用MODELS计算线路感应电压:程序如下:$ ?! m3 O- f. \4 ?
MODEL indloss 0 m7 B1 y4 I( o; tCONST N2 y5 R4 n: \+ HTmax {VAL:500} 9 Y8 s3 S+ G- q% n9 Wn {VAL:2}/ m6 C: v" _9 `9 T: Z4 u1 _: K
c {VAL:3.e8} 0 d5 y+ ]9 F7 C7 I0 s6 D
I0 {VAL:1} # {* N" Z( U7 c& n3 t* S% {
eps0 {val:8.85e-12}/ Z$ C% ]% }4 A! K
INPUT UAP[0...n],UBP[0...n] : N2 G0 `& i. b. M3 HDATA Y,XA,XB 9 S# z$ p/ l6 [# s( }( }: n' I$ X" k, }4 Jz[1...n] {DFLT:10} , c( O" H) P& x) z3 O6 c0 P4 WIm {DFLT:3e4} + V1 L; e' ~; }8 ]3 m! R8 F% Q% m
tc {DFLT:5e-5} s: n" C5 B& s. N# Y( Y% Uth {DFLT:2e-6}4 H6 V+ X" t1 C0 ~* K
v {DFLT:1.5e8} : ]# e7 @3 c6 i9 l% u3 ysigma {DFLT:0.001} : O1 j3 w/ y' k! B- l0 A
epsr {DFLT:10} " j. F2 U) _8 E& m( Q+ d
OUTPUT UrA[0...n],UrB[0...n] % n5 ^8 J/ X* a8 q8 Z4 JVAR UindA0[0...Tmax],UindB0[0...Tmax],g1[0...Tmax],g2[0...Tmax], ' `0 J- m3 ]3 Z5 n& ~$ R/ Q# s" S; y. yUindAD[0...Tmax],UindBD[0...Tmax],Ui0,UiD, 6 a9 Y. H8 y5 u6 W K, MUrA[0...n],UrB[0...n],Tr,k,i,AB,dt,uk[1..4],) }* z. K! O* K9 M4 i% i
b,L,x,tau,a1,b1,c1,c2,c36 w; X ~! ?7 C6 F; t% A- D# M$ P
FUNCTION F0(x,tr):= (c*tr-x)/(y*y+(b*(c*tr-x))**2) H0 Q3 f w5 B# _* m# h3 q
FUNCTION F1(x,tr):= (x+b*b*(c*tr-x))/sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)), |8 D: |+ ~5 d" k
FUNCTION F2(x,tr):= x+b*b*(c*tr-x)+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)) * T, c# f* m6 u; `. {- \, `" B& TFUNCTION F3(x,tr):= (v*tr+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)))/sqrt(x*x+y*y) - \" Y W+ p- ]4 I, pFUNCTION t0(x):= sqrt(x*x+y*y)/c ) h9 t2 B1 j# V% v/ m4 IHISTORY . L! V1 y! }) C/ w, BUrA[1...n] {dflt:0}8 v( c" u7 |2 L
UrB[1...n] {dflt:0} ) e5 D2 N* R$ b: mUAP[1...n] {dflt:0}# N2 B$ `+ v. y, F5 X) {
UBP[1...n] {dflt:0} 7 M# d& V' z2 U, G' DDELAY CELLS DFLT: (XA-XB)/(c*timestep)+1 2 ~- b2 N& R6 I [; b6 Q( |) c$ n- ^INIT- Z& f `: w4 r# d6 n
k:=sqrt(eps0*epsr/(PI*sigma*dt))# k/ V- G; G4 U) y$ `3 @" h, k8 F) v
dt:= timestep b:=v/c L:=XA-XB tau:=L/c 0 r; A2 ]; f2 la1:=Im/(I0*th)" k. C5 j7 y- {& R
b1:=0.5*th/(tc-th)+1 7 T C6 _3 \* V) z4 _$ v& O7 Y, pc1:=a1*k*dt/sqrt(epsr)" d) L* y% N' e; A b% `; h$ \
c2:=-1.073*k+0.2153*(k**3)+4/3 " P) J, R; x" Q' ec3:=-0.2153*(k**3)+1/6 M1 _$ s1 Z2 Z, | FOR AB:=1 TO 2 DO - u5 x4 j) S( m; V; O- f- u& Mif AB=1 then4 W! p7 z' B; X, C( M2 @+ M2 l
x:=XA else x:=-XB" F% X7 e6 p& E9 @+ d* \- G
endif7 S0 Z3 Z# I5 j6 |& r7 o @; ^
FOR i:=0 TO Tmax DO- N7 Y" D3 c# J2 R# X o
Tr:=i*dt 6 `: N5 F8 w( Y, h# y# }( mif Tr>t0(x)) h0 H9 S9 e( [ a
then + r$ H% l1 n+ }( Q# s$ Iif Tr>t0(x-L)+tau " R9 ~/ I/ K5 I8 m2 Cthen4 x- g; z9 b- K7 m
Ui0:=f0(x,Tr)*(f1(x,Tr)-f1(x-L,Tr-tau)) 2 K+ R: B# q* }' }0 n6 \% lUiD:=ln( f2(x,Tr)/f2(x-L,Tr-tau) )-1/b*ln( f3(x,Tr)/f3(x-L,Tr-tau) )% g: _, o0 R2 G W& g( C. o
else0 Y! y1 ^& g, g+ ^, O2 `5 W8 |+ B
Ui0:=f0(x,Tr)*(f1(x,Tr)+1)# C. p3 F2 [( ]
UiD:=ln( f2(x,Tr)*f0(x,Tr) )-1/b*ln( f3(x,Tr)/(1+b) )* ?& u3 C# _% h6 Q3 c* [
endif1 x# s/ A1 o8 b& w, P6 e: U
else 1 p: \& F( a1 w G' e4 VUi0:=0, UiD:=0 0 |5 \+ ]9 f7 i7 [endif* X' w [3 h- X2 A9 u- v/ D
if AB=1 then9 {% A* `3 L: \( q. q% M. c
UindA0[i]:=Ui04 e3 [! m! S. f
UindAD[i]:=UiD* J) C# m; z& W& B- Y" @* V3 J
g1[i]:=a1*dt 9 K! @2 R( c2 D* c$ Fif i>0 6 k) _* `' I3 q' a* ?) Xthen+ F( c1 |9 p* b1 w
g2[i]:=a1*sqrt(eps0/(PI*sigma*Tr))*dt8 t: X6 O, f6 k% x4 }4 ?- |
endif 0 G! b2 b, q! h8 y+ }. w# uelse ( V1 u- k/ i' o7 NUindB0[i]:=Ui0 ' b1 j7 M- V- {2 IUindBD[i]:=UiD8 `7 t" E, s$ V! E, t
endif0 c* S- e5 N3 l d
ENDFOR- N6 x x w0 l; L/ j
ENDFOR + n0 T3 y7 ^1 L& d4 ~i:=Tmax( \1 g: C2 k3 l6 o: m
WHILE i>1 DO " J$ z+ k) K/ W) luk[1...4]:=0 ' C6 a% k( J2 @( @FOR Tr:=1 TO i-1 DO : I; x$ A$ ~! o- Q+ luk[1]:=uk[1]+UindA0[Tr]*g1[i-Tr]/ v# |- l; j( @ X4 o( B
uk[2]:=uk[2]+UindB0[Tr]*g1[i-Tr] 1 T' s& b, c2 z; w. Q; N* M S$ B7 n
uk[3]:=uk[3]+UindAD[Tr]*g2[i-Tr] 5 o6 z: k i/ m# {, _! B/ S# L4 |- l" x
uk[4]:=uk[4]+UindBD[Tr]*g2[i-Tr] ' @3 K, u" P: d& ?5 B/ T1 _* U/ _1 Z" n
ENDFOR $ I0 A4 @$ Y; Q/ rUindA0[i]:=uk[1]+0.5*UindA0[i]*g1[0]( q. b# m) e1 ]$ [9 h
UindB0[i]:=uk[2]+0.5*UindB0[i]*g1[0] 2 L4 B [: _# p; BUindAD[i]:=uk[3]+(UindAD[i]*c2+UindAD[i-1]*c3)*c1 # v9 n" J! }4 B1 ^8 a. kUindBD[i]:=uk[4]+(UindBD[i]*c2+UindBD[i-1]*c3)*c1 ' m' u& o; P$ r+ Ii:=i-1 / j1 x7 D5 J1 z! iENDWHILE / C/ J3 V3 b7 J, S# L9 PTr:=trunc(th/dt)) t; v, `/ V0 O
s+ Z+ ?7 ]* f- rFOR i:=Tmax TO Tr BY -1 DO 9 v2 w) P7 M! n" Q3 JUindA0[i]:=UindA0[i]-b1*UindA0[i-Tr]2 W% W& J1 D' E8 p/ [* J: Y. T5 D/ E
UindB0[i]:=UindB0[i]-b1*UindB0[i-Tr]1 m9 o" f1 y+ y& J
UindAD[i]:=UindAD[i]-b1*UindAD[i-Tr]. K4 a; }* {' ?$ m7 ^7 Q
UindBD[i]:=UindBD[i]-b1*UindBD[i-Tr]# f1 C: e3 O* `( d3 s' a
endif" p4 N, h; d! q
ENDFOR7 H' _* C8 _! n' e3 N* o
ENDINIT ' H) y6 Z/ V/ ^EXEC/ Q( n9 `* q# S7 g6 S# \! W4 T* m* n
FOR i:=1 to n DO: u. Y8 o0 j$ t" o; A; H# A7 M
UrA[i]:=60*I0*b*(z[i]*UindA0[t/dt] - UindAD[t/dt]) +2*delay(UBP[i],tau-dt,1)-delay(UrB[i],tau,1)$ R% Y, _, }' }& C8 x
UrB[i]:=60*I0*b*(z[i]*UindB0[t/dt] - UindBD[t/dt]) +2*delay(UAP[i],tau-dt,1)-delay(UrA[i],tau,1) 2 g+ r" d4 L$ q; F6 m9 ?! x/ X7 D9 Q' dENDFOR 6 ~2 T: I6 r0 O: Y. A4 kENDEXEC # H4 O! ]3 j7 e/ |3 I$ |ENDMODEL% g3 y) a+ i5 }; Z/ }( i
( `: P! I) K4 ?9 F$ a0 S$ R
程序报错如下0 Z/ f- Z# m; c: A/ a- V; b6 P
KILL = 422. The present statement is interpreted as a value assignment statement, and the preceding name is interpreted as a* H5 q1 q+ K; P+ b
variable to which a value is being assigned. The identification of this variable is interpreted as complete, and should now be7 ^' x' x( ?5 r( G( n$ X- ]
followed by ":=", in the following format: * b6 f' _3 V7 w; G) C( T* a variable_identification := expression4 J$ L* C2 s* s1 }' m i
" ?! u K" U% m- z5 ~2 U3 h6 P6 [本人已经仔细检查了每个等式都加:=了,不知道为什么还是不行,有兴趣的可以仿真一下,大家交流交流。% i& P1 p! q. K' D1 J, `- A& V