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发表于 2009-11-18 11:36:55
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Name : SatTrafo - General saturable transformer. 3 phase. 2 or 3 windings.
7 H) ~% m/ e, ?' t6 w- x, ^ Wye, Delta with all phase shifts. Auto, and Zigzag with most common configurations.& u; z& s4 b, b$ \8 ?( W3 x
Card : BRANCH# \5 f& X' M3 y& D) y
Data : Io= Current [A] through magnetizing branch (MB) at steady state.
+ W- i' D% ^- c$ ^6 ]% ` Fo= Flux [Wb-turn] in MB at steady state.# Q' B4 N* b2 R& i3 C
The pair Io, Fo defines the inductance in MB at steady state." A! d! [2 R4 c6 @% l2 v3 p
Rm= Resistance in magnetizing branch in [ohm]. 5-leg core or 3-leg shell., q! A, ]8 A5 _, J& [
The magnetizing branch is always connected to the PRIMARY winding and Rm is referred to this voltage.
: P6 j$ @0 p' Y3 L% F R0= Reluctance of zero-sequence air-return path for flux. 3-leg core-type
" I1 s3 c0 `0 B! b+ T9 r' n Vrp= Rated voltage in [V] primary winding (only the voltage ratios matter).
- K( {) d+ h; ~* q" V Rp= Resistance in primary winding in [ohm].
6 M) f* h$ q$ q; `# d Lp= Inductance in primary winding in [mH] if Xopt.=0& \9 P3 g, }6 T+ h7 M2 B+ [8 I
Inductance in primary winding in [ohm] if Xopt.=power freq., o' W4 w- M* G* c- c7 \
Vrs= Rated voltage in [V] secodary winding. 7 s; A1 r, g7 c# o' q
Rs= Resistance in secondary winding in [ohm].
& u3 o, P/ F& B- N- q1 H% [8 L Ls= Inductance in secondary winding in [mH] if Xopt.=0
/ R2 l' n, g2 f! X( g9 Y8 Q Inductance in secondary winding in [ohm] if Xopt.=power freq.
7 y, W K Y: s/ i8 l* n# w Vrt= Rated voltage in [V] tertiary winding.
8 g ~9 A3 t j! k5 @8 Q, S h1 B Rt= Resistance in tertiary winding in [ohm].# Y( }" U- i8 M" C& h, h' Z& N
Lt= Inductance in tertiary winding in [mH] if Xopt.=07 p5 e3 A$ I" f5 |8 `4 g; i# }5 T
Inductance in tertiary winding in [ohm] if Xopt.=power freq.
6 H4 r- F/ I, \ RMS= unchecked: Current/Flux characteristic must be entered.
; @$ t! z5 e7 l! J/ m checked: Irms/Urms characteristic must be entered.0 G V3 d8 P* [. g, j- s' z
ATPDRAW performs a SATURATION calculation.) W: `7 _ B5 s
3-leg core = checked: 3-leg core type transformer assumed. TRANSFORMER THREE PHASE
6 Y2 n2 G0 `3 i0 B unchecked: 5-leg or 3-leg shell type assumed. TRANSFORMER.1 Z- s2 Z8 U0 n6 e
3-wind.= turn on tertiary winding.
. a! [4 ?' z5 e* gOutput specified the magnetization branch output (power&energy not supported).
: C. r& [# {, UNode : P= Primary side. 3-phase node.) i1 X. ]; _$ u& J0 c
S= Secondary side. 3-phase node.
1 m& b4 [; X% i+ T$ d PN= Neutral point primary side.
3 L& x6 A8 E+ ` SN= Neutral point secondary side.
9 F: I7 E& o w Q T= Tertiary side. 3-phase node.
$ i$ G! m! T/ r TN= Neutral point tertiary side.
& f2 _/ D ~: z# w Sat= Internal node, connection of the magnetization circuit with saturation.
. ?* X7 P, Q5 k W! P% N2 X: XThe coupling is specified for each winding, with four coupling options: Y, D, A, Z: r8 y; x, K4 k, Z
All phase shifts are supported.
6 i, w3 t8 J1 H; q: xSpecial note on Auto-transformers:
7 ]) M/ d9 H' k The primary and secondary windings must be of coupling A(uto).$ I' d9 J" p- `' T5 d5 |
Special note on ZigZag-transformers: 4 E2 Z5 s/ A I
For this type the user can specify a phase shift in the range <-60,0>&<0,60>.2 S, D# S& `& g- e* w
Note that the values -60, 0 and +60 degrees are illegal (as one of the winding parts degenerates).
3 K, i9 r" P6 c. c The phase shift is given relative to a Y-coupled winding.
5 q- x+ I! o% Z3 ? i, { If the primary winding is Zigzag-coupled, all other windings will be shifted with it.
9 k7 ?- [3 x6 W. c2 M/ p* N( o If the primary winding is D-coupled, 30 deg. must be added/subtracted to the phase shifts.
! _' `4 q5 S% G- m' h For negative phase shifts the phase A winding starts on leg 1 (called z with voltage Uz) * r- P+ r, X5 M* u
and continues in the opposite direction on leg 3 (called y with voltage Uy).% L o+ Z% ~8 b
For negative phase shifts the phase A starts on leg 1
( L% [; j, j5 h. X# j9 J3 w6 s- ` and continues in the opposite direction on leg 2. p* ~5 z$ U2 h k
The normal situation is to specify a phase shift of +/- 30 deg.
2 I# b/ d+ O1 l- R in which case the two parts of the winding have the same voltage level and leakage impedance.+ ?/ f5 k- s) ^
In general the ratio between the second part of the winding Uy and the first part Uz is * S1 U6 N0 V# j* ~4 v# y
n=Uy/Uz=sin(a)/sin(60-a) where a is absolute value of the phase shift.: @, |& B/ @8 t
This gives:
n, e! ~( I7 n+ v0 y* L& i Uz=U/(cos(a)+n*cos(60-a)) and Uy=Uz*n
0 x+ \* W& j* y$ {9 z+ |; | Lz=L/(1+n*n) and Ly=Lz*n*n, Rz=R/(1+n) and Ry=Rz*n 5 d6 i c( J' U; K
where Lz and Ly are the leakage inductance of each part of the winding (L is the total leakage inductance)
: Z" X/ R4 s# p: B' Y and Rz and Ry are the winding resistance of each winding part (R is the total).
: \/ b' I! _% I7 C, X9 `* N The parameters Uz, Uy, Zz, and Zy are automatically calculated by ATPDraw based on the
+ o+ \# v5 r/ d* z( w0 [$ w' Q equivalent parameters U and Z and the phase shift, a.
/ m$ l3 j. ]" y1 }7 v6 q) J ^- U8 f
' |) E% B; ~3 PPoints: It's possible to enter 9 points on the current/flux characteristic.% ?/ Y3 i9 U/ N" C8 s/ x
The required menu is performed immedeately after the input menu.( M3 _5 w" E8 L/ _" I. P
The points should be entered as increasingly larger values.
$ c; ?% o0 L: G The point (0,0) is not permitted (added internally in ATP).
7 Y! _% O- v. @2 @RuleBook: IV.E.1-2 or 3. |
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