ATP-EMTP运行出错误

ruodengxidai

利用ATP做大型电网仿真 一直出现如下错误
) r# D5 a4 d" N1 s. g1 D6 P# A- d* C
  D) a: x8 x$ x ++++  Type-59 S.M. number 44  begins operation on segments 0  and 0.
: B" Z; J2 E0 f6 q% ?$ `0 ^9 h  REDUCT.  M, N, J, IJ = 0 3 3 6
) |. V7 c: ^& z# v: {3 I# D4 ~
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$ B) Z  P# @) \. ~+ S+ j9 J: Q2 DERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
+ |. y$ B, m( `5 q3 v' MERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
4 T9 u0 }# M0 \! W  ?; ]$ u7 ~) |6 u0 o------------------------------------------------------------------------------------------------------------------------------------
You lose, fella.   The EMTP logic has detected an error condition, and is now going to terminate program execution.  The following
/ v$ T9 [3 c9 J7 ?! {# Wmessage summarizes the circumstances leading to this situation.  Where an otherwise-unidentified data card is referred to, or where
. @( D  Q/ ], N# bthe "last" card is mentioned, it is the most recently read card of the input data that is meant.  The 80-column image of this card
is generally the last one printed out prior to this termination message.  But possibly this last-read card has not yet been
displayed, so a copy follows:
5 }7 x1 ^, l% w6 Z "                                                                                "
              KILL code number                Overlay number               Nearby statement number
                         86                         13                               4233
KILL = 86.   Singularity has been detected within  SUBROUTINE REDUCT,  which does Gaussian elimination.   The diagonal element for
, H) j# o# q; R6 h  Z5 Qrow  3   is equal to  -1.#IND0000E+000,   which is less than the tolerance  EPSILN  of the floating-point miscellaneous data card.
7 S/ S4 D4 F5 }$ I& r5 G9 EOther local variables that might be valuable to Program Maintenance in interpreting the trouble are as follows :   N = 3     M = 0
7 k2 `% q- K/ v3 }% h.
这是哪里的问题？？？

ruodengxidai

有没有高手能来指点一下啊。。。

风月无边

谢谢楼主

zhiyonggao_etap

使用ETAP仿真大电网，是再好不过！推荐使用ETAP

ruodengxidai

唉~ 因为我是把PSSE的数据格式转化过来的 时间来不及也不能选择别的软件了 虽然知道EMTP做大电网并不方便