1 ) -------------------------------------------------------------------------------------------------------------------------------2 A) c" N5 X) u9 a1 b
Statistical distribution of peak voltage at node "X0002A". The base voltage for per unit printout is V-base = 6.53197300E+050 y$ K" J3 {. Z8 s$ N0 H
Interval voltage voltage in Frequency Cumulative Per cent n* X# d4 @4 ?7 j$ n+ J3 b
number in per unit physical units (density) frequency .GE. current value 0 J0 d+ \/ O6 q1 L2 p5 { 22 1.1000000 7.18517030E+05 0 0 100.000000 7 ] D7 `2 H/ e 23 1.1500000 7.51176895E+05 27 27 77.500000% {7 T, n) j: K
24 1.2000000 7.83836760E+05 51 78 35.0000003 [+ A) G* f* \3 D
25 1.2500000 8.16496625E+05 39 117 2.500000 1 r9 [! C9 [) d% x0 I 26 1.3000000 8.49156490E+05 3 120 .0000000 S2 ~ ~6 }# j" \8 o6 X1 k
Summary of preceding table follows: Grouped data Ungrouped data 8 I$ Y) ?; J: z8 g Mean = 1.18250000E+00 1.18075096E+00 ' ?* t( N( }" ? Variance = 1.58193277E-03 1.50641231E-03& p6 ]* T A: e. h( U6 ^ ]: U* @+ E
Standard deviation = 3.97735185E-02 3.88125278E-02, _$ o3 a7 |/ r: }3 T0 D% `8 _
上面的结论是做操作过电压仿真计算出来的，采用统计开关按120次正态分布。请问这里面frequency和.GE. current value是什么意思？还有最后四行Grouped data和Ungrouped data有什么区别？Mean、Variance和Standard deviation代表了什么？谢谢各位大侠指教！
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发表于 2010-1-27 05:44:07
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