ATP对二次电弧建模时% V) o+ {: i8 N8 O+ o3 B
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二次电弧模块的程序如下 0 P6 _: T2 u/ XMODEL arc2 * G, F1 X7 B [! U$ T7 LINPUT U,I 1 E& L+ o6 ^6 H$ f' }DATA L0,IS, 7 B2 ?* A9 s% ?+ d. v8 CVAR GS,TS,US,LS,GS1,TE,TR,trip,R2,UR,H( B* V! |, P: J
OUTPUT trip,R24 l3 `* L" n0 I
INIT 0 p4 b! H! G! @# G9 N6 f TR:=0) T5 Z% A4 V' E4 Y" i
TE:=0& _1 ?. k/ w2 k2 h9 i% {9 d2 S/ f
trip:=1+ G3 M3 T; A" q- f0 I
ENDINIT4 M3 D$ r6 c" j5 r; s
EXEC / f5 X# \3 Z! b6 l TR:=TR+timestep . B: j* i, K3 {/ n# L9 Y `/ m* H6 M K
IF TR<=0.1 THEN # p- E. s" }- q# @ LS:=L0 ' P4 w3 }3 m9 B" A; k1 g0 F. w+ ` ELSE5 O$ D2 |/ b2 N1 V
LS:=10*TR*L0 1 ~' F8 K) H5 n ENDIF % p+ ?( a8 q: i0 o* s US:=75*IS**(-0.4)% H! X) S+ `) ?3 Y, f: p
GS:=ABS(I)/(US*LS)6 W# ^7 h- D% |3 L$ G. T
TS:=2.57E-3*(IS**1.4)/LS4 u$ U# X7 o2 [
GS1:=GS*(1-EXP(-1*TR/TS))0 x% d& t, a3 |
R2:=1/GS1 0 y8 g/ ^7 B1 ?/ \9 }. w, A IF ABS(I)<0.01 THEN 5 V' q2 W, z7 T; ? TE:=TR2 n( i0 `* A0 A) k/ Q7 d6 y
ENDIF* e0 R8 W8 V- n, j) z
IF TR-TE>=0 THEN / J- _/ I& _" ?) S3 a; Q H:=1; F- W0 w& e/ W' k& ~+ y9 }
ELSE + x' ?1 s$ b' Y6 T z H:=0; Q; K6 k0 N' S8 g% v
ENDIF ! e( f' v- @1 m3 J+ ^ UR:=[5+1620*TE/(2.15+IS)]*(TR-TE)*H*LS*1E3 " v# _" Y: ~6 B4 a& d IF U<UR THEN . r; ^/ G. h8 q& t$ X trip:=1% [5 \9 h; T, Q/ q1 u3 e
ENDIF 5 A7 A( Q* e( }# N& m( x, n8 O
ENDEXEC9 ^7 T4 k, G& f# G0 h: S5 R
ENDMODEL( L; Y% {( D' t" F" L$ B2 x1 e
+ e. _; g) U& T8 c6 S0 {7 J; j, k但在运行时出现如下错误:: [6 N) I' f& z/ T4 {
Execution of the program is interrupted in the MODELS section of the data case.7 @$ ]& }9 d* H1 U M
The model in use is identified by the following use pathname: y m5 S' ?8 J5 j# y: x* F; D
MODELS.ARC2) \- O' O5 X$ Z( V; K+ P, o% b
KILL = 682. Attempted explicit division by a zero-valued factor within an expression.- F; Z: l1 K# k3 w6 B
divisor value = 0.00000000E+00 " h0 x* y' B' o+ N2 w- s7 f: a, h/ R. m L2 e/ y3 ~& Q8 N
请各位大侠帮我i改改,本人急用 4 S% u, H# b4 B+ k, W, _4 c( O/ U# F! U- O1 y" s R& M
联系QQ:nan245515165@qq.com。