TA的每日心情 | 开心 2020-10-6 21:19 |
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签到天数: 20 天 连续签到: 1 天 [LV.4]偶尔看看III 累计签到:20 天 连续签到:1 天
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发表于 2009-8-19 11:04:39
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另外,有没有高人解释下,P=37.42怎么出来的,换成单相功率为12.475 ?! C7 a/ A5 T
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按照Fixload的公式,P=P0*(V/V0)^NP*(1+Kpf*dF)
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式中
) y0 u8 p1 ]+ G9 d5 t6 F dP/dV : Voltage index for real power
8 ?' n" j; W1 v7 o& }3 O7 { dP/dF : Frequency index for real power
/ y0 A$ X/ {$ ?3 Z3 W: A" y! V1 Dlz设置的都为零。
+ L& `+ a: D% b2 H) ? 再按照后面的解释:If used in a 3-phase, single-line mode, the RLC values of all phases are changed when the voltage of any one of the phases goes through a zero crossing. The load remains in constant impedance form until 10 cycles of the fundamental frequency is passed. The non-linear characteristic is effective within ±20% of the rated RMS voltage and ±DF% of the rated frequency (DF is defined as minimum of 10, 90/KPF and 90/KQF). Outside this range, the load reverts to constant impedance. 9 g9 M6 |% D/ c; R
& z! n6 j7 w: U* V Y$ P% |) V如果电压为额定电压的20%之内表现非线性属性,超过这个范围,这个负载变为常阻抗。那么现在电压为额定电压的1/sqrt(3)=57%,若按照常阻抗来算的话功率应该和电压平方成正比,当电压减小根号3倍,功率应减小3倍???? |
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