利用ATP做大型电网仿真 一直出现如下错误 / F% k) a3 v" l6 J7 t( ]0 r4 o7 F5 @
++++ Type-59 S.M. number 44 begins operation on segments 0 and 0.3 q$ L& X- z) Q4 ? b2 ]1 T6 K
REDUCT. M, N, J, IJ = 0 3 3 6* o) g8 Z3 P6 B2 L
4 M1 w9 {5 b3 I" ^+ m* M$ `! K------------------------------------------------------------------------------------------------------------------------------------/ J3 \) u" H ]' H* o7 D1 ]
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/9 {: }- A3 c! S4 E% c
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/$ F; S! ]2 V, q# G; q
------------------------------------------------------------------------------------------------------------------------------------0 \5 g' @! J3 l6 E) ?" V- _1 r
You lose, fella. The EMTP logic has detected an error condition, and is now going to terminate program execution. The following" g0 s0 g' K' O3 ~. k. e
message summarizes the circumstances leading to this situation. Where an otherwise-unidentified data card is referred to, or where8 \" x* N) l- |0 Z0 |
the "last" card is mentioned, it is the most recently read card of the input data that is meant. The 80-column image of this card " ?7 Z6 u& ^8 k) l% S f# gis generally the last one printed out prior to this termination message. But possibly this last-read card has not yet been4 P1 F6 f6 c5 Y8 ~
displayed, so a copy follows: . O/ g) s! m/ H' V' n( A# c! E " "( E) L- F; t, ^8 Z" r, u8 c0 C) p
KILL code number Overlay number Nearby statement number 5 n/ A% I! K0 L' ~. n 86 13 4233 , \6 I) V: W1 f# J8 _+ F' ?KILL = 86. Singularity has been detected within SUBROUTINE REDUCT, which does Gaussian elimination. The diagonal element for 5 y3 y8 f" \$ t# `+ p& V/ i/ prow 3 is equal to -1.#IND0000E+000, which is less than the tolerance EPSILN of the floating-point miscellaneous data card. 3 w/ V9 L3 n9 F- F7 c" T5 lOther local variables that might be valuable to Program Maintenance in interpreting the trouble are as follows : N = 3 M = 0/ k# y4 x$ M/ t/ J5 |% k& v7 U
.$ Q) y6 g, v- d
这是哪里的问题？？？
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发表于 2014-7-17 00:30:49
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