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发表于 2011-9-19 10:05:40
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本帖最后由 wangdc 于 2011-9-19 10:13 编辑 0 t! I h1 D! m+ H1 W' _ I! @% Q
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回复 5# zhaoxiangen ; l* t* o: B& [/ o5 H
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那个你勾选的话,在计算结果LIS文件中就会列出最严重的值,不勾选就不列出;但是否勾选对PL14没有影响,电路图上只要有电压电流测量点,PL14都会有画图的,看一下我的结果
8 }, G6 _6 U1 Z3 l* T% s6 G13 ) -------------------------------------------------------------------------------------------------------------------------------
9 i- T& `) P0 x- _1 kStatistical distribution of peak energy for branch "MOV3LA" to "X0017A". Base energy for per unit output = 2.50000000E+07 & P4 ]0 e) |2 T4 o7 C: M; y
Interval energy energy in Frequency Cumulative Per cent
& l6 a) K; n2 L* I L% p9 ` number in per unit physical units (density) frequency .GE. current value * W0 I- z* G% w4 [
21 1.0500000 2.62500000E+07 0 0 100.000000 ! `- N8 _3 J/ Q; S9 n* Z. H; X
22 1.1000000 2.75000000E+07 74 74 26.000000
+ | U3 a: \! ^+ g2 B1 J& ` 23 1.1500000 2.87500000E+07 19 93 7.000000
6 A: U7 Q, D. R 24 1.2000000 3.00000000E+07 7 100 .000000 6 I5 M; z: u( M
Summary of preceding table follows: Grouped data Ungrouped data 9 _/ e" L. w3 y7 C' I) H- g
Mean = 1.09150000E+00 1.09587467E+00
& |- m; h% E' g- i1 A Variance = 9.11868687E-04 6.64562405E-04 6 U' l0 q5 C, N6 ?; a
Standard deviation = 3.01971636E-02 2.57791079E-02 . w1 [7 h1 |; u- P4 X$ e
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8 |' b, x6 b' @) E0 |Statistical distribution of peak energy for branch "MOV3LB" to "X0017B". Base energy for per unit output = 2.50000000E+07
$ r; g8 r2 R9 E$ {- p Interval energy energy in Frequency Cumulative Per cent " L, l0 |& n7 \' x: R, _
number in per unit physical units (density) frequency .GE. current value ' `/ d+ p( J$ i6 V7 ?0 a7 V$ o
21 1.0500000 2.62500000E+07 0 0 100.000000 0 [* T2 @6 X1 p) K( }7 W: b' ]
22 1.1000000 2.75000000E+07 83 83 17.000000 0 K5 m( _6 g( j3 n3 R/ {) q
23 1.1500000 2.87500000E+07 11 94 6.000000 # W! ~0 G0 k$ s9 N* s
24 1.2000000 3.00000000E+07 6 100 .000000
; t, [5 n1 _8 X% ASummary of preceding table follows: Grouped data Ungrouped data 0 ]8 K/ m. o' {; ?0 S% |; c0 M4 I
Mean = 1.08650000E+00 1.08919324E+00
8 V3 H$ [* \0 v' a' } Variance = 7.50252525E-04 6.91174224E-04 : J8 B; r8 B. j2 H h* S% m
Standard deviation = 2.73907379E-02 2.62901925E-02
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0 F% v4 M% d) @$ ]7 R. Y) L* ]Statistical distribution of peak energy for branch "MOV3LC" to "X0017C". Base energy for per unit output = 2.50000000E+07 2 N( X! O" q% H) Y( ?7 b; n
Interval energy energy in Frequency Cumulative Per cent
% A/ l8 d& f" \, R9 b8 O1 L number in per unit physical units (density) frequency .GE. current value
2 w/ Q( a2 W* M# I3 s- W* \ 48 2.4000000 6.00000000E+07 0 0 100.000000
( J) H9 ]* Y# l& F" r& _ 49 2.4500000 6.12500000E+07 21 21 79.000000
: f! k* {7 o5 W3 b/ G- k: `$ t 50 2.5000000 6.25000000E+07 47 68 32.000000 2 G, j% c& U/ `3 {' U
51 2.5500000 6.37500000E+07 32 100 .000000
/ U& r1 U4 f- G3 N2 _6 m# mSummary of preceding table follows: Grouped data Ungrouped data
; {( P0 U9 v# `1 }6 w Mean = 2.48050000E+00 2.47717072E+00 ' N2 X6 c# H9 z) t; s$ X
Variance = 1.30782828E-03 9.07356635E-04
8 R4 G0 N- ?+ p8 d0 c; S- l8 ^1 \( m/ @ Standard deviation = 3.61639086E-02 3.01223610E-02 1 V/ c& o' F7 }+ n9 a8 c
; N9 }* ]: S+ t5 f16 ) -------------------------------------------------------------------------------------------------------------------------------. t( |- V0 e4 b# F% q9 ~
SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY
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A distribution of peak values among all output branches of the last data card that have the same base value follows. This
- f: S" A( X% z, q8 j5 U5 i! g+ Gstatistical distribution is for the maximum of the peaks at all of these output branches having base energy = 2.50000000E+07
$ Z* B" U# Z* X Interval energy energy in Frequency Cumulative Per cent
* D9 u9 ^* t2 L number in per unit physical units (density) frequency .GE. current value
: m0 z) Q9 l; ]! _( E 48 2.4000000 6.00000000E+07 0 0 100.000000 2 n3 ?' r; ^" w" Y( N1 ~. [ j, R0 J
49 2.4500000 6.12500000E+07 21 21 79.000000
" c1 @# w) i" f e 50 2.5000000 6.25000000E+07 47 68 32.000000
y- D) O8 Z: I" @4 { 51 2.5500000 6.37500000E+07 32 100 .000000 ( a8 F' I x+ d1 m3 w
Summary of preceding table follows: Grouped data Ungrouped data / p. j9 B) y0 s' x4 Z' M0 p" p
Mean = 2.48050000E+00 2.47717072E+00 : q7 ~2 i+ C6 k* H4 D1 Q$ R- v
Variance = 1.30782828E-03 9.07356635E-04 9 v4 S) s4 g* X. D
Standard deviation = 3.61639086E-02 3.01223610E-02 ! ?+ @* M: @1 E7 e# T+ i& r K$ p
Blank card ends statistical tabulation requests. |BLANK STATISTICS
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. p* D. j8 X2 H: U3 D( S) P% Y Sample curve symbols : "A", "B", and "C"
/ S9 m/ P6 E. ~1 _+ U# I Theoretical curve symbol : "*"( o4 j$ b4 i& j0 O
Common curve symbol : "X" |
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