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for m=1:Npq
* H K+ y9 V& z1 O/ u7 B for n=1:Nbus
) C f) y9 C! _5 ~3 Q- v pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率' P3 j8 h5 Y& b; B: o. s& O
qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率8 u$ n4 j) j& u* x7 [- \
end
- P5 c* Q2 \5 i' x3 f | Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量
% H- ?! R8 _2 ^0 K# X Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量" p: `" p F& ~9 X
end %[Unbalance]是节点不平衡量矩阵; Q$ z+ }. o1 X5 u+ X: s
. k* u% h* x4 Q* a( [' q0 h1 P. F for m=1:Npq1 | O9 j" U2 C
for n=1:Nbus0 B+ y% z, y8 V9 \8 C
h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
& L9 [$ b+ {# ]: u0 l, N n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
, }8 b$ \+ K' n7 `( E' B8 @ j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));# p5 [3 f( H% K* U6 \! I$ F6 o
l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));; m0 n% p* [, w+ G. ?0 o
end
" y0 T8 @. G6 Y* z0 S) U* c H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));4 S# h3 V: Y6 w9 H/ t1 `% g3 C
N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);
/ E- {2 k2 t o$ h! ? J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));
# X' r, d9 q W8 S& D B L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);
/ t0 ~& k2 v' t% }# Z Jacobi(2*m-1,2*m-1)=H(m,m);
) L* j5 y3 G( U6 L: B Z( F Jacobi(2*m-1,2*m )=N(m,m);0 F2 o3 ~/ i% Q) a& S2 e
Jacobi(2*m ,2*m-1)=J(m,m);2 L* J' v* R. o
Jacobi(2*m ,2*m )=L(m,m);+ ^9 ^' z6 }; j2 |9 o C* p
end %计算m=n情况下的Jacobi矩阵中的子矩阵元素) N/ n& P/ K( p( W' n) f3 X5 m
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for m=1:Npq
3 S7 b) n: J0 j- z( f for n=1:Npq
7 Q7 h! s; R) r if m==n* P# G% `6 m9 o# L6 V; a
else
: s/ h9 a) c z) ^% p H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));% }7 Z7 T2 f- Q1 g6 A( ?. u
J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
; p8 a# \4 p) b4 X) a; M; o N(m,n)=-J(m,n);
- o6 u: J& o& l* ~! Q) H, U L(m,n)= H(m,n);
( B/ `: }5 J! P8 |- y Jacobi(2*m-1,2*n-1)=H(m,n);
9 f. ~8 D' P/ ^ Jacobi(2*m-1,2*n )=N(m,n);8 i* C4 u7 j) Q8 E7 Y5 C5 F
Jacobi(2*m ,2*n-1)=J(m,n);
, [; S% y* h* K5 `7 \% F9 R' g9 T Jacobi(2*m ,2*n )=L(m,n);+ R% r" W5 }# ^. C6 e
end
, ^ I8 ]& N# ?4 U( a3 A end
4 W, v. ~9 B9 F& P, P7 \" R7 z- e& t end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素* G6 q/ l) g0 L
9 N1 N$ R2 ]7 G1 z# R
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢) m4 u3 s& ]1 \# h
2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?
( C4 H' K( j0 f4 O- O- {# a u觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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