1 ) ------------------------------------------------------------------------------------------------------------------------------- / R1 {4 h2 o+ ~6 n- z- Z' @Statistical distribution of peak voltage at node "X0002A". The base voltage for per unit printout is V-base = 6.53197300E+05/ ?' \2 T5 g; M
Interval voltage voltage in Frequency Cumulative Per cent : E p0 R0 y! Q6 E) n7 a5 ` number in per unit physical units (density) frequency .GE. current value 3 l) A+ Y( B K0 @! t 22 1.1000000 7.18517030E+05 0 0 100.000000 " \' v }4 T9 _: s4 M3 S 23 1.1500000 7.51176895E+05 27 27 77.500000 . p7 L& v/ m- e 24 1.2000000 7.83836760E+05 51 78 35.0000001 d, O7 g& p8 k# I) C* @) |% M
25 1.2500000 8.16496625E+05 39 117 2.500000 " `! j8 v/ E4 b 26 1.3000000 8.49156490E+05 3 120 .000000" v0 ~; X D* h; b! _5 c& Q, \+ \/ I
Summary of preceding table follows: Grouped data Ungrouped data 5 ^7 J5 Z4 }7 e$ C+ d1 r Mean = 1.18250000E+00 1.18075096E+00 9 o6 o' I, e" u6 M$ w. ~ Variance = 1.58193277E-03 1.50641231E-03 3 M D* X: q6 ^7 c: N1 p Standard deviation = 3.97735185E-02 3.88125278E-02! Y m" R/ z* E+ `/ `+ l& }
上面的结论是做操作过电压仿真计算出来的，采用统计开关按120次正态分布。请问这里面frequency和.GE. current value是什么意思？还有最后四行Grouped data和Ungrouped data有什么区别？Mean、Variance和Standard deviation代表了什么？谢谢各位大侠指教！
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发表于 2010-1-27 05:44:07
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