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for m=1:Npq- n2 E. Y! H0 S
for n=1:Nbus, v! z* V: @$ i; C+ A+ t4 p- ?" Q% m
pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率
1 @6 w/ L6 F6 b. j( t" O& B& z4 `( C qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率
- N# I$ Z, x7 Q end) ?) P" `( |- Z+ }( ^
Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量3 m0 u; Y2 g: `) q8 A1 @; m [
Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量& J4 U% F- ]6 f; X$ W1 m" l4 g( u
end %[Unbalance]是节点不平衡量矩阵! S6 m% m$ s u/ Y, K1 O" V
* A0 v, a) Y; w1 ^$ \
for m=1:Npq) I9 S) u0 |0 @' j3 @
for n=1:Nbus( u2 X. _. `$ ^# c1 y/ v$ j8 k
h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));9 d1 N g6 C/ b% j7 n5 P
n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));9 h6 g# |5 r; G, v# Z c3 ?
j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
5 I+ ^2 I T2 Q- T l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));' m0 w- _* Z9 B% f
end
( q3 _7 P# w% X" n7 |7 v H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));/ v9 g4 ^+ d6 x3 m3 r0 D) ?
N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);. |& b/ |8 Q& C* b0 i: H
J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));
8 U* M8 v2 B$ a/ p L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);
7 l& C4 _5 V, g" a Jacobi(2*m-1,2*m-1)=H(m,m);
' h% @. G0 W1 s7 {' y Jacobi(2*m-1,2*m )=N(m,m);5 H& z; @) U9 g+ T1 y, [
Jacobi(2*m ,2*m-1)=J(m,m);8 F' ?4 b7 U2 n, G
Jacobi(2*m ,2*m )=L(m,m);
+ m8 F9 c8 ?8 M end %计算m=n情况下的Jacobi矩阵中的子矩阵元素: [% g" }" X) l' O# H
+ M T' w% u* ?/ ?+ c for m=1:Npq
$ }: C @, M3 ^7 y/ Q$ { for n=1:Npq* i" x( \' k5 a1 `4 f
if m==n
) N/ @0 {+ \7 j; ?# d else' Z3 C( z' t- \4 ^2 H( F
H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));; l! c/ |. F$ c! i+ _ ?
J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));/ C/ {0 a+ g6 [4 y4 e
N(m,n)=-J(m,n);- P/ ?6 p/ t( e5 i' p) p
L(m,n)= H(m,n);
+ g, u8 J: `, o& d) ~" r Jacobi(2*m-1,2*n-1)=H(m,n);
% ?- d# g$ o" l' n3 v Jacobi(2*m-1,2*n )=N(m,n);$ N2 `( V/ m* q5 r! z
Jacobi(2*m ,2*n-1)=J(m,n);7 F% X4 x7 p3 U
Jacobi(2*m ,2*n )=L(m,n);) f9 n! X7 S9 H, K+ u& o8 N7 z
end
! Q0 r! U7 ?2 y' ^0 w1 h end
$ V9 p* r' D+ F7 q end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素
! S) ^6 l" X6 a+ [+ }/ i s
9 M5 V, o. I% {+ H6 c( ?# X问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢$ }4 y5 L$ |% z4 D% \
2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?
% B/ x9 j! t: n( T觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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