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这是PSAT2.1.2说明书中的一个命令行例子:
$ Z, n/ V" `7 C& u- v% initialize PSAT6 B9 o: J, o. Q4 o4 A
initpsat
0 q1 j: p( @+ _' v. y% do not reload data file
' B9 A6 E$ C6 T6 {- U" L6 jclpsat.readfile = 0;
+ s# M3 S# P8 h! r+ k2 ?; J% set data file
# u2 [' `* F6 ?8 ~' n, T( drunpsat('d_006_mdl','data')
+ |, W+ \+ p' s1 q+ v% solve base case power flow
9 S D5 o& g: mrunpsat('pf')" t y; m p- _7 a0 o3 N5 E
voltages = DAE.y(1+Bus.n:2*Bus.n);
- o7 S4 L; w3 y4 @$ o1 v" y% increase base loading by 50%$ |% Y0 [& R1 ?9 X! x
for a = 1:10 X3 }" S8 f3 E a- F! S4 o
PQ.store(:,[4,5]) = (1+a/20)*[0.9, 0.6;1, 0.7;0.9, 0.6];
& _. N5 x0 z! \. x PV.store(:,4) = (1+a/20)*[0.9; 0.6];4 l1 w, q% F" S- }$ g4 f
runpsat('pf')
4 {" T v! X7 x7 [9 m voltages = [voltages, DAE.y(1+Bus.n:2*Bus.n)]; e0 A- T8 n1 v0 n0 ?2 x
end. i, C) q0 `8 I+ a* x8 P" ?* p* ~
2 ?! j8 l/ u3 u5 |% o但运行之后出错:
8 }4 \: a% y( y0 E9 v??? Index exceeds matrix dimensions. x% @8 J# E7 f7 @
, F) z) k8 ]; Q) { ] _$ xError in ==> BUclass.getbus at 37 Q* q9 ]. B6 d
u = a.int(round(idx));. q3 P; e$ t4 Q+ ?
' g$ y( m0 {# F: ^9 _' I, g& Q/ r
Error in ==> LNclass.setup at 15; ?4 B6 P5 c' v) `
[a.fr,a.vfr] = getbus(Bus,a.con(:,1));
" r) |. M% x; I Q& {) \3 u) K# \5 ]9 [4 I
Error in ==> LNclass.restore at 7! {% A* k) ? J# z6 B; G9 S6 T6 I
a = setup(a);9 Z9 A) F3 N3 }* }3 U2 j; P9 j* }
8 m) ^% @ Q4 }! Z' oError in ==> fm_restore at 16
$ S* ~! b1 W1 ULine = restore(Line);
) D2 V( J5 a& ?* y2 p
0 h, D8 `& _5 | b9 dError in ==> runpsat at 259$ |$ }: T0 l& U7 e' M! }9 {2 D
fm_restore
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Error in ==> Example54 at 14
/ s$ {0 b o/ N- ?+ Y& F runpsat('pf')" G, S$ ]# H2 D* l
/ @+ u% p: h5 [2 J/ T& `2 O% ?
这是什么原因?望高手请教!谢谢!
4 j G$ y/ z" r" g$ M% J1 e
5 p9 T; C; b- `) b% m) {如果使用命令行做连续潮流,中间过程的数据都在哪里?
. f; D0 a% G* \& v
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PS:寻找PSAT的研究者,有意加本人QQ:272843822,非诚勿扰! |
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