You lose, fella. The EMTP logic has detected an error condition, and is now going to terminate program execution. The following5 o u: [5 c- d
message summarizes the circumstances leading to this situation. Where an otherwise-unidentified data card is referred to, or where 1 W$ L: l* q: X" W \0 O; jthe "last" card is mentioned, it is the most recently read card of the input data that is meant. The 80-column image of this card* m1 o& W; ?4 e- g6 d$ O+ D) D
is generally the last one printed out prior to this termination message. But possibly this last-read card has not yet been# g' q( C& ?/ J9 s& w) J/ [1 i
displayed, so a copy follows:) ], z Y; Y ^6 p: p
"14source 0 311. 50. -1. 1."5 Z( |- {$ [& M
KILL code number Overlay number Nearby statement number8 C4 {" J. q& Z
12 5 4246 ~4 p" }( Z% z0 J5 w; H
KILL = 12. The bus name that was read from columns 3-8 of the last source card is unrecognizable, not having been previously* | B& z& p, L) C0 s2 o7 `
defined by a branch card or a switch card. The name read from the data card is "source". The user is not allowed to connect 3 E3 o/ k5 K! \% p0 G& ?sources to network nodes that are not a part of the network that was previously defined by branch and switch cards of this data! ~, U" Z- B2 b# L# O
case. Any such new node would be completely disconnected from the network, so could not affect the solution. Most probably, one or $ ^: v7 [( { R( T" m, pmore spelling errors (including the positioning of imbedded blanks) have been made in the keying of one or more node names on EMTP 6 V m* z" M% }% Jdata cards. ( T! x" |, @: _7 I; I5 a" L S2 y- _8 p! V
. L8 T4 P% L8 F; Y5 \: katp中的data card是* G Q5 k3 Y- P7 x
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狗仔卡
发表于 2009-5-29 16:29:50
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