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for m=1:Npq
0 e$ }% m1 y2 x P* B$ t- e9 ^( |! W for n=1:Nbus
. h! K! N) J2 f1 @8 l pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率2 s# Y% K8 ]7 @" g: e
qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率
% q) i$ ]6 {2 ]7 N4 ]2 B1 W" K" m end% h. ]* T$ Z2 j% a, _9 _" z% I
Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量7 s- K7 ]9 M2 I; f' O3 i
Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量6 g+ ?% y" ]# s+ e7 b/ j
end %[Unbalance]是节点不平衡量矩阵9 C. o! r- B4 x
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for m=1:Npq
! ~8 | i; Q6 z$ { for n=1:Nbus
; U* b, k1 B+ p% @8 y$ X! v h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
* y) {" Z, ?* Y* r: l) `; b! q% _ n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));; v1 f& |4 o0 N( h0 e
j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));' O: f! K% g- e, V; p3 v3 O
l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
' l8 D! E$ k+ J3 O1 I! I end
7 |% X4 O9 m; p+ @+ y* F2 V H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));+ `" G- g" z, { F& K% F/ N. M5 _6 `
N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);
3 z: j7 r9 i. p9 Z0 b J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));; |. l5 x f# t8 }% P; \* a
L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);
+ u" W& @4 A+ {# E3 ^% q7 u& ` Jacobi(2*m-1,2*m-1)=H(m,m);) Z. Q; q# `* ~, Z1 n
Jacobi(2*m-1,2*m )=N(m,m);1 y# L( R) L8 g$ n k4 L
Jacobi(2*m ,2*m-1)=J(m,m);( o& g% m1 \) K+ k8 d
Jacobi(2*m ,2*m )=L(m,m);
+ n, h% U/ d% p* Q end %计算m=n情况下的Jacobi矩阵中的子矩阵元素9 S- ?! J1 v; w" n
\) r+ I& t$ i6 b for m=1:Npq
; {! x: \! H, m/ O' K5 x* y0 t7 ~ for n=1:Npq
! v) O# Z- I4 F' `4 p if m==n3 M2 G5 Z/ d: H% n0 U: G# X# j' A
else/ ^' \2 J* D* Y
H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));+ c2 T( g4 z. w2 D) Y8 j: V
J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));# s- {) H u, L1 P/ d) T7 `
N(m,n)=-J(m,n);
2 Y6 i9 v4 a0 s0 M- ] L(m,n)= H(m,n);
+ M0 g9 o8 n4 ?; [$ f Jacobi(2*m-1,2*n-1)=H(m,n);; y. V! m$ Q J5 c3 n
Jacobi(2*m-1,2*n )=N(m,n);; O" ~3 O* K1 M" O% n% j
Jacobi(2*m ,2*n-1)=J(m,n);# h, ]$ R o2 S* x' B
Jacobi(2*m ,2*n )=L(m,n);
4 t F, D0 }. h$ m* @5 s end
8 E, d d1 E: G8 v end
X' i8 |9 q. q* ~! v7 ? end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素& v. q3 f, G3 X9 ~7 U3 |
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问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
$ f# U7 _9 x) ]( n 2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?
, ~ Q( w6 ?1 Y3 X' w. X! ?觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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辩手:0 ( 加入 )
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