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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？ `; d7 k ~4 P. \3 s' z
注：
9 l) P( s. r% sMachine: G2 4 z7 R7 q: Q9 R4 ~( Y
Nominal: 100 MVA 10.5 kV rms
2 L3 r3 n0 v# v( Y. ^$ J/ ^# \$ uBus Type: Swing bus
; E0 \ v5 I1 k/ x0 [$ z* S1 XUan phase: -40.27° + f$ a+ p M( d7 S4 }
Uab: 52029 Vrms [4.955 pu] -10.27°
% j/ ^: p2 b$ G; VUbc: 48895 Vrms [4.657 pu] 157.70° ) Z8 ]* M7 C) D, |
Uca: 11025 Vrms [1.05 pu] -122.71° 8 x$ x& D" W9 L+ B1 n% R
Ia: 16777 Arms [3.051 pu] -9.91°
9 c4 Q/ t8 I. v. q* e' _( bIb: 16777 Arms [3.051 pu] -129.91° ' a; f7 E4 ]- U& t. S, V5 p+ j; b0 q
Ic: 16777 Arms [3.051 pu] 110.09° ! A7 {8 b2 m( ? y# Y
P: 1.3046e+009 W [13.05 pu] * H+ l* }6 J, s
Q: -7.6415e+008 Vars [-7.642 pu] ; F5 l O* D& d; o4 ?4 R( [0 ]5 a
Pmec: 1.3079e+009 W [13.08 pu]
) _' L- U/ _/ S# D7 l. L+ eTorque: 8.3264e+006 N.m [13.08 pu] " h$ L) B0 V* z) g
Vf: 6.067 pu
( h% o; K$ v0 c" `! s3 i, P% W
$ }% I0 Q9 m& m Q5 }! |) jMachine: G1
) H8 u! N, |/ R+ A- b* fNominal: 100 MVA 10.5 kV rms
; }- i' D7 _$ I5 VBus Type: P & V generator
- W+ E0 K. |# T6 \, i, {1 ]Uan phase: -40.45°
4 ^' ^( P" q" t* C t' YUab: 55176 Vrms [5.255 pu] -10.45°
# Q$ r" O2 \6 l/ \ U6 XUbc: 50638 Vrms [4.823 pu] 158.65°
# [7 s: o+ C' y) n" k# rUca: 11025 Vrms [1.05 pu] -130.09°
3 L9 H2 I$ {8 }4 o/ @+ j2 |Ia: 17338 Arms [3.153 pu] -21.32°
, x0 Y* L5 d8 ?% r1 tIb: 17338 Arms [3.153 pu] -141.32°
$ T/ p4 y) R$ S6 c( F1 {' ^3 zIc: 17338 Arms [3.153 pu] 98.68°
1 g: z3 `$ ^6 ]7 U }1 IP: 1.5654e+009 W [15.65 pu] * F/ X; g$ ?6 ^3 p6 I; ^( w4 x
Q: -5.4297e+008 Vars [-5.43 pu] ; k2 Z/ `* m+ `( F1 ~
Pmec: 1.569e+009 W [15.69 pu]
6 c' r5 |' v+ e8 D1 s2 ~Torque: 9.9887e+006 N.m [15.69 pu] # T/ I, `! o; m0 _5 b2 K$ p
Vf: 6.7898 pu 3 [( L k7 N& K" q' H2 v/ Q: ~$ V
6 [" T W6 {* x3 R" ~: QMachine: Load3
% F7 Q. m& x l; g3 s$ o! ZNominal: 115 kV rms 0 Y5 A* W1 c! ~( V6 X' s
Bus Type: P & Q load
* r6 W7 R" e1 O1 v' Q, r7 w, tUan phase: -46.14°
. c& q0 F/ O) p: D: ^Uab: 6.2602e+005 Vrms [5.444 pu] -16.14° 7 z7 f) |7 m/ a: b4 B1 f9 _
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43°
4 a& y- D1 y9 {; g- U+ pUca: 30061 Vrms [0.2614 pu] -136.62° " G6 X' @. [# Y$ `1 A: `
Ia: 300.16 Arms -102.68°
E5 B% ~, z9 d' o! QIb: 300.16 Arms 137.32° ( j( i6 \ g/ Z# C
Ic: 300.16 Arms 17.32° : Z7 r7 f. R$ }
P: 1.7944e+008 W , Q' }4 b: [, ]" j" d5 F
Q: 2.7153e+008 Vars
) \0 z* O* R. q# y2 z1 N3 c# m& @
. w! b) s+ l& d0 X& l) qMachine: Load2 ' H) D& N \* [! n- |9 B! g
Nominal: 115 kV rms " @+ e+ }" d3 r$ F e+ w! t9 g
Bus Type: P & Q load
/ z6 O, s- i% d/ O: ^9 d/ fUan phase: -41.18° 1 d; B& g$ O! y2 Y7 c2 D8 y( H) v
Uab: 6.0512e+005 Vrms [5.262 pu] -11.18° ( G3 `2 ]0 v1 p6 r9 n0 n& `4 C
Ubc: 5.7431e+005 Vrms [4.994 pu] 157.92°
- d" K( K2 p3 X5 gUca: 1.1609e+005 Vrms [1.009 pu] -121.95°) B: i; w4 b1 K/ E1 C
Ia: 798.9 Arms -92.72° % t- V1 e* T0 s# w
Ib: 798.9 Arms 147.28° 1 O7 J ~( D$ Q0 V' t
Ic: 798.9 Arms 27.28° 7 m- Q* V5 _$ F
P: 5.2087e+008 W
: ]$ d0 k, s: S* w g) N rQ: 6.5561e+008 Vars
) }7 r# W+ z! _1 |+ ~5 D
, j1 p+ ?5 o& t0 S/ _. p; XMachine: Load1
0 F0 v* V: X2 D' i0 B) G; }Nominal: 115 kV rms
9 t* T7 Y( K8 UBus Type: P & Q load
- o0 _* h" H8 p; J3 @Uan phase: -40.94° + t, W" x' N" ?" w9 y
Uab: 6.3759e+005 Vrms [5.544 pu] -10.94°
: b4 P9 b& K* ~- D/ aUbc: 5.8926e+005 Vrms [5.124 pu] 158.63° 2 q- s& l$ \9 t( i/ r" c
Uca: 1.2147e+005 Vrms [1.056 pu] -129.49°7 h" c5 F9 ~0 w" _3 h( B
Ia: 433.21 Arms -97.84°
! H' P( x6 J0 y% d) h" S9 DIb: 433.21 Arms 142.16°
+ ]7 N) f- C3 a& [Ic: 433.21 Arms 22.16°
* E9 y* U y+ ^P: 2.6123e+008 W
9 c# I: h9 l) I' Y; w" B6 CQ: 4.0079e+008 Vars |
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发表于 2012-4-29 16:06:35
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