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for m=1:Npq
+ \* b. @ f3 W* i, A for n=1:Nbus
& W# X- O, W* g7 B# s pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率
/ J3 V+ e+ V( k* r" V4 d' R qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率6 ~* J: I- c* z+ p6 n/ l5 ]
end% d9 J6 r8 V" L# _5 i( S- k. C
Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量* C1 B8 J2 Q |) L0 X
Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量
1 I4 F1 S4 u4 I, Uend %[Unbalance]是节点不平衡量矩阵
# E' o$ e& d+ u1 T
4 W- M# j5 ^' t( @. Z! @5 q for m=1:Npq
: X, x) j3 k) G ~* t6 D for n=1:Nbus
( O( p; Y2 s6 d, ~2 j9 }1 W h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));1 m8 y/ n4 ~+ e4 S; J% i
n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
7 I U6 o; r+ H( w j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));3 \4 q ~" T8 E+ F6 G6 q/ f
l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
& _9 H |7 q! { end
% u, N) n) d( C: C H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));
& t7 X3 @$ h+ V N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);
5 `& g1 ]5 G7 z i J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));! k* X ~% K8 B& w
L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);/ x! x& m/ ^2 `. O
Jacobi(2*m-1,2*m-1)=H(m,m);
- Y+ Q5 ?" |% ~& D7 d Jacobi(2*m-1,2*m )=N(m,m);
! F0 H" @1 Z S( n( w Jacobi(2*m ,2*m-1)=J(m,m);
# ]% Q. \) t* N! { Jacobi(2*m ,2*m )=L(m,m);% \4 r' S+ g% }3 J+ k1 B
end %计算m=n情况下的Jacobi矩阵中的子矩阵元素1 ^! s/ `& X' R; c9 q$ V4 E9 ^
. |0 m% P, s% n0 n0 n' Q
for m=1:Npq
1 K% t9 o7 E2 u9 ], s: g for n=1:Npq
! a# W) Y# E' e, f if m==n
/ Z6 F, W, U+ a8 F& L- u else
" |; n: J S/ C3 ~# N/ |# P H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));- Y. n" T7 t% }1 s2 r' J
J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));, Z# B5 w6 K, L; O! ~% C; O( @0 t
N(m,n)=-J(m,n);
- P+ C- @" K/ Y# S+ P2 {; O9 s/ K6 E) I L(m,n)= H(m,n);5 |2 p8 \7 l) u9 t) K
Jacobi(2*m-1,2*n-1)=H(m,n);
* B. W, {; Y. E. Q4 x Jacobi(2*m-1,2*n )=N(m,n);* D, I; B+ Y( u7 y5 t
Jacobi(2*m ,2*n-1)=J(m,n);. t0 ?6 O1 f: K. Z7 s" t5 i
Jacobi(2*m ,2*n )=L(m,n);% y/ W+ H2 _0 I. d3 x, `: Y# j
end) B+ {& M; k, m9 p, ^2 g
end" i0 A& v3 e8 I" _: G
end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素4 O3 `6 b" v! H2 F" U7 o1 Z. w
. r+ _' Q/ t; R8 m3 u% M
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
/ P" k: z2 \* ?+ T' o0 U2 C, F 2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?2 ?: Z% ?$ L: ?' M) c
觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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