You lose, fella. The EMTP logic has detected an error condition, and is now going to terminate program execution. The following " t9 l7 Y; r. E" d9 b8 xmessage summarizes the circumstances leading to this situation. Where an otherwise-unidentified data card is referred to, or where& B7 C/ N4 [* p. |' @7 h f! k) M
the "last" card is mentioned, it is the most recently read card of the input data that is meant. The 80-column image of this card; w6 Y: @4 R2 A# R
is generally the last one printed out prior to this termination message. But possibly this last-read card has not yet been ) C4 D4 s- M+ ~. X$ H& S/ L" Gdisplayed, so a copy follows:' [! X5 L. p7 C3 n6 \
"14source 0 311. 50. -1. 1."6 X0 i& Z2 C: x) v+ Z
KILL code number Overlay number Nearby statement number: a: q1 J! v1 T3 W
12 5 4246; l! S, Q: X% ~0 Z' y0 v
KILL = 12. The bus name that was read from columns 3-8 of the last source card is unrecognizable, not having been previously / ?7 h$ ^6 l& k5 m# Edefined by a branch card or a switch card. The name read from the data card is "source". The user is not allowed to connect . t6 g' N- c& H! a, r5 v' Esources to network nodes that are not a part of the network that was previously defined by branch and switch cards of this data 0 o$ I: i( D- R6 G1 D) {case. Any such new node would be completely disconnected from the network, so could not affect the solution. Most probably, one or 8 U) X0 n3 H+ ?( ~% W& n0 s w/ V3 \7 g. omore spelling errors (including the positioning of imbedded blanks) have been made in the keying of one or more node names on EMTP! Z0 U {& e+ R* T: d" ~& P
data cards. 6 a- j" @" g/ b' m7 F4 H) {( D( J6 V+ M" Z* Y d6 W! o
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狗仔卡
发表于 2009-5-29 16:29:50
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