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for m=1:Npq9 n6 T: U& K# T2 T3 [
for n=1:Nbus3 ~5 j0 J. \% F4 ?. }6 Y3 w
pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率* G6 x( `* `) L% H9 k4 s
qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率: F! e$ a2 v5 R2 ?
end) T3 ?) h' M, E/ I) c3 X7 ]2 P# h
Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量
" U5 Y% `% I" W8 k Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量8 Y: F8 E; ~; i
end %[Unbalance]是节点不平衡量矩阵
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9 y5 S2 d, \) v( s, P9 | for m=1:Npq" C2 [& w5 ^" a; [0 t9 f
for n=1:Nbus
! X" B2 Y9 F# l3 m, e% F' ^5 H* q W h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));% R+ f. H, o, N `& {+ t! |
n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));$ R* x, D) B/ s+ ~6 G+ A( c+ D1 w
j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
! B& k Y+ l* V' K+ N l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
4 y" o7 l6 g. r end
5 d7 ^% ~7 T# U8 r4 L5 L H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));4 ~3 j7 s- l! G5 o
N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);
# v& K8 r6 H8 r J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));; l' s* m% x8 i1 T$ x
L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);" K/ M- J& t @! d& l+ u
Jacobi(2*m-1,2*m-1)=H(m,m);5 _. I1 s2 n' h3 f; z
Jacobi(2*m-1,2*m )=N(m,m);9 E3 p0 s, u1 l$ n/ L6 R% f
Jacobi(2*m ,2*m-1)=J(m,m);
2 H( W/ n0 v2 u( E Jacobi(2*m ,2*m )=L(m,m);
8 H% Q! f& x% [! V7 ^, r end %计算m=n情况下的Jacobi矩阵中的子矩阵元素
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+ x9 M$ U6 j* f& N5 d for m=1:Npq4 b4 m( K4 }2 J1 z
for n=1:Npq
2 w8 {5 E. h3 S3 B2 y if m==n% @ T" _; V5 @
else
9 {- O4 F# u. b. f* s H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); \9 s& Q# C1 I/ T; P# d3 X
J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));: y+ [! z8 J9 S) r- z2 I* ?
N(m,n)=-J(m,n);
/ y" Q0 m6 h% w% N L(m,n)= H(m,n);" b+ j& m5 ?0 q! k2 d
Jacobi(2*m-1,2*n-1)=H(m,n);7 x) N5 \2 d! d1 c4 x
Jacobi(2*m-1,2*n )=N(m,n);$ ~9 d2 A) r; ]" T0 @, `1 j0 @
Jacobi(2*m ,2*n-1)=J(m,n);6 K0 {4 n4 o1 l/ H
Jacobi(2*m ,2*n )=L(m,n);
& s7 S6 G+ B2 N _) @ end6 x1 ?/ } j$ C7 t- m
end
9 H3 G0 ]; @1 c. N+ N2 ~ end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素
; `3 S+ {) X' R' n, {' C# @! o) J# W7 r" b3 b
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢3 A: D! n6 e S l1 {: |
2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?6 X; |8 Y. M6 K# [1 g
觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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辩手:0 ( 加入 )
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