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楼主 |
发表于 2012-9-14 20:40:37
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这个是不加电动机动态数据时动态仿真初始化是的发电机输出,跟潮流计算时结果一致
E/ S/ K# Q6 } BUS# X-- NAME --X BASKV ID ETERM EFD POWER VARS P.F. ANGLE ID IQ; e+ Q5 Q4 D3 {- T+ f4 O+ w
10 BUS1G 13.800 1 1.0000 1.0090 4000.27-1093.27 0.9646 22.44-0.2029 0.8042
" s; z; K! H7 ?, o 11 BUS2G 13.800 1 0.9999 0.9795 478.78 -423.69 0.7489 14.46-0.5060 0.6186
0 z1 ]9 L: ?) H1 l1 {. H0 s% E 12 BUS5G 13.800 1 1.0000 0.9923 2111.22 -423.93 0.9804 11.35-0.0405 0.7166+ z- f; m" z2 Y. m
13 BUS7G 13.800 1 0.9998 1.0394 2420.75 1699.04 0.8185 1.73 0.5897 0.7903
/ L( m* h- Y$ j( o: s7 u 14 BUS9G 13.800 1 0.9999 1.0430 2276.93 1606.56 0.8171 1.87 0.6721 0.8894
) h; m1 `4 v4 k d+ X& x下面是加了电动机动态数据后,动态仿真初始化时的发电机数据,差别太大了
, a! [8 c" h+ {6 o. o" n/ ~1 [' y) uBUS# X-- NAME --X BASKV ID ETERM EFD POWER VARS P.F. ANGLE ID IQ$ L: M4 ?- M t% _5 c! k
10 BUS1G 13.800 1 1.0000 1.0089 3973.13-1109.69 0.9631 22.43-0.2064 0.7988' Y i& o/ K8 u4 y* C* z( p
11 BUS2G 13.800 1 1.0025 0.9683 142.82 -594.74 0.2335 13.19-0.7395 0.1867. z9 w, c+ N# L- ?1 w
12 BUS5G 13.800 1 1.0000 0.9923 2111.22 -423.93 0.9804 11.35-0.0405 0.7166
4 f: w" z6 F0 H, }5 I g 13 BUS7G 13.800 1 1.0052 1.0296 -838.19 476.87-0.8692 0.31 0.1609-0.27637 C& v( G/ M" t
14 BUS9G 13.800 1 1.0028 1.0378 1143.75 1080.04 0.7271 1.28 0.4383 0.4491 |
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