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2021-5-6 11:24 |
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发表于 2009-2-12 14:13:01
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非常感谢，问题已经解决了，能够使用。$ r$ c2 a6 V8 f* V- O; R
7 [, W1 H9 @& lrunpf('case9')& [) ]! z r+ }" d0 m7 L) f: n
6 `2 j5 R1 N1 f* _
Newton's method power flow converged in 4 iterations.; r; B/ O. M! \
9 A) M" Y1 _4 \' S( A$ PConverged in 0.72 seconds
8 F# z. P4 e, G+ v================================================================================1 ?# O2 A8 E6 Q& [2 t& l& ]
| System Summary |5 |6 F1 L, {9 e
================================================================================5 J/ C" N1 c1 P8 b% A
6 |& t0 n% d+ M. [6 s) ZHow many? How much? P (MW) Q (MVAr)
0 `1 s% U6 h5 |" {- z* K1 v) n( T8 Z/ ^* F--------------------- ------------------- ------------- -----------------: T8 g S) Q' V1 A1 N. m
Buses 9 Total Gen Capacity 820.0 -900.0 to 900.0
! |# X" |0 B* X) z0 ^Generators 3 On-line Capacity 820.0 -900.0 to 900.0) f) k" y4 l' `2 I! q
Committed Gens 3 Generation (actual) 320.0 34.9; e) w9 y2 s4 q0 K. `2 R j
Loads 3 Load 315.0 115.0
2 }$ z4 z/ e# c Fixed 3 Fixed 315.0 115.0
: q2 C) w% @3 T2 K6 g3 C) F/ F Dispatchable 0 Dispatchable -0.0 of -0.0 -0.0
6 q' `, }4 A; Z- zShunts 0 Shunt (inj) -0.0 0.06 P. j r% ~0 B' S6 j4 P$ t( Z1 x
Branches 9 Losses (I^2 * Z) 4.95 51.31
0 Q# }8 [ S) E: e% tTransformers 0 Branch Charging (inj) - 131.4
, l \6 Z) `* F4 N+ Q3 x& M" BInter-ties 0 Total Inter-tie Flow 0.0 0.0- K8 m _* c6 e4 l
Areas 1) C3 [! O8 j, M0 G
' Z' a' r1 R4 b7 J0 o
Minimum Maximum' {' w$ V& }1 @, _" n- a; X* c* j
------------------------- --------------------------------( u; e1 j$ t/ x) y
Voltage Magnitude 0.958 p.u. @ bus 9 1.003 p.u. @ bus 6 ; ?* K8 O7 @( x' R$ h
Voltage Angle -4.35 deg @ bus 9 9.67 deg @ bus 2
/ i( W' G1 ]' f/ r+ }) s% X0 VP Losses (I^2*R) - 2.46 MW @ line 8-9
8 C' Y/ K/ Z- [3 L( GQ Losses (I^2*X) - 16.74 MVAr @ line 8-24 k# {0 Q- J% [7 S% g6 T
4 e- _# x! Q6 _- O; u3 z( L2 V================================================================================; \% {+ m( x% p l
| Bus Data |9 L% ]! v9 R5 w% M
================================================================================
2 u. s6 m, h: c- F Bus Voltage Generation Load / Q% n* R* W4 N
# Mag(pu) Ang(deg) P (MW) Q (MVAr) P (MW) Q (MVAr)3 r7 L) ]( W2 ]0 o; B. n
----- ------- -------- -------- -------- -------- --------+ k7 O6 X* r) }0 X9 F
1 1.000 0.000 71.95 24.07 - -
1 t( F; T k/ [( N" n9 r& A A 2 1.000 9.669 163.00 14.46 - -
& z4 W3 r2 \' h- J7 C 3 1.000 4.771 85.00 -3.65 - - # O5 P2 o* Z" Y
4 0.987 -2.407 - - - -
U4 O* \6 a1 T 5 0.975 -4.017 - - 90.00 30.00 5 C: {) g* w! q7 t7 m( ?
6 1.003 1.926 - - - -
( a! H2 a; _7 V7 \! t 7 0.986 0.622 - - 100.00 35.00
4 [' ^! u1 o/ c% k8 H 8 0.996 3.799 - - - -
# N- d+ Q5 c5 G$ ]' a 9 0.958 -4.350 - - 125.00 50.00 & q! F7 T/ l1 G% b8 B
-------- -------- -------- --------
' j: `: w, J- r* g1 Q Total: 319.95 34.88 315.00 115.00
0 u, I! u# m9 L- N7 l$ v
1 I$ C) A. @1 u! u1 [4 f================================================================================
8 x" L, d: e5 J* S| Branch Data |
0 |' f+ q* H7 a0 s+ H) w0 e================================================================================
, G+ a, i6 L5 ]: y3 \' l0 {Brnch From To From Bus Injection To Bus Injection Loss (I^2 * Z)
& x0 {0 H# M; R+ [9 X# } # Bus Bus P (MW) Q (MVAr) P (MW) Q (MVAr) P (MW) Q (MVAr)" T m9 C$ n( n: j6 d) \# M6 {% t
----- ----- ----- -------- -------- -------- -------- -------- --------- i, _$ v$ O9 P/ S$ u0 A. j
1 1 4 71.95 24.07 -71.95 -20.75 -0.000 3.32& p8 R0 p7 \- t6 Z5 D
2 4 5 30.73 -0.59 -30.55 -13.69 0.174 0.94
( J& T/ q" P9 D1 K$ t# d; I" r1 C" Z 3 5 6 -59.45 -16.31 60.89 -12.43 1.449 6.314 @5 s2 ?3 ]+ o' P; _
4 3 6 85.00 -3.65 -85.00 7.89 -0.000 4.24
6 U r4 \0 H; r* d! U% g 5 6 7 24.11 4.54 -24.01 -24.40 0.095 0.81: z* F% {4 w* |6 B& z
6 7 8 -75.99 -10.60 76.50 0.26 0.506 4.29/ o, H- t2 l& B
7 8 2 -163.00 2.28 163.00 14.46 -0.000 16.74
0 l& ^/ D# R! Z/ R6 R: ~( y 8 8 9 86.50 -2.53 -84.04 -14.28 2.465 12.40
x/ `& t8 w e5 t8 s' u4 ` 9 9 4 -40.96 -35.72 41.23 21.34 0.266 2.26) a' y ]4 f9 A2 F* R5 X" Y3 r0 m
-------- --------( `% N+ m; x( O% w( E
Total: 4.955 51.31 |
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