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这个错误是什么原因

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发表于 2009-11-20 12:27:14 | 显示全部楼层 |阅读模式

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------------------------------------------------------------------------------------------------------------------------------------/ u" d# [) P4 X, N9 g: k  V) {3 H' W+ k
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/- z/ L2 o4 H  _  a2 A
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/  O' A5 g; J8 D3 _$ i9 H% u' y; S
------------------------------------------------------------------------------------------------------------------------------------( F! S7 n5 S5 w5 i4 k7 T
You lose, fella.   The EMTP logic has detected an error condition, and is now going to terminate program execution.  The following5 _3 N1 i( T2 A( m5 Y/ R9 u
message summarizes the circumstances leading to this situation.  Where an otherwise-unidentified data card is referred to, or where
/ g. R0 t; R/ tthe "last" card is mentioned, it is the most recently read card of the input data that is meant.  The 80-column image of this card
7 V# ]9 Q4 P% v  \is generally the last one printed out prior to this termination message.  But possibly this last-read card has not yet been
; j; v. X1 n& X% odisplayed, so a copy follows:  \* i- ?1 L: X0 Z' u
"             0.0             0.0                                                "
( N3 y8 v/ B+ n; w9 B0 b$ v              KILL code number                Overlay number               Nearby statement number2 X7 y# k5 U% d) m" w6 M
                          5                          3                                181
* T7 [- K2 N2 V' u. }: {9 JKILL = 5.  The user has been defining the characteristic of a nonlinear or a pseudo-nonlinear element.  Each point of the
7 T* u( d6 E$ J# l: wpiecewise-linear curve is defined by a pair of data values, which must be in order, moving ever to the right and upward in the x-y
  `7 u; ?6 K- g7 z: p2 M5 g& hplane.  But the just-inputted characteristic is not monotone increasing in this way as the EMTP requires, since a decrease in one of
+ ?) H* z) F' e" cthe two coordinate points has been detected on the last-read data card.
; ^! a; p+ h1 R0 p------------------------------------------------------------------------------------------------------------------------------------( p1 ?; I  i; B
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
( v! b  u  v, n9 _ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/& r/ y+ n8 e: O4 Z5 W
------------------------------------------------------------------------------------------------------------------------------------
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发表于 2009-12-22 18:06:12 | 显示全部楼层
我也遇见这样的问题,初学者,( A, ]5 u6 X/ T. D7 w2 S! J& p
那位高手解释一下吧
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