TA的每日心情 | 郁闷 2021-5-6 11:24 |
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签到天数: 1 天 连续签到: 1 天 [LV.1]初来乍到 累计签到:1 天 连续签到:1 天
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发表于 2009-2-12 14:13:01
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非常感谢,问题已经解决了,能够使用。7 f; Z5 C8 \3 O, _4 Y- a- Q
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runpf('case9')
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Newton's method power flow converged in 4 iterations.$ U0 `0 y( D* G+ Z+ e; d
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Converged in 0.72 seconds# M' V' f; {' ~, J' p
================================================================================, ~* m3 ^7 f0 Q1 r M. e3 F
| System Summary |
; \; h0 u1 q3 n% s; _# J# n================================================================================" e1 v, k% x" C+ {9 B
0 F5 }* M2 h: I( V( vHow many? How much? P (MW) Q (MVAr)
9 E5 @9 b* T% M1 v: \--------------------- ------------------- ------------- -----------------; V" U! ~! M) m. H1 G9 v& `8 l
Buses 9 Total Gen Capacity 820.0 -900.0 to 900.0( @% B D0 ]5 d$ K7 ]
Generators 3 On-line Capacity 820.0 -900.0 to 900.0. m! q; n u# J
Committed Gens 3 Generation (actual) 320.0 34.9 a; n- Q6 ]3 u$ `
Loads 3 Load 315.0 115.0: B. a/ l) \$ ?* d1 o j
Fixed 3 Fixed 315.0 115.0
0 P/ M5 ]6 S3 n5 M3 ^ Dispatchable 0 Dispatchable -0.0 of -0.0 -0.0
" t, y$ {& X/ a* W0 y6 z! nShunts 0 Shunt (inj) -0.0 0.0
8 _" v, V% _1 s p3 OBranches 9 Losses (I^2 * Z) 4.95 51.31* _) b0 u; r; ]# {* |
Transformers 0 Branch Charging (inj) - 131.45 H6 l- ^$ q% U2 A+ L0 J
Inter-ties 0 Total Inter-tie Flow 0.0 0.0
# O+ I8 u2 d2 K) y bAreas 1
& b! ^7 d& T; s V
% f* u4 f7 g) S6 E$ y Minimum Maximum6 x9 A! e3 V; R
------------------------- --------------------------------' ~$ p/ s1 X K
Voltage Magnitude 0.958 p.u. @ bus 9 1.003 p.u. @ bus 6
1 V4 V6 G0 P& m0 C" }Voltage Angle -4.35 deg @ bus 9 9.67 deg @ bus 2 % u' a0 f# F& T, e5 L* o
P Losses (I^2*R) - 2.46 MW @ line 8-9- I, |9 ?! d; B3 Q4 I Y
Q Losses (I^2*X) - 16.74 MVAr @ line 8-2- n; N. e( N/ X$ r$ R; p
% ], l" B! H+ @: k================================================================================
" P: Q" P; t7 o% _' c9 `; ^' n| Bus Data |
* I4 v! ^6 j8 l4 @================================================================================. }( L! x( _ G2 a z) h
Bus Voltage Generation Load
8 n% t3 J6 h: ^! R/ W2 B # Mag(pu) Ang(deg) P (MW) Q (MVAr) P (MW) Q (MVAr) _2 ]. V. H( I- I( b5 u+ P
----- ------- -------- -------- -------- -------- --------
1 x+ T4 D& J/ E/ h) [ 1 1.000 0.000 71.95 24.07 - -
3 F0 O. g6 q8 Q) M1 l! F 2 1.000 9.669 163.00 14.46 - -
, w# l: K0 U% P 3 1.000 4.771 85.00 -3.65 - -
( N! N* L& ^2 r1 I. I 4 0.987 -2.407 - - - -
- a+ @0 S$ A; }6 T" l 5 0.975 -4.017 - - 90.00 30.00 + C+ `9 @$ E0 |- u
6 1.003 1.926 - - - - % {* H1 R6 `3 n0 d
7 0.986 0.622 - - 100.00 35.00 R% T h& Y5 i1 B0 R- W+ f9 A
8 0.996 3.799 - - - - ' z$ ^. t0 S3 D Y9 s0 C2 B0 I
9 0.958 -4.350 - - 125.00 50.00
3 {2 U( M' o8 X+ W" E5 U0 K -------- -------- -------- --------
( o9 @0 ^9 V) q: k) F% r" A a5 s Total: 319.95 34.88 315.00 115.00" i; O: z1 E8 u) ?. N
6 E. p( d' q/ E$ f1 B================================================================================) E1 G: M9 V, Z: q" h
| Branch Data |
* L1 Z- W. `3 g9 j z! T1 c- j5 _9 E- L================================================================================
% {; F3 l& _" `3 TBrnch From To From Bus Injection To Bus Injection Loss (I^2 * Z) ) _& y! w1 e5 V* }; z1 Z5 ]
# Bus Bus P (MW) Q (MVAr) P (MW) Q (MVAr) P (MW) Q (MVAr)+ U* |9 E- T$ v. y- c" y2 ]# Y
----- ----- ----- -------- -------- -------- -------- -------- --------5 I L& D0 u5 X6 s' M1 C7 z
1 1 4 71.95 24.07 -71.95 -20.75 -0.000 3.32$ o; c' ]8 Q" p0 ~1 F
2 4 5 30.73 -0.59 -30.55 -13.69 0.174 0.94 m( P7 |# l3 @- J! n
3 5 6 -59.45 -16.31 60.89 -12.43 1.449 6.31* I# ]8 k% x6 x" ^+ U! h
4 3 6 85.00 -3.65 -85.00 7.89 -0.000 4.245 J, Q$ _7 w1 ~: z) K; z
5 6 7 24.11 4.54 -24.01 -24.40 0.095 0.81
7 T8 X; s6 u5 u- Q( r+ w 6 7 8 -75.99 -10.60 76.50 0.26 0.506 4.29; b$ F; q; c2 R3 Z0 P; Y
7 8 2 -163.00 2.28 163.00 14.46 -0.000 16.74
$ }. n# }: B/ s& w5 O* H 8 8 9 86.50 -2.53 -84.04 -14.28 2.465 12.40
( c" a# E5 B7 t. S9 U' y& D y 9 9 4 -40.96 -35.72 41.23 21.34 0.266 2.26
2 g* b9 m0 [2 e0 N g4 O& U( ` -------- --------
4 b; y5 O5 r. k `/ ]3 o7 a1 u Total: 4.955 51.31 |
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