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发表于 2009-8-19 11:04:39
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另外,有没有高人解释下,P=37.42怎么出来的,换成单相功率为12.474 \. ]7 h' S4 e
$ s0 m. N, ]3 e' y8 ^按照Fixload的公式,P=P0*(V/V0)^NP*(1+Kpf*dF)9 ^8 M F# H# }. l1 B) ~
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! f1 ]' r- }& ?: T8 K dP/dV : Voltage index for real power! I ]; d3 P6 v3 O3 w+ Q# w. D' j& Z
dP/dF : Frequency index for real power
. Z8 q. H$ N8 jlz设置的都为零。1 K7 A2 u: r# u7 q2 d
再按照后面的解释:If used in a 3-phase, single-line mode, the RLC values of all phases are changed when the voltage of any one of the phases goes through a zero crossing. The load remains in constant impedance form until 10 cycles of the fundamental frequency is passed. The non-linear characteristic is effective within ±20% of the rated RMS voltage and ±DF% of the rated frequency (DF is defined as minimum of 10, 90/KPF and 90/KQF). Outside this range, the load reverts to constant impedance. , C2 Y7 h# L/ b9 `& Q
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如果电压为额定电压的20%之内表现非线性属性,超过这个范围,这个负载变为常阻抗。那么现在电压为额定电压的1/sqrt(3)=57%,若按照常阻抗来算的话功率应该和电压平方成正比,当电压减小根号3倍,功率应减小3倍???? |
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