关于计算线路感应电压模型讨论

不学无术

用MODELS计算线路感应电压：程序如下：
MODEL indloss
CONST
: N! G3 |! N) BTmax {VAL:500}
3 U- Z) N+ ~  _! c5 D3 G* qn {VAL:2}
: D( @& c7 @+ Ic {VAL:3.e8}
6 I& A; }7 r) QI0 {VAL:1}
eps0 {val:8.85e-12}
# a6 h1 ?# D) {7 Y; {. z8 FINPUT UAP[0...n],UBP[0...n]
6 Z: I8 E* a" B1 v/ L) m: Z. _DATA Y,XA,XB
z[1...n] {DFLT:10}
  S( u+ g7 U0 {1 ~. AIm       {DFLT:3e4}
" b: k# @' U& B# v2 l9 E1 j2 b1 H1 g' Utc       {DFLT:5e-5}
) o. z- L  U2 A* `8 Wth       {DFLT:2e-6}
v        {DFLT:1.5e8}
! U" O  T) f% Ksigma    {DFLT:0.001}
; f8 t! ?7 _) }9 `epsr     {DFLT:10}
5 \% E: q- M* x+ b& t3 @9 Y" YOUTPUT UrA[0...n],UrB[0...n]
VAR UindA0[0...Tmax],UindB0[0...Tmax],g1[0...Tmax],g2[0...Tmax],
* M. R6 A( w& _$ uUindAD[0...Tmax],UindBD[0...Tmax],Ui0,UiD,
4 Q( R- D) G5 s& V7 w2 tUrA[0...n],UrB[0...n],Tr,k,i,AB,dt,uk[1..4],
b,L,x,tau,a1,b1,c1,c2,c3
FUNCTION F0(x,tr):= (c*tr-x)/(y*y+(b*(c*tr-x))**2)
# O: o/ e) ]. ^4 e0 q4 UFUNCTION F1(x,tr):= (x+b*b*(c*tr-x))/sqrt((v*tr)**2+(1-b*b)*(x*x+y*y))
FUNCTION F2(x,tr):= x+b*b*(c*tr-x)+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y))
FUNCTION F3(x,tr):= (v*tr+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)))/sqrt(x*x+y*y)
7 }: j8 f8 q# ~- l& vFUNCTION t0(x):= sqrt(x*x+y*y)/c
- d( I0 b! f& u7 x, h8 @' Q# W2 dHISTORY
UrA[1...n] {dflt:0}
. R( J* M  Z& s% ^# r6 ]# p/ n' wUrB[1...n] {dflt:0}
, q9 m* g2 }/ h* E% T/ pUAP[1...n] {dflt:0}
. ~+ `! t# E, z' RUBP[1...n] {dflt:0}
DELAY CELLS DFLT: (XA-XB)/(c*timestep)+1
- p- p1 S: i, z' Y) D; GINIT
k:=sqrt(eps0*epsr/(PI*sigma*dt))
dt:= timestep b:=v/c L:=XA-XB tau:=L/c
a1:=Im/(I0*th)
b1:=0.5*th/(tc-th)+1
9 p9 F$ s6 B; wc1:=a1*k*dt/sqrt(epsr)
c2:=-1.073*k+0.2153*(k**3)+4/3
c3:=-0.2153*(k**3)+1/6
, j; q- w  y/ g: n; |) r. C1 j+ g FOR AB:=1 TO 2 DO
+ _1 d2 v& A1 J; J: A% `if AB=1 then
x:=XA else x:=-XB
3 v% r  u5 H5 g1 T: @& cendif
FOR i:=0 TO Tmax DO
Tr:=i*dt
if Tr>t0(x)
then
2 |8 D& }! b7 qif Tr>t0(x-L)+tau
5 Q. F2 h  O- o# s/ o, bthen
  H; w2 t6 ?/ nUi0:=f0(x,Tr)*(f1(x,Tr)-f1(x-L,Tr-tau))
) g& P9 z1 f9 o) d& F( i" f' eUiD:=ln( f2(x,Tr)/f2(x-L,Tr-tau) )-1/b*ln( f3(x,Tr)/f3(x-L,Tr-tau) )
else
" }2 Y7 J$ U$ p8 V" gUi0:=f0(x,Tr)*(f1(x,Tr)+1)
UiD:=ln( f2(x,Tr)*f0(x,Tr) )-1/b*ln( f3(x,Tr)/(1+b) )
endif
else
6 a" b+ J+ l& |" }( d3 pUi0:=0, UiD:=0
endif
if AB=1 then
UindA0[i]:=Ui0
2 Z% \; s: l9 R* y+ IUindAD[i]:=UiD
g1[i]:=a1*dt
& v/ f6 K9 H. E% ?if i>0
then
% V1 E0 N$ n& dg2[i]:=a1*sqrt(eps0/(PI*sigma*Tr))*dt
) M! T4 A& Q2 X1 m3 |" Z3 Qendif
6 o" R$ q1 f8 j# Z: I/ p  u8 relse
UindB0[i]:=Ui0
! O, _2 k( ?5 M  a/ E/ HUindBD[i]:=UiD
endif
* x# ~5 f3 K& K6 I7 Z0 uENDFOR
' W* W8 ?# g% DENDFOR
- c: F% y: }$ E7 {5 ji:=Tmax
( q0 G; x4 @. k9 w+ ]& LWHILE i>1 DO
: B  n. A* h; suk[1...4]:=0
5 l& Z; u! F& t$ ?# ~" r& wFOR Tr:=1 TO i-1 DO
6 E7 x9 p5 |  e8 Q7 ouk[1]:=uk[1]+UindA0[Tr]*g1[i-Tr]
uk[2]:=uk[2]+UindB0[Tr]*g1[i-Tr]
5 B/ _# l  o" L9 U
2 i1 j1 T$ L5 i3 \/ _# ~uk[3]:=uk[3]+UindAD[Tr]*g2[i-Tr]

+ M# [9 j6 G8 V2 B2 kuk[4]:=uk[4]+UindBD[Tr]*g2[i-Tr]
, F. N' w. @) v' H. c3 v. P- i
ENDFOR
UindA0[i]:=uk[1]+0.5*UindA0[i]*g1[0]
  J! y3 `( W) r8 k7 MUindB0[i]:=uk[2]+0.5*UindB0[i]*g1[0]
- ]* H& n( O7 E: q$ iUindAD[i]:=uk[3]+(UindAD[i]*c2+UindAD[i-1]*c3)*c1
% l; _# E" q" E/ ^0 cUindBD[i]:=uk[4]+(UindBD[i]*c2+UindBD[i-1]*c3)*c1
i:=i-1
* l$ f/ d0 N- a  v2 A) W  q/ B6 yENDWHILE
Tr:=trunc(th/dt)
. S1 E8 ?, p, g
FOR i:=Tmax TO Tr BY -1 DO
UindA0[i]:=UindA0[i]-b1*UindA0[i-Tr]
, b5 m6 F: p1 r  v! KUindB0[i]:=UindB0[i]-b1*UindB0[i-Tr]
  Z- P7 S7 V( N$ U6 r1 XUindAD[i]:=UindAD[i]-b1*UindAD[i-Tr]
UindBD[i]:=UindBD[i]-b1*UindBD[i-Tr]
endif
ENDFOR
ENDINIT
" `2 ~0 Z% e- }$ f; O) F5 @' lEXEC
9 r' T) _: ]1 k9 `$ WFOR i:=1 to n DO
: f+ J. i% d8 d- aUrA[i]:=60*I0*b*(z[i]*UindA0[t/dt] - UindAD[t/dt]) +2*delay(UBP[i],tau-dt,1)-delay(UrB[i],tau,1)
! x- P% @1 @7 [0 e, \2 X* N/ bUrB[i]:=60*I0*b*(z[i]*UindB0[t/dt] - UindBD[t/dt]) +2*delay(UAP[i],tau-dt,1)-delay(UrA[i],tau,1)
; p" C; c' o9 V7 y5 e# I& i: v; vENDFOR
! ?1 {! }9 m" o5 V; dENDEXEC
9 t/ `: o$ ?  dENDMODEL

) ~' s6 L+ e  k! k程序报错如下
KILL = 422.  The present statement is interpreted as a value assignment statement, and the preceding name is interpreted as a
, O5 k; }, ]- w8 [variable to which a value is being assigned.  The identification of this variable is interpreted as complete, and should now be
. S% c* @9 H6 P  D& Zfollowed by ":=", in the following format:
     variable_identification := expression
3 n; M1 H# r0 u/ ]2 L
本人已经仔细检查了每个等式都加：=了，不知道为什么还是不行，有兴趣的可以仿真一下，大家交流交流。
& u* N: n( C3 S' a9 T* `) x8 [2 o

twjcly

Exa 15就是原模型 自己对照看下

不学无术

我看到你发的帖子了，但是已修改里面的参数，整个模型就不一样了，如果想修改sigma参数，你知道怎么改吗，改完之后模型不变

twjcly

对，要重新修改MODEL的界面呢，在Edit definitions里面，修改Data和NOdes界面，增加变量，更改变量的节点位置。另外你点回复帖子，这样你回复了我都看不到。
% L9 i9 |+ R6 X0 M; {7 g

twjcly

不学无术 发表于 2017-10-13 14:02
  R5 h. E# ?1 Z, F我看到你发的帖子了，但是已修改里面的参数，整个模型就不一样了，如果想修改sigma参数，你知道怎么改吗， ...

7 ?9 s# N9 f% |! Y% ?- y每层楼下面有个回复，不是大的回复。