利用ATP做大型电网仿真 一直出现如下错误 9 W' N' B" }: ^( ^5 j0 w7 p( m % e/ B" H4 y" J: R ++++ Type-59 S.M. number 44 begins operation on segments 0 and 0.: B; Y+ M+ L: H2 X( S
REDUCT. M, N, J, IJ = 0 3 3 6 ( I- R$ m k: d* { 4 h7 H! s. H, M4 s' ~# d9 k/ M; H
------------------------------------------------------------------------------------------------------------------------------------9 X( [# x2 s5 k# L8 A
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/5 K: @) E, j9 V: v$ K( X! t% H
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/7 p9 F- t. G* j8 x! K
------------------------------------------------------------------------------------------------------------------------------------ : _% j3 i1 G, R7 O' |You lose, fella. The EMTP logic has detected an error condition, and is now going to terminate program execution. The following 8 g7 f- U- V8 _# Z, {% y" R0 Y' Vmessage summarizes the circumstances leading to this situation. Where an otherwise-unidentified data card is referred to, or where % G" n. s3 A% ^& [6 othe "last" card is mentioned, it is the most recently read card of the input data that is meant. The 80-column image of this card/ s6 N% z& ]1 b5 O/ Z
is generally the last one printed out prior to this termination message. But possibly this last-read card has not yet been # b8 X x' d. _' E5 Cdisplayed, so a copy follows:2 s; P- H' ]7 a' }1 _
" "7 V1 d# t# H) W
KILL code number Overlay number Nearby statement number 2 V1 J, v8 I: ?9 ~2 Q( P 86 13 4233 9 ~3 I( |. q3 K/ Z- UKILL = 86. Singularity has been detected within SUBROUTINE REDUCT, which does Gaussian elimination. The diagonal element for0 H$ a* n- z) y+ K$ T/ t7 N
row 3 is equal to -1.#IND0000E+000, which is less than the tolerance EPSILN of the floating-point miscellaneous data card. ) s- x6 s0 Z) r1 P7 BOther local variables that might be valuable to Program Maintenance in interpreting the trouble are as follows : N = 3 M = 02 k/ q& o( O' g J
. * H9 y$ Q6 w% V- X: ]' j# v0 s这是哪里的问题???