TA的每日心情 | 郁闷 2021-5-6 11:24 |
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发表于 2009-2-12 14:13:01
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非常感谢,问题已经解决了,能够使用。% c5 N" _5 r C! H6 Z/ ?; H
8 L1 U( `( x* A, X7 ^, f! Trunpf('case9')
) E# s% }2 d ?2 m d9 y7 |. t) G6 y4 L' j# B+ `3 D0 z
Newton's method power flow converged in 4 iterations.
% v8 D# f- X5 t6 z( A( k" M2 a0 X4 s
Converged in 0.72 seconds2 `, {5 D' ~$ A- f9 ~
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) l/ o* q8 f# `, f$ N, e8 j| System Summary |
8 {1 ^8 I5 M- z8 |================================================================================/ B, F* b: ]. C. ]3 L
& p/ O. Z$ f, w! V7 z$ o6 t
How many? How much? P (MW) Q (MVAr)$ {4 m6 ~0 `3 h2 a0 ?' N0 r
--------------------- ------------------- ------------- -----------------
2 V, ?! o; h0 SBuses 9 Total Gen Capacity 820.0 -900.0 to 900.0
/ {# }+ e: f/ {Generators 3 On-line Capacity 820.0 -900.0 to 900.09 u1 e! j0 P8 [" d
Committed Gens 3 Generation (actual) 320.0 34.9+ C" G2 Z0 n, m) Q2 A7 E1 |
Loads 3 Load 315.0 115.0
- A/ U" P( w- }% O" O% u Fixed 3 Fixed 315.0 115.0
: V& n# J8 K: t4 L8 o. O Dispatchable 0 Dispatchable -0.0 of -0.0 -0.0
; `: Q6 M# L! N+ k. S% F$ gShunts 0 Shunt (inj) -0.0 0.0
. s( F; S. m0 y0 KBranches 9 Losses (I^2 * Z) 4.95 51.31
- u& x8 ^8 g9 f5 ?+ s; Y# pTransformers 0 Branch Charging (inj) - 131.4. z5 X5 M& ~2 `3 b* U
Inter-ties 0 Total Inter-tie Flow 0.0 0.0
3 p2 ^ Z1 }/ ]9 ~+ I# s, rAreas 1
7 |' d% Z i+ B' S+ B0 {+ `
; |, ?( F" v" U2 l Minimum Maximum
! A% J& m! B+ @! U$ L ------------------------- --------------------------------1 {, j5 m1 F7 ~& `# R
Voltage Magnitude 0.958 p.u. @ bus 9 1.003 p.u. @ bus 6 8 t! G: h6 t' W" A R$ t/ B
Voltage Angle -4.35 deg @ bus 9 9.67 deg @ bus 2 5 ~2 r" z1 G0 s% y, {3 p
P Losses (I^2*R) - 2.46 MW @ line 8-9$ h' F9 w- x1 Z. }1 m1 I
Q Losses (I^2*X) - 16.74 MVAr @ line 8-2
: B! B0 B1 ^) @5 M5 \, o" O
8 C1 |# l2 R" `- U================================================================================. t( v. C# K$ ?3 F- d: d$ r
| Bus Data |
4 R* n' F" j1 f; `' K9 k0 Q( f================================================================================
h' H) u" z" l' U% o Bus Voltage Generation Load
% Z4 r7 A6 }3 U5 p& d' j # Mag(pu) Ang(deg) P (MW) Q (MVAr) P (MW) Q (MVAr)
+ ^7 H9 p, M' p" `----- ------- -------- -------- -------- -------- --------
$ f6 t! d. M: M: D( D# o 1 1.000 0.000 71.95 24.07 - - 0 T g" P; \; a/ v8 D* z
2 1.000 9.669 163.00 14.46 - -
( y, r7 y% N) d$ V: c3 f9 e2 d+ L 3 1.000 4.771 85.00 -3.65 - - * |5 Q6 c) p- v( q
4 0.987 -2.407 - - - -
# _: |/ B; _- p7 A 5 0.975 -4.017 - - 90.00 30.00 - |6 ~# |% K0 ^, @
6 1.003 1.926 - - - - ( m% O3 B) b7 k0 E# t$ V
7 0.986 0.622 - - 100.00 35.00 3 I0 c/ h, ^) ~6 X$ s7 N6 G
8 0.996 3.799 - - - -
: K2 N( f& k9 ^& P h 9 0.958 -4.350 - - 125.00 50.00
1 _; X* Z8 X0 d. u& d7 P) v -------- -------- -------- --------
3 T! I! b( H" @2 Q Total: 319.95 34.88 315.00 115.00 `/ `8 ]$ X' T# \
/ z6 Y& \) L7 A================================================================================/ C+ ? ]; K* D) z# U
| Branch Data |
. r2 X/ d# Y( ?) d================================================================================" n$ F& _$ r& y" k: m$ s7 o: D; K
Brnch From To From Bus Injection To Bus Injection Loss (I^2 * Z)
: l, o$ K6 b; Y! e # Bus Bus P (MW) Q (MVAr) P (MW) Q (MVAr) P (MW) Q (MVAr)+ L$ _2 L8 a& Q
----- ----- ----- -------- -------- -------- -------- -------- --------
\4 ]1 C ~8 O2 D/ a4 J. B1 R1 S 1 1 4 71.95 24.07 -71.95 -20.75 -0.000 3.32 K' O7 f8 {% _* r. q
2 4 5 30.73 -0.59 -30.55 -13.69 0.174 0.94
; b! P2 k( h8 T) }& H 3 5 6 -59.45 -16.31 60.89 -12.43 1.449 6.315 q4 a4 D& {+ v5 _% B9 G3 j
4 3 6 85.00 -3.65 -85.00 7.89 -0.000 4.246 ]" Z& o0 a* {) G) d
5 6 7 24.11 4.54 -24.01 -24.40 0.095 0.81! w* h) z( z4 p0 n$ S. \) V
6 7 8 -75.99 -10.60 76.50 0.26 0.506 4.292 |' {) ] ~0 n- Q+ a- g4 y
7 8 2 -163.00 2.28 163.00 14.46 -0.000 16.74
' J! L2 |# I' C* K3 q1 n' f 8 8 9 86.50 -2.53 -84.04 -14.28 2.465 12.40. D3 [5 i$ E( D9 C9 o( @7 w
9 9 4 -40.96 -35.72 41.23 21.34 0.266 2.26. k( Q1 d1 v8 U
-------- --------8 G+ C% |- u/ Y. b
Total: 4.955 51.31 |
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