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for m=1:Npq. I- b" `9 @: {& z2 x) G4 `
for n=1:Nbus
. k; N# _2 M6 Z! C% N pt(n)=u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n))); %由节点电压求得的PQ节点注入有功功率% `& C# A! t( k
qt(n)=u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n))); %由节点电压求得的PQ节点注入无功功率
; @/ b1 L5 y8 Q1 o/ W( Y+ u0 m2 O end/ Q! E6 j; w7 \5 K
Unbalance(2*m-1)=p(m)-sum(pt); %计算PQ节点有功功率不平衡量
3 r" z3 y6 S$ ^0 Q6 j" d% N$ t Unbalance(2*m )=q(m)-sum(qt); %计算PQ节点无功功率不平衡量
; F \8 U* Q$ \1 |- Z% _- \end %[Unbalance]是节点不平衡量矩阵
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for m=1:Npq
2 Z& g* J8 d3 I" E" v for n=1:Nbus+ N/ \# u8 N: g) Y5 p8 D
h0(n)= u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));) e+ r/ c* z1 l
n0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
* P# G4 b# g, u1 ^4 q" \ D j0(n)=-u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));6 T( Z$ B/ P+ J4 N& A6 R
l0(n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));% ]2 J, v5 U8 V, [- S; \0 S
end# r* s# j x9 h$ d% b, T
H(m,m)=sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));$ G; `5 ~2 ^6 l ` h" M# ~
N(m,m)=sum(n0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)))-2*u(m)^2*G(m,m);
8 j- t" {* p" J8 J9 r J(m,m)=sum(j0)+u(m)^2*(G(m,m)*cos(delt(m)-delt(m))+B(m,m)*sin(delt(m)-delt(m)));9 I& E" H( V1 l Z+ k
L(m,m)=sum(l0)+u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)))+2*u(m)^2*B(m,m);" r5 `. h: z3 @( [- g5 i& m6 B
Jacobi(2*m-1,2*m-1)=H(m,m);, {, {, K) u& d2 v$ }$ _ [" `
Jacobi(2*m-1,2*m )=N(m,m);# S' K9 c; T( s' z: L5 r
Jacobi(2*m ,2*m-1)=J(m,m);; ?7 g B! s, m. r
Jacobi(2*m ,2*m )=L(m,m);
S/ d" y/ U, c! ?6 z+ \ J$ X6 H end %计算m=n情况下的Jacobi矩阵中的子矩阵元素
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for m=1:Npq
3 n( H! `- [+ V( v for n=1:Npq" O3 X* _( a/ k/ G7 z; j9 W. ?$ c- R
if m==n) o( p/ |; P, o+ b$ D8 \$ g2 U
else8 U: l% q, ^) o/ a w- f
H(m,n)=-u(m)*u(n)*(G(m,n)*sin(delt(m)-delt(n))-B(m,n)*cos(delt(m)-delt(n)));
3 h1 g) X0 z. H% y! w J(m,n)= u(m)*u(n)*(G(m,n)*cos(delt(m)-delt(n))+B(m,n)*sin(delt(m)-delt(n)));
' B( H6 Y: H6 c, F6 \' j" ] N(m,n)=-J(m,n);7 J. q; M% z/ v9 C: ^
L(m,n)= H(m,n);: H- Y9 ~/ H, H, k9 e# }0 r% h" [
Jacobi(2*m-1,2*n-1)=H(m,n);
) @! Y6 V& @7 r* u$ E- r0 J Jacobi(2*m-1,2*n )=N(m,n);
8 N' s9 I* i7 w0 V" q Jacobi(2*m ,2*n-1)=J(m,n);( n, v8 `* @* j/ ?5 ~
Jacobi(2*m ,2*n )=L(m,n);6 p. G9 t, g9 `3 A* p
end
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end %计算m≠n情况下的Jacobi矩阵中的子矩阵元素1 a2 U: u. s3 ]- n, Z0 X
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问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
) e* t' q8 i' z' V! k7 f0 R 2、对角元素H(m,m),N(m,m),J(m,m),L(m,m)中还有u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等,书上不是就u(m)^2*G(m,m)+Q(i)?
* c/ L, C- |* R$ ]8 ^; J" l3 x觉得很疑问?谢谢大家回答我! |
正方观点 (0)
问题:1、在算对角元素时候,为什么不能用前面pt(n)和qt(n)代呢
2、对角元素H(m,m),书上不是就u(m)^2*G(m,m)+Q(i)?
觉得很疑问?谢谢大家回答我!
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反方观点 (0)
对角元素H(m,m)为sum(h0)-u(m)^2*(G(m,m)*sin(delt(m)-delt(m))-B(m,m)*cos(delt(m)-delt(m)));等
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辩手:0 ( 加入 )
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