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for m=1:Npq9 ? q1 c z/ Z" q A6 c
for n=1:Nbus/ g( T) F/ n# f' ^' p
pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率
7 [4 i i6 Q! b) O1 } qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率# E2 K+ F" \/ B; p, K
end
& P$ Q; s* j+ ~. x2 y5 N, K! v Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量- }; D4 F3 Q( i2 B9 h, d2 h+ c
Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量$ J; P* A% M& j+ s/ v. v
end %[Unbalance]是节点不平衡量矩阵
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0 K& ?2 o7 L( c9 Z; j8 j for m=1:Npq
- I$ ~9 _8 Q% B" P for n=1:Nbus
/ `! Y, j' q# X5 s h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));8 P% Z) Q2 M l' O7 _: {
n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
% l* z9 E" r3 a5 N1 K j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
9 Z- E$ W' @6 `7 W; n- ] l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
# w: V7 W, H6 K0 @ end
9 R5 D/ |6 `* A/ j- f; `) Z H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));' j) b7 U% r/ Y. s
N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);5 B0 _# L {2 g
J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));4 b/ P9 y' L0 s7 t0 I9 P5 g
L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);
% A/ T# d! c# m% [( n" D Jacobi(2*m-1,2*m-1)=H(m,m);3 {) P( j% B2 J
Jacobi(2*m-1,2*m )=N(m,m);; F4 P o) K% G3 T; P2 g
Jacobi(2*m ,2*m-1)=J(m,m);
) P" t4 V: n' U! _ Jacobi(2*m ,2*m )=L(m,m);5 A6 Y& l h" h
end %计算m=n情况下的Jacobi矩阵中的子矩阵元素
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* q7 l5 ~9 V4 Z2 |( u& E4 e9 n7 T { for m=1:Npq
- d# ]& R0 B, d. I: ~% o) @, r/ ?& R for n=1:Npq$ z5 N& L- X) g3 }+ x
if m==n9 f1 H, N2 w% l4 `) A
else% ~! L- L6 N7 w
H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
5 U) _) X. o5 I5 k" Q- C5 i9 {4 C. T J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));$ c- f+ E, W' i) G* ^
N(m,n)=-J(m,n);
& Z# T. F! t7 B' ?9 | L(m,n)= H(m,n);
2 Z% d# Y9 |7 J# t3 F Jacobi(2*m-1,2*n-1)=H(m,n);
* r9 D- D9 f# W4 q& q Jacobi(2*m-1,2*n )=N(m,n);
3 B: \: w, y3 q" L, j/ x9 M# h7 L Jacobi(2*m ,2*n-1)=J(m,n);
2 v/ l' S. V M4 M( H Jacobi(2*m ,2*n )=L(m,n);
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end3 u4 l, i' k* {
end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素2 }5 F" T. E) [9 ]
! r. A9 _$ I/ H问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢4 @ b% g! C! E f) e$ W
2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?
( a4 e' s- h' B4 D觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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