIa: 17338 Arms [3.153 pu] -21.32° + e7 L% m: f. f, o6 |, T
Ib: 17338 Arms [3.153 pu] -141.32° ' J, T/ c/ G6 V& r8 I+ W
Ic: 17338 Arms [3.153 pu] 98.68°
. k) Q& B Z$ e6 W3 Y# ~/ p; L# bP: 1.5654e+009 W [15.65 pu] 5 Z$ u1 r/ N. J8 l9 v4 ]) N, u+ l( t
Q: -5.4297e+008 Vars [-5.43 pu] , p" C2 e6 L) f
Pmec: 1.569e+009 W [15.69 pu]
) I! B$ q8 p; i2 w; e' y7 F% W4 fTorque: 9.9887e+006 N.m [15.69 pu]
, B" |3 q' W8 l" A. lVf: 6.7898 pu
& Q1 E& j3 B6 p/ y! h* m 8 N, i/ L& d |3 ^3 F9 h2 |! V+ k$ S
Machine: Load3
) E+ D7 P# E. y% INominal: 115 kV rms
4 E# ]" h! D# U, P: t, ^# B' zBus Type: P & Q load ( L. Z' k/ J) K, a! {
Uan phase: -46.14°
% X" T3 N8 U! x- c$ ~$ Z: \+ i6 \$ uUab: 6.2602e+005 Vrms [5.444 pu] -16.14° ! }0 I2 k, _1 V1 j% K
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43°
2 n/ U* N3 K( M' P5 _* M6 a$ z6 z1 UUca: 30061 Vrms [0.2614 pu] -136.62° & [# c& l( M5 |- M8 h
Ia: 300.16 Arms -102.68° ! p. T7 C8 s3 o/ b
Ib: 300.16 Arms 137.32° * o$ n( c6 ]: v# [! L
Ic: 300.16 Arms 17.32° * x8 G5 W6 |, u" d4 y8 z
P: 1.7944e+008 W
, l5 q# u% g8 Y$ O' sQ: 2.7153e+008 Vars
& |2 }- F1 Z$ M7 b
" r; ]0 x" a0 N, lMachine: Load2
! T% p5 I, [8 r# g6 R; cNominal: 115 kV rms * l- R+ G& v. X4 F5 [2 E
Bus Type: P & Q load
z+ i+ a# ?* PUan phase: -41.18° * B, b, X( X1 @3 D2 C
Uab: 6.0512e+005 Vrms [5.262 pu] -11.18°
1 P! }. Y5 n' SUbc: 5.7431e+005 Vrms [4.994 pu] 157.92° 2 N0 v8 e1 N V2 m' a0 v
Uca: 1.1609e+005 Vrms [1.009 pu] -121.95°% j/ S5 i) u% B
Ia: 798.9 Arms -92.72° # k7 y% a1 @) d( o0 s% @
Ib: 798.9 Arms 147.28°
! h+ ?' Y* A) W& A& [/ rIc: 798.9 Arms 27.28°
7 D2 G! M0 q/ A& I- {. [+ ]P: 5.2087e+008 W
, [9 g! |0 m5 d" QQ: 6.5561e+008 Vars
1 c/ L5 n+ I S" N / A/ G# S# D+ x5 A$ M8 @% s, ?
Machine: Load1
7 ^+ p% Q* U0 |9 SNominal: 115 kV rms
( j% N, ^! }0 r& ^7 BBus Type: P & Q load
' }" |1 n( F* s3 U4 UUan phase: -40.94°
- }: p& \* [/ ]8 IUab: 6.3759e+005 Vrms [5.544 pu] -10.94° " p# n0 ~, Z4 v. Y6 Q* C8 |
Ubc: 5.8926e+005 Vrms [5.124 pu] 158.63°
! N6 m, y) r. y, h4 w9 P# a9 @Uca: 1.2147e+005 Vrms [1.056 pu] -129.49°3 g4 n: L( {, {9 v+ Z8 s* ~; W# ?. j8 U
Ia: 433.21 Arms -97.84° + M- j+ x9 m2 w) }; J' K
Ib: 433.21 Arms 142.16°
/ a/ v! Z6 u+ X' G( g$ J4 OIc: 433.21 Arms 22.16°
; D& E' E" E% H/ BP: 2.6123e+008 W
4 E- d7 |) d/ e8 O- m2 g% n3 z4 G2 KQ: 4.0079e+008 Vars |