请教：分相电流差动当线路充电状态时发生故障保护是如何动作的？
应该和线路运行时保护动作情况不太一样吧，未合环一侧无法发出允许信号啊，求高手解答，能否解释得具体点，谢谢 未合环一侧线路开关在跳位，固定向对侧发允许信号搞定 So what are you talking about: current differential scheme or pilot schemes?
For current differential scheme it will trip even though the breaker at the other end is openned. At the energied end the relay detect the fault current and receive no currents from the other end. So current difference is the fault current itself and should be large enough to trip.
Not sure how Chinese manufacturers designed the relays. So the above comments are based on US relaying schemes, just for your reference. 本帖最后由 tz_19660401 于 2010-7-22 19:22 编辑
回复 1# hurong228
未合闸侧，开关断位；这样的话，如果线路有故障，送端侧发出允许信号，而未合环侧“跳位转发功能”，可以使送端侧开关出口跳闸。这个功能在两端联调时需要进行试验。
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