用MODELS计算线路感应电压：程序如下： 5 x. Q4 y& V. v7 L% T! kMODEL indloss ( {2 T) m- Q: P9 nCONST ; n( x8 e! e' h S, g3 j3 v
Tmax {VAL:500} ; L3 h" N3 S$ r6 @
n {VAL:2} 5 | s, @1 T( R% u# Bc {VAL:3.e8} 0 X. ?7 S! g# o7 T4 M BI0 {VAL:1} . A m; D" f8 R5 ]0 t# p
eps0 {val:8.85e-12} ' b4 s* Q1 ]% NINPUT UAP[0...n],UBP[0...n]/ d) r9 M$ T, D8 F
DATA Y,XA,XB7 A% D2 C3 ^+ a
z[1...n] {DFLT:10} 7 B2 n( g0 Y8 `+ ]Im {DFLT:3e4} : b( _% B0 h9 y/ @% z1 V4 x
tc {DFLT:5e-5} - H$ p H$ I. m w9 F, W
th {DFLT:2e-6}: c+ M, N7 D8 U* r6 y. t) a" P, [
v {DFLT:1.5e8} " I- S7 q9 d4 l' f* _sigma {DFLT:0.001} # h! m, b$ F, l3 K
epsr {DFLT:10} x" m' Q9 X% t- z R8 F5 jOUTPUT UrA[0...n],UrB[0...n]. x$ e& r" _9 u1 v$ y
VAR UindA0[0...Tmax],UindB0[0...Tmax],g1[0...Tmax],g2[0...Tmax], 6 c$ Z+ h5 C# u1 s- ~. @UindAD[0...Tmax],UindBD[0...Tmax],Ui0,UiD,5 U. W# S, i9 f& R
UrA[0...n],UrB[0...n],Tr,k,i,AB,dt,uk[1..4],) l$ X% H4 A. v$ c$ g) L
b,L,x,tau,a1,b1,c1,c2,c38 l* T& b' m7 n2 q4 f3 m# a
FUNCTION F0(x,tr):= (c*tr-x)/(y*y+(b*(c*tr-x))**2) . H4 P/ I' d& k9 r. u: t+ D- vFUNCTION F1(x,tr):= (x+b*b*(c*tr-x))/sqrt((v*tr)**2+(1-b*b)*(x*x+y*y))3 ~: F/ b, j- i4 ~
FUNCTION F2(x,tr):= x+b*b*(c*tr-x)+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)) $ m% D; p" D! eFUNCTION F3(x,tr):= (v*tr+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)))/sqrt(x*x+y*y)4 z' Z5 s) r4 L% S, f. E/ ~
FUNCTION t0(x):= sqrt(x*x+y*y)/c 5 v1 W6 L; v1 k% _- YHISTORY, t; [/ [( B6 j8 n4 F% j b$ P
UrA[1...n] {dflt:0}0 a7 A2 F) ?2 Z" }
UrB[1...n] {dflt:0}7 N! l0 v" E8 w" z) {: n
UAP[1...n] {dflt:0} - c+ N+ c7 q2 q: \1 u8 r4 PUBP[1...n] {dflt:0}$ A2 a4 ]: x% A& _* A
DELAY CELLS DFLT: (XA-XB)/(c*timestep)+1- P- ?) b' l8 K1 D, A( g
INIT , A, M+ l2 q: S+ Wk:=sqrt(eps0*epsr/(PI*sigma*dt))) C# w4 v l( _) Z, i
dt:= timestep b:=v/c L:=XA-XB tau:=L/c2 X! `8 M; Q, `1 w
a1:=Im/(I0*th)& p. [1 k- x' i9 J+ A" o8 J
b1:=0.5*th/(tc-th)+1. D; H% H( R- O4 p, j7 x; W; `
c1:=a1*k*dt/sqrt(epsr)& n/ \) h4 d% k. _: n" T+ l5 Z" \9 J
c2:=-1.073*k+0.2153*(k**3)+4/3/ P4 [* O7 C# }. s% W7 q" s7 L
c3:=-0.2153*(k**3)+1/6 ! E# Z5 T/ r, e# j: A FOR AB:=1 TO 2 DO 9 ~' W' n3 Z- `' ^, q' X$ xif AB=1 then " ~) o# o2 W" h1 K- |x:=XA else x:=-XB 2 n- X' U* q% l; m' d5 t7 Oendif 4 f5 ?5 e* ?0 ~6 r$ d0 d, DFOR i:=0 TO Tmax DO9 t% h# M8 H1 B7 T1 m5 G
Tr:=i*dt( {% M) V$ T/ m) y5 k
if Tr>t0(x) : C2 N! ~4 L2 K6 fthen3 ~/ \7 K5 r( A5 i' i
if Tr>t0(x-L)+tau3 R3 o1 V) D0 C+ A" b7 j4 c
then- f1 ~2 q. G0 W( q6 Q
Ui0:=f0(x,Tr)*(f1(x,Tr)-f1(x-L,Tr-tau))* {2 i/ O: A3 [* Z; @5 V
UiD:=ln( f2(x,Tr)/f2(x-L,Tr-tau) )-1/b*ln( f3(x,Tr)/f3(x-L,Tr-tau) )/ W: X k* h* K5 N$ b8 R
else 1 }# r4 R+ N' V5 n; J; T4 kUi0:=f0(x,Tr)*(f1(x,Tr)+1) ! u# w6 r& B* ^/ TUiD:=ln( f2(x,Tr)*f0(x,Tr) )-1/b*ln( f3(x,Tr)/(1+b) ) s( `8 ] s9 [( |
endif3 Z+ k+ u9 o: I9 A: l) x: s+ T0 H$ x4 \) j
else & i6 Q0 K" }! j5 E$ W! B6 rUi0:=0, UiD:=0' Y+ w2 ], i/ E8 l1 |
endif7 B* }9 H& f( I3 Y& ?
if AB=1 then( q5 u) H# j1 s ]: I0 R
UindA0[i]:=Ui02 E: w: l5 S' r) m
UindAD[i]:=UiD' A" J; Q) @: d' M9 L
g1[i]:=a1*dt # E( z( S" V4 m w( j7 j, cif i>0 8 [! ?5 T# B& `% Rthen+ ] e4 l1 R0 D7 ?: g
g2[i]:=a1*sqrt(eps0/(PI*sigma*Tr))*dt- x, y3 v+ H# `
endif: I# K* I$ E A' N
else . Z# N# E% W# V- u: d lUindB0[i]:=Ui0" P6 A+ g+ |% K6 _1 ]% Z3 J9 M
UindBD[i]:=UiD 8 Q+ S) b2 i$ W+ U( Vendif # ?3 I1 b# h- pENDFOR 7 L* N& }5 z# u( ?2 t% v0 }ENDFOR " p3 y+ f; D) E0 v; @6 M9 A5 k! Gi:=Tmax# n$ p, t3 `0 M( z
WHILE i>1 DO0 U; \/ H) r. X) _
uk[1...4]:=0) Q6 T9 E2 E4 J/ m
FOR Tr:=1 TO i-1 DO& B" R* X4 V* p
uk[1]:=uk[1]+UindA0[Tr]*g1[i-Tr] ; t& L C8 P! `/ g0 c. | kuk[2]:=uk[2]+UindB0[Tr]*g1[i-Tr] , X* w, r7 H. y$ M" B) C 3 T$ ^" x* i. A' e( Zuk[3]:=uk[3]+UindAD[Tr]*g2[i-Tr] [9 b! T6 S, Z) K. ]$ G& Y . E6 A4 u% o, O1 E6 h \" wuk[4]:=uk[4]+UindBD[Tr]*g2[i-Tr]9 D( K0 R6 s9 r# P: h! P
$ I6 `/ w5 q* E) j
ENDFOR- w0 ]' X4 b- p$ e0 ] G. _
UindA0[i]:=uk[1]+0.5*UindA0[i]*g1[0] 5 g* k! x6 b3 ~- F' MUindB0[i]:=uk[2]+0.5*UindB0[i]*g1[0] + }$ y4 T y) a6 O7 a5 E3 AUindAD[i]:=uk[3]+(UindAD[i]*c2+UindAD[i-1]*c3)*c1 + ~1 C! Q& ^& i% X- C2 WUindBD[i]:=uk[4]+(UindBD[i]*c2+UindBD[i-1]*c3)*c17 i; S' P" Y+ e* `# X) D
i:=i-1" o9 i0 o! Q4 R1 T
ENDWHILE ' r5 h9 g0 V' k% f( f6 a: dTr:=trunc(th/dt)) Y( j" z% P- H/ l/ y
$ o. j' d* b2 G$ \# GFOR i:=Tmax TO Tr BY -1 DO & C: r7 ~1 Q2 p1 R6 e$ d5 RUindA0[i]:=UindA0[i]-b1*UindA0[i-Tr] w* ?; z0 R1 K: }/ ^0 \0 W9 t' P
UindB0[i]:=UindB0[i]-b1*UindB0[i-Tr]9 F' g3 `* G; X- J' E o* s6 n
UindAD[i]:=UindAD[i]-b1*UindAD[i-Tr] # K- G0 p9 `- U, }7 L( ] t4 t/ E2 BUindBD[i]:=UindBD[i]-b1*UindBD[i-Tr]9 s# @4 I* Q$ G6 J
endif , k9 u* i0 k- ~. I- s# W; ]ENDFOR& H0 k3 O4 b' w9 B
ENDINIT 5 m. L, D/ g( I# ?, UEXEC - G. c/ p, T3 m' r) `1 z. U% tFOR i:=1 to n DO & h1 C; Q8 W! nUrA[i]:=60*I0*b*(z[i]*UindA0[t/dt] - UindAD[t/dt]) +2*delay(UBP[i],tau-dt,1)-delay(UrB[i],tau,1) * d, \ f" e# y$ }) H1 z9 H. ]UrB[i]:=60*I0*b*(z[i]*UindB0[t/dt] - UindBD[t/dt]) +2*delay(UAP[i],tau-dt,1)-delay(UrA[i],tau,1)7 e" r) c9 N8 q3 \
ENDFOR2 \& q9 j0 A9 o+ b* a& M2 u2 E% ^( \% v
ENDEXEC1 |4 ?% S* w7 z. \. k
ENDMODEL ) t1 s( T# Q- s9 N - |% {, a- n% u* c* T程序报错如下 : h3 |3 m; h9 }" E2 v- sKILL = 422. The present statement is interpreted as a value assignment statement, and the preceding name is interpreted as a, [" w% ^/ _% B3 `; E
variable to which a value is being assigned. The identification of this variable is interpreted as complete, and should now be , i J: d0 \( r7 D( ]9 M dfollowed by ":=", in the following format: % t* ?9 M5 M2 Z7 r variable_identification := expression h) p& ^7 l( v" E. [4 z
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发表于 2017-10-12 16:25:24
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