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2021-5-6 11:24 |
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发表于 2009-2-12 14:13:01
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非常感谢，问题已经解决了，能够使用。+ K( M. l3 |3 ~, G5 Z3 E0 ]
P7 n+ o8 F& \ brunpf('case9')" Z+ ?- P0 u) E% Y5 P" w1 b% m, ]
8 P7 G* |' F9 r0 D
Newton's method power flow converged in 4 iterations.. w6 H- K( [7 D1 p0 G( N8 f
6 M; S8 c9 h7 j' h
Converged in 0.72 seconds
7 A/ a4 K' s# Y; z- P. E2 F% A0 K================================================================================' I, b2 ~ I: p) e
| System Summary |+ e0 U! W( Y; O
================================================================================0 V: l7 i5 J/ Q9 B# a
" u! F, F' g4 S; {" K; mHow many? How much? P (MW) Q (MVAr)" A0 T/ P7 L* Y$ a8 R4 Z
--------------------- ------------------- ------------- -----------------4 s4 H8 w `3 b2 t" n
Buses 9 Total Gen Capacity 820.0 -900.0 to 900.0& R3 ^5 ?& ~% q
Generators 3 On-line Capacity 820.0 -900.0 to 900.0
7 r8 L& Q, W' BCommitted Gens 3 Generation (actual) 320.0 34.9
& s: R4 b5 w$ I; u; aLoads 3 Load 315.0 115.05 Z; {$ o& Z* c) u# |. J# K
Fixed 3 Fixed 315.0 115.0: G2 S3 P: j/ E7 T, u
Dispatchable 0 Dispatchable -0.0 of -0.0 -0.0, K" o ?; o; @& Q5 Z& [; w: _9 c
Shunts 0 Shunt (inj) -0.0 0.0
! C( y" M1 N2 j7 A3 e+ V7 aBranches 9 Losses (I^2 * Z) 4.95 51.31
3 t6 v( i' P2 j( p6 BTransformers 0 Branch Charging (inj) - 131.4
' k7 X* V# [! E$ _& K3 Y) \' z2 nInter-ties 0 Total Inter-tie Flow 0.0 0.0
8 D% y/ W9 }: c" s* _Areas 1
- V; F' ^9 v* t! ^' F6 U4 s- K U$ r7 ], g$ g; |) Z8 x0 t6 |) k: O& ~
Minimum Maximum
+ ]) n7 q' U k0 o- ~; X' P7 p ------------------------- --------------------------------1 _+ x+ o. X$ ~% h
Voltage Magnitude 0.958 p.u. @ bus 9 1.003 p.u. @ bus 6 - a4 A; L! c: n$ {$ Q3 x8 q; R
Voltage Angle -4.35 deg @ bus 9 9.67 deg @ bus 2
$ \% v2 D* A1 w9 z6 z- ]P Losses (I^2*R) - 2.46 MW @ line 8-9
; A, O6 l ?+ X/ z" eQ Losses (I^2*X) - 16.74 MVAr @ line 8-2
' r5 I& c# Y9 Q4 |% q3 M& L3 C- ^) n b- G& g3 D x
================================================================================8 x! N0 N% K, c" x$ s% Q
| Bus Data |
/ K# J& w9 ~/ I: S================================================================================) W8 w/ v6 ?, _' P; Z) w) m. l- D
Bus Voltage Generation Load c r/ a8 k; W) N8 |, T- X4 [3 N
# Mag(pu) Ang(deg) P (MW) Q (MVAr) P (MW) Q (MVAr)( o* u* T7 ]3 A) D% U+ @
----- ------- -------- -------- -------- -------- --------
9 e/ o0 I6 N% C- t 1 1.000 0.000 71.95 24.07 - - ' [! L, h% s) A7 x
2 1.000 9.669 163.00 14.46 - - 9 g! n( p% `: F7 i
3 1.000 4.771 85.00 -3.65 - -
6 \& }9 V2 h3 q/ I6 [( v5 i; }; P. ^ 4 0.987 -2.407 - - - -
( `# \3 G7 o. Q' {1 ~ 5 0.975 -4.017 - - 90.00 30.00 0 p" t+ M0 g- e: U- N+ L
6 1.003 1.926 - - - - * ]% ]. e8 [! D! i6 l: N
7 0.986 0.622 - - 100.00 35.00
0 [' x, d$ j, K1 T' P7 e 8 0.996 3.799 - - - - - q7 l4 S5 k7 Y2 W0 j
9 0.958 -4.350 - - 125.00 50.00
% F* S& A4 k" L) p -------- -------- -------- --------
4 C3 A+ R' I4 u3 S& ?6 c Total: 319.95 34.88 315.00 115.007 J+ L2 n, s. ~, o
8 `4 y" X# f" b* C( Z% }1 b4 r================================================================================
; ^# b1 m) j0 o. `( Y" s. H3 z| Branch Data |# ]8 A& p- h/ ^
================================================================================& }$ ~$ }0 Y, Q
Brnch From To From Bus Injection To Bus Injection Loss (I^2 * Z)
, A b6 d H& w0 k5 u # Bus Bus P (MW) Q (MVAr) P (MW) Q (MVAr) P (MW) Q (MVAr)
) g4 B& x* m2 b" r! U: ?----- ----- ----- -------- -------- -------- -------- -------- --------$ s: n. E5 [; e2 m T. A
1 1 4 71.95 24.07 -71.95 -20.75 -0.000 3.32
7 D4 u" L. f2 B/ V4 u5 C 2 4 5 30.73 -0.59 -30.55 -13.69 0.174 0.946 [4 Z h8 v2 K( [( q" B
3 5 6 -59.45 -16.31 60.89 -12.43 1.449 6.31
- u' X. N% I) {+ f: o5 u 4 3 6 85.00 -3.65 -85.00 7.89 -0.000 4.24$ Z3 | Z' ^, s
5 6 7 24.11 4.54 -24.01 -24.40 0.095 0.81$ n* F1 L2 a( H6 v3 h
6 7 8 -75.99 -10.60 76.50 0.26 0.506 4.299 S0 D. z& [( Z
7 8 2 -163.00 2.28 163.00 14.46 -0.000 16.74% k3 Z" ?+ v8 z6 Z! U$ Z
8 8 9 86.50 -2.53 -84.04 -14.28 2.465 12.40
& u; ]9 W, V- s( [1 g. g 9 9 4 -40.96 -35.72 41.23 21.34 0.266 2.26: T" { ?. \8 G
-------- --------
' q' z% E5 X& D) P4 W Total: 4.955 51.31 |
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