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《MATLAB/Simulink电力系统建模与仿真》中94页中的2机5节点电力系统潮流计算仿真，我参数完全按照书中设置，但调试有问题，Update Load Flow之后，得出发电机的三相电压不对称，数据如注释所示。哪位高手知道为啥？
. z+ J# ~5 d! I/ W. L注：
: A0 l Q% u& U+ G9 s) x- t7 CMachine: G2 , ~9 D x$ G& P) E. A) g
Nominal: 100 MVA 10.5 kV rms
4 i" N( g: c y0 z( F, ]2 uBus Type: Swing bus
/ V7 s) I6 O/ F# V2 q8 ZUan phase: -40.27° " x9 Q r) z& q$ W1 ]' ?; B& C
Uab: 52029 Vrms [4.955 pu] -10.27° 1 D r6 b( O: i0 y
Ubc: 48895 Vrms [4.657 pu] 157.70°
& q6 ~& W: ]9 |- ]4 eUca: 11025 Vrms [1.05 pu] -122.71° # _8 W ^1 I6 e' `7 x! }. d7 q
Ia: 16777 Arms [3.051 pu] -9.91°
3 J& E1 D. j% H" v. bIb: 16777 Arms [3.051 pu] -129.91° 3 U6 P1 q2 A+ [; L0 n
Ic: 16777 Arms [3.051 pu] 110.09° 8 Y/ A. R: W% ?, g2 T
P: 1.3046e+009 W [13.05 pu] , P8 u: D C* e0 P) U9 K3 b! u
Q: -7.6415e+008 Vars [-7.642 pu]
* v% \( `3 s3 C5 h3 J5 v9 ePmec: 1.3079e+009 W [13.08 pu]
/ H* b! A& F) n2 F, mTorque: 8.3264e+006 N.m [13.08 pu]
, s* I$ H% ~* r: h( ?/ A+ R) C6 NVf: 6.067 pu
9 T& F, @! \( L0 [9 _3 `0 z$ ^# l4 i) ~6 m
9 W/ l9 b9 P$ r! N& P' ^ D; dMachine: G1
0 [4 |: G0 u( ^ @7 S* kNominal: 100 MVA 10.5 kV rms
' B2 D1 Z9 x! \Bus Type: P & V generator
' Y3 o' X% x' W5 GUan phase: -40.45°
, A0 Q2 ?3 ~! r2 a# U, q) i! WUab: 55176 Vrms [5.255 pu] -10.45° . s T4 X) \4 D4 ]" N; P
Ubc: 50638 Vrms [4.823 pu] 158.65°
6 b3 s ?$ j8 V, F) j4 HUca: 11025 Vrms [1.05 pu] -130.09°
( B4 K, y1 E1 X1 Q# m2 K4 eIa: 17338 Arms [3.153 pu] -21.32° 7 K" ^0 ]* u w S
Ib: 17338 Arms [3.153 pu] -141.32°
+ H, f$ F* M4 ~Ic: 17338 Arms [3.153 pu] 98.68° 0 Y- R9 ^4 M1 g6 \" f
P: 1.5654e+009 W [15.65 pu] # @! j( c$ B7 W. z- \9 q6 f
Q: -5.4297e+008 Vars [-5.43 pu] % H3 r6 u9 `1 A |* L* F, x
Pmec: 1.569e+009 W [15.69 pu] ! u( K: H3 l, Y7 h8 Z
Torque: 9.9887e+006 N.m [15.69 pu] , Q( F" Y6 }& C% z% l1 {
Vf: 6.7898 pu * C9 G& d1 y0 \/ k4 b+ N
* N; j- v* R$ N f% v# c
Machine: Load3
3 z2 E3 W q) ?6 i. b% N9 K# }* iNominal: 115 kV rms
0 S% D& y! w( y% {( F, k. SBus Type: P & Q load
0 t4 Y$ x2 R' ]$ ~ R5 oUan phase: -46.14° 9 _5 y8 V/ R$ Z
Uab: 6.2602e+005 Vrms [5.444 pu] -16.14° ( j K7 \1 z: Y3 t
Ubc: 6.1132e+005 Vrms [5.316 pu] 161.43° . v8 Q! c" w3 `2 x0 Q
Uca: 30061 Vrms [0.2614 pu] -136.62°
d6 G( |& _. B0 K$ H" |+ V2 }Ia: 300.16 Arms -102.68°
) H2 }1 U' @. L1 K3 uIb: 300.16 Arms 137.32° % x1 v; g$ T* T9 q$ I( a
Ic: 300.16 Arms 17.32° 3 O& v% t! a; j3 T! m/ z/ v
P: 1.7944e+008 W
/ I r9 s5 `! k, l6 I6 p) PQ: 2.7153e+008 Vars " A: d0 e+ G& b# F
- P6 f$ o3 [0 z$ m! @/ P- \
Machine: Load2
' b) k3 b1 X* b# uNominal: 115 kV rms 1 t( K" Q" V; w9 d, H
Bus Type: P & Q load
- u: R" f4 |# [: LUan phase: -41.18°
6 c6 b) F2 N. d% X& b6 G; Z% `Uab: 6.0512e+005 Vrms [5.262 pu] -11.18° ) I) Q, x" y/ p! t
Ubc: 5.7431e+005 Vrms [4.994 pu] 157.92° . i' w' f- G# g1 d
Uca: 1.1609e+005 Vrms [1.009 pu] -121.95°
# b$ b0 S* J& Z5 T! K; \ iIa: 798.9 Arms -92.72°
9 Q9 ?# Z. p( ~! d/ O SIb: 798.9 Arms 147.28° 1 s% U: i- a% J" |, `; R
Ic: 798.9 Arms 27.28° 9 s0 _6 X2 d# S
P: 5.2087e+008 W / ?& N- r; g& W( T. e/ O
Q: 6.5561e+008 Vars
: w u2 n U2 q* u. q0 a
( r8 ?# K0 ]; e9 C, b+ `6 pMachine: Load1
5 ?0 x2 B' P+ j4 h" i" \Nominal: 115 kV rms
& A$ Y& W: w! T6 Y* v/ [Bus Type: P & Q load + P+ r+ Q i( n- G. x7 b h% D
Uan phase: -40.94° S7 Q4 k" e/ g. M3 b* f$ B, O
Uab: 6.3759e+005 Vrms [5.544 pu] -10.94° * {' H8 ~- N% l% X
Ubc: 5.8926e+005 Vrms [5.124 pu] 158.63°
2 R T4 r* [) L+ F! X. @) F: AUca: 1.2147e+005 Vrms [1.056 pu] -129.49°8 d; @; e/ o7 T9 P9 ]8 H
Ia: 433.21 Arms -97.84°
1 c+ l1 D( M9 \. \1 g% `- KIb: 433.21 Arms 142.16° ' m# W1 E7 Q* G
Ic: 433.21 Arms 22.16° 5 E2 o, F \8 ^8 {+ H6 {
P: 2.6123e+008 W
3 M' I$ y/ M# c9 I h oQ: 4.0079e+008 Vars |
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发表于 2012-4-29 16:06:35
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