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在变压器仿真中，得到的RL矩阵如下
# k h+ s" z, Y0 Q) d$VINTAGE, 1,2 O. J6 O2 Y2 a
1st of PI-ckt. 6.943E+03 0.000E+00 0.000E+00 | 1T_BUSAT_BUSC 6942.8436268432
4 i5 F8 j. Q/ Z! e1 _% S9 GPhase 2. 0.0000E+00 0.0000E+00 0.0000E+00 | 2T_BUSBT_BUSA 0.01 b. S6 R( {! h; g, \- M
Cont. 6.9428E+03 0.0000E+00 0.0000E+00 | 6942.8436268432
* a7 }" m2 n) nPhase 3. 0.0000E+00 0.0000E+00 0.0000E+00 | 3T_BUSCT_BUSB 0.0, \ w0 O0 z# A. r8 g$ u1 o
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.03 w+ @" y3 [' U7 ?# c0 a; E
Cont. 6.9428E+03 0.0000E+00 0.0000E+00 | 6942.8436268432! j2 r) X3 Z+ U: x, I
Begin coupled, lumped elements using [A], [R]. | USE AR5 I7 o! ?9 W' Q& j
1st of PI-ckt. 3.289E+00 4.246E-01 0.000E+00 | 1H_BUSAL_BUSA 3.2888630659697 .424623487216125 Q- S3 A7 t9 X. u- u- B
Phase 2. -7.2313E+00 0.0000E+00 0.0000E+00 | 2L_BUSA -7.231251366149 0.0
, y) Z8 v" ^# |5 u Cont. 3.4681E+01 9.4926E-02 0.0000E+00 | 34.681001957452 .09492595191772
1 o! D; c* g! a! kPhase 3. 2.3450E+00 0.0000E+00 0.0000E+00 | 3T_BUSAT_BUSC 2.3450004639366 0.0
, h# C0 e& L1 H6 ^5 L Cont. -8.4675E+01 0.0000E+00 0.0000E+00 | -84.67537379274 0.0: |! j4 A1 c$ w& I5 @- Y
Cont. 3.3835E+02 0.0000E+00 0.0000E+00 | 338.34949508527 0.0" K% `+ m: O) A6 M' V% o9 k+ F" @
Phase 4. 0.0000E+00 0.0000E+00 0.0000E+00 | 4H_BUSBL_BUSB 0.0 0.0
( g% m% ?& a+ g6 e" B, v+ z Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0) X; h8 O/ n: i# C( l
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
. U' P7 z0 Z/ W$ n Cont. 3.2889E+00 4.2462E-01 0.0000E+00 | 3.2888630659697 .42462348721612
! b; f( _7 `: `Phase 5. 0.0000E+00 0.0000E+00 0.0000E+00 | 5L_BUSB 0.0 0.0
4 U8 x. v9 y* ~0 u Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.02 h3 q$ \4 D w" y
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0' q; N; ~, I q; e2 c4 Z- r* e; l5 t
Cont. -7.2313E+00 0.0000E+00 0.0000E+00 | -7.231251366149 0.0
* L% X: L1 }7 V, q/ K& m' g Cont. 3.4681E+01 9.4926E-02 0.0000E+00 | 34.681001957452 .094925951917726 |" k* \ z4 a# o4 Q+ s
Phase 6. 0.0000E+00 0.0000E+00 0.0000E+00 | 6T_BUSBT_BUSA 0.0 0.07 N3 f' }; L$ q& i" S' {/ g& s
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.06 h& l: G5 l; b* o" H0 r
Cont. -6.5427E-05 0.0000E+00 0.0000E+00 | -.6542678427E-4 0.0/ L0 _/ W9 r, K+ n4 U
Cont. 2.3450E+00 0.0000E+00 0.0000E+00 | 2.3450004639366 0.01 N+ E/ H8 E4 a: Z# K7 C* H# w
Cont. -8.4675E+01 0.0000E+00 0.0000E+00 | -84.67537379274 0.0( k. x% M! ~# y! I
Cont. 3.3835E+02 0.0000E+00 0.0000E+00 | 338.34949508527 0.09 A M& r9 X1 k/ y% A
Phase 7. 0.0000E+00 0.0000E+00 0.0000E+00 | 7H_BUSCL_BUSC 0.0 0.0
L1 M) b6 F$ d5 v. T8 I/ o Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
: H: f% x) n. K* J; Y% s* l$ L3 X3 Y Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
\ A o4 Y3 E8 Z( y4 V: X Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.00 X- J$ u- x. I: y- C
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.00 A+ A7 o2 H2 o, r$ d$ u' e
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0+ H7 [/ ]1 V% W4 w5 _
Cont. 3.2889E+00 4.2462E-01 0.0000E+00 | 3.2888630659697 .42462348721612; o, C( ?: L! m+ V, w# |* [) @: T
Phase 8. 0.0000E+00 0.0000E+00 0.0000E+00 | 8L_BUSC 0.0 0.0' j2 S& F. l+ Q1 e( B5 q
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.03 D! D2 f0 q1 w& G+ G+ z
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
$ r3 X7 S$ m2 b i% F Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
* N4 Z/ r) P" v0 s# F0 I$ g Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.07 J2 [' G2 G* L- |2 F5 z0 R7 H' H- U
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0$ a4 S [8 t0 l0 W+ S
Cont. -7.2313E+00 0.0000E+00 0.0000E+00 | -7.231251366149 0.01 M8 E7 l4 e" o7 r
Cont. 3.4681E+01 9.4926E-02 0.0000E+00 | 34.681001957452 .09492595191772
/ w; Z, j6 L/ d9 o/ l, GPhase 9. 0.0000E+00 0.0000E+00 0.0000E+00 | 9T_BUSCT_BUSB 0.0 0.0# ?$ W- j5 o$ J. E. e; X- D
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0
1 Z1 z# b6 H: R; H+ S- C Cont. -6.5427E-05 0.0000E+00 0.0000E+00 | -.6542678427E-4 0.0
6 Q8 s6 k: g1 ~8 E Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0, P S6 N) K3 N
Cont. 0.0000E+00 0.0000E+00 0.0000E+00 | 0.0 0.0* t4 G2 J; ]( s4 M7 t( X1 q
Cont. -6.5427E-05 0.0000E+00 0.0000E+00 | -.6542678427E-4 0.0( S# j+ |( R. U* Q9 M
Cont. 2.3450E+00 0.0000E+00 0.0000E+00 | 2.3450004639366 0.07 h9 L5 M: d4 Y$ o5 p
Cont. -8.4675E+01 0.0000E+00 0.0000E+00 | -84.67537379274 0.0/ w5 l8 n( y# W; Y$ r
Cont. 3.3835E+02 0.0000E+00 0.0000E+00 | 338.34949508527 0.0
; V0 N2 s; e: V! n; h& pNew MOLDAT = 0 (data vintage). |$VINTAGE, -1,
. [% N# M3 Z1 E/ M, m但是，电阻存在互电阻的情况，与文献分析对应不起来。想问一下大家这个和附件中的分析之间的关系。' u) n4 ^* D2 b
谢谢！ |
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