TA的每日心情 郁闷 2017-12-26 18:33
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用MODELS计算线路感应电压:程序如下:
; Z* p/ O4 h6 i MODEL indloss
9 Y! e9 o( k, O- P: j CONST + t8 |# ~' M5 h7 I% l' `$ C, F
Tmax {VAL:500}
* `. z2 V$ j( c/ S$ f- r n {VAL:2}! q8 h2 t, a4 E, S5 _
c {VAL:3.e8}
/ t3 d/ V0 k# ` I0 {VAL:1}
: b: C- y4 g9 ?+ W, l3 P eps0 {val:8.85e-12}
& }) S" q4 l8 p P. {* b INPUT UAP[0...n],UBP[0...n]
5 g5 o2 |! K% a% \* I9 j/ P- B DATA Y,XA,XB9 G! J5 ]: z: c8 K* l
z[1...n] {DFLT:10}
3 L& h% j8 R. A0 V& R Im {DFLT:3e4} 9 }7 G! T2 Y& Z
tc {DFLT:5e-5} h7 R3 a8 _! @3 U: q9 q3 |
th {DFLT:2e-6}
$ V8 G' s- N+ { v {DFLT:1.5e8}
9 B! | L8 A0 A sigma {DFLT:0.001}
5 T# I) I" ?7 S& T/ M; l5 y epsr {DFLT:10} + G" M0 ]( K" S/ E4 f1 K; h. B, z4 l
OUTPUT UrA[0...n],UrB[0...n]
0 S* r: ?9 v! T( |% o: W VAR UindA0[0...Tmax],UindB0[0...Tmax],g1[0...Tmax],g2[0...Tmax],! L* q# t* S3 O4 G: \3 c
UindAD[0...Tmax],UindBD[0...Tmax],Ui0,UiD,
$ u6 R* U: v/ j( ~ UrA[0...n],UrB[0...n],Tr,k,i,AB,dt,uk[1..4],
7 U4 R8 [% ^0 D- d8 k# Q b,L,x,tau,a1,b1,c1,c2,c3
: [ r. P8 D: u* p& z FUNCTION F0(x,tr):= (c*tr-x)/(y*y+(b*(c*tr-x))**2)
; o# g+ L) U. O, S1 C% [ FUNCTION F1(x,tr):= (x+b*b*(c*tr-x))/sqrt((v*tr)**2+(1-b*b)*(x*x+y*y))
+ |+ ^" q0 Z d FUNCTION F2(x,tr):= x+b*b*(c*tr-x)+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y))
1 |! m( F5 J3 v8 U0 o1 F6 e FUNCTION F3(x,tr):= (v*tr+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)))/sqrt(x*x+y*y)1 `0 Y2 T* l K' J) q7 I
FUNCTION t0(x):= sqrt(x*x+y*y)/c3 T3 s k& `9 x b3 O0 j6 C
HISTORY X( A, i0 {# o
UrA[1...n] {dflt:0}
( ~, g+ P( }9 S9 c UrB[1...n] {dflt:0}. l* M0 \/ ?" E/ s) S s9 o
UAP[1...n] {dflt:0}
! ]4 F& K2 d: {- s UBP[1...n] {dflt:0}6 i2 V: h2 l5 |# S: Z1 B% b
DELAY CELLS DFLT: (XA-XB)/(c*timestep)+1
, g; K; N8 r8 b8 L6 p& J INIT$ O* q+ r6 g/ y6 x. V" O3 P
k:=sqrt(eps0*epsr/(PI*sigma*dt))
% Z) }$ ]9 f6 L- q* \1 O$ C dt:= timestep b:=v/c L:=XA-XB tau:=L/c* n9 Q, @ j8 Y( A6 C' P) J
a1:=Im/(I0*th)
3 k4 o; H/ I; Z! y. P) c1 x( d b1:=0.5*th/(tc-th)+1; K: ~! `% L# ~% k( [
c1:=a1*k*dt/sqrt(epsr); ~: j* s" B. P# h
c2:=-1.073*k+0.2153*(k**3)+4/32 N5 T& D% Y5 R
c3:=-0.2153*(k**3)+1/6
: `4 L% Z4 K0 ]; m0 G8 N* ^ FOR AB:=1 TO 2 DO8 L1 g0 u/ H2 E0 s5 N+ j7 A
if AB=1 then- I/ T9 c- ?. ~9 w, a0 q g
x:=XA else x:=-XB) }6 r, V& Y& e& e3 p
endif7 a/ a+ e! _# g- U6 X
FOR i:=0 TO Tmax DO
( ? a+ H" p2 [) k Tr:=i*dt0 K- a1 Y6 e7 n8 ^0 ^! `
if Tr>t0(x)
7 B/ M" [$ X R( Y$ l then& f, I" D: {, ~- J# m
if Tr>t0(x-L)+tau) _# w2 k4 D0 O: v! t% C# f, m
then
2 ~( W8 r; y- c' | Ui0:=f0(x,Tr)*(f1(x,Tr)-f1(x-L,Tr-tau))
9 L7 X) d( U6 Z7 A3 k UiD:=ln( f2(x,Tr)/f2(x-L,Tr-tau) )-1/b*ln( f3(x,Tr)/f3(x-L,Tr-tau) ); I# U9 n% v8 j; j
else, h! {0 B- ^' @) g; O/ F: M N
Ui0:=f0(x,Tr)*(f1(x,Tr)+1)
4 p' z& |& M S UiD:=ln( f2(x,Tr)*f0(x,Tr) )-1/b*ln( f3(x,Tr)/(1+b) )/ J1 P, m9 v4 E3 l" X
endif$ _ { }+ ^8 q& W; E+ G9 L
else
* J; e" n/ ~5 \ d9 {! X$ G7 L Ui0:=0, UiD:=0
2 y: `, c7 ]) v2 r endif
5 Y0 Y% d0 |1 ~ i( G% c/ m* N9 E if AB=1 then
/ S6 m8 D4 K5 s( k1 ^ UindA0[i]:=Ui0
2 r) e7 o$ ], u5 x* Z a, G' ?1 Z ]/ r UindAD[i]:=UiD1 w. Q& c3 Q7 | |9 @
g1[i]:=a1*dt- N# C; b6 M5 l7 Y' u+ j6 l6 {
if i>0
; [7 H l: G. z! x% P4 ? then
$ G% b( ~0 I1 f g2[i]:=a1*sqrt(eps0/(PI*sigma*Tr))*dt
% k( `* Q; J% s) X! i7 g endif
$ z5 `& R1 k1 u5 Q+ F S ` else! Y" b! w. k9 F' k# a
UindB0[i]:=Ui0: s. E( r. ^) S
UindBD[i]:=UiD0 I' @6 e; j0 l8 s9 y, X
endif5 ] n+ ^9 _8 d% D9 j
ENDFOR* ]% w" m$ `# L9 \5 W
ENDFOR
5 r, C0 f% c- S0 Y i:=Tmax
& z- D$ o2 |( t6 y1 h WHILE i>1 DO1 J& J: E( ^+ n& u
uk[1...4]:=0
1 `& k7 ~5 I; E3 x/ r& q* G, F FOR Tr:=1 TO i-1 DO
$ y) Q; x, Y- N* W$ Y) d; A uk[1]:=uk[1]+UindA0[Tr]*g1[i-Tr]: U, M- k+ x4 ~0 x {8 {5 t
uk[2]:=uk[2]+UindB0[Tr]*g1[i-Tr]7 \/ N" @; `% w+ ^2 ~
' C; x( ]7 V, s uk[3]:=uk[3]+UindAD[Tr]*g2[i-Tr]
" N1 l! O% j" o
' z" J+ L5 g8 v, O2 J) C( A; j2 a6 Q" G uk[4]:=uk[4]+UindBD[Tr]*g2[i-Tr]
& {, ]% t5 ~+ u1 t2 M" z- f
9 ]! {0 D/ ~' P. k ENDFOR
& _0 O( [! p+ r" H( D UindA0[i]:=uk[1]+0.5*UindA0[i]*g1[0]
) }0 `, @) j+ C& N v2 o UindB0[i]:=uk[2]+0.5*UindB0[i]*g1[0]
7 ~- P" a5 f( _1 l6 T6 E UindAD[i]:=uk[3]+(UindAD[i]*c2+UindAD[i-1]*c3)*c1
# B& P+ J- h+ t+ u! o UindBD[i]:=uk[4]+(UindBD[i]*c2+UindBD[i-1]*c3)*c1- Q( |( a, U @5 [
i:=i-1
+ x. {3 T) @ o4 ~# Q4 d+ U: w ENDWHILE
6 y r ]+ A5 U h) f Tr:=trunc(th/dt)/ d2 s4 u6 A; H" }0 D* g& A
# N+ f4 q& ^/ ~/ G) t, i8 S0 n FOR i:=Tmax TO Tr BY -1 DO
( n; ~9 Z& p1 u UindA0[i]:=UindA0[i]-b1*UindA0[i-Tr]
0 p( h2 O4 L" [: q UindB0[i]:=UindB0[i]-b1*UindB0[i-Tr]. n* D9 h7 m2 C" L) {6 o0 h
UindAD[i]:=UindAD[i]-b1*UindAD[i-Tr]
! v2 s$ S+ X2 e" V, Q8 @3 c UindBD[i]:=UindBD[i]-b1*UindBD[i-Tr]$ X0 ]5 E' m0 E+ r9 x
endif# P8 M' O% H6 f3 T$ F3 `9 S6 [; w
ENDFOR! W: t" s1 Q" w
ENDINIT6 t2 l% }7 W1 W+ y
EXEC; t% ~; g1 V+ y" x6 e' \& b* d
FOR i:=1 to n DO# j0 j- P- x7 Z1 p: B" Q0 A4 F
UrA[i]:=60*I0*b*(z[i]*UindA0[t/dt] - UindAD[t/dt]) +2*delay(UBP[i],tau-dt,1)-delay(UrB[i],tau,1) w( X3 p( ~& l7 V1 g
UrB[i]:=60*I0*b*(z[i]*UindB0[t/dt] - UindBD[t/dt]) +2*delay(UAP[i],tau-dt,1)-delay(UrA[i],tau,1)) \& e; I- x& K8 f; z3 B7 t4 a6 h
ENDFOR7 D% P. t5 E) o0 k) v
ENDEXEC+ _# T. U( ~6 L# k2 `" N0 A6 n
ENDMODEL
( l" `7 @" {( A9 d% C) R
* z$ X& c, R0 k( X; t7 L 程序报错如下- Z$ ^; o# C& n$ {2 D# }
KILL = 422. The present statement is interpreted as a value assignment statement, and the preceding name is interpreted as a
! p$ m8 {* ^3 s ], j variable to which a value is being assigned. The identification of this variable is interpreted as complete, and should now be
2 o7 p8 @1 n& E& ]2 l followed by ":=", in the following format:
3 U T/ J7 n, i% z# M; ? variable_identification := expression
8 W2 \ Z3 a; V6 m+ C1 c # N4 y7 h1 F) z& V
本人已经仔细检查了每个等式都加:=了,不知道为什么还是不行,有兴趣的可以仿真一下,大家交流交流。 N9 ~2 c. S- w, b
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