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这个错误是什么原因

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发表于 2009-11-20 12:27:14 | 显示全部楼层 |阅读模式

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------------------------------------------------------------------------------------------------------------------------------------/ C# E. K% U- ]$ Z- W% l
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/9 Z+ \- ^; g* U3 n
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/- z( r& D, j) B7 s1 q  \. E
------------------------------------------------------------------------------------------------------------------------------------% i2 l8 z  C. G' `- `0 a
You lose, fella.   The EMTP logic has detected an error condition, and is now going to terminate program execution.  The following
1 X$ _; ]2 f4 s0 Lmessage summarizes the circumstances leading to this situation.  Where an otherwise-unidentified data card is referred to, or where
+ [. |0 P7 D5 L7 h8 tthe "last" card is mentioned, it is the most recently read card of the input data that is meant.  The 80-column image of this card& J1 D, @) z6 g' T6 x
is generally the last one printed out prior to this termination message.  But possibly this last-read card has not yet been5 G/ x4 M- U% P" M. D" f( {# V* }
displayed, so a copy follows:# G& }5 j+ j1 W
"             0.0             0.0                                                "
% Y/ @, u, r3 G4 b              KILL code number                Overlay number               Nearby statement number
7 `: u! B2 ~' L8 [" P) q0 f- n$ U                          5                          3                                181
& _$ L4 J/ V' v! C7 aKILL = 5.  The user has been defining the characteristic of a nonlinear or a pseudo-nonlinear element.  Each point of the$ c) m, n" S2 \6 F
piecewise-linear curve is defined by a pair of data values, which must be in order, moving ever to the right and upward in the x-y
6 E% J7 l3 D- e3 B5 nplane.  But the just-inputted characteristic is not monotone increasing in this way as the EMTP requires, since a decrease in one of5 M9 P. |7 u6 C+ c
the two coordinate points has been detected on the last-read data card.) a; k5 Z9 J- L" F' l
------------------------------------------------------------------------------------------------------------------------------------3 a) }& c4 }7 w3 S, B2 B
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
+ M& `* L, {- G! ~* E( `ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/  H" E6 }1 P3 i  }
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发表于 2009-12-22 18:06:12 | 显示全部楼层
我也遇见这样的问题,初学者,# T+ {9 U% j# g$ U. {' c
那位高手解释一下吧
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