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for m=1:Npq2 j6 `/ x* I7 U& e( \# ?
for n=1:Nbus
0 L3 h& o( G i6 K0 V! e4 P pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率
6 Y# s' J1 s( G2 X- b4 @2 h qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率( P2 M% N1 \& |
end
5 m- \* Q" @# x, D Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量* S9 \" M& M3 s" _( g+ R) f: `- o5 b
Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量
' i% F. J8 G$ h% ?7 ~end %[Unbalance]是节点不平衡量矩阵2 q3 b7 f% v: ]' v
, p V" d9 t# s: f0 T9 i! I. [+ E
for m=1:Npq U/ G1 v& b1 f5 \; ^6 J
for n=1:Nbus- n3 t( S; F" d8 _
h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
: u. D: e4 L8 n: ^" ? n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));* v% C3 J/ O* C2 R( H: F
j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
* w- S' H3 m8 \# _% M l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
9 y' l, b! N. D( N4 v end) {& [) z! Y& _" K2 v, M
H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));: v2 `" v$ L" J! K0 L9 s. }2 p: V
N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);# u" y: s# x/ {) [
J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));5 B& ?* Z* S$ k0 E0 n9 c6 @& T3 t' }
L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);8 P, Y9 C' ~/ F" d5 Z/ y
Jacobi(2*m-1,2*m-1)=H(m,m); y4 H: D+ F5 O8 M* F3 q+ l
Jacobi(2*m-1,2*m )=N(m,m);
" h. R5 |; P4 ]9 H# |+ [ Jacobi(2*m ,2*m-1)=J(m,m);
/ ^ E8 m4 [1 ^2 j1 } Jacobi(2*m ,2*m )=L(m,m);
8 \$ E2 f! a5 K% p end %计算m=n情况下的Jacobi矩阵中的子矩阵元素& |$ u, t2 V% n, B/ E: u* i! ?# @
* q: ~ n. W; e" @, x
for m=1:Npq
8 d4 K/ S7 W, u: C1 g0 W) W6 W- W for n=1:Npq
, R) \" a+ g& t5 J5 f' C" E if m==n
( g( u5 Q- m- h else1 @' ^" J6 U: P5 T: f+ d
H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));0 d: P8 |& E% n3 n# g. g+ N, A& Y
J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));1 i# [! A3 h% {# w O" K) C! W
N(m,n)=-J(m,n);1 }* V+ N4 @& U, W( p* \+ J
L(m,n)= H(m,n);) C& I4 ^" D, N, K; P U
Jacobi(2*m-1,2*n-1)=H(m,n);" m. F' C! U9 ]- B
Jacobi(2*m-1,2*n )=N(m,n);; A ]6 ~+ Q1 F, Y/ U
Jacobi(2*m ,2*n-1)=J(m,n);
1 m a2 v" H2 z: l% e8 u8 v9 I Jacobi(2*m ,2*n )=L(m,n);- z. T% ?( S8 m* W
end- ^; k( i6 ?1 @2 r( A* u: W
end! t7 o& g" j) d; }) z1 W+ ]
end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素8 h- r# X# `6 I& U/ o5 G1 q( X6 u" x
# v% E6 G* y# Q/ X- S问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢0 c" P% Z, u ? K2 j
2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?+ e; t/ j5 u! y: X8 V& Q |
觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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辩手:0 ( 加入 )
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