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本帖最后由 biligjs 于 2010-11-9 20:24 编辑 ; G. }, n* [! Z$ Z
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BPA潮流计算结果中，每条线路最后都会有一项QC，比如，Bus1到BusA最后一项是4.7QC，这个项到底代表的是什么意思？
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另外下面SUMMARY OF SYSTEM QUANTITIES FOR ZONE 01中，有一项是LINE INJECTION (QC) 72.3，这个72.3是上面潮流计算中所有的QC项相加的结果，这一项代表什么意思？如果将这一项加进去的话，无功似乎无法平衡了。
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在SYSTEM INJECTION: 中SUBTOTAL (INJECTION) 3.4 -23.5 显示系统缺少23.5Mvar的无功，为什么下面LINE AND TRANSFORMER LOSSES -3.4 23.5 这一项却显示是正值。显示正值是不是说明这项是线路的分布电容所发出的无功？如果指的是线路的分布电容所发出的无功，那么恰好可以补偿上面系统所缺少的无功。这样子的话那项72.3又要做何解释？- i1 I" n( J8 a; g+ ]% @, G
, R! w7 O8 Z/ C3 q$ s请高手解答下？! A: L- B6 C6 p& B& c3 L
＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝系统自带的IEEE9节点算例程序＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝
+ ]/ V) |% p4 m: _0 h$ M(POWERFLOW,CASEID=IEEE9,PROJECT=IEEE_9BUS_TEST_SYSTEM): ]9 ?6 W) Z; }. _9 O, l+ _6 z
/SOL_ITER,DECOUPLED=2,NEWTON=15,OPITM=0\3 k) ~. a H( K. ]9 [2 m4 \" Y
/P_INPUT_LIST,ZONES=ALL\9 _# t: u; h2 X- g
/P_OUTPUT_LIST,ZONES=ALL\$ D: g3 ~; l# T* h
/RPT_SORT=ZONE\# c* V1 f _ B
/NEW_BASE,FILE=IEEE90.BSE\5 y3 n: T4 }5 J! t& ^" c
/PF_MAP,FILE = IEEE90.MAP\
& T1 o* ]3 U3 ~, I* z/NETWORK_DATA\
1 a4 |5 {# W h0 h1 mBS Gen1 16.501 999. 999. 1.019 V& q8 n$ `- p3 z, {5 m; E
B Bus1 230.01
+ X8 T0 x5 ^! P! O R8 yB BusA 230.01 125. 70.0 20.
0 K4 [3 g9 n# M s/ XB BusB 230.01 90. 40.0 10.
6 v+ U# z) `6 X P( w% G1 J9 w2 WB BusC 230.01 100. 55.0 20. 000
" O$ r6 v7 h6 Z+ g& e$ kB Bus2 230.01 35.0 10.0
6 e( O; X" l( l8 a8 C* R6 ]$ yBE Gen2 18.001 163. 999 1.01
/ `" \# `3 ?6 D- V. V/ FB Bus3 230.01 5 i! ^# [' c) i. p, l. B- |. Z
BE Gen3 13.801 85. 999. 1.01
7 f' U i q& S* J K1 A. o' ~* w.L ----------------- transmission lines ----------------------------5 T, A: I$ i# B9 D+ o
L Bus1 230. BusA 230. .0100 .0850 .04408 A8 m4 h# ~3 }" q- G
.L Bus1 230. BusA 230.2 .0100 .0850 .0440
* z8 D8 L5 p7 M& m8 QL Bus1 230. BusB 230. .0170 .0920 .0395% u9 K8 z: @% O- z& N) E
L BusA 230. Bus2 230. .0320 .1610 .07650 q$ m2 V" G1 i! J: ?1 r1 M- p% B
L BusB 230. Bus3 230. .0390 .1700 .0895
5 A, Q. ]% A& F: RL Bus2 230. BusC 230. .0085 .0720 .037254 ?# O; j: y6 y( |
L BusC 230. Bus3 230. .0119 .1008 .05225' W; \* L* Y% I; Y, L* N
.T ----- transformers ---------: q$ n3 O" u# K, @9 x; Q
T Gen1 16.5 Bus1 230. .0567 16.5 242.
3 g0 e. p4 e$ H( U5 r1 w8 r# d! AT Gen2 18.0 Bus2 230. .0625 18.0 242.
8 s- Y! T2 u1 ~$ F. i& A# uT Gen3 13.8 Bus3 230. .0586 13.8 242.0 U6 m& \4 r/ o( T H
(END)
: _# P5 G" y# ?; Q0 u+ t- d; N＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝计算结果＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝* W! V" y1 s6 g" p1 S6 s2 B" _
Bus1 230.0 238.9KV/ -3.4 ZONE 01 0.0PLOAD 0.0QLOAD 1.039PU KV BUS TYPE
7 t: j' U# f- u( S6 l& M; u e" m BusA 230.0 01 62.5PIN 29.2QIN 0.4682PLOSS -5.22QLOSS 4.7QC * D8 H1 l: `. R! s0 s6 i3 m1 o Q
BusB 230.0 01 43.0 7.2 0.3116 -6.70 4.3 7 V/ v4 v5 u( R; h+ @1 s* I! v6 T- E
Gen1 16.5 01 -105.4 -36.4 0.0000 7.24 242.0/ 16.5 V: X* Q7 S2 N4 a
0.0PNET 0.0QNET
4 O# ?% n- \* C IBus2 230.0 239.9KV/ -0.7 ZONE 01 35.0PLOAD 10.0QLOAD 1.043PU KV BUS TYPE 8 C+ m( s) `+ w+ s9 G4 r
BusA 230.0 01 64.3PIN 5.7QIN 1.2735PLOSS -9.66QLOSS 8.3QC
" B: N1 x% A" C6 U, I" i BusC 230.0 01 63.7 5.7 0.3246 -5.27 4.1
& z- @! Z3 {* d# T+ ~ Gen2 18.0 01 -163.0 -21.4 0.0000 17.19 242.0/ 18.0
* I+ O1 D' j0 v; s5 | -35.0PNET -10.0QNET & h! J9 y. T( `& J
Bus3 230.0 242.3KV/ -1.3 ZONE 01 0.0PLOAD 0.0QLOAD 1.053PU KV BUS TYPE & W/ `2 P# e! S; i( T
BusB 230.0 01 48.2PIN 0.0QIN 0.8515PLOSS -15.57QLOSS 9.9QC
2 S \4 D" r/ s6 z1 {' r% p8 j BusC 230.0 01 36.8 12.9 0.1826 -9.82 5.8 / Z, d8 [3 ]6 T
Gen3 13.8 01 -85.0 -12.9 0.0000 4.32 242.0/ 13.8
F* H1 Y+ {/ O4 \ 0.0PNET 0.0QNET
/ V5 {" i* M- J4 eBusA 230.0 231.4KV/ -6.2 ZONE 01 125.0PLOAD 70.0QLOAD 1.006PU KV BUS TYPE
9 ?% V# h8 c) ?0 _. n1 n! L; x4 O Bus1 230.0 01 -62.0PIN -34.4QIN 0.4682PLOSS -5.22QLOSS 4.5QC : c. u( E" K4 B9 B
Bus2 230.0 01 -63.0 -15.3 1.2735 -9.66 7.7
+ k5 @2 d8 x; @ 20.2QUSED 20.2QCAP SCHEDULED : Z6 J0 J! h, \ D+ q* i
-125.0PNET -49.8QNET
+ w% W2 s! p/ f8 k) jBusB 230.0 235.1KV/ -5.5 ZONE 01 90.0PLOAD 40.0QLOAD 1.022PU KV BUS TYPE
( |6 K4 V6 k; g) C5 W) q Bus1 230.0 01 -42.6PIN -13.9QIN 0.3116PLOSS -6.70QLOSS 4.1QC 6 }( h! m) S* Z( x! s& }9 b
Bus3 230.0 01 -47.4 -15.6 0.8515 -15.57 9.4 ' [5 W# y- N4 c" E' N7 P
10.4QUSED 10.4QCAP SCHEDULED 0 M) D5 w8 q6 L. C
-90.0PNET -29.6QNET 7 N0 R' k. z1 ^0 k
BusC 230.0 237.3KV/ -3.1 ZONE 01 100.0PLOAD 55.0QLOAD 1.032PU KV BUS TYPE
1 ?5 F7 U( b5 i6 f$ _ Bus2 230.0 01 -63.4PIN -11.0QIN 0.3246PLOSS -5.27QLOSS 4.0QC 7 v$ @/ w& ^% Z5 k
Bus3 230.0 01 -36.6 -22.7 0.1826 -9.82 5.6
$ {9 y! O; G8 q 21.3QUSED 21.3QCAP SCHEDULED % X8 D. E1 N) w; ]
-100.0PNET -33.7QNET " N# R) V3 G+ w9 f
Gen1 16.5 16.7KV/ 0.0 ZONE 01 105.4PGE 43.7QCOND 0.0PLOAD 0.0QLOAD 1.010PU KV BUS TYPE S
5 f+ o* i5 E( |( K7 l Bus1 230.0 01 105.4PIN 43.7QIN 0.0000PLOSS 7.24QLOSS 16.5/242.0
; o/ k7 R9 M" l# A t$ F9 F5 Y 105.4PNET 43.7QNET -893.6 SLACK ADJ
) ^+ T4 j: v4 hGen2 18.0 18.2KV/ 5.1 ZONE 01 163.0PGE 38.6QCOND 0.0PLOAD 0.0QLOAD 1.010PU KV BUS TYPE E 3 T' } i* {4 Q, c. w6 X+ P& f
Bus2 230.0 01 163.0PIN 38.6QIN 0.0000PLOSS 17.19QLOSS 18.0/242.0
+ F/ {+ d4 j" V8 g# { 163.0PNET 38.6QNET % G2 Y% v3 p" T% y( @0 ], ?
Gen3 13.8 13.9KV/ 1.5 ZONE 01 85.0PGE 17.2QCOND 0.0PLOAD 0.0QLOAD 1.010PU KV BUS TYPE E
. f& \9 _4 G, c% d6 j Bus3 230.0 01 85.0PIN 17.2QIN 0.0000PLOSS 4.32QLOSS 13.8/242.0
+ R7 j/ n) F% h6 _ ] 85.0PNET 17.2QNET , V* @! z1 I' u4 |" K+ @# _! m
SUMMARY OF SYSTEM QUANTITIES FOR ZONE 01 # m4 U- X7 Y" r4 J( H) i# E6 S
GENERATION LOAD LOSSES SHUNT QC % _8 B& L( z8 }$ t7 q
MW MVAR MW MVAR MW MVAR MW MVAR MVAR
2 _9 ^& |; T7 H% K& j 353.4 99.5 350.0 175.0 3.4 -23.5 0.0 52.0 72.3 0 z% `+ g4 S# c+ E
OUTPUT CHECK --- LINE EXPORT SUMS LINE IMPORT SUMS LINE LOSSES 4 w; L/ f. }' S# S
3.4 -23.5 3.4 -23.5 3.4 -23.5 5 Y- S/ ?0 w( S+ U# ]: p
SUMMARY OF SYSTEM TOTALS (MW) (MVAR) 2 U; t0 j; o _ J. m1 u' T- Y
SYSTEM INJECTION:
! |( \, O6 \; j6 I, M GENERATION 353.4 99.5 ) r; Q: q7 L* ~' U
LOAD -350.0 -175.0 + V) J% C6 j8 [9 Y
BUS SHUNT ADMITTANCE 0.0 52.0
! q) U+ a/ }9 r$ ?2 m UNSCHEDULED SOURCES 0.0 0.0
S) Z: q3 H8 Y3 P SUBTOTAL (INJECTION) 3.4 -23.5 $ D4 d( s$ Z1 a; K1 B5 S, p
SYSTEM LOSSES: 5 `- X/ L+ k+ G0 a' f
EQUIVALENT SHUNT ADMITTANCE 0.0 0.0
* ~: _3 J7 W0 V0 ^: @ LINE AND TRANSFORMER LOSSES -3.4 23.5
; x$ O; G3 W9 p- g( P! Y2 | LINE INJECTION (QC) 72.3 9 O5 l3 f: i: }. a( R, w
DC CONVERTER LOSSES 0.0 0.0
: \! i- R# A; c% b$ | SUBTOTAL (LOSSES) -3.4 23.5
' f- Z( ^# n3 O3 c! d Z; H3 Q5 e9 w NET SYSTEM EXPORT: 0.0 0.0 |
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发表于 2010-11-7 23:48:05
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