TA的每日心情 | 郁闷 2017-12-26 18:33 |
|---|
签到天数: 21 天 连续签到: 1 天 [LV.4]偶尔看看III 累计签到:21 天 连续签到:1 天
|
马上加入,结交更多好友,共享更多资料,让你轻松玩转电力研学社区!
您需要 登录 才可以下载或查看,没有账号?立即加入
×
用MODELS计算线路感应电压:程序如下:0 ~: i2 p( _5 b5 Z& Z+ Y
MODEL indloss6 w3 l+ C0 V8 b/ v- d. A
CONST 5 L6 c5 B" H' Q$ O
Tmax {VAL:500} % G z# o; U; J: L) P
n {VAL:2}+ c& D; j& I& o% r$ ~
c {VAL:3.e8} 8 _& l6 f0 `. k7 W' y7 E3 p% N: |
I0 {VAL:1} : l, j7 H6 n: V; g. i* B! ^
eps0 {val:8.85e-12}/ j# U% D9 g! c+ Y4 r) g
INPUT UAP[0...n],UBP[0...n]4 b q. D3 h) l
DATA Y,XA,XB
/ z% d) _/ W& D7 J' Y0 f# t" z2 sz[1...n] {DFLT:10}
5 \* F7 W0 K% o+ Q3 l% p1 I6 p5 `5 m( uIm {DFLT:3e4}
) K G; H& k* Q1 a# Htc {DFLT:5e-5}
. F* p6 p3 k# c- W0 T! Tth {DFLT:2e-6}
2 @9 y+ A* v: Ev {DFLT:1.5e8}
) T+ E5 E% M. o* z! A9 Usigma {DFLT:0.001}
% W: H0 @! N9 L# D8 H7 nepsr {DFLT:10}
6 g$ a4 W- Y" ]" fOUTPUT UrA[0...n],UrB[0...n]4 F* A: E2 @- P0 q' k
VAR UindA0[0...Tmax],UindB0[0...Tmax],g1[0...Tmax],g2[0...Tmax],
8 Y* g0 u+ f3 u. H" fUindAD[0...Tmax],UindBD[0...Tmax],Ui0,UiD,
4 p2 d6 n- h: @* Y, v F, gUrA[0...n],UrB[0...n],Tr,k,i,AB,dt,uk[1..4],; t7 M+ S8 k9 ]3 h
b,L,x,tau,a1,b1,c1,c2,c3
$ _. b3 f+ a- _FUNCTION F0(x,tr):= (c*tr-x)/(y*y+(b*(c*tr-x))**2)
) d0 X4 |! U+ T' d, Y! ~FUNCTION F1(x,tr):= (x+b*b*(c*tr-x))/sqrt((v*tr)**2+(1-b*b)*(x*x+y*y))7 f! p# G7 f( m4 z! g; b
FUNCTION F2(x,tr):= x+b*b*(c*tr-x)+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y))
9 K/ p$ h- b, s6 qFUNCTION F3(x,tr):= (v*tr+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)))/sqrt(x*x+y*y)
. i8 g7 y1 Y, W8 HFUNCTION t0(x):= sqrt(x*x+y*y)/c5 _7 g/ K1 i) x) `) _2 L- y
HISTORY9 m3 {" t" R7 R! I* x1 J q
UrA[1...n] {dflt:0}' L( x6 O6 k A6 U1 ?+ m# Q+ T
UrB[1...n] {dflt:0}
' K+ F6 ]$ R) K9 h! A" w* uUAP[1...n] {dflt:0}( g: h: X3 @( C) j" u. J
UBP[1...n] {dflt:0}
' H0 P K* o' m$ R+ R8 F; T% nDELAY CELLS DFLT: (XA-XB)/(c*timestep)+1
5 @% D4 M9 ], FINIT# V* Z+ Z. {0 ~ n4 R/ l
k:=sqrt(eps0*epsr/(PI*sigma*dt))
q6 E9 f2 e" |7 x! z7 s' Udt:= timestep b:=v/c L:=XA-XB tau:=L/c; o ~* x1 T; a+ W7 L
a1:=Im/(I0*th)) u, u9 ?8 Q: E" f' T
b1:=0.5*th/(tc-th)+1
; n9 W9 V! l' z1 q7 R, s' s. Kc1:=a1*k*dt/sqrt(epsr)- X& x* }1 _" D G
c2:=-1.073*k+0.2153*(k**3)+4/3% q. Q% }$ [( z4 |4 c
c3:=-0.2153*(k**3)+1/6
5 \( w5 n, n! E; _0 Z( o( q/ P FOR AB:=1 TO 2 DO
) Z! g' G; J0 R# A6 p/ S% U" I; [if AB=1 then6 k" ]1 N& M% c& }+ J0 d* _
x:=XA else x:=-XB
: l; ?* o p) W g) B3 H7 n) M; _endif# A3 B/ V1 _$ e) C8 p
FOR i:=0 TO Tmax DO( A$ j8 k! ?' y9 t) O
Tr:=i*dt
9 X- w- N* R: ]) Q; o( {! o' z5 M/ Tif Tr>t0(x)
7 w5 n. J* ~ d: \: z9 b, a Q' ethen
; I9 t9 M& j5 ]if Tr>t0(x-L)+tau
7 O4 `( a* d. kthen
7 V) u2 S T; n* [. `; y1 p5 t4 [Ui0:=f0(x,Tr)*(f1(x,Tr)-f1(x-L,Tr-tau))3 e6 [- L: u7 S# H
UiD:=ln( f2(x,Tr)/f2(x-L,Tr-tau) )-1/b*ln( f3(x,Tr)/f3(x-L,Tr-tau) )
8 S8 ~& c! }9 g' E) K" N) z' Selse8 T3 k8 h- K Q: g
Ui0:=f0(x,Tr)*(f1(x,Tr)+1)
- c \3 c0 A" v/ E& H1 S1 I# ]7 oUiD:=ln( f2(x,Tr)*f0(x,Tr) )-1/b*ln( f3(x,Tr)/(1+b) )
4 |# r8 |. l4 T8 O8 sendif
. {8 ]) V) T9 Aelse
4 V9 ^* \9 ?$ c# T5 H( R0 GUi0:=0, UiD:=01 m* p( N( ^. Q1 n
endif
# r4 w- K+ B3 [- {3 bif AB=1 then
+ ]: F" u% L3 l& N2 RUindA0[i]:=Ui08 q" G5 \9 W ?9 I& \( N0 P
UindAD[i]:=UiD0 \" d( k- v1 b/ u+ V7 E/ w p
g1[i]:=a1*dt
0 l( U8 ^9 \0 p% Cif i>0+ E8 w0 N8 G9 l/ T, K2 n0 t
then
+ l' q: z! E% Ig2[i]:=a1*sqrt(eps0/(PI*sigma*Tr))*dt. W% l$ K+ R9 O/ ]/ \# J* {
endif* }2 l; Q" [3 X m
else
1 C/ Z6 g5 I# d. i5 b1 m$ jUindB0[i]:=Ui0
+ U6 C1 x8 c& t9 v5 J/ ~UindBD[i]:=UiD
: {2 _* l' U* h% h4 rendif! T/ a7 C( H0 e! x* l
ENDFOR
. O3 x( A9 y' \. D5 [ }ENDFOR, k) p0 E/ a, `' {0 f, ~) a' i
i:=Tmax4 {8 _$ w: O( n6 d4 `* }/ ~6 i
WHILE i>1 DO, M4 y! v8 I% g
uk[1...4]:=0
( Z! F4 k6 x6 J2 l& v d3 j$ d; sFOR Tr:=1 TO i-1 DO5 {9 a8 j( x8 J$ D$ M, d$ O
uk[1]:=uk[1]+UindA0[Tr]*g1[i-Tr]
+ E6 u/ d/ V) q, Q/ D, ~! quk[2]:=uk[2]+UindB0[Tr]*g1[i-Tr]
) h6 d" o `1 h! @! Q6 b$ a N7 d! N4 E; f9 D, |- R
uk[3]:=uk[3]+UindAD[Tr]*g2[i-Tr]
6 q) D$ r) C6 v5 y- o+ H) h4 X p& m$ T0 Y& L3 f& q
uk[4]:=uk[4]+UindBD[Tr]*g2[i-Tr]6 C5 ?! A6 X. O% l% j
/ w0 L% g* G& i5 @
ENDFOR" _7 M8 y4 `! i2 X: _8 y2 N
UindA0[i]:=uk[1]+0.5*UindA0[i]*g1[0]# b' G8 o/ m% F& k$ _
UindB0[i]:=uk[2]+0.5*UindB0[i]*g1[0], a B* q/ o* u: H$ F2 L) M
UindAD[i]:=uk[3]+(UindAD[i]*c2+UindAD[i-1]*c3)*c13 y6 B: [1 g( r6 }% O5 t: C+ R
UindBD[i]:=uk[4]+(UindBD[i]*c2+UindBD[i-1]*c3)*c12 J$ o. v" X! P; Q: `
i:=i-1
8 k# j% d7 ?- jENDWHILE; S: V" n' i4 U
Tr:=trunc(th/dt)( i5 }2 n+ @% ?7 O! k
. Z5 B; S( J, `, `* ]) ^
FOR i:=Tmax TO Tr BY -1 DO0 ^1 W9 p$ S/ g- \
UindA0[i]:=UindA0[i]-b1*UindA0[i-Tr]
" V% j( P2 x8 vUindB0[i]:=UindB0[i]-b1*UindB0[i-Tr]( {8 c( n- F" w2 K2 ~+ U% D7 R
UindAD[i]:=UindAD[i]-b1*UindAD[i-Tr]
& X7 t; U% B1 b; C6 v$ @' A# jUindBD[i]:=UindBD[i]-b1*UindBD[i-Tr]: ^" h, c" |0 d8 m( ~- b
endif0 S, M0 n( ~7 i5 P* c
ENDFOR8 d ^7 j3 ^; Z, @
ENDINIT
& {7 _3 ^" V6 H8 N# V9 cEXEC# I, T0 o, C+ D o
FOR i:=1 to n DO" P- E# Y6 v N
UrA[i]:=60*I0*b*(z[i]*UindA0[t/dt] - UindAD[t/dt]) +2*delay(UBP[i],tau-dt,1)-delay(UrB[i],tau,1)
, y* y7 Y. M2 u1 _# b: dUrB[i]:=60*I0*b*(z[i]*UindB0[t/dt] - UindBD[t/dt]) +2*delay(UAP[i],tau-dt,1)-delay(UrA[i],tau,1)* O1 c' A* p, E% c- g
ENDFOR: R* v3 U( n- [4 b8 I1 J
ENDEXEC% Q9 K8 l1 h6 G/ O
ENDMODEL
6 T0 p( M* V0 Q% _6 Y% y2 G3 h: N. a5 E/ e. E1 y
程序报错如下
- Q0 h$ }" U# _# QKILL = 422. The present statement is interpreted as a value assignment statement, and the preceding name is interpreted as a
/ _& q+ W2 D+ n2 L$ v: ?$ rvariable to which a value is being assigned. The identification of this variable is interpreted as complete, and should now be' l% w. J9 Q, J/ |. A Z
followed by ":=", in the following format:
3 Y0 z( k# u: z- A& ] variable_identification := expression
. y- _! }5 `. }
; C6 Z, b7 ~* ?2 X本人已经仔细检查了每个等式都加:=了,不知道为什么还是不行,有兴趣的可以仿真一下,大家交流交流。6 D1 _! K3 o1 C% Z4 c
|
|