You lose, fella. The EMTP logic has detected an error condition, and is now going to terminate program execution. The following R# J0 B9 x c7 R7 A) H# {( Cmessage summarizes the circumstances leading to this situation. Where an otherwise-unidentified data card is referred to, or where1 J- a6 ^7 g6 L9 b
the "last" card is mentioned, it is the most recently read card of the input data that is meant. The 80-column image of this card * W0 O$ W* \+ l1 J! vis generally the last one printed out prior to this termination message. But possibly this last-read card has not yet been& b, r* J2 \8 K/ V8 I
displayed, so a copy follows:0 O* J6 J8 ^/ v4 u
"14source 0 311. 50. -1. 1." ; v2 B% C& M+ C% r7 l; |( w0 e KILL code number Overlay number Nearby statement number 8 p) u3 T5 W* s* a2 G' ~1 M 12 5 4246 F6 B6 E b7 _7 M( H4 ~KILL = 12. The bus name that was read from columns 3-8 of the last source card is unrecognizable, not having been previously ; p) }) n" s. v2 s4 r K |defined by a branch card or a switch card. The name read from the data card is "source". The user is not allowed to connect . o$ n, @7 U6 B' k+ ^sources to network nodes that are not a part of the network that was previously defined by branch and switch cards of this data, B3 k4 f: j, R C+ a6 T
case. Any such new node would be completely disconnected from the network, so could not affect the solution. Most probably, one or 3 T7 k# p; D' {* T! Tmore spelling errors (including the positioning of imbedded blanks) have been made in the keying of one or more node names on EMTP . M N+ T* S6 S, R) U: odata cards. 8 T( V6 ?2 B! {; h : Y" I. c( v. _6 \& G/ M. q/ v* [) m) K$ a
atp中的data card是 7 A+ g! X7 O7 l U9 d ~什么东西来的？
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狗仔卡
发表于 2009-5-29 16:29:50
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