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发表于 2011-9-19 10:05:40
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本帖最后由 wangdc 于 2011-9-19 10:13 编辑 ! [1 [! V8 } A | f. _" T8 q* z
* p- J+ k. V- a6 T6 {& d回复 5# zhaoxiangen , I* ] i; U L% \
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9 e6 k( ]$ r. y1 k 那个你勾选的话,在计算结果LIS文件中就会列出最严重的值,不勾选就不列出;但是否勾选对PL14没有影响,电路图上只要有电压电流测量点,PL14都会有画图的,看一下我的结果 Q5 h' A$ b0 F3 N& a6 M
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- ^8 [9 Y) }* Q0 |9 H9 t$ q+ GStatistical distribution of peak energy for branch "MOV3LA" to "X0017A". Base energy for per unit output = 2.50000000E+07
0 T9 X9 K# a! S Interval energy energy in Frequency Cumulative Per cent 4 W8 Q5 P" j: C. c9 V9 g2 H/ S
number in per unit physical units (density) frequency .GE. current value
( r1 N, Y# v9 \! k- `% T 21 1.0500000 2.62500000E+07 0 0 100.000000
" W! j! ?0 O# s6 L 22 1.1000000 2.75000000E+07 74 74 26.000000 3 z5 t8 G7 X' P0 V
23 1.1500000 2.87500000E+07 19 93 7.000000 3 K* U5 r$ ^1 h" B9 Z
24 1.2000000 3.00000000E+07 7 100 .000000
; W( t( t! K! }! O, Z; qSummary of preceding table follows: Grouped data Ungrouped data
p2 e6 w; Z4 I5 O4 K Mean = 1.09150000E+00 1.09587467E+00
& b/ g+ w# Z$ X2 x Variance = 9.11868687E-04 6.64562405E-04
: ?! I5 P) V' W- ]) q. J Standard deviation = 3.01971636E-02 2.57791079E-02 / g3 U p7 j) c, t) V" z
6 w4 ?6 x: Y5 j) K; l. Q' W8 y14 ) -------------------------------------------------------------------------------------------------------------------------------) b: Y! `9 |8 Y( z
Statistical distribution of peak energy for branch "MOV3LB" to "X0017B". Base energy for per unit output = 2.50000000E+07
7 V' {; o; A( d9 f0 ] Interval energy energy in Frequency Cumulative Per cent 0 Z" }$ K9 _- \) j
number in per unit physical units (density) frequency .GE. current value # A$ t9 G3 J1 o4 m0 M- H. j) [
21 1.0500000 2.62500000E+07 0 0 100.000000 . J! I' D: o1 m
22 1.1000000 2.75000000E+07 83 83 17.000000 / _* G! a" j1 {' A
23 1.1500000 2.87500000E+07 11 94 6.000000
1 n. S6 H7 |7 k8 ~+ u# e$ t; C 24 1.2000000 3.00000000E+07 6 100 .000000
- d9 V0 h5 z% i$ s$ o( s& p3 q1 ZSummary of preceding table follows: Grouped data Ungrouped data
6 R' x) \ d7 B; G X2 p8 W/ g Mean = 1.08650000E+00 1.08919324E+00
1 a4 p; r C, d* R$ b Variance = 7.50252525E-04 6.91174224E-04 , |/ Y( c3 n: x. _0 c3 ^
Standard deviation = 2.73907379E-02 2.62901925E-02
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Statistical distribution of peak energy for branch "MOV3LC" to "X0017C". Base energy for per unit output = 2.50000000E+07 1 U6 X( P O5 `; c$ w8 V1 i* L1 {3 v
Interval energy energy in Frequency Cumulative Per cent 0 ^. R# T9 K2 ~% U! S2 u
number in per unit physical units (density) frequency .GE. current value ) F; X& b: n8 o1 X- `2 J
48 2.4000000 6.00000000E+07 0 0 100.000000 M3 Z& X, ?+ r
49 2.4500000 6.12500000E+07 21 21 79.000000 0 s- D) Z- o' R w7 s" N+ e8 M7 J+ L
50 2.5000000 6.25000000E+07 47 68 32.000000 / g( r, d4 o! R) |, A3 F
51 2.5500000 6.37500000E+07 32 100 .000000
: @: J3 Q' d; Q9 B) P+ `7 GSummary of preceding table follows: Grouped data Ungrouped data " B a! {1 \. Y8 H
Mean = 2.48050000E+00 2.47717072E+00 * P6 \' c6 u5 v+ b
Variance = 1.30782828E-03 9.07356635E-04
( f l. `. x+ e% u: y6 h Standard deviation = 3.61639086E-02 3.01223610E-02 - r! u+ m, a0 e3 {; v: C6 E
& O% h' _$ j* Y; D g16 ) -------------------------------------------------------------------------------------------------------------------------------
& E- a( K& t/ H SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY
/ ^: s+ ?. F) ^7 j8 _) r8 e16 ) -------------------------------------------------------------------------------------------------------------------------------
8 l) l3 \7 W" z$ H3 KA distribution of peak values among all output branches of the last data card that have the same base value follows. This & i: B5 b4 {) L. ?, @1 I' ^
statistical distribution is for the maximum of the peaks at all of these output branches having base energy = 2.50000000E+07 * n4 z2 u% l# g, y) W
Interval energy energy in Frequency Cumulative Per cent % e! i, P5 `- e1 k/ y6 E7 i
number in per unit physical units (density) frequency .GE. current value
% D: x, u+ f. y9 ? 48 2.4000000 6.00000000E+07 0 0 100.000000 # [1 S( ?& e, \; M; |" ~# U+ V
49 2.4500000 6.12500000E+07 21 21 79.000000 7 V, v; L) V# |0 S$ |: W
50 2.5000000 6.25000000E+07 47 68 32.000000 K9 X! n. e7 i
51 2.5500000 6.37500000E+07 32 100 .000000 7 O+ w! [% M$ X. I2 K R) j
Summary of preceding table follows: Grouped data Ungrouped data
* ~$ i1 U2 S1 u1 t Mean = 2.48050000E+00 2.47717072E+00 : ~6 s6 M% j, _. i& F/ h2 v
Variance = 1.30782828E-03 9.07356635E-04 % a* M4 H6 n( T( a
Standard deviation = 3.61639086E-02 3.01223610E-02
; S8 T2 W S X- D! o c0 IBlank card ends statistical tabulation requests. |BLANK STATISTICS: h4 u' Z+ K' k. a" Q
) t0 S. n! P* x6 H1 C+ H% ~ Sample curve symbols : "A", "B", and "C"
/ J- G% e- O4 w1 Z. A Theoretical curve symbol : "*"
7 q* h) ^& K V& u9 g Common curve symbol : "X" |
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