(1996) Reliability Evaluation of Power Systems一书中介绍的可靠性评估PJM方法有下面几句话: 7 l6 F% l- P5 M8 v/ K6 m1) 8 t3 V4 n4 `+ ZIt is necessary in a practical system to first define an acceptable risk level in order to determine the maximum demand that a particular committed system can meet. 2 n$ J3 a8 F* k# S2)Consider, for example, that a risk of 0.001 is acceptable. If additional generation can be made available in System A within 1 hour, the required spinning reserve is only 30 MW and a demand of 170 MW can be supplied. 8 u: N q* c; a3) In practice an operator would use the PJM risk assessment method by adding, and therefore committing, one unit at a time from a merit order table until the unit commitment risk given by the generation model became equal to or less than the acceptable value for the demand level expected.% F/ y5 u) S: ~8 Y O 1 ~1 ~9 B1 A( [原文2句的意思:假设系统允许的风险水平为0.1%。对系统A,若在1h内可以获得额外发电容量的支持,那么,A系统的旋备需求为30MW,可带负荷170MW。 . } U$ T b) ]% `1 C4 K2 d$ V3 L- w9 Z9 _; d6 L+ l/ q4 P
我的疑问: ( B6 i1 g, Y+ I$ `& N3 E从表5.2可见,A系统停运容量大于30的累积概率=运行容量小于170的累积概率=0.0915%,即运行容量大于170概率99.9%,此情形下系统可以带负荷170MW,若还可以获得额外30MW旋备,系统可带负荷就应该是200MW。 2 H# ]. J2 ? H. f$ n e, C为何原文讲“170 MW can be supplied”?0 g9 {8 Z: J! C
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