可逆矩阵求特征值，其特征值矩阵得到的为嘛不正交啦？？？

小周周

两个矩阵，分别求特征值和特征矩阵，按理说特征矩阵应该是正交的，满足T的转置等于T的逆，但是我求出来的却不是！求问原因。Yg=[0.302794262821957 - 3.79296757057053i,0.00000000000000 + 0.00000000000000i,0.0874945715832985 + 0.641221324267202i;0.00000000000000 + 0.00000000000000i,0.00000000000000 - 5.48550000000000i,0.00000000000000 + 0.00000000000000i;0.0874945715832984 + 0.641221324267202i,0.00000000000000 + 0.00000000000000i,170.000000000000 + 0.00000000000000i]

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Yg2=[0.972678496874197 - 2.19149951986028i
0.247515468245944 + 0.721616638839712i
0.289597088366804 + 1.08389127598852i;
0.247515468245944 + 0.721616638839712i
0.270106378209774 - 1.95560247734671i
, }$ ]* P  M5 g* s, ]0.196726501279043 + 1.22862731973151i;
0.289597088366804 + 1.08389127598852i
0.196726501279043 + 1.22862731973151i
0.163424123781682 - 2.34585747664809i];

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[T1,X1]=eig(Yg);[T2,X2]=eig(Yg2);
% f$ Y9 c7 [* e- n" jT1*T1'不等于E，应该不是正交矩阵啦？

小周周

已经知道原因了。复矩阵的正交要取hermite 就是要让虚部取个负号再转置

cxxgtxy

回复 2# 小周周

$ x& @: S9 C0 a" C& h  V# b
    这个matlab help里面写的非常清楚，你help一下就知道了