用MODELS计算线路感应电压:程序如下:3 q# l0 }6 R8 v8 o# l+ D. n
MODEL indloss + r" C- }! g. f ?9 N' B$ PCONST 2 u0 u# c( w' Q6 r0 q0 b. N
Tmax {VAL:500} : I3 s7 X. f5 Rn {VAL:2}* ]5 o9 _7 @' N# Q
c {VAL:3.e8} ' j- w0 p8 H1 y) u, y3 y: f5 OI0 {VAL:1} ! d! G! Y$ Q8 q" `3 t5 ceps0 {val:8.85e-12}( W: g2 _- ~4 p% s; D+ Y- S6 e4 G
INPUT UAP[0...n],UBP[0...n]% g- `8 P% b( {+ [/ V& m
DATA Y,XA,XB 3 [* Y W$ Z# bz[1...n] {DFLT:10} # `# ^" n, _" b5 J. j2 O4 VIm {DFLT:3e4} + R/ f* T; y6 _, w9 ctc {DFLT:5e-5} 7 R) ?+ Y. t( r1 ]+ S, Tth {DFLT:2e-6} f9 J3 F# e8 V) p
v {DFLT:1.5e8} + E7 G$ Y- C) f( b' Osigma {DFLT:0.001} ! [$ o3 ?# s" o% n% a
epsr {DFLT:10} 7 M/ I- x( y" Z: M% HOUTPUT UrA[0...n],UrB[0...n] $ O9 w1 a: a1 D( r% V! VVAR UindA0[0...Tmax],UindB0[0...Tmax],g1[0...Tmax],g2[0...Tmax], $ J: _) m$ O6 K4 x9 ]UindAD[0...Tmax],UindBD[0...Tmax],Ui0,UiD, ! [$ {1 Y& Z0 T7 NUrA[0...n],UrB[0...n],Tr,k,i,AB,dt,uk[1..4],2 }, }; F5 K: K! {5 }* ]
b,L,x,tau,a1,b1,c1,c2,c3) B4 i: {* N: K. x) w: m* `' n4 Z
FUNCTION F0(x,tr):= (c*tr-x)/(y*y+(b*(c*tr-x))**2) " O V* x2 }2 L( V U5 bFUNCTION F1(x,tr):= (x+b*b*(c*tr-x))/sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)) F/ d+ h3 `# n# v4 e8 ^& Q nFUNCTION F2(x,tr):= x+b*b*(c*tr-x)+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)). a. l+ V5 g/ r+ W9 x, c
FUNCTION F3(x,tr):= (v*tr+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)))/sqrt(x*x+y*y)# |3 T, j* Y, y1 k- L
FUNCTION t0(x):= sqrt(x*x+y*y)/c % j% ]2 a* S* @6 V p$ ?, dHISTORY* X4 A4 H$ c# g
UrA[1...n] {dflt:0} : ~6 i1 O7 f8 m5 v' S/ sUrB[1...n] {dflt:0} $ @7 O% B" d8 ]# x5 J* f0 u" h EUAP[1...n] {dflt:0} 8 m+ d! i$ T- FUBP[1...n] {dflt:0}; e: \- C5 A3 d
DELAY CELLS DFLT: (XA-XB)/(c*timestep)+1 3 v- c- Q1 ~% ?& I) y* Q( }2 xINIT% p( z3 ~/ G2 ]! j5 i
k:=sqrt(eps0*epsr/(PI*sigma*dt)) # @# H5 S- }4 x$ t: E& Wdt:= timestep b:=v/c L:=XA-XB tau:=L/c7 m6 Z1 i+ }; g8 {
a1:=Im/(I0*th), S& V0 y/ _( }( D
b1:=0.5*th/(tc-th)+1 ( E# Q0 |6 h( T3 U1 Tc1:=a1*k*dt/sqrt(epsr) ' Q5 A! W/ R3 p( |# Fc2:=-1.073*k+0.2153*(k**3)+4/3. z. Z/ U2 K6 t$ P8 J( b7 j1 W
c3:=-0.2153*(k**3)+1/6" y- n7 O0 Q7 W7 e: H6 H" R( a, H; Q
FOR AB:=1 TO 2 DO . c7 t4 q4 F* j, xif AB=1 then ; N9 V9 c. B7 ?x:=XA else x:=-XB$ Q; u0 h9 O3 L$ `
endif 0 E: x6 i% n% e: j/ F3 LFOR i:=0 TO Tmax DO# a" p: `, W8 c' @6 i' v
Tr:=i*dt3 L: @/ X0 J$ m; u
if Tr>t0(x) 2 j# c1 y9 i2 _1 Gthen; m7 F( f) V5 S) w7 b* l0 a
if Tr>t0(x-L)+tau " v* |/ S) d' t# O2 l6 ?# wthen+ F# A6 v% T; `" [4 ~. Q
Ui0:=f0(x,Tr)*(f1(x,Tr)-f1(x-L,Tr-tau)) % P3 C0 s. |4 iUiD:=ln( f2(x,Tr)/f2(x-L,Tr-tau) )-1/b*ln( f3(x,Tr)/f3(x-L,Tr-tau) ) / V6 @# I: k$ G+ I$ ^. Y7 oelse + |" w# w5 F1 @4 E9 E4 p, l# i+ r- [Ui0:=f0(x,Tr)*(f1(x,Tr)+1) - t6 |9 D4 r) O+ B7 x; RUiD:=ln( f2(x,Tr)*f0(x,Tr) )-1/b*ln( f3(x,Tr)/(1+b) )9 w' m8 J. Y$ S1 ? b* Q
endif , R7 V( o; H- r0 g6 zelse. ?, i* Q6 \# \ D
Ui0:=0, UiD:=0 5 T' O9 W+ `2 H9 S! \# ?* pendif - b+ x5 J1 q: m/ K' |) ]8 Kif AB=1 then* M7 W2 V( t9 H) h( u
UindA0[i]:=Ui0 ' u/ Y& r6 a4 i) GUindAD[i]:=UiD! w6 J6 }" A# Y6 u0 t
g1[i]:=a1*dt & G4 m/ _& T" x* ?% `) Pif i>0 ! M7 `, t. n1 K M5 fthen0 ~) p4 [, j( { V3 C* K1 q
g2[i]:=a1*sqrt(eps0/(PI*sigma*Tr))*dt8 a6 V8 C* U/ t# ^ C
endif & A, V, }7 v, z" m: Zelse $ i: g/ l- l4 F8 W2 g: U2 }7 O8 eUindB0[i]:=Ui0) i8 r9 v) j) }1 p4 [$ O/ ~, r1 N
UindBD[i]:=UiD$ @# T% U9 K: v8 }
endif 3 e/ o' @: z, r# G* ~ENDFOR 6 I6 \9 q- B2 {6 B3 nENDFOR8 o/ \: J( q& ]4 H9 l) n( s1 }6 ^
i:=Tmax& j' R0 v3 M- d" e- p
WHILE i>1 DO( i Y6 \& v- E+ f1 G- c. J
uk[1...4]:=09 q) l6 B3 G5 [1 c' }7 Q4 N
FOR Tr:=1 TO i-1 DO , S" i* m* h/ w& d$ `; huk[1]:=uk[1]+UindA0[Tr]*g1[i-Tr] 8 {& f$ O" z; h) Wuk[2]:=uk[2]+UindB0[Tr]*g1[i-Tr]% |2 Z; K7 D5 i, S; q
5 a4 X' ^9 J% N) _: Uuk[3]:=uk[3]+UindAD[Tr]*g2[i-Tr]$ H; E, e* n5 }4 e: S3 g+ Y
2 A4 t8 }( {% H0 U E' @, u: H+ tuk[4]:=uk[4]+UindBD[Tr]*g2[i-Tr]( Q4 d2 O; o$ j. P
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ENDFOR+ P$ o6 W! k& }/ y e) a
UindA0[i]:=uk[1]+0.5*UindA0[i]*g1[0]" v6 |8 E/ V P3 U$ d* s. q6 S
UindB0[i]:=uk[2]+0.5*UindB0[i]*g1[0]- W! E' H( T6 Z3 E$ a! y" [4 Y
UindAD[i]:=uk[3]+(UindAD[i]*c2+UindAD[i-1]*c3)*c1* b$ M* X+ [! k: @3 ^
UindBD[i]:=uk[4]+(UindBD[i]*c2+UindBD[i-1]*c3)*c1( w+ G. K' w' L+ Q9 T0 ~2 W- x$ T
i:=i-1& d6 S" i$ w# J r+ S
ENDWHILE + J. h& P( g0 j+ D; S/ rTr:=trunc(th/dt)0 ~1 l7 ?% O/ |2 J6 a. X
/ y' a# A% f ?: l t/ iFOR i:=Tmax TO Tr BY -1 DO1 G% m2 A& d' ?9 ^7 p: ]8 ]
UindA0[i]:=UindA0[i]-b1*UindA0[i-Tr] # U& c: E- L1 h+ }7 S7 x) ~UindB0[i]:=UindB0[i]-b1*UindB0[i-Tr]8 |1 J( u7 S- L4 n) t
UindAD[i]:=UindAD[i]-b1*UindAD[i-Tr] 4 h. ?, q) T1 j2 G# A/ ^UindBD[i]:=UindBD[i]-b1*UindBD[i-Tr]1 Y8 ^! u0 o7 I& |& B
endif + k) g! d9 C& \ ~$ UENDFOR % i- M8 N. E, AENDINIT W- i2 M4 Z7 y5 g% s; D8 ]
EXEC * [4 ?( U' y+ y6 UFOR i:=1 to n DO2 h4 l: b ^% c1 r0 f% T. ^* E
UrA[i]:=60*I0*b*(z[i]*UindA0[t/dt] - UindAD[t/dt]) +2*delay(UBP[i],tau-dt,1)-delay(UrB[i],tau,1)" f& M& x: J! H/ e [; h% `
UrB[i]:=60*I0*b*(z[i]*UindB0[t/dt] - UindBD[t/dt]) +2*delay(UAP[i],tau-dt,1)-delay(UrA[i],tau,1) 0 L- a ]! d- v* a- M, JENDFOR % m& O) M H. s; Z. `ENDEXEC" f1 A0 e8 V" A8 j
ENDMODEL, V9 W2 Q6 f* {3 Y+ [
( O( k! u. m; V# f' D程序报错如下1 C5 H4 k' O& F. J9 x" v
KILL = 422. The present statement is interpreted as a value assignment statement, and the preceding name is interpreted as a 1 Z# I( {$ @3 T+ }) u0 j$ {variable to which a value is being assigned. The identification of this variable is interpreted as complete, and should now be0 v: d' I; ~0 g( V+ }
followed by ":=", in the following format:- O4 A. X+ a8 d
variable_identification := expression 3 D3 o' [' x% W% O' L$ t, [' P7 D5 A0 T, Q
本人已经仔细检查了每个等式都加:=了,不知道为什么还是不行,有兴趣的可以仿真一下,大家交流交流。 6 E! S* L* v9 G7 u1 B$ f6 `