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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？' | s7 n1 u7 [/ ? l( x+ O
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Machine: G2 9 J0 m/ ]' }" G) d9 F2 J* \
Nominal: 100 MVA 10.5 kV rms
' o) e* M! s2 v3 L! i! U3 X1 p) sBus Type: Swing bus A5 W W. I1 x2 t+ M1 g
Uan phase: -40.27° $ |3 H. M/ l7 J7 U$ r- }/ S
Uab: 52029 Vrms [4.955 pu] -10.27°
- Z! O. Q5 h8 G8 N7 Y; a0 t1 uUbc: 48895 Vrms [4.657 pu] 157.70°
! u- k0 }4 s O1 r1 @! P# rUca: 11025 Vrms [1.05 pu] -122.71° + q9 r k* s! m5 a3 C, B/ i# Q
Ia: 16777 Arms [3.051 pu] -9.91°
4 t5 P' z6 p. h: \- PIb: 16777 Arms [3.051 pu] -129.91°
% z) \. m9 |; A7 p2 IIc: 16777 Arms [3.051 pu] 110.09°
- Z+ w: Y% m- t# j; qP: 1.3046e+009 W [13.05 pu]
! z, E" p M- G# PQ: -7.6415e+008 Vars [-7.642 pu]
3 v$ n3 s; L. ~8 e9 x, }4 TPmec: 1.3079e+009 W [13.08 pu] , r4 E# }7 C0 K/ F6 U
Torque: 8.3264e+006 N.m [13.08 pu]
! j/ U1 l& i( g6 WVf: 6.067 pu
; z; `' c7 m& o& D3 b; r
/ m, e+ H- E& {4 ~* I! _- @! I1 lMachine: G1 9 a, t1 I3 d$ h! ?* o: `" s
Nominal: 100 MVA 10.5 kV rms " |% X* L5 O" t6 j+ n1 x
Bus Type: P & V generator 9 Z1 G; G z s( H- c
Uan phase: -40.45° ( }7 A" Z! Z# y
Uab: 55176 Vrms [5.255 pu] -10.45°
( s: G' V# {% i, F! gUbc: 50638 Vrms [4.823 pu] 158.65° 8 r6 @2 W4 Q# N( G3 i) L
Uca: 11025 Vrms [1.05 pu] -130.09° 8 q1 s& Y0 }" |9 V1 m: G- L) u
Ia: 17338 Arms [3.153 pu] -21.32° 8 I8 a/ k! c6 {# h0 p
Ib: 17338 Arms [3.153 pu] -141.32°
6 W9 n4 h8 Y7 E1 P! ^Ic: 17338 Arms [3.153 pu] 98.68°
8 G9 X" A) v. o- M8 vP: 1.5654e+009 W [15.65 pu]
& K S2 }5 I8 z1 l; \; U9 FQ: -5.4297e+008 Vars [-5.43 pu] & e8 |' t( e2 |3 S
Pmec: 1.569e+009 W [15.69 pu]
, k: O; I6 o. A, ?Torque: 9.9887e+006 N.m [15.69 pu] * O8 w3 j. R I7 V- I0 c. N2 K& _
Vf: 6.7898 pu
. Z* p3 s! k4 K. g& W# H9 l6 k
$ O. Q# Q! X2 T% o! oMachine: Load3 7 q: { R; V5 O7 q' ~" B
Nominal: 115 kV rms 7 o2 {$ d {- @! R9 F4 [% X
Bus Type: P & Q load ! |- y. V, T: ?! ^* q2 b# h
Uan phase: -46.14°
+ `& s) H3 @5 @. f: SUab: 6.2602e+005 Vrms [5.444 pu] -16.14° # {0 A7 R6 d, T3 z F0 P- ~4 p% M D
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43°
, W6 Y+ @" h4 Z8 ]. _" D1 q; BUca: 30061 Vrms [0.2614 pu] -136.62°
2 B8 W, E, x" P' M; cIa: 300.16 Arms -102.68° : D% p% `1 d0 c
Ib: 300.16 Arms 137.32° ( c8 V4 v5 `$ _5 B7 ]5 Q
Ic: 300.16 Arms 17.32° & @# W* Z+ I* i$ \) J5 |% J
P: 1.7944e+008 W
( S9 K8 N' O9 p- Z! m1 j$ _ }# JQ: 2.7153e+008 Vars , X# w2 Y2 ~2 ^4 I K5 ^+ R5 ~
1 e: k8 J1 X1 y N
Machine: Load2 8 `( ~8 [# I9 I: a% H) n) t& Y/ G0 D
Nominal: 115 kV rms ' |; y& u8 r& W$ @* ~& Q
Bus Type: P & Q load - R W- W( r) ]+ ~9 o
Uan phase: -41.18°
2 N& R' h+ b) H! B5 d6 h$ FUab: 6.0512e+005 Vrms [5.262 pu] -11.18°
: k' o8 c( X. _0 C) f hUbc: 5.7431e+005 Vrms [4.994 pu] 157.92° ! Y$ C2 p$ K6 O7 b
Uca: 1.1609e+005 Vrms [1.009 pu] -121.95°
4 D4 l7 H: L# X4 rIa: 798.9 Arms -92.72° . w9 k7 B( J6 c! k7 ?. K
Ib: 798.9 Arms 147.28° & b4 E; I% ~# q& C" u' J
Ic: 798.9 Arms 27.28°
1 r. l& R) L+ ^0 I; v1 q" z' N4 sP: 5.2087e+008 W " h1 r& y. Q, V8 N) |3 T
Q: 6.5561e+008 Vars
; C. ~3 a5 P3 |$ s l
! D! O1 |; ~7 a1 M0 Z' PMachine: Load1
) C8 I s$ L4 tNominal: 115 kV rms , h5 _9 l- O. c0 E) U# H
Bus Type: P & Q load
% }2 D, M6 m4 x: I5 o( EUan phase: -40.94° + S5 `. I: A* Q- S0 ^- n
Uab: 6.3759e+005 Vrms [5.544 pu] -10.94° " O' l, S4 L( p, m) ]
Ubc: 5.8926e+005 Vrms [5.124 pu] 158.63° Z2 Z! t/ n, ~+ k% I( H& F* ]
Uca: 1.2147e+005 Vrms [1.056 pu] -129.49°
8 m/ n* f0 M) m! `% [Ia: 433.21 Arms -97.84°
: H1 F) T$ n. x7 {* N# LIb: 433.21 Arms 142.16°
* ]4 e+ J+ E9 b i6 U0 oIc: 433.21 Arms 22.16°
2 d r* U; Q" l. G2 nP: 2.6123e+008 W - f8 r, |5 H5 H6 F# P
Q: 4.0079e+008 Vars |
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发表于 2012-4-29 16:06:35
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