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2021-5-6 11:24 |
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发表于 2009-2-12 14:13:01
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非常感谢，问题已经解决了，能够使用。
5 U* h1 k5 B: d7 Q v
8 S6 r9 b3 g6 i. R ~runpf('case9')
' w% G8 k: ?7 h1 k6 [, |! w* J- J+ l3 o" _7 p
Newton's method power flow converged in 4 iterations.
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1 ^+ t8 M' J4 n' BConverged in 0.72 seconds4 r k, D+ z j
================================================================================4 }9 f2 n" j; L; V# [* J* k: E0 U9 P
| System Summary |/ ~9 C# A ?7 q$ g3 s
================================================================================/ j, R* L1 s% X7 ]/ D# M5 f
! {: e" E# Z4 V, S! aHow many? How much? P (MW) Q (MVAr)) N" ~, R# c' l! \' A7 J: V
--------------------- ------------------- ------------- -----------------
# J. T) A9 @3 i9 f" d# {Buses 9 Total Gen Capacity 820.0 -900.0 to 900.0" V5 h: u- V5 O5 d* \
Generators 3 On-line Capacity 820.0 -900.0 to 900.0; v4 `0 o9 [0 ^" M3 a. l
Committed Gens 3 Generation (actual) 320.0 34.9
. P- {! J2 @ z+ eLoads 3 Load 315.0 115.0
) D3 |$ D3 l& ] Fixed 3 Fixed 315.0 115.0
5 f. _: o! ^6 k; ?8 i# C, P" X Dispatchable 0 Dispatchable -0.0 of -0.0 -0.0
}: }' S! L$ |; s, o3 {Shunts 0 Shunt (inj) -0.0 0.0
* O5 `; `; f* c ^Branches 9 Losses (I^2 * Z) 4.95 51.319 V8 l, j5 O, w" W
Transformers 0 Branch Charging (inj) - 131.4/ r' x" v- Q4 i) L6 p
Inter-ties 0 Total Inter-tie Flow 0.0 0.0
o$ g% e; C/ oAreas 1
+ Z: I0 E% a' {- v# b4 w9 h
1 I: p5 j5 O0 b Z- S. o Minimum Maximum+ `* B# g/ ?5 ~- }! I/ T8 H! X) i" M
------------------------- --------------------------------
. v$ ?: a5 t8 M, g& wVoltage Magnitude 0.958 p.u. @ bus 9 1.003 p.u. @ bus 6 6 n0 h& B1 E% v/ X% g9 u
Voltage Angle -4.35 deg @ bus 9 9.67 deg @ bus 2
) ^9 g! n0 o, QP Losses (I^2*R) - 2.46 MW @ line 8-9
' @& u1 S% M- y qQ Losses (I^2*X) - 16.74 MVAr @ line 8-2- c5 I( u9 G1 l$ y D( H' H
1 s1 H, z1 ?# p1 `================================================================================
( R+ \2 @' s7 p| Bus Data |
2 y: b) d. M. J( M) K/ d0 K ?================================================================================1 E" ] b6 ^- K0 [7 P m
Bus Voltage Generation Load
' m4 |9 ]9 P ]& q$ d6 n # Mag(pu) Ang(deg) P (MW) Q (MVAr) P (MW) Q (MVAr)
/ |. u8 o( B ~8 }4 s: ?----- ------- -------- -------- -------- -------- --------
# K+ l( Z9 q6 [" c% {# t 1 1.000 0.000 71.95 24.07 - -
& _; V5 j' o5 o: F8 Z, F$ l 2 1.000 9.669 163.00 14.46 - -
; q4 E, ]( v& q) j! Q- V( n 3 1.000 4.771 85.00 -3.65 - - : l) i1 o. y8 `& m4 K# h
4 0.987 -2.407 - - - - 2 u9 i2 q5 w+ J j
5 0.975 -4.017 - - 90.00 30.00
7 i& H' F+ v, g+ D# C 6 1.003 1.926 - - - -
3 V" U- ?$ g$ |: B9 d! d, t- _, W 7 0.986 0.622 - - 100.00 35.00 % m- Y/ s0 S8 k, q
8 0.996 3.799 - - - -
4 J/ X7 M' Y1 [& |& v! f 9 0.958 -4.350 - - 125.00 50.00
0 ], ]" p# Q, } -------- -------- -------- --------$ [/ s( f7 \9 g3 `" Y7 d/ Q" C7 k
Total: 319.95 34.88 315.00 115.00
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+ X5 [3 n5 }# `+ G, S( L================================================================================
( R1 r! ~9 K" Z% Y7 @| Branch Data |9 g5 Y; M! J3 F$ l; f4 }. ^0 p
================================================================================ |( z* s1 g+ G7 ^' c$ V
Brnch From To From Bus Injection To Bus Injection Loss (I^2 * Z)
8 }8 D( i, j. {/ m3 e" m$ ] # Bus Bus P (MW) Q (MVAr) P (MW) Q (MVAr) P (MW) Q (MVAr)
6 c e- L. g7 e5 v& B$ h----- ----- ----- -------- -------- -------- -------- -------- --------3 v$ P5 g! Y5 P! o2 z5 D
1 1 4 71.95 24.07 -71.95 -20.75 -0.000 3.321 D- H0 [$ c0 @3 P/ B' Y! p
2 4 5 30.73 -0.59 -30.55 -13.69 0.174 0.94. V" q0 y7 @' R7 C# x M* @3 q
3 5 6 -59.45 -16.31 60.89 -12.43 1.449 6.31
9 q) q: B% M' E, ~6 U 4 3 6 85.00 -3.65 -85.00 7.89 -0.000 4.247 U% ^4 Y0 ?5 j% L% @
5 6 7 24.11 4.54 -24.01 -24.40 0.095 0.81
& U7 X v1 w" Z$ P: G 6 7 8 -75.99 -10.60 76.50 0.26 0.506 4.29/ ^* u+ ^: w6 j: @1 }( S+ t. g
7 8 2 -163.00 2.28 163.00 14.46 -0.000 16.74
- g1 }: z5 S8 Q1 h, n 8 8 9 86.50 -2.53 -84.04 -14.28 2.465 12.40
3 u0 x) F( {3 g6 h6 d+ v4 r 9 9 4 -40.96 -35.72 41.23 21.34 0.266 2.266 c" h4 U3 a) B0 Y; K& L
-------- --------& c* B2 K( p2 k
Total: 4.955 51.31 |
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