利用ATP做大型电网仿真 一直出现如下错误 4 `0 Z, P. M9 _, C0 N: Z. \. o! o " N% s3 D( N/ G2 }) K ++++ Type-59 S.M. number 44 begins operation on segments 0 and 0. , c4 _. G# d9 I' U' \0 @" K* t3 y REDUCT. M, N, J, IJ = 0 3 3 6. D6 C; O$ o! A+ k
& Y! v* R4 O6 Z! v" O' L$ l+ s------------------------------------------------------------------------------------------------------------------------------------ 3 O, V( S0 ?7 ]$ T5 \9 hERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/1 T7 a0 c8 n7 [6 x4 B) N% w6 l
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ : u( ? I! D* R5 {. K------------------------------------------------------------------------------------------------------------------------------------ + p% h# z' G# z4 pYou lose, fella. The EMTP logic has detected an error condition, and is now going to terminate program execution. The following4 p ^2 E& c0 c
message summarizes the circumstances leading to this situation. Where an otherwise-unidentified data card is referred to, or where* q7 H& ?% B D' _
the "last" card is mentioned, it is the most recently read card of the input data that is meant. The 80-column image of this card ! [2 Q' X' w) n% G! }5 nis generally the last one printed out prior to this termination message. But possibly this last-read card has not yet been+ A# t. A, A2 a
displayed, so a copy follows: ' p. K+ a. w, n& C; ]. q8 ~ " " 0 `# z4 [' S# ]9 l- c- J KILL code number Overlay number Nearby statement number7 Q1 r% g" f# p0 v5 f+ a) e) O7 _1 s
86 13 4233$ P" \! s& g! ~9 E1 K6 r/ C
KILL = 86. Singularity has been detected within SUBROUTINE REDUCT, which does Gaussian elimination. The diagonal element for! \3 o5 |% ?* g& m0 X' ^' t* X
row 3 is equal to -1.#IND0000E+000, which is less than the tolerance EPSILN of the floating-point miscellaneous data card." a- o5 ~6 U3 F5 t4 [
Other local variables that might be valuable to Program Maintenance in interpreting the trouble are as follows : N = 3 M = 0! I' ~/ h3 @$ k9 o* \2 h
. 6 @( _7 [. \4 Q! H" i/ X$ T/ S! O这是哪里的问题???