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发表于 2014-12-31 11:34:51
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本帖最后由 shanby 于 2014-12-31 11:45 编辑 * H/ {3 F- l* l8 N7 O' T, R
接线情况:模拟2台150MW,35kV的发电机分别接入2台分裂升压变压器,再由220kV接入大电网。在35kV母线接 ...
; F7 S& N/ a; r7 T' c$ pshanby 发表于 2014-12-21 21:06 . Z8 c3 d' v: N5 T+ ^4 f
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( N. f5 S/ D6 R5 z* I$ ?( L 查看如下帮助文档:Assumptions1 `4 H4 h+ D: W
The electrical system of the Simplified Synchronous Machineblock consists solely of a voltage source behind a synchronous reactanceand resistance. All the other self- and magnetizing inductances ofthe armature, field, and damping windings are neglected. The effectof damper windings is approximated by the damping factor Kd. The threevoltage sources and RL impedance branches are Y-connected (three wiresor four wires). The load might or might not be balanced.Limitations. G& t5 H& u: {8 ]) w
When you use Simplified Synchronous Machine blocks in discretesystems, you might have to use a small parasitic resistive load, connectedat the machine terminals, in order to avoid numerical oscillations.Large sample times require larger loads. The minimum resistive loadis proportional to the sample time. As a rule of thumb, remember thatwith a 25 μs time step on a 60 Hz system, the minimum load isapproximately 2.5% of the machine nominal power. For example, a 200MVA simplified synchronous machine in a power system discretized witha 50 μs sample time requires approximately 5% of resistive loador 10 MW. If the sample time is reduced to 20 μs, a resistive loadof 4 MW should be sufficient.
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1.简单同步发电机模型采用带电阻和电抗、独立电压源,三相Y连接的电气模型;, \/ C6 E/ f3 c0 M$ {
2.使用边界限制:如果是采用离散系统仿真,则需要在发电机端子连接寄生小电阻,其阻值或功率与离散系统的采样时间成比例(举例有计算实例)
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$ z& R) C5 y+ C, ]试错结论:
9 I6 G9 `! B) ?# s: T7 [1.错误提示说简单同步发电机是电流源,需要并联高值电阻。这与帮助文档电压源的说法不一致(尽管电压源和电流源和也互相变换)
* Y g5 \5 N& d% |2.将powergui模块参数设置为continous,仿真报错与设置为discrete的报错信息一样。
. Z6 T a! Y5 d% F3.将powergui模块参数设置为discrete, 按错误提示边栏电阻,则仿真不报错(虽然结果不是预期)。
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ShortCurrentFor300MW2.rar
(9.71 KB, 下载次数: 1)
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电压波形
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5 k: n. v0 V% ~疑问:; o2 r8 f/ [% W) t9 b) w6 S- C$ b5 f
1.如何解释模型搭建、报错和试错结论?
- L* i* X( p" V0 h2 \6 S7 ?/ D2.Simulink仿真的逻辑?
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