设置了两个mov ,出现以下问题。 6 r* y2 _/ p; N* B! F1 cYou lose, fella. The EMTP logic has detected an error condition, and is now going to terminate program execution. The following# z3 D3 W- h0 y5 p6 b7 q, D
( Y( p! @, w) C1 @% d% C9 K9 i
message summarizes the circumstances leading to this situation. Where an otherwise-unidentified data card is referred to, or where3 v @3 g2 f6 A
the "last" card is mentioned, it is the most recently read card of the input data that is meant. The 80-column image of this card, x: d H: f2 |* V K# k4 E+ J
is generally the last one printed out prior to this termination message. But possibly this last-read card has not yet been + Q: ?# M& y2 f' a! }displayed, so a copy follows:# ?* R" l2 }, Z& ]; {5 c. ]
" " , f% ?* j& c0 b8 X' C! w; Y KILL code number Overlay number Nearby statement number : y$ X5 |$ O2 s0 H 209 18 3501 - @, n/ Q1 f9 _KILL = 209. ZnO solution by Newton`s method of 2 coupled arresters has failed due to singularity of the Jacobian matrix. This 0 ^: m7 L5 P7 y# M5 X+ l, H2 Sis measured by tolerance EPSILN, which is defined by the floating-point miscellaneous data card. The iteration count is 2, and+ f7 }( ^7 [, Q+ I
the coupled group of arresters can be identified from the knowledge that the first (in order of input) connects bus "XX0035" with* V y6 a7 v( h$ @& W" L3 H8 K- s# U/ \- X
bus "XX0010". The simulation time is T = 1.00000000E-06. * w% Q2 d9 M& U9 F' ]- ? 5 T2 b& ]0 M- p( l( K; {