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这是PSAT2.1.2说明书中的一个命令行例子:, }+ N6 h/ @ k
% initialize PSAT% k* Q j) o3 N1 i6 a) z# E
initpsat, o) Y# M3 a" i. k2 X
% do not reload data file! j4 Z& g; L% L0 m0 X7 l# f
clpsat.readfile = 0;1 ~4 F: w- |: s; Z" ~; x
% set data file
. J6 r) w* n* g) u* Y1 grunpsat('d_006_mdl','data')
: o& j( k: d- \+ a* X+ a% solve base case power flow1 J2 v( j1 N4 b1 F7 |+ F) ^( F
runpsat('pf')
& t5 P9 Q9 f* A2 H+ n4 E% cvoltages = DAE.y(1+Bus.n:2*Bus.n);
1 }7 p7 q5 k5 i% increase base loading by 50%
( R4 l% h* u0 Ofor a = 1:10
! \- C6 I7 C( U7 M @' f PQ.store(:,[4,5]) = (1+a/20)*[0.9, 0.6;1, 0.7;0.9, 0.6];- L7 q. H9 p9 O3 B5 d2 f& K
PV.store(:,4) = (1+a/20)*[0.9; 0.6];
) G. T+ @% Z) D Y runpsat('pf')
) Q9 m' U a0 U. v& E voltages = [voltages, DAE.y(1+Bus.n:2*Bus.n)];
8 J( S4 @( ]: rend
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" J3 w8 T; O0 R7 s但运行之后出错:# H7 Q4 H* @! j* j, X. L
??? Index exceeds matrix dimensions.
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$ H0 z5 ~* n' W2 R9 }4 l# y% ]Error in ==> BUclass.getbus at 3
& e" x1 ]" P& b) i0 Fu = a.int(round(idx));+ q8 d! a( s3 _2 x+ \) h
# d2 {( H7 `1 k2 NError in ==> LNclass.setup at 15
& B4 U% n' l' ~0 [1 {[a.fr,a.vfr] = getbus(Bus,a.con(:,1)); e6 X- r- t# Y
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Error in ==> LNclass.restore at 7
0 G; F8 M7 K9 ~! z( a a = setup(a);! G9 P4 Y# @1 ]/ `& \+ `+ u* j! o' K
8 m4 L) t0 v* B9 U6 d; w4 |2 QError in ==> fm_restore at 16
' {, I% [( c# {( n+ ^* pLine = restore(Line);
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( r0 Q9 R6 Q1 O% lError in ==> runpsat at 259
& ^- n m7 o W* n" R3 W$ q% _ fm_restore1 f k* n: P" T" y- I( u5 b, O$ u
, |1 C/ V- j2 q1 C* q- |$ @Error in ==> Example54 at 144 j! T6 }& f3 ^' i- \$ g
runpsat('pf')
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这是什么原因?望高手请教!谢谢!, T$ e1 U: R9 ?, F3 s2 \
* S5 K; C3 g0 V" T0 m: y! |如果使用命令行做连续潮流,中间过程的数据都在哪里?5 G9 S: c) C; g( O* @
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PS:寻找PSAT的研究者,有意加本人QQ:272843822,非诚勿扰! |
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