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在变压器仿真中，得到的RL矩阵如下
3 I {& y# I+ F0 I; l8 o! [: i$VINTAGE, 1,* Q* n/ g1 P( B6 D% L& d! C
1st of PI-ckt. 6.943E+03 0.000E+00 0.000E+00 | 1T_BUSAT_BUSC 6942.84362684328 C0 i: z6 C# l6 x# j. y2 H
Phase 2. 0.0000E+00 0.0000E+00 0.0000E+00 | 2T_BUSBT_BUSA 0.0 S# B7 f) {* e) X
Cont. 6.9428E+03 0.0000E+00 0.0000E+00 | 6942.8436268432; I# r1 _/ p6 T; \ ?3 a
Phase 3. 0.0000E+00 0.0000E+00 0.0000E+00 | 3T_BUSCT_BUSB 0.0: L k' i7 W. Y) W M3 Q8 H8 v2 M
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0
- z* G# e5 z9 O Cont. 6.9428E+03 0.0000E+00 0.0000E+00 | 6942.8436268432; d7 U8 A" q }
Begin coupled, lumped elements using [A], [R]. | USE AR
- ^( {+ E; R* D; V' A0 ~1st of PI-ckt. 3.289E+00 4.246E-01 0.000E+00 | 1H_BUSAL_BUSA 3.2888630659697 .424623487216128 x% _' D" R, {4 l
Phase 2. -7.2313E+00 0.0000E+00 0.0000E+00 | 2L_BUSA -7.231251366149 0.0, J/ F5 R* P$ z
Cont. 3.4681E+01 9.4926E-02 0.0000E+00 | 34.681001957452 .094925951917722 q3 G" h5 A5 Q" m2 t% L+ I
Phase 3. 2.3450E+00 0.0000E+00 0.0000E+00 | 3T_BUSAT_BUSC 2.3450004639366 0.0
9 x. I8 S6 }8 S Cont. -8.4675E+01 0.0000E+00 0.0000E+00 | -84.67537379274 0.0, A' W* ~1 e2 J0 a# U* X
Cont. 3.3835E+02 0.0000E+00 0.0000E+00 | 338.34949508527 0.05 ? n0 E$ \( v0 x3 F$ H/ p
Phase 4. 0.0000E+00 0.0000E+00 0.0000E+00 | 4H_BUSBL_BUSB 0.0 0.0" w, |% q0 K" ?$ h }
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0" Z1 x6 R- e F! [! c
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
2 ^( S* v3 q$ u8 U Cont. 3.2889E+00 4.2462E-01 0.0000E+00 | 3.2888630659697 .42462348721612
; |2 H' c* j: K0 [Phase 5. 0.0000E+00 0.0000E+00 0.0000E+00 | 5L_BUSB 0.0 0.0
6 r: @5 L" ]# ~ Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.07 u) @+ ^8 u) p; V1 _& z
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.03 e$ l; ]/ v$ U: C
Cont. -7.2313E+00 0.0000E+00 0.0000E+00 | -7.231251366149 0.02 c9 J* H O( J! J
Cont. 3.4681E+01 9.4926E-02 0.0000E+00 | 34.681001957452 .09492595191772
* U; s+ U2 w' V" n x7 C/ U2 nPhase 6. 0.0000E+00 0.0000E+00 0.0000E+00 | 6T_BUSBT_BUSA 0.0 0.0
$ F4 h& B- q: E8 g" O+ [* x# p Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
! R3 s# K; p+ ~: m% B Cont. -6.5427E-05 0.0000E+00 0.0000E+00 | -.6542678427E-4 0.0
, N; M- ~. O- W; S% V Cont. 2.3450E+00 0.0000E+00 0.0000E+00 | 2.3450004639366 0.0
( C# p9 u: P! z Cont. -8.4675E+01 0.0000E+00 0.0000E+00 | -84.67537379274 0.0( t. x& ^. x, c- D( `
Cont. 3.3835E+02 0.0000E+00 0.0000E+00 | 338.34949508527 0.0
/ {8 C! ^/ ^0 R# O# H# GPhase 7. 0.0000E+00 0.0000E+00 0.0000E+00 | 7H_BUSCL_BUSC 0.0 0.0
9 ~! m6 } Z1 ]2 d& H1 F. \8 R1 f Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0. j! q8 S( M* R: z3 g2 Y; i" N" X% S
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.09 J8 x. S; _& ^
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
4 P5 @0 y3 u, Z5 e; r Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
4 Y0 `7 P9 m8 O$ h: d Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
: _( Z. f m+ j, a2 L$ \ Cont. 3.2889E+00 4.2462E-01 0.0000E+00 | 3.2888630659697 .424623487216128 J: C0 o0 H. ]/ ^ y
Phase 8. 0.0000E+00 0.0000E+00 0.0000E+00 | 8L_BUSC 0.0 0.0
: q5 o& a4 P/ D. @+ @1 N Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0& t5 L! `7 ?! b1 X1 W. z z
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.03 B1 a& w) X, W% g/ ^# R( z
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0& m6 X& z+ Q1 K
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0( \$ [# G' G) ^" [
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
6 H( z' L. v' r& ~6 v, n9 r Cont. -7.2313E+00 0.0000E+00 0.0000E+00 | -7.231251366149 0.0! p8 ?7 J5 f# U
Cont. 3.4681E+01 9.4926E-02 0.0000E+00 | 34.681001957452 .09492595191772$ \4 S$ C. x" v: V0 f5 X/ R
Phase 9. 0.0000E+00 0.0000E+00 0.0000E+00 | 9T_BUSCT_BUSB 0.0 0.0
# G9 d: S, W$ e. x& E5 } Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
" d; ~: t5 ?6 k$ b- Q/ y+ ^ Cont. -6.5427E-05 0.0000E+00 0.0000E+00 | -.6542678427E-4 0.09 j3 i; s! s ~- Z% \+ o1 D0 |
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.01 S4 L/ v- L3 `) g; e6 Y3 F
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0* x+ N/ J3 p' x; f! N0 a) O! _
Cont. -6.5427E-05 0.0000E+00 0.0000E+00 | -.6542678427E-4 0.05 v" @$ T. s3 h
Cont. 2.3450E+00 0.0000E+00 0.0000E+00 | 2.3450004639366 0.0
" D- E0 y: G* K1 I Cont. -8.4675E+01 0.0000E+00 0.0000E+00 | -84.67537379274 0.0+ m( C" r8 k9 ?! }( s6 I0 k5 x
Cont. 3.3835E+02 0.0000E+00 0.0000E+00 | 338.34949508527 0.0
; o5 d9 @5 f: x, r) ONew MOLDAT = 0 (data vintage). |$VINTAGE, -1,
1 K% h j, d5 ?8 i但是，电阻存在互电阻的情况，与文献分析对应不起来。想问一下大家这个和附件中的分析之间的关系。1 @/ Q/ ~- y, v. F
谢谢！ |
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