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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？9 W4 D5 Z8 M$ ~4 a
注：
s7 K1 v6 k2 e9 P2 yMachine: G2 ( f5 }. V5 I# u2 H/ ~$ V) P1 |
Nominal: 100 MVA 10.5 kV rms
! F( P; {6 @' L* f4 q7 \Bus Type: Swing bus / i# U5 S. |6 D# X' t, j
Uan phase: -40.27°
6 [4 l4 Y% h) F. @% V- {2 xUab: 52029 Vrms [4.955 pu] -10.27° 1 C* h9 N* F# C
Ubc: 48895 Vrms [4.657 pu] 157.70° . K8 l7 Z) k2 r
Uca: 11025 Vrms [1.05 pu] -122.71° ' ~% O( O j2 ^% n- h- o3 m
Ia: 16777 Arms [3.051 pu] -9.91° * q5 ^8 j* m$ O: C
Ib: 16777 Arms [3.051 pu] -129.91° ! q' E( e2 v9 ?
Ic: 16777 Arms [3.051 pu] 110.09°
/ Z( ^0 s- a4 Y$ J! u3 Q; m6 K3 TP: 1.3046e+009 W [13.05 pu] - v) S U5 I# e8 L) n' K% r) T
Q: -7.6415e+008 Vars [-7.642 pu] ) z0 X8 P) h+ z/ v' F! _
Pmec: 1.3079e+009 W [13.08 pu]
9 U( Z! g/ y$ ^1 h4 g( i, o" ATorque: 8.3264e+006 N.m [13.08 pu]
2 r& L8 y4 t' Y% T2 u/ I; \5 {Vf: 6.067 pu
0 ?: ]5 `& o: `$ |. p 4 w/ n3 Z2 w1 k0 ~+ V1 a9 R# ^" R
Machine: G1
, n5 T, r- s6 s- C8 cNominal: 100 MVA 10.5 kV rms # k: E$ ~5 F* `6 W! M7 _
Bus Type: P & V generator ]8 B+ W- t& C6 b5 ~8 {4 W
Uan phase: -40.45° ; v' p* \$ `$ \2 [. F) S. S
Uab: 55176 Vrms [5.255 pu] -10.45°
5 K# K! I7 {" s$ f8 ]) C" \/ bUbc: 50638 Vrms [4.823 pu] 158.65°
8 }6 D4 T! _- i/ K1 ?4 e! h! K% F+ oUca: 11025 Vrms [1.05 pu] -130.09°
$ M+ j+ t8 J) h+ s' W* G4 Z( FIa: 17338 Arms [3.153 pu] -21.32° 7 w; E# L P3 H: j2 Y! l
Ib: 17338 Arms [3.153 pu] -141.32°
$ W% I3 [3 o9 OIc: 17338 Arms [3.153 pu] 98.68°
$ A7 x: j+ [* n( A+ ~P: 1.5654e+009 W [15.65 pu]
9 p9 m; {6 |: e9 v+ P0 yQ: -5.4297e+008 Vars [-5.43 pu]
* Q; G. w% K, `" x/ f4 M5 a+ ^, TPmec: 1.569e+009 W [15.69 pu]
R! g8 k! u3 F" J" u7 ~( zTorque: 9.9887e+006 N.m [15.69 pu]
# }) r: c$ ^$ N, q1 qVf: 6.7898 pu
) o" q( v. l; c8 F- G/ I ; B* q; o/ i# c
Machine: Load3 5 L/ c4 N- U* i; c [
Nominal: 115 kV rms 6 F }7 |9 J6 F1 s) ^# d" c
Bus Type: P & Q load 4 J% N) o, w; Z( @. \% S
Uan phase: -46.14°
; [, x' |6 y# H: q' x4 q" PUab: 6.2602e+005 Vrms [5.444 pu] -16.14° 2 @% o" y* b, n' R* Q
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43° 7 V( k" }8 E# c3 H" S& @% ~
Uca: 30061 Vrms [0.2614 pu] -136.62°
$ Q- j, X+ q. ~1 a2 I3 E/ o3 lIa: 300.16 Arms -102.68° % R/ Q# F. c m3 C" D% y
Ib: 300.16 Arms 137.32° / j% r! I& F. B# Y6 Q4 k
Ic: 300.16 Arms 17.32°
' E; K& z0 u8 n ~P: 1.7944e+008 W - Y; \4 L: V# L8 d3 A
Q: 2.7153e+008 Vars
7 N; E" |3 O& _+ h0 H# o 5 G8 f# p9 u' w3 G
Machine: Load2
& }# R1 e% s. V4 ~% E* mNominal: 115 kV rms + f* _/ Q+ E: T3 {3 W3 T
Bus Type: P & Q load
# ?* x3 Y( d. vUan phase: -41.18° 0 a& F k$ y) H8 h y: Q% [
Uab: 6.0512e+005 Vrms [5.262 pu] -11.18°
+ b! R6 @# `+ D2 {1 R2 }Ubc: 5.7431e+005 Vrms [4.994 pu] 157.92° ) R" v* j( C, x1 _' h y
Uca: 1.1609e+005 Vrms [1.009 pu] -121.95°9 Y5 ]* q6 b$ ]$ ^% i
Ia: 798.9 Arms -92.72°
6 l/ g) X+ g* \+ {8 Z PIb: 798.9 Arms 147.28°
7 M, {, J# W/ I% m1 ~+ a; R9 ~Ic: 798.9 Arms 27.28°
" |. }% Y8 h$ P- OP: 5.2087e+008 W * [6 P4 F) K6 I$ Y; n. _
Q: 6.5561e+008 Vars . {- r% s5 r/ Z. j' c7 S- c4 Z
2 k' m' w) m: P5 pMachine: Load1 , E/ x+ l3 l5 h
Nominal: 115 kV rms - p$ p) E% A* N- A l) M+ _
Bus Type: P & Q load
. f( h' c; M' m3 m4 k V: MUan phase: -40.94° & |: E: u5 P; g5 s8 g+ {
Uab: 6.3759e+005 Vrms [5.544 pu] -10.94° ( {, ~) D2 g; }
Ubc: 5.8926e+005 Vrms [5.124 pu] 158.63°
6 f& {/ y7 P$ oUca: 1.2147e+005 Vrms [1.056 pu] -129.49°/ _1 j$ @4 f/ x8 W
Ia: 433.21 Arms -97.84° 3 ?9 D/ h& D$ M4 g" P" H4 A
Ib: 433.21 Arms 142.16° 8 e: P1 V. h" ?4 Y( L* n1 {, S' V
Ic: 433.21 Arms 22.16° 1 q) f0 x0 D9 O- Y1 x) }
P: 2.6123e+008 W : V, P9 {* k" d8 t. H
Q: 4.0079e+008 Vars |
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发表于 2012-4-29 16:06:35
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