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在变压器仿真中，得到的RL矩阵如下
5 ?3 b. m. f }$VINTAGE, 1,4 `: l( t! _- }$ B5 I/ `4 I
1st of PI-ckt. 6.943E+03 0.000E+00 0.000E+00 | 1T_BUSAT_BUSC 6942.84362684321 E: w4 T+ L1 j
Phase 2. 0.0000E+00 0.0000E+00 0.0000E+00 | 2T_BUSBT_BUSA 0.0" ]% q3 U1 u5 O6 _' q, u+ ^" Y7 y
Cont. 6.9428E+03 0.0000E+00 0.0000E+00 | 6942.8436268432, x [& |5 p+ m
Phase 3. 0.0000E+00 0.0000E+00 0.0000E+00 | 3T_BUSCT_BUSB 0.0
" q: v! g$ Q x) s; \+ J( u) L Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.01 |& V1 z' }& \1 \
Cont. 6.9428E+03 0.0000E+00 0.0000E+00 | 6942.84362684326 Z/ {. ^2 U. q7 D5 A
Begin coupled, lumped elements using [A], [R]. | USE AR
, ?7 ?% g, x( |2 L1st of PI-ckt. 3.289E+00 4.246E-01 0.000E+00 | 1H_BUSAL_BUSA 3.2888630659697 .424623487216126 [% U2 V( M8 ?# K
Phase 2. -7.2313E+00 0.0000E+00 0.0000E+00 | 2L_BUSA -7.231251366149 0.0
4 @: `" p. M y/ x, J Cont. 3.4681E+01 9.4926E-02 0.0000E+00 | 34.681001957452 .09492595191772
; A3 L9 x1 ~5 M7 e, gPhase 3. 2.3450E+00 0.0000E+00 0.0000E+00 | 3T_BUSAT_BUSC 2.3450004639366 0.0) z& }! @$ w* Z+ N* V
Cont. -8.4675E+01 0.0000E+00 0.0000E+00 | -84.67537379274 0.0
; Q2 i# ~9 O% ]( t0 q! z Cont. 3.3835E+02 0.0000E+00 0.0000E+00 | 338.34949508527 0.0, y. G9 b& l1 I1 H, o' q* N( ^
Phase 4. 0.0000E+00 0.0000E+00 0.0000E+00 | 4H_BUSBL_BUSB 0.0 0.0! n. w/ F$ v3 m8 m6 k( G
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
+ ]; Q P" M* d# B9 C- B a Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0, z; @$ v$ \" g% `
Cont. 3.2889E+00 4.2462E-01 0.0000E+00 | 3.2888630659697 .42462348721612* F" [; W% H9 n" Q$ K( W: t3 _
Phase 5. 0.0000E+00 0.0000E+00 0.0000E+00 | 5L_BUSB 0.0 0.0
2 @! v& h* A) P) [7 |+ x Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
" @; t7 o( F) @2 l1 d Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
6 e2 }; P! b: F! A: E. h Cont. -7.2313E+00 0.0000E+00 0.0000E+00 | -7.231251366149 0.00 p m ^6 R6 z. `# ~
Cont. 3.4681E+01 9.4926E-02 0.0000E+00 | 34.681001957452 .09492595191772
/ x2 G U5 Y P$ QPhase 6. 0.0000E+00 0.0000E+00 0.0000E+00 | 6T_BUSBT_BUSA 0.0 0.0
1 h+ K* x' A5 I/ Q' A Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0% E' P2 z. V4 W a/ g+ F
Cont. -6.5427E-05 0.0000E+00 0.0000E+00 | -.6542678427E-4 0.0" }% q& M5 y& V; ~
Cont. 2.3450E+00 0.0000E+00 0.0000E+00 | 2.3450004639366 0.0) U, R `) H0 o) F8 j* @/ M
Cont. -8.4675E+01 0.0000E+00 0.0000E+00 | -84.67537379274 0.0' K8 ^9 M% ]6 a5 o3 e5 |- r
Cont. 3.3835E+02 0.0000E+00 0.0000E+00 | 338.34949508527 0.0- c. {6 n! p+ s, Q+ K: E/ G1 i
Phase 7. 0.0000E+00 0.0000E+00 0.0000E+00 | 7H_BUSCL_BUSC 0.0 0.0
5 c, J! a. O) P Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
( S& ^' Y% q4 p7 l Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.04 F3 r" B) J+ b( H
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
1 f* F' k/ h, l Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0! ]# l2 K$ m! V! N5 D: R
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0% |2 ]( U4 Z: O
Cont. 3.2889E+00 4.2462E-01 0.0000E+00 | 3.2888630659697 .42462348721612" Y5 [0 x, s/ T, a& X" l. F
Phase 8. 0.0000E+00 0.0000E+00 0.0000E+00 | 8L_BUSC 0.0 0.0
! j- R$ }( H& \0 p( V! s! O. T Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
6 Q9 B$ Y& v* k9 V6 U. q c Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
5 N0 {1 Z6 s0 q7 y) Y Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.00 b( q# x9 `8 G; a" v
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
2 v. z" A: u" A( o5 L Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
( f2 T! b$ ?0 O6 D0 X0 B0 N Cont. -7.2313E+00 0.0000E+00 0.0000E+00 | -7.231251366149 0.0
+ y) P! _ W8 X6 P1 H/ q5 E! F Cont. 3.4681E+01 9.4926E-02 0.0000E+00 | 34.681001957452 .09492595191772
& {6 U$ U; V, a. v; U1 H3 z1 e: rPhase 9. 0.0000E+00 0.0000E+00 0.0000E+00 | 9T_BUSCT_BUSB 0.0 0.0
7 W! c4 X+ A' ^: W2 E1 [( n0 Y Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
# Q" B6 g5 L2 O% {( ]' d Cont. -6.5427E-05 0.0000E+00 0.0000E+00 | -.6542678427E-4 0.0 w, ~- M# z) W: Z* j* @0 ^0 A. {' k
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
: N: _6 c7 h p- ]. _ Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.07 }. H) T- l/ O4 f( K
Cont. -6.5427E-05 0.0000E+00 0.0000E+00 | -.6542678427E-4 0.0; k T! ]7 K8 t
Cont. 2.3450E+00 0.0000E+00 0.0000E+00 | 2.3450004639366 0.01 y2 B- x7 b, c! I: y! [
Cont. -8.4675E+01 0.0000E+00 0.0000E+00 | -84.67537379274 0.0
' J; M6 p* o+ z& Y; W7 W Cont. 3.3835E+02 0.0000E+00 0.0000E+00 | 338.34949508527 0.0
$ [8 g; M, m- e+ sNew MOLDAT = 0 (data vintage). |$VINTAGE, -1,
/ X1 z/ p6 R: o% s! A" O, n+ N' {; L但是，电阻存在互电阻的情况，与文献分析对应不起来。想问一下大家这个和附件中的分析之间的关系。
! i9 I# v9 ?% {% |; P. c谢谢！ |
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