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[讨论] 这个错误是什么原因

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发表于 2009-11-20 12:27:14 | 显示全部楼层 |阅读模式

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------------------------------------------------------------------------------------------------------------------------------------9 d5 D4 g( _& z, S( d% y. l2 b* {
ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
- l' |; }$ P; D4 @' aERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
2 Z+ }  O/ h. r) `8 C------------------------------------------------------------------------------------------------------------------------------------1 t5 ]3 J9 ?( H& W
You lose, fella.   The EMTP logic has detected an error condition, and is now going to terminate program execution.  The following
! @4 C- Y6 b8 \! B( b* Nmessage summarizes the circumstances leading to this situation.  Where an otherwise-unidentified data card is referred to, or where
) d5 j3 B& c( E, @+ Uthe "last" card is mentioned, it is the most recently read card of the input data that is meant.  The 80-column image of this card9 A: P1 ~0 V7 |! e3 S& H  v: s( h
is generally the last one printed out prior to this termination message.  But possibly this last-read card has not yet been( V7 B% h$ t5 w5 j. E2 e
displayed, so a copy follows:
2 o, j3 J6 R* J& Z"             0.0             0.0                                                "
) i* K! `- I- }* x- U0 n# U8 s              KILL code number                Overlay number               Nearby statement number5 A3 D) l5 H" ~
                          5                          3                                1815 o( `( U0 _8 B( i# L1 e5 C9 y" d
KILL = 5.  The user has been defining the characteristic of a nonlinear or a pseudo-nonlinear element.  Each point of the
% B+ o8 ]: u* K# a9 Z* R  Z4 r- O5 B& ypiecewise-linear curve is defined by a pair of data values, which must be in order, moving ever to the right and upward in the x-y# X5 L4 J! h4 s* z
plane.  But the just-inputted characteristic is not monotone increasing in this way as the EMTP requires, since a decrease in one of; U4 m; W. S* w8 W
the two coordinate points has been detected on the last-read data card.
; ~" Q' \6 G) |1 Q% v( x) m# t------------------------------------------------------------------------------------------------------------------------------------
4 `$ F% p( |! lERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
; h3 `9 z* D' B1 T7 t, zERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/ERROR/
2 `8 B) {- m5 d------------------------------------------------------------------------------------------------------------------------------------
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发表于 2009-12-22 18:06:12 | 显示全部楼层
我也遇见这样的问题,初学者,
0 I2 j5 P1 i2 T( w7 ^" S那位高手解释一下吧
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