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for m=1:Npq: f: O. W; j$ Y
for n=1:Nbus0 @" x2 } @: ?7 X
pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率) U. f2 u0 @4 K" c* X
qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率
: Z2 c# s6 {9 v2 F' B end N( X; R, t8 K' y
Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量
) O, J/ }' ]* I/ e2 t/ k v Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量5 o5 Q8 @) ?: y
end %[Unbalance]是节点不平衡量矩阵
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9 M/ ~) b, I$ |5 X) L* |* ^: z for m=1:Npq
# s% u* C1 E9 Z0 T) S for n=1:Nbus* F9 R- V3 w& F4 W' O
h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
& u6 C2 B3 |0 h3 K3 d' {0 u n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));& v5 m5 N( B& |0 ~8 O0 U
j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
% a* k. J: a& T; g" q! M/ T$ f l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
7 u! y+ ~. P) V end, |7 h) I6 o4 ~) v5 L, A5 q7 Z
H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));) h2 M* E" E% k7 B2 T
N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);$ I- a2 w1 y( Y
J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));) r4 W3 N5 \& u/ T3 d; D* m
L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);
c8 N5 k5 _5 i' B1 F2 ?; b Jacobi(2*m-1,2*m-1)=H(m,m);5 l8 j! [7 |, y- d. f, ~ J8 B
Jacobi(2*m-1,2*m )=N(m,m);
! h3 G+ \" C% O* y- v Jacobi(2*m ,2*m-1)=J(m,m);
" W9 Z3 o, w& U' _0 I( S Jacobi(2*m ,2*m )=L(m,m);
' W: T6 n% a8 _/ `4 `7 W end %计算m=n情况下的Jacobi矩阵中的子矩阵元素9 @2 q1 ?& ]# G9 \+ X/ v; W
2 \1 l! N4 V3 G2 G/ Q for m=1:Npq/ F# ~. Z+ X" m8 I* i
for n=1:Npq( g. a1 l7 Q# P! l! S* ]
if m==n
5 b4 O! b( C4 D& k/ c else
" V8 v: I2 v P; W% J2 S+ } H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));) t" e! D: H7 [; k) \
J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
6 M& [3 ?9 n7 l. R1 \/ i N(m,n)=-J(m,n);
6 o6 d& g- v. `& o$ H" p L(m,n)= H(m,n);( h( U$ \# D: \( J) _& O( ?0 R
Jacobi(2*m-1,2*n-1)=H(m,n);, G* z) ]% M! O# f+ u9 D* k
Jacobi(2*m-1,2*n )=N(m,n);
1 o. l7 D9 m; c2 e( r; F9 S3 s: j8 S$ T Jacobi(2*m ,2*n-1)=J(m,n);
# o( u2 l: t" I T Jacobi(2*m ,2*n )=L(m,n);2 d8 b* d( V# _) r. i, ]
end
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end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素9 E. a9 {+ q% ^0 e2 H3 _
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问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢* g$ h6 E$ ]" K( y! r' R
2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?
, W% @0 t4 F8 t( l# P F- h( E6 z觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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VS |
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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辩手:0 ( 加入 )
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