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ATP对二次电弧建模时
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二次电弧模块的程序如下
) Z% U: {3 Y1 M4 v- t# b6 ?8 KMODEL arc23 ]3 Z; C3 y) w. Q( }( l$ B
INPUT U,I, l7 p* Y- @/ X2 G; O
DATA L0,IS,
' j" [% p: M% T5 Z0 K' VVAR GS,TS,US,LS,GS1,TE,TR,trip,R2,UR,H
& j& C' m5 `0 s" i- COUTPUT trip,R2
4 ~/ ~! D, g" {; ?, m- j4 c$ y% u- NINIT
6 O; |6 G0 u' f8 E# w, m+ | W6 d TR:=0: m2 F6 M. B* B; F. ^. H4 d( m
TE:=0
/ U0 Z3 g% q( \. s trip:=1' H& ]9 I' y% |/ w) h0 M
ENDINIT- P' O3 o0 a' z9 o! X( [. V8 F1 W; g
EXEC. T2 C2 g7 ^8 \5 \5 P0 ~: m1 ]1 s
TR:=TR+timestep 6 p6 q/ A M; V: a; W/ h* Y) J6 O5 ]
IF TR<=0.1 THEN0 t3 o+ H0 F# j: M8 u
LS:=L0
/ ?9 w, E. @; m( `2 J& z ELSE
) e9 B* D1 P$ @% R% X3 B$ V1 C; U LS:=10*TR*L04 i! W4 T; P" i2 [, `
ENDIF
, E: V6 d& z$ ^4 z US:=75*IS**(-0.4)2 g% C. k5 {: [0 Y- l, C. `3 ?# B3 W
GS:=ABS(I)/(US*LS)8 S3 {$ Q+ s7 l9 g6 g" `1 U# s
TS:=2.57E-3*(IS**1.4)/LS
8 \/ B0 f& d7 h4 r9 a) k( N GS1:=GS*(1-EXP(-1*TR/TS))
$ I2 K2 z0 I+ Y R2:=1/GS1
" q& ?1 W- F$ i8 h IF ABS(I)<0.01 THEN
& G2 a- J. O+ T( { TE:=TR
& o/ l: D3 ~1 H/ p. p ENDIF. H9 g* Z: d6 U5 b) d7 v) g
IF TR-TE>=0 THEN4 C/ H) R9 j0 f/ e1 g
H:=1
' e4 H4 O0 J3 b& J% J# u ELSE
# J- _4 H1 v3 S ` H:=0
0 o: W( b- w8 n5 B+ ~6 y! H ENDIF! [$ ~/ `. S- s. [( `
UR:=[5+1620*TE/(2.15+IS)]*(TR-TE)*H*LS*1E3
9 ^- t3 a/ p& ~9 D5 E* D IF U<UR THEN + e! S1 i' E) ?4 }& I' }; z
trip:=1$ T: |5 Q: M4 [& _
ENDIF 4 O0 u J* c3 B3 E( l) r0 d8 B! z
ENDEXEC5 J+ _8 v+ o, C: |, D8 W. b1 j
ENDMODEL7 R K$ Y" L% e: T( y' q+ U
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但在运行时出现如下错误:' _" A( `7 `% A$ G( w/ A# G* ~
Execution of the program is interrupted in the MODELS section of the data case.
9 u" m/ o! M( {5 NThe model in use is identified by the following use pathname:& |# |. ?6 Z8 B7 l
MODELS.ARC24 ]! @4 Q& o: }2 X0 @( B
KILL = 682. Attempted explicit division by a zero-valued factor within an expression.; b2 [# Z6 h2 w; S9 w, j
divisor value = 0.00000000E+006 ?7 x I6 T8 C8 r( I
& }6 `" K9 r: J3 ^. k$ I; h请各位大侠帮我i改改,本人急用
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1 Z8 S+ V9 o! n" y) i6 U1 w联系QQ:nan245515165@qq.com。 |
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