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发表于 2009-6-23 21:12:59
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IEEE5的数据如下:, m& C3 T' w1 v) t" P$ U$ r! o
PowerSystemComputation P.168
) M; ], U4 I! M. y8 r+ u/ S0 o# ]lftype.h
3 d* t' e+ D6 V. [+ O*********************
& B4 B. ^- }! K. E2 TTHTRFO TFR1 bus_5 bus_3 0. 0.03 105.
" @7 o+ C( U+ ^2 wTHTRFO TFR2 bus_4 bus_2 0. 0.015 105./ P8 b+ O+ ?7 l7 `( J
THLINE LINE1 bus_1 bus_2 0.04 0.25 -0.25 2 {- N! I1 H* x) v1 B
THLINE LINE2 bus_1 bus_3 0.1 0.35 0. * S4 d5 J$ h0 p [8 _) i# G4 a
THLINE LINE3 bus_2 bus_3 0.08 0.30 -0.25
2 ~8 @5 s( S F) A1 {& q! Y8 h8 _* t
4 g3 G/ Q9 w4 n* |" W/ d+ [
THLOAD LOAD1 bus_1 1.6 0.8
/ r: W2 s. P& D# l; @* t" \THLOAD LOAD2 bus_2 2. 1.05 c8 P; Z& v- H: O$ L& P: Q
THLOAD LOAD3 bus_3 3.7 1.3
6 v& x! R+ i5 X" Y3 t u- L 6 Q% ?9 z8 N/ e8 s
GENER GEN1 bus_5 0 0 1.0
$ ?- O7 g1 Z$ L! |% [8 z! nGENERCV GEN2 bus_4 500. 0 1.05 1.0
9 a0 k3 q% |# ^. \THSLACK GEN1 1.05 0. 1.0: H% y {" X# ]! D, T. ~
==================================3 p8 k" _4 j: ]% o) e# Q
**** Solved case ****
4 I$ Z. M) ~ g# d. ]% i* xRES_V bus_5 1.050000 0.000000 1
2 s( M3 T" J* L5 {. ^: s9 iRES_V bus_3 1.036411 -4.281930 1
! b8 e+ S, W- s4 u& G. hRES_V bus_4 1.050000 21.843319 1
$ I- ^5 c, Z% \2 d' c! a, r$ iRES_V bus_2 1.077916 17.853530 1 h+ M* N& x3 T; U& g5 o. D6 m9 l- W# a
RES_V bus_1 0.862150 -4.778511 1
/ J5 W0 r1 d5 jRES_MAC GEN1 bus_5 257.94273 229.94021 17 [9 m3 N2 D# H% Q
RES_MAC GEN2 bus_4 500.00000 181.30840 1 |
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