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各位~~我根据下图的一个系统用MATLAB编写了一段程序,是电流型前推回代法的三相配电系统潮流计算,但是现在结果不是我想要的,不收敛。请各位帮我看一下,提提建议。图片见附件了。还有个问题:已知的线路都是三相对称线路的阻抗值,那么线路的阻抗矩阵中的互阻抗应该如何计算,是什么样的形式,应用怎样的公式?这里我不是很清楚。- %程序名:qiantuihuitui_I_3.m & M( t9 A, p! H! \+ G" u C
- %功能:支路电流前推回推法求解潮流 8 {! k6 R) u# Y# h1 w4 i% w
- clc 0 z) f7 P) H0 @: j
- clear all;
2 z3 Y" l5 e5 }& T3 z# u - %--------------输入网络参数-------------- : ?0 R) z! Z$ u9 ~% E# C
- %1-支路编号,2-首节点,3-尾节点,4-自阻抗,5-尾节点复功率,6-支路性质(1-馈线段支路,2-变压器支路),7-尾节点是否带负荷7 O2 S; \( ~: F, G9 \
- DB=[1 1 2 0.000167+j*0.000208 0.42+j*0.31 1 1) Z* j' \, |) w# F# G( C" j
- 2 2 3 0.000151+j*0.000188 6.15 1 0
, m, i4 U; k7 |; V' v4 j7 X9 Y - 3 2 4 0.000066+j*0.000082 0.38+j*0.29 1 1
; \" K/ `( T f& o+ V- w2 X% {$ y - 4 2 5 0.000249+j*0.000310 0 1 0
: \ F9 |3 t0 p4 Q; e! I8 Y - 5 2 6 0.000172+j*0.000215 0 1 0: m! @2 y u/ a( E
- 6 4 7 0.000156+j*0.000195 6.06 1 0
( t* e: Q4 _8 v: b - 7 4 8 0.000162+j*0.000202 6.04 1 0 2 Z. G5 c! y- o8 D, a
- 8 4 9 0.000345+j*0.000430 0 1 0 ( i7 w1 l6 S8 b3 r( ]$ q: ~. a
- 9 4 10 0.000287+j*0.000358 0 1 0
8 {6 }0 r1 P! D4 z0 V; N0 b - 10 5 11 0.020563+j*0.321594 0 2 0 # f; v3 V4 j2 e, r
- 11 6 12 0.020563+j*0.321594 0 2 0& ^, ]! _# B0 u9 @) H. x
- 12 9 13 0.020563+j*0.321594 0 2 0
, f; Z; F1 k4 O# }: {9 _ - 13 10 14 0.020563+j*0.321594 0 2 0 , r% C0 r* Q. w9 o; Q
- 14 11 15 0.000237+j*0.000408 5.72+j*0.12 1 1 ! O$ W! i3 w0 T& L* N
- 15 12 16 0.000237+j*0.000408 5.76+j*0.09 1 1
7 d9 y8 \+ L O3 k4 S$ H5 ` - 16 13 17 0.000292+j*0.000502 5.86+j*0.11 1 1
! n6 N0 E: ^/ w: s - 17 14 18 0.000274+j*0.000470 5.81+j*0.14 1 1]; ' C) Z6 ]0 J3 }2 C' z
- [n,m]=size(DB); " }4 `2 | ]3 u! i+ r5 V9 ^% H9 k( E
- B=[1 sin(2*pi/3)+j*cos(2*pi/3) sin(4*pi/3)+j*cos(4*pi/3)];
* b3 c( M- C4 n D) | - C=[1.02 1 1.02 1 1 1 1.02 1.02 1 1 1 1 1 1 1 1 1 1];1 B: f$ h) s# r9 H
- U(:,1)=B(1,1)*C';- X4 L' K# v' o6 j
- U(:,2)=B(1,2)*C';, z6 j# \' g f2 C" C4 Y
- U(:,3)=B(1,3)*C';
- d% ~- _. s2 {) r* m6 n - %-------------------求解潮流----------------- & D( B7 L$ a& J/ F
- for k=1:15 $ \3 @% Q9 ]+ X
- % I(:,k)=((DB(:,5).')*(diag(1./U(:,k))))';
" U1 n- ?3 ] H @3 z9 B! N# C! ^ - for i=n:-1:1 ! e, k5 G6 a* a, k& a9 c" Y
- %如果尾节点带恒功率负荷,需计算节点上负荷注入的电流. T5 ?( ?$ \7 G& Y: ~& m
- if DB(i,7)==1+ b9 }* n) q( _$ R! Q% A7 \
- c=DB(i,5)/3;% H V) b: B. P
- d=c/U(i+1,(3*k-2));
- K6 ]4 s2 H( x- M3 l7 V( p - IL(i,3*k-2)=conj(d);" u; i+ D' @* c: Y2 b5 ^0 \
- d=c/U(i+1,3*k-1);* o8 y4 g) Z& s5 n( } @
- IL(i,3*k-1)=conj(d);7 {7 X, t3 i; `& o1 h
- d=c/U(i+1,3*k);
' h. f6 B& l4 Q# Q - IL(i,3*k)=conj(d);
8 K! y( b' H$ D" Z; @- d. o+ E - else" D* r8 u- J# P8 D
- IL(i,3*k-2)=0;( ]9 P! t; R" G7 o
- IL(i,3*k-1)=0;3 b F9 j" N: }1 ^% e. q
- IL(i,3*k)=0;
' S0 w+ n E1 ?8 v - end; n; `4 {8 p# {( o8 h/ H* h* T
- %找出所有与尾节点相连的支路,计算进支电流(末端电流),存IKj) e3 e9 e5 }! m( o1 V
- A=(find(DB(:,2)==(i+1)));
2 a, d# } H/ K i# s; B# F. ~ - if isempty(A)~=12 ~5 m/ n5 n( E8 X
- IKj(i,3*k-2)=IL(i,3*k-2)-sum(IKj(A,3*k-2));
( W. {, s8 y* t, z0 J - IKj(i,3*k-1)=IL(i,3*k-1)-sum(IKj(A,3*k-1));( p$ d7 d- S* v% O4 V2 v, z
- IKj(i,3*k)=IL(i,3*k)-sum(IKj(A,3*k)); P" X9 f( N" Q5 g* T
- else
" Y8 k: [& |8 r, F. ^; d - IKj(i,3*k-2)=IL(i,3*k-2);
( D& r p, ~ [7 s# N' g$ B7 A - IKj(i,3*k-1)=IL(i,3*k-1);
$ P4 A% Z( h: m! O5 J- y - IKj(i,3*k)=IL(i,3*k);/ N+ Y, l* b9 A
- end3 e- O/ ?, @ S
- %计算出支电流(始端电流),存IKi2 R4 Y% Q5 k* m$ K8 K4 u9 U' B
- a=DB(i,2);( S/ l% S4 X- N ?4 }
- b=DB(i,3);
# ?. @' D0 N5 F1 d0 g: }2 j8 K - Yi=1/DB(i,4)*eye(3);+ Y' S0 j' } [- G
- if DB(A,6)==1
! U4 }6 o; \5 }: W; M - F=0.5*Yi*[(U(a,3*k-2)+U(b,3*k-2)) (U(a,3*k-1)+U(b,3*k-1)) (U(a,3*k)+U(b,3*k))]'+[IKj(i,3*k-2) IKj(i,3*k-1) IKj(i,3*k)]';
# a: E7 X4 v; f8 n- T - IKi(i,3*k-2)=F(1,1);
" s+ W+ P: W5 _ - IKi(i,3*k-1)=F(2,1);( Z1 R% g& {8 `* G6 \6 Z4 v8 a$ @( r
- IKi(i,3*k)=F(3,1);7 a' Z( u7 p& x" w' Z' R4 r) S
- else* S+ b1 I" Q7 R0 b
- YT=1/real(DB(i,4))+j*(1/imag(DB(i,4)));- m$ t( p0 L7 ?5 p! _$ ]# o% ^! O( g
- YI=YT*eye(3);
" p7 V% C* M7 `% @ - YII=YT*eye(3);
' Q2 \, w8 `0 Y- K( ]0 v* \ - YIII=-YT*eye(3);
- y2 n5 ^) K& l% b0 T( T; P - D=inv(YIII)*(-[IKj(i,3*k-2) IKj(i,3*k-1) IKj(i,3*k)]'-YII*([U(b,3*k-2) U(b,3*k-1) U(b,3*k)]'));
3 G) ]- j; |- J6 Y- J; P: X% z3 p - U(a,3*k+1)=D(1,1);# y- Y) U O( _' t
- U(a,3*k+2)=D(2,1);& c1 @# R3 r. Z) G
- U(a,3*k+3)=D(3,1);
; I5 {0 g# G0 [9 H# p - E=YI*[U(a,3*k+1) U(a,3*k+2) U(a,3*k+3)]'-YIII*[U(b,3*k-2) U(b,3*k-1) U(b,3*k)]';# t, N, M, [) V" `' e
- IKi(i,3*k-2)=E(1,1);1 L% ]: o' q0 i
- IKi(i,3*k-1)=E(2,1);
) Y W4 m! }# Z+ r- m - IKi(i,3*k)=E(3,1);
/ u) L5 h5 l, _ - end
/ Z1 L' S$ J7 u* v" h4 B) { - end
. P; j4 |7 i/ Y% }0 @% l: _ - %前推电压 5 G, F6 _' W7 |! C: I' w
- for j=2:n& V9 _4 i5 e4 u+ e# g
- U(1,3*k-2)=1.02;
; o/ h5 ^2 u) c" y& k - U(1,3*k-1)=1.02*(sin(2*pi/3)+j*cos(2*pi/3));: ~6 H& k* `" J4 t) P6 d) R- x
- U(1,3*k)=1.02*(sin(4*pi/3)+j*cos(4*pi/3));/ H, }6 c+ |' Z! b; B. p
- a=DB(j-1,2);
1 W4 k4 j5 g, Z- X$ K. k" K - if DB(j-1,6)==1
) z/ }2 d! b" |9 b5 Z1 h) \( o5 O+ q - Yi=1/DB(j-1,4)*eye(3); c( D( b! n7 b* z5 L* l8 R, ~2 d
- G1=[IKi(a,3*k-2) IKi(a,3*k-1) IKi(a,3*k)]';0 x; I) b& m/ r- e& e9 p4 ~
- G=[U(a,3*k-2) U(a,3*k-1) U(a,3*k)]'-DB(j-1,4)*eye(3)*(G1-0.5*Yi*[U(a,3*k-2) U(a,3*k-1) U(a,3*k)]');
. R" X8 T% u$ |3 s, V7 q/ | - U(j,3*k+1)=G(1,1); 2 X* N+ s! G9 G- [% r3 S
- U(j,3*k+2)=G(2,1);* Z3 i+ `) A( `' U! U
- U(j,3*k+3)=G(3,1);
0 P. u& h V% `' D3 F - else2 |, L# ], ~" ]. t
- YT=1/real(DB(i,4))+j*(1/imag(DB(i,4)));, N# j* a$ \8 }/ P9 [# a( F+ N! S
- YI=YT*eye(3);( n# ?+ T$ h/ g1 {
- YII=YT*eye(3);" F+ {8 Q W W) h6 e5 g. p
- YIII=-YT*eye(3);
6 Z9 n. k; q- S! X# T. {/ Y+ t. x2 L - H=inv(YIII)*([IKi(a,3*k-2) IKi(a,3*k-1) IKi(a,3*k)]'-YI*[U(a,3*k+1) U(a,3*k+2) U(a,3*k+3)]');
" h% U. |# o( w, ^9 ~8 b - U(j,3*k+1)=H(1,1);# T% }2 c4 Y* a! |
- U(j,3*k+2)=H(2,1);
5 v( C. I: A! ?# N0 `. E4 t - U(j,3*k+3)=H(3,1);# `4 b# i/ [7 Q& i' x; U
- end 3 W- b# F: |, ?1 N4 Y1 t, G% E
- end
8 o) J) O& p/ p6 U9 R( s1 j6 z5 p7 V - dU1=U(:,3*k+3)-U(:,3*k); " R0 l* g; Z- }- }+ A
- dU2=U(:,3*k+2)-U(:,3*k-1); + q5 y g* p, h; `% F1 |, e/ B
- dU3=U(:,3*k+1)-U(:,3*k-2); + z/ y# G$ \" _) K$ ~" h
- if (max(abs(dU1))<0.001&&max(abs(dU2))<0.001&&max(abs(dU2))<0.001) 7 s! J$ o7 k/ B) N* G
- break;
) _9 g+ }" m0 f - else $ ^5 B' X$ S3 [4 U3 j% J
- k=k+1; 8 i& G6 l' {0 `. N3 J- q
- end
/ ^" K% l9 z4 z' e6 {9 K - end9 F% A* V+ O( ?' b
- U: [: t" ~( o. Q
- IL
! I' g; j6 U! n2 i - IKj
+ i) ^- ]6 f9 J8 R - IKi& R4 L( m+ e% }$ |" t2 K
- k
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