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[讨论] 这个错误是什么原因

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发表于 2009-11-20 12:27:14 | 显示全部楼层 |阅读模式

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------------------------------------------------------------------------------------------------------------------------------------9 L) Q6 E* ~7 U! D# B* `% G0 G
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
/ z) z7 _% V" u/ iERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/+ i5 F  l2 @% P2 \7 s4 a" I* ^
------------------------------------------------------------------------------------------------------------------------------------
; \) K. c. ~6 P* C; NYou lose, fella.   The EMTP logic has detected an error condition, and is now going to terminate program execution.  The following2 |( V+ y( s! d9 i( t: Y" d: O& g
message summarizes the circumstances leading to this situation.  Where an otherwise-unidentified data card is referred to, or where
9 |( `# {- p/ i4 \" Gthe "last" card is mentioned, it is the most recently read card of the input data that is meant.  The 80-column image of this card# n6 }; B' F+ i  T
is generally the last one printed out prior to this termination message.  But possibly this last-read card has not yet been) @. X4 V0 _# j7 }% o0 k/ P+ Y$ i
displayed, so a copy follows:
9 ]6 ^5 j( a7 V7 E% w, `"             0.0             0.0                                                ") d2 M/ k" J) ]' w
              KILL code number                Overlay number               Nearby statement number/ E7 R' ^4 y$ L, c. f1 X6 |
                          5                          3                                1811 e  ]$ p+ T; U, P0 k
KILL = 5.  The user has been defining the characteristic of a nonlinear or a pseudo-nonlinear element.  Each point of the
" y$ u$ a2 r7 w6 Wpiecewise-linear curve is defined by a pair of data values, which must be in order, moving ever to the right and upward in the x-y
) K# K7 B" @( v/ [plane.  But the just-inputted characteristic is not monotone increasing in this way as the EMTP requires, since a decrease in one of
8 ~/ @- J# f/ n! ]the two coordinate points has been detected on the last-read data card.- ]* j  M0 y) k. V3 X4 @# f$ P0 n
------------------------------------------------------------------------------------------------------------------------------------
; k5 t3 F. h" D  |6 b# W7 NERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
1 _& `' R; \  t3 e/ q6 fERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
8 `" X" Z* o6 L9 v# l------------------------------------------------------------------------------------------------------------------------------------
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发表于 2009-12-22 18:06:12 | 显示全部楼层
我也遇见这样的问题,初学者,
/ ~) e3 Q0 N& t. T  J2 a' ^那位高手解释一下吧
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