ATP对二次电弧建模时 6 t! A* f: D* C7 X3 s# H4 Z5 Q4 z 1 g5 v# s4 T9 H# ] j' Y: L( |二次电弧模块的程序如下, {3 S/ @: y1 d4 R# T
MODEL arc2" T5 ?& M; F! @8 U# Q' ]
INPUT U,I ; e" ]0 v+ X* o% I* E! V4 h! {. B2 eDATA L0,IS,0 r9 m4 O- t. Z9 \( N, J. P5 S, \: e
VAR GS,TS,US,LS,GS1,TE,TR,trip,R2,UR,H- A' e& k5 `2 w& m; T: ]3 ^' B
OUTPUT trip,R2 + q4 a2 m, F1 }! H* s& ~3 _$ R% T' jINIT: I7 r* f( l X5 S! q1 M, [& J
TR:=00 E$ y! Q1 U1 \; @7 ?
TE:=0- J- g0 S$ e; J8 } ^
trip:=14 k8 i( t) {( O: m/ I( @2 F& D6 d
ENDINIT - H& _+ O9 O6 C5 f5 ]! ?1 v EXEC ! M4 [; |2 t B8 _ `# r TR:=TR+timestep 4 |- j R" r, o0 F. Y) M9 E
IF TR<=0.1 THEN + u1 Q- }3 @8 \9 S; E8 r: U- ] LS:=L0 # R3 A' @; M$ J; {4 h+ K ELSE 6 h' X; R; a2 g( ~8 ^ LS:=10*TR*L01 k' x; F4 N& K0 J# u
ENDIF 7 S: l# j& x2 ]# H% s9 c- i
US:=75*IS**(-0.4) % k4 ]6 F) ?* Z; E$ b d: X: Q GS:=ABS(I)/(US*LS) + g3 Q* i: z, q' F! h( O: c TS:=2.57E-3*(IS**1.4)/LS! U4 [+ [, T: w1 Y) g
GS1:=GS*(1-EXP(-1*TR/TS)) / B. P, |# o- d1 n6 j1 @- F/ m R2:=1/GS1 $ V) t/ Y* }# K& l+ E" l* X IF ABS(I)<0.01 THEN 6 O* W4 o k9 Z$ Z* M: G TE:=TR H5 ]* j/ ?' U+ Y8 S ENDIF - K6 e% b7 _6 J/ x IF TR-TE>=0 THEN . r6 r: Q4 j7 v3 W, Q H:=1: y; a: m& {+ i' L) V4 ]: ~
ELSE8 D1 s8 ]# o2 T' a Q8 e$ R
H:=0 ' {9 n' X1 p( t" e ENDIF 3 Z+ l! M/ t+ v$ Y UR:=[5+1620*TE/(2.15+IS)]*(TR-TE)*H*LS*1E3) T; L5 V* P) f0 ]9 H
IF U<UR THEN & n7 P+ _" ~* a. C
trip:=1 / W- X S9 d% ? ENDIF 7 s4 }7 T" ^3 ^. T2 u* u* | ENDEXEC2 V1 g2 e: s) n
ENDMODEL, o9 h% T U4 D
/ @7 B4 A a9 Q. J0 _2 q- ?) Q! s但在运行时出现如下错误: ) A2 x5 H% }( m$ J2 QExecution of the program is interrupted in the MODELS section of the data case. . |6 a* g/ J8 Q F5 [% v: fThe model in use is identified by the following use pathname:" J4 |2 C( N' D2 c
MODELS.ARC2) Y" q( N( u$ J% h$ }, U
KILL = 682. Attempted explicit division by a zero-valued factor within an expression.) A& O+ \" Z6 N% s+ Y( m3 a# G
divisor value = 0.00000000E+008 E2 ?. u; }. M
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请各位大侠帮我i改改,本人急用( c' N' V2 L1 P' a# H/ S
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