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for m=1:Npq* U* q) A( y) O: H; e. j; F q
for n=1:Nbus
- C @1 K9 B5 L pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率1 K; R! N# K% q# I p7 O
qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率
* h7 z/ m( g% J1 |8 Y end
# q4 G& W8 \* |" p* l% L) Q1 h Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量, q( h6 L3 x+ q, Y+ b- P! B
Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量) ^4 e# @% f' Y* l% N: v4 v3 }* [
end %[Unbalance]是节点不平衡量矩阵
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for n=1:Nbus9 q0 s" ^' [* t
h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); J* r9 \, J& f- w+ @
n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));6 K8 Z, U2 L9 D! t
j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
6 I2 l1 l; p# `2 J$ A4 m l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));/ h3 A' V& `. i# n
end8 m. E4 K {/ y0 p( S
H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));
' J. m& h( G' n N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);
+ |' i; Z+ F& |3 p3 R# o, d$ X J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));9 g7 k; {' u' o9 b6 h4 m. g
L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);' v" b7 C/ t1 s6 u1 h4 B: v( s9 z2 n
Jacobi(2*m-1,2*m-1)=H(m,m);
2 E0 K: T4 p: ~& U/ N) [1 J Jacobi(2*m-1,2*m )=N(m,m);. P/ S) g! c! {3 {, ~# \
Jacobi(2*m ,2*m-1)=J(m,m);$ H1 z* W) C! S$ [- H9 p
Jacobi(2*m ,2*m )=L(m,m);
; V3 v8 w( ^1 \: ^ N end %计算m=n情况下的Jacobi矩阵中的子矩阵元素% X# \' B2 `; O
8 k l' a1 W- K7 W) Y- a1 z
for m=1:Npq
- U& ?# e7 J- e( m/ z- X0 R0 _4 m for n=1:Npq9 i3 {. R% z \4 _1 R
if m==n
* H1 D* r" b7 r1 z( m else8 [7 Z7 o6 w2 q. _5 ?; p2 E6 Y! g* p
H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
" L) V5 s5 u5 {, ~7 c. s$ U J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));( @7 J; ? N) I
N(m,n)=-J(m,n); ~& }7 g) ]$ U# _2 o; F X P; r6 u
L(m,n)= H(m,n);
( G3 W* N$ M6 A+ G3 X, A Jacobi(2*m-1,2*n-1)=H(m,n);
2 v- N. F" O) Z U h Jacobi(2*m-1,2*n )=N(m,n);
9 D4 f2 P( I E' N: x, ^' d Jacobi(2*m ,2*n-1)=J(m,n);
; }: f$ R4 J q' u& i Jacobi(2*m ,2*n )=L(m,n);
' j4 T* q3 R4 k- \- ]- M end: q* I. |% D& ^6 f5 t. h
end+ Y d6 W2 B& Z' X( w: N
end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素
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问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
. f7 M4 t3 ~% {# y0 o3 I9 ]0 u7 Q# |% M 2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?6 m _1 {! o1 r- `
觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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