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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？
; B4 \3 ]3 A! d; p* F t5 q: G% m注：( i6 r8 b6 X# V! ]; C# X. ^4 A$ A j! W% u
Machine: G2
w' c; B- m: [) D- WNominal: 100 MVA 10.5 kV rms * R0 Q O7 l5 C# }- t
Bus Type: Swing bus
4 K% X3 @+ O, [9 V" NUan phase: -40.27°
" u& s5 O9 ~ X4 ^8 K, f: m5 ZUab: 52029 Vrms [4.955 pu] -10.27° ! H/ d/ T+ P1 Y1 j! z! R |
Ubc: 48895 Vrms [4.657 pu] 157.70° ; v7 [( y4 H+ G* W9 w; O9 V; G' J
Uca: 11025 Vrms [1.05 pu] -122.71° & A& q+ E- q& M, ], C
Ia: 16777 Arms [3.051 pu] -9.91° & ^% i& Q! E; d. k9 t/ A; N7 K7 w! x
Ib: 16777 Arms [3.051 pu] -129.91°
( W% N z6 H4 \% z) b# @Ic: 16777 Arms [3.051 pu] 110.09°
3 V B0 W# F/ I" a0 D) t$ UP: 1.3046e+009 W [13.05 pu] ; B' d+ H8 y& x
Q: -7.6415e+008 Vars [-7.642 pu] $ ?3 b: B7 ?! [9 G l, v6 Q+ S) Q
Pmec: 1.3079e+009 W [13.08 pu] & i2 l' }/ i* L3 O# y' d w. } k
Torque: 8.3264e+006 N.m [13.08 pu]
, O! I/ E1 X% `# S, y- qVf: 6.067 pu
% w9 v$ B& O( `) s: b/ g$ P- T
. b; W3 M, t/ M5 u$ x( n- xMachine: G1 7 I# P; B. S3 G0 g, {( M$ j
Nominal: 100 MVA 10.5 kV rms
! j& f- C6 F7 _- N8 u* @4 e% NBus Type: P & V generator
' g8 O0 ]: {* r R1 [, fUan phase: -40.45°
. b! I. L. f& w, F2 aUab: 55176 Vrms [5.255 pu] -10.45° - T4 c& A" W8 o) R3 ]. J
Ubc: 50638 Vrms [4.823 pu] 158.65° 2 I' H* v& ]& t( L( W7 {' K
Uca: 11025 Vrms [1.05 pu] -130.09° " U4 U0 d% _" L3 Z
Ia: 17338 Arms [3.153 pu] -21.32°
$ H; E7 F& p* O# ]Ib: 17338 Arms [3.153 pu] -141.32° & o% i9 U: E( E% l3 x0 R* E
Ic: 17338 Arms [3.153 pu] 98.68° & d+ I: b- j2 i
P: 1.5654e+009 W [15.65 pu]
. H/ t' L- m3 Z5 z. \4 X NQ: -5.4297e+008 Vars [-5.43 pu] # D. X5 V# f& r0 h
Pmec: 1.569e+009 W [15.69 pu]
' H7 D& d1 G& ?- MTorque: 9.9887e+006 N.m [15.69 pu]
8 k$ U% ]* u5 c8 a( V& J5 @Vf: 6.7898 pu . R( Q) O+ o: Y) _9 b& H
, A6 G @7 c) m+ R( yMachine: Load3
' r# K4 W. W+ L2 N* b3 }8 k- h( X! Y6 uNominal: 115 kV rms
5 V' q# }* U, K& n/ UBus Type: P & Q load & w( @1 E$ X* h! y8 T2 ?. V) a
Uan phase: -46.14°
5 A- k3 i2 w: W. x1 QUab: 6.2602e+005 Vrms [5.444 pu] -16.14° 4 X$ @7 H, K, e5 s1 U/ ]; x7 z' B
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43°
# [; I' T5 ^: ~. oUca: 30061 Vrms [0.2614 pu] -136.62°
; K3 q( |" ]1 uIa: 300.16 Arms -102.68° 5 R. Z5 O& W$ B! P" E
Ib: 300.16 Arms 137.32° + I( w0 n# L! W% T4 d4 K
Ic: 300.16 Arms 17.32° + u5 ]2 y9 ~. H1 C0 P7 z5 D
P: 1.7944e+008 W 2 k% u3 O0 H, S0 S2 R' H
Q: 2.7153e+008 Vars
4 M- |: O# v" P 7 {% C" ?/ i, `; C
Machine: Load2 ; C* z8 g8 E& H4 g# g0 o
Nominal: 115 kV rms
7 }5 u% u0 {3 ]Bus Type: P & Q load ( i \8 A9 U. y& s: l- {$ u$ G
Uan phase: -41.18° 5 L! u: Z" H2 _' S2 {9 O$ r$ q$ g
Uab: 6.0512e+005 Vrms [5.262 pu] -11.18°
8 W3 x2 d& ~/ a* O9 E. C' jUbc: 5.7431e+005 Vrms [4.994 pu] 157.92° [8 i" A. `8 H6 R( Q
Uca: 1.1609e+005 Vrms [1.009 pu] -121.95°
* S) S) Q( r; J- o q( `Ia: 798.9 Arms -92.72° ' C9 X V; @4 M3 R! a/ r
Ib: 798.9 Arms 147.28°
' N: d P$ F- N) p: NIc: 798.9 Arms 27.28°
+ \8 v5 X: B FP: 5.2087e+008 W ( a5 n* q u1 b3 F$ v; c
Q: 6.5561e+008 Vars ' ^8 i- z# T0 s- o4 ~
! E1 h7 G1 u% ^2 M, K( _! y7 z& WMachine: Load1 ; N" u+ J3 N( i3 t$ m: W- G
Nominal: 115 kV rms
* x$ x8 r: o) sBus Type: P & Q load
8 a" y6 o( w {) a* {1 N; A8 W5 OUan phase: -40.94° 9 p* h7 n9 C8 {& d) K; _. g1 X$ [' h
Uab: 6.3759e+005 Vrms [5.544 pu] -10.94° $ R5 r! F$ m+ j: F4 ?
Ubc: 5.8926e+005 Vrms [5.124 pu] 158.63° # U8 k8 M) n' h" N5 J
Uca: 1.2147e+005 Vrms [1.056 pu] -129.49°( h. ?$ |6 E, o5 E* U P
Ia: 433.21 Arms -97.84°
% s t, Y! Z' S' ^+ QIb: 433.21 Arms 142.16° # m+ b* E5 _" B. `" G0 V
Ic: 433.21 Arms 22.16°
! n5 ^: F3 Y$ L! AP: 2.6123e+008 W
1 k0 m6 ]8 g" G) q$ L {Q: 4.0079e+008 Vars |
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发表于 2012-4-29 16:06:35
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