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发表于 2011-9-19 10:05:40
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本帖最后由 wangdc 于 2011-9-19 10:13 编辑 3 J: T& c9 @" j; C; S
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回复 5# zhaoxiangen " m5 s1 f7 U8 ]) y
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9 [; ?" c8 b4 C; F% u' O 那个你勾选的话,在计算结果LIS文件中就会列出最严重的值,不勾选就不列出;但是否勾选对PL14没有影响,电路图上只要有电压电流测量点,PL14都会有画图的,看一下我的结果7 @& `9 u* x* W8 u) e( w
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Statistical distribution of peak energy for branch "MOV3LA" to "X0017A". Base energy for per unit output = 2.50000000E+07
2 N) l8 M$ m- L% a6 Y6 A( u Interval energy energy in Frequency Cumulative Per cent 1 ?1 A, v6 G& [0 [3 {" B
number in per unit physical units (density) frequency .GE. current value 4 @% h1 ~9 p& _6 x
21 1.0500000 2.62500000E+07 0 0 100.000000 " ?3 ?9 ~) w s' I( d
22 1.1000000 2.75000000E+07 74 74 26.000000
# {7 s0 Q8 o( j4 V+ V D 23 1.1500000 2.87500000E+07 19 93 7.000000 5 @7 B; ?5 m0 I$ a7 n# s
24 1.2000000 3.00000000E+07 7 100 .000000
) _, Q8 ~3 C/ o8 }Summary of preceding table follows: Grouped data Ungrouped data
- s& F0 _; O: A) ?* ] Mean = 1.09150000E+00 1.09587467E+00 0 q( z) m0 h9 ~* ]" L# O4 Q
Variance = 9.11868687E-04 6.64562405E-04
6 n9 C% c' F# @# G* h Standard deviation = 3.01971636E-02 2.57791079E-02 6 l4 W* H& `0 a0 W Y$ q
0 V) P4 |$ R0 S14 ) -------------------------------------------------------------------------------------------------------------------------------
. D; M; b$ f, z5 P9 P( t6 rStatistical distribution of peak energy for branch "MOV3LB" to "X0017B". Base energy for per unit output = 2.50000000E+07
0 t4 z7 h2 d4 h( V, i# u# d2 ~ Interval energy energy in Frequency Cumulative Per cent
+ L: |5 K$ F' r* f number in per unit physical units (density) frequency .GE. current value
) b* \) U8 d/ F9 J: j3 v% ]/ _ 21 1.0500000 2.62500000E+07 0 0 100.000000 4 g, |/ n5 q9 F
22 1.1000000 2.75000000E+07 83 83 17.000000 " H b; v6 C, L! P
23 1.1500000 2.87500000E+07 11 94 6.000000 7 ~7 U- k7 {" }- b: [0 N
24 1.2000000 3.00000000E+07 6 100 .000000 6 ?6 O: y& z8 B0 p' }7 W0 h2 c
Summary of preceding table follows: Grouped data Ungrouped data q' J) x! \- H6 @; ?' ] A
Mean = 1.08650000E+00 1.08919324E+00
3 Z. S9 n8 v G0 A Variance = 7.50252525E-04 6.91174224E-04
$ u1 ?1 ]+ R( p0 ^9 d+ C) v Standard deviation = 2.73907379E-02 2.62901925E-02
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! m- P. J! G7 q# S3 IStatistical distribution of peak energy for branch "MOV3LC" to "X0017C". Base energy for per unit output = 2.50000000E+07 ( R R$ q: {8 K& U$ ?
Interval energy energy in Frequency Cumulative Per cent
# C* v- _+ p+ Z# C* O* k number in per unit physical units (density) frequency .GE. current value
, i0 E8 z. l! { 48 2.4000000 6.00000000E+07 0 0 100.000000 * V. z8 a6 E- R& n
49 2.4500000 6.12500000E+07 21 21 79.000000
. v$ S* j( A* S" P$ n6 m6 B3 E$ e: ~ 50 2.5000000 6.25000000E+07 47 68 32.000000
6 W! n3 q3 }% ~! n. T4 Y8 u 51 2.5500000 6.37500000E+07 32 100 .000000 & n+ @8 @+ \ ]
Summary of preceding table follows: Grouped data Ungrouped data z7 l k2 c; j9 P8 e
Mean = 2.48050000E+00 2.47717072E+00
3 i# [: r" N2 r$ [% C* { Variance = 1.30782828E-03 9.07356635E-04
, g5 t& V' T& N" z0 V) I, u# V* j Standard deviation = 3.61639086E-02 3.01223610E-02
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SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY
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A distribution of peak values among all output branches of the last data card that have the same base value follows. This ) j( m& n5 [/ _5 x4 L- P
statistical distribution is for the maximum of the peaks at all of these output branches having base energy = 2.50000000E+07
' g: o) n- c% G X6 q6 j Interval energy energy in Frequency Cumulative Per cent
$ ?; x2 G2 O: p; B6 L8 w: q number in per unit physical units (density) frequency .GE. current value
/ _# C N3 {% s+ b$ h" n9 c 48 2.4000000 6.00000000E+07 0 0 100.000000 ) \1 e) X. H! A; g
49 2.4500000 6.12500000E+07 21 21 79.000000
: C- d5 J; B; N3 W3 T2 E 50 2.5000000 6.25000000E+07 47 68 32.000000 3 v |8 @% d! e. N8 e/ _ b
51 2.5500000 6.37500000E+07 32 100 .000000 % a; l, z* K( |+ l5 U9 J- z
Summary of preceding table follows: Grouped data Ungrouped data - }' m# E3 Z( z% Q& h
Mean = 2.48050000E+00 2.47717072E+00
6 {) D3 U9 K& l, G$ X Variance = 1.30782828E-03 9.07356635E-04
* A6 l* ~4 U2 @: v7 ^! P: ?" ?$ b" z Standard deviation = 3.61639086E-02 3.01223610E-02 $ x/ y* ?: M! o
Blank card ends statistical tabulation requests. |BLANK STATISTICS
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Sample curve symbols : "A", "B", and "C"
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- b* \: m* b: @4 K) z2 w0 F, q% u( p Common curve symbol : "X" |
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