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for m=1:Npq
9 Y- H* c0 }. z; ]. J( J4 w for n=1:Nbus
' `4 S w* _6 a! R! J2 D8 j2 Z* P pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率
, {! Q; {. R3 R* V qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率
) v, B8 ^ d- \: d; @" S4 I end
; O) l" m3 r& n Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量
$ W; d2 o E/ k) |: K( @/ L% z Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量
! D# |& S1 ?) V/ nend %[Unbalance]是节点不平衡量矩阵1 f; F c# D6 X ?, I1 l6 ]
5 c2 e: R6 }& ]5 O. Z1 x* F4 Z
for m=1:Npq; p4 u! Z3 x) S4 T
for n=1:Nbus
% I0 [2 t# T2 D h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
2 Y) t x7 |$ N n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
* u( R+ ?) M; z7 J. X3 o j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); C2 k R# Z O: e E
l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
& X0 _, {0 W5 w: a5 z: u' d* \$ b end
* R, B+ [. T8 O' k6 s3 ` H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));
( s9 A9 {2 r' ]9 o1 i i7 w N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);
" w/ c- W! C R _9 g1 [6 d J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));' z& a" a- L _, b7 u/ `4 U
L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);* x4 m# U0 ^ |$ O
Jacobi(2*m-1,2*m-1)=H(m,m); w: O; ? y ~0 u$ x6 t$ _% x5 h$ G4 G
Jacobi(2*m-1,2*m )=N(m,m);3 R7 i$ `6 r! {2 I8 J Z5 Q- }
Jacobi(2*m ,2*m-1)=J(m,m);
- ^: |6 A8 G; @ a! j' [ Jacobi(2*m ,2*m )=L(m,m);
. t: X+ K1 d0 G3 T8 @ end %计算m=n情况下的Jacobi矩阵中的子矩阵元素1 U( l, D5 s' f: c
% Z6 ^2 F/ G. C3 k w
for m=1:Npq
: q1 z k: ]# G, }! ?/ x for n=1:Npq
+ r. {' E- k2 c. m if m==n
1 l0 V3 I I0 F& f else
1 f4 ]0 ]/ ^% m- e+ j H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
+ {5 ~6 Q, h, J4 h J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));5 Q: d ^ e! o( C% x
N(m,n)=-J(m,n);
+ C R2 N4 x7 K, k" R' A L(m,n)= H(m,n);; A, W9 u3 F: N% T2 z* U
Jacobi(2*m-1,2*n-1)=H(m,n);
5 V1 p" A& C+ S% M% z) u, \+ P# I s Jacobi(2*m-1,2*n )=N(m,n);
4 ?: J4 s' z. ~8 V Jacobi(2*m ,2*n-1)=J(m,n); a5 g ^* |! Z9 f6 n; q1 b( s
Jacobi(2*m ,2*n )=L(m,n);
5 E) u. Y' ~( X O3 w9 I3 N end
, g2 P+ c6 ^2 F3 f$ w9 t/ V end
0 r* v r; B% G" M0 P# C, B end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素
9 R f4 J) r. i/ K7 R' a Q8 z! U) ~; ~
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
8 n4 S0 J( f* M- u- l5 g 2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?
$ h' G2 m" |+ x0 M; @2 I' Q觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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辩手:0 ( 加入 )
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