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发表于 2012-9-22 06:17:26
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看了看那个例子没看懂,貌似楼主应该看看example2之后,到example3之前的那些定义,然后在帮助里找找storf和stori这些东西...
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int test_cfun__(int *arg)
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return 2*(*arg);
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/* set of typedef's needed for
' m2 X/ [ M5 z/ }; m! W compability purpose with -r8 option
& ?+ I# f) Q+ N Z6 b7 E; R1 K% o6 s of Fortran compiler,
" v* N& [3 H' f5 Y used when gcc called without any options! W7 L4 u1 L: e- j) o
excecpt -c (gcc -c <filename>.c) */7 u2 t% z$ P, R4 X% j
) @( b9 x' T* x+ I& e5 n/ K' Jtypedef double real;; E* x) P3 m* }. x K
typedef long int integer;7 t7 Z% f4 m6 |* K
typedef struct { real r, i; } complex;/ g0 \2 ^( E8 s% u+ m5 A: Y8 E
typedef long int logical;
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1 d/ Y( O. Z/ A. ^1 e4 T/* structure representing 8 q) M/ W- |2 ?6 _3 O+ e; s
common block 'emtstor' */+ |5 K: }3 \% M0 P2 D
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struct emtstor_ {
' @& [ {9 z( K8 _* J- W( m complex storc[10000];
) _2 Y5 u' b: p: `) a- s( i/ g real storf[10000];! [! ]6 d) C. H9 _( g
integer stori[10000];) O! l* j" y9 C3 u, S9 R
logical storl[10000];, K4 x# i- q# N1 G
integer nstorc, nstorf, nstori, nstorl, this;6 V ]9 G7 E- X# m: y* T# i
};3 @. G( Z$ d# R$ r( @; k/ D( u5 d& ~
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/* structure representing
6 G" d% T/ O- U% K common block 's1' */
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struct s1_ {
( ~+ R* T( W2 i6 {8 V% N' v real time, delt, print, fintim;
- [* m2 h* h$ ]$ A% N/ y s logical timezero, firststep, laststep, onstep;
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, d% z9 @9 t( w3 m0 o+ }0 b" k/* structure representing ; R2 U9 ~' T; v9 S
common block 's0' */
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struct s0_ {0 Q( A8 F) `! a) q" z! D; w* h$ @' a
real rdc[400000] /* was [200][200][10] */;
- a/ D0 w- e, ^5 c g real ccin[2000] /* was [200][10] */;
* Y$ v% I8 C6 M- s Q real vdc[2000] /* was [200][10] */; * U, G* b0 u( V
real gm[400000] /* was [200][200][10] */;2 W6 N6 T$ s% _: [; Z: [
real ccgm[2000] /* was [200][10] */;! q' f! u" w" u/ ]
real ccgmd[2000] /* was [200][10] */;
$ h( J) Y2 m! T real ccli[2000] /* was [200][10] */;
! Z D" o' G& g8 H0 j( `) q real ggin[2000] /* was [200][10] */;
, {' n9 @; [% V7 Z; L$ x real ca[200];. d6 _8 u# b9 t3 R7 o. Y2 n7 n
real cdctr[300] /* was [10][30] */;+ U d# C( D* U) @' z+ y7 p& _
real cdctro[300] /* was [10][30] */;
0 {* s8 F3 t/ q3 p: i, P# G integer mbus[10];5 q1 U6 I: G, a* x5 e
logical idealss[10];3 l. u0 k3 `; f& k# w
logical enabccin[2000] /* was [200][10] */;
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' E0 ]: i8 L: T. j# \7 h2 F- R( ~/* structure representing
( S y% y/ }+ A+ `' R" ~9 ?- |3 I common block 'branches' */. W8 k$ D; d# M) z7 a8 {0 n- o
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struct branches_ {
! `5 S8 j0 R. A" v3 B real cbr[20000] /* was [2000][10] */;
) @) w( V' I3 x5 G real ccbr[20000] /* was [2000][10] */;, x- n4 y% C& y6 O
real ccbrd[20000] /* was [2000][10] */;
2 F* j p- r& M7 j% B; o' N real ebr[20000] /* was [2000][10] */;6 S" [( d# i7 d! y% c- @2 o
real ebrd[20000] /* was [2000][10] */;
. O% I! w6 {+ ]7 ` real ebron[20000] /* was [2000][10] */;) w5 R Z4 t8 g( O/ f
real ebrof[20000] /* was [2000][10] */;
4 y, Z( a3 s, m2 E8 W; [$ H' Z real swlevl[20000] /* was [2000][10] */;
1 H' V/ W& M( c. P9 D real geq[20000] /* was [2000][10] */;
4 E9 N8 t% m9 ~# R6 x& g real geqon[20000] /* was [2000][10] */;( n' L$ o1 |$ H) K
real geqof[20000] /* was [2000][10] */;
% p2 Q/ ?# K) q real geqd[20000] /* was [2000][10] */;
7 U" ]7 Y; W- o/ p5 X+ \4 e real rlg[20000] /* was [2000][10] */;
( I8 Q1 n) P$ [% d, f5 w8 V* D real rcg[20000] /* was [2000][10] */;
. O* f$ b3 R! u# o( Q% M9 T$ [( q real rcl[20000] /* was [2000][10] */;, `! z: v$ }% a/ T
real rsc[20000] /* was [2000][10] */;
# `- D4 @. f% c; b: ? real rsl[20000] /* was [2000][10] */;1 f( K6 }; J( s
real ccl[20000] /* was [2000][10] */;1 _4 y& [* z/ M4 B( X1 E9 w
real ccld[20000] /* was [2000][10] */;
* c" q' T0 d4 x! N2 E6 X9 W real ccc[20000] /* was [2000][10] */;
- ]% D: R0 C1 |+ R real cccd[20000] /* was [2000][10] */;
' ]: o1 J+ v4 ~) f B; h0 j real g2l[20000] /* was [2000][10] */;
. i* e5 M5 j5 A real g2c[20000] /* was [2000][10] */;# }! P, J+ i7 \5 o$ J& D
real v12l[20000] /* was [2000][10] */;2 ?/ h8 \$ f" h4 e
real v20l[20000] /* was [2000][10] */;# G5 C" E! n- p
integer nsw[10];
8 O$ H; j+ M( |3 ]2 h) v integer brnsw[20000] /* was [2000][10] */;
7 X& y2 X ?6 S* s/ e- i' k% f, o integer iet[20000] /* was [2000][10] */;% D+ _6 c( R* {0 t' M. m, b
integer ief[20000] /* was [2000][10] */;* e/ A5 o- @6 Y% v) f3 M( T
integer thisbr[20000] /* was [2000][10] */;
3 l$ Y3 p, w) n logical resistor[20000] /* was [2000][10] */;
1 r" d8 ^" |9 V0 Z* d3 o" F2 @7 Q logical inductor[20000] /* was [2000][10] */;
& }' Y0 r! M3 [9 O' B* s0 k+ O* z logical capacitr[20000] /* was [2000][10] */;2 A7 l9 k6 H" @' ]+ Z
logical source[20000] /* was [2000][10] */; I# H' U4 G& n1 t1 n
logical switch__[20000] /* was [2000][10] */;
1 V; a G P9 k& [" X, @ logical idealbr[20000] /* was [2000][10] */;+ T5 ~ M# k$ I9 H
logical openbr[20000] /* was [2000][10] */;
4 h; H* c* h. b' I. O* v) O6 j. @9 r logical defrdbr[20000] /* was [2000][10] */;
9 {2 {5 J' V6 w4 m2 g logical flipidlbr[20000] /* was [2000][10] */;
' v" e! ]8 V: v5 q logical geqchange[2000] /* was [2000] */;
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/* --------- */6 g& ]5 Z, y. D+ h9 M5 p# m2 ^
/* Example 3 */% q6 u1 Y5 C( n1 ^. S) u
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void test_cblck_one__(struct emtstor_* s, int* arg)4 T4 h4 W2 c! w
{
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s->stori[(s->nstori)-1]=1;
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