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用MODELS计算线路感应电压:程序如下:
# p2 t3 q/ g8 N2 l( }" V) ]MODEL indloss
; K$ A" F1 s6 t" U+ E9 W3 @CONST ' n# J: S5 \/ j, F$ d `
Tmax {VAL:500}
% D6 ?, s) L1 V/ {% N. On {VAL:2}- L8 u7 t% x( u" u, C! @) g
c {VAL:3.e8} ! E0 }! e7 |$ ]1 a. ^9 I+ X
I0 {VAL:1}
3 [9 i4 g1 y4 Ceps0 {val:8.85e-12}0 [4 j6 @0 G4 u4 o
INPUT UAP[0...n],UBP[0...n]
: R2 E. \7 f, _* hDATA Y,XA,XB
8 I1 T0 C+ @0 m% T5 ~z[1...n] {DFLT:10} % l Q, A# i& U* X; m/ }- T/ r
Im {DFLT:3e4} ; E" U* t7 A: |. S8 P3 r
tc {DFLT:5e-5} & P# B! P5 y3 R+ u0 x
th {DFLT:2e-6}- w' i, i' r" R" ? a
v {DFLT:1.5e8} 3 d# p4 Y9 h2 q$ J8 b
sigma {DFLT:0.001} : l- w" P _5 S2 e& V5 J
epsr {DFLT:10} " e" F6 ~& L; k6 D
OUTPUT UrA[0...n],UrB[0...n]
" H+ E! D5 `, b2 J) w% ` hVAR UindA0[0...Tmax],UindB0[0...Tmax],g1[0...Tmax],g2[0...Tmax],: K" S* b" m5 Q2 u- e @
UindAD[0...Tmax],UindBD[0...Tmax],Ui0,UiD,
2 f" \2 }9 [2 |) HUrA[0...n],UrB[0...n],Tr,k,i,AB,dt,uk[1..4],
* B8 a% R2 v2 _ g' j9 [5 [6 ob,L,x,tau,a1,b1,c1,c2,c3
# ~- I( Y1 A4 M! d+ P$ pFUNCTION F0(x,tr):= (c*tr-x)/(y*y+(b*(c*tr-x))**2)
4 m% {7 D; [5 v" MFUNCTION F1(x,tr):= (x+b*b*(c*tr-x))/sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)), O2 m3 l& D! y1 C. }
FUNCTION F2(x,tr):= x+b*b*(c*tr-x)+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y))2 `3 {1 F0 p( y
FUNCTION F3(x,tr):= (v*tr+sqrt((v*tr)**2+(1-b*b)*(x*x+y*y)))/sqrt(x*x+y*y)
" d5 V3 ^/ L1 F4 [% f' f6 h! ^FUNCTION t0(x):= sqrt(x*x+y*y)/c
, N2 E$ W" @; q) W V! f* AHISTORY; i: [" `$ Y! n
UrA[1...n] {dflt:0}
1 w, L/ n: k: B3 h9 }UrB[1...n] {dflt:0}) k. [. v; i2 ^/ f! C. z: E# Z
UAP[1...n] {dflt:0}- W+ w! r" F9 C/ u3 N7 Q" W
UBP[1...n] {dflt:0}
: i4 _- n6 N$ R$ iDELAY CELLS DFLT: (XA-XB)/(c*timestep)+1
$ C9 l" k9 D; B- y4 t+ | FINIT2 ^9 ]3 V6 ^' |4 \3 E2 L
k:=sqrt(eps0*epsr/(PI*sigma*dt))" X8 X1 w0 N+ s t7 }5 P- Z5 u: f. D+ b
dt:= timestep b:=v/c L:=XA-XB tau:=L/c V# D7 R( k$ K0 b8 y& ~# P& u
a1:=Im/(I0*th)( {7 t7 `4 H# L2 V- ?) K1 A5 J
b1:=0.5*th/(tc-th)+15 i& L. I1 c. b. Y$ C
c1:=a1*k*dt/sqrt(epsr)' ~9 ? m" d" w! F# |; u
c2:=-1.073*k+0.2153*(k**3)+4/3
3 Q' |; ]7 O" V: cc3:=-0.2153*(k**3)+1/6
5 B2 _4 u" [8 C' L FOR AB:=1 TO 2 DO& J. k) A) P( Q: r& d3 P
if AB=1 then
# z: m( V2 v6 _5 d5 vx:=XA else x:=-XB
+ u6 {9 s6 a; U4 g; lendif0 H& H. S7 `7 C4 ~
FOR i:=0 TO Tmax DO
7 t8 Y; c2 f/ U7 g% d8 _4 @Tr:=i*dt
7 u/ u+ O( [4 eif Tr>t0(x)8 a4 O4 D8 V8 E5 G* S
then5 B0 F! J, @4 l1 Q" X
if Tr>t0(x-L)+tau7 U9 ~% F z/ U7 r0 T
then
/ d9 Y+ s; u. O. lUi0:=f0(x,Tr)*(f1(x,Tr)-f1(x-L,Tr-tau))
! i$ e" R% W, o$ r+ r6 LUiD:=ln( f2(x,Tr)/f2(x-L,Tr-tau) )-1/b*ln( f3(x,Tr)/f3(x-L,Tr-tau) )- V- k& l) G( P1 W4 k d
else
; r5 e6 Y9 `/ \* E. D! k% o. rUi0:=f0(x,Tr)*(f1(x,Tr)+1)- H) S& n' E& y( d; [
UiD:=ln( f2(x,Tr)*f0(x,Tr) )-1/b*ln( f3(x,Tr)/(1+b) )
4 }+ |/ Z: w% U7 H; t/ r8 jendif/ v8 ~4 u% d, m% l0 G% W( b
else
& p5 q! s: h. b2 G( R2 l! z) dUi0:=0, UiD:=0
* @+ Q4 j1 ?) q, xendif
/ h8 K, V$ |- q1 Z+ a! U6 yif AB=1 then6 S! h" b! m* X9 `# e
UindA0[i]:=Ui0$ c p6 J. x" N# b7 I
UindAD[i]:=UiD- R* C2 w* ~ Q- I8 K/ Z7 u$ T
g1[i]:=a1*dt: w. s4 Z# V0 G2 Z p
if i>0& c! l6 S7 x5 v2 }$ ~( P% R
then. G, O2 K1 \: X! D, {
g2[i]:=a1*sqrt(eps0/(PI*sigma*Tr))*dt* ?8 a$ _# K, ?5 f4 y1 C& v
endif
3 J2 l+ i: W( S" l& c+ celse
" M& ?0 ?& W" d# F. O. XUindB0[i]:=Ui0
( c# m; m% H( U h) vUindBD[i]:=UiD ]2 _* V7 G1 t
endif
3 E& `. p% U6 K* B+ n4 Q* M- eENDFOR
3 s. ?) h* a4 [& f" s( p/ Q5 F3 hENDFOR/ N( F4 N% f8 o. p
i:=Tmax
& V) u! V1 ?1 E) x9 ~WHILE i>1 DO3 G! S- W3 \7 V: Q" d8 k
uk[1...4]:=0. ?! d1 I, [! f% b
FOR Tr:=1 TO i-1 DO s* U3 Y. v8 W+ `
uk[1]:=uk[1]+UindA0[Tr]*g1[i-Tr]
3 y+ g% I9 k5 R( g: B% Xuk[2]:=uk[2]+UindB0[Tr]*g1[i-Tr]
/ n4 A+ Y* |! {4 Z% ^2 @: j
4 T2 A* w5 H1 M6 L. iuk[3]:=uk[3]+UindAD[Tr]*g2[i-Tr]
4 t- r7 }+ h5 S, ~7 \) A/ }5 o/ Q$ g6 Z; T D( `1 t) i. x1 Q. X
uk[4]:=uk[4]+UindBD[Tr]*g2[i-Tr]( S& s* I# o( ^ y5 p; ~- y9 ~3 \+ ]
2 {: ?, g# e: @0 V% [: w/ i+ r
ENDFOR' s. C/ P4 {! f. n4 }
UindA0[i]:=uk[1]+0.5*UindA0[i]*g1[0]3 a) o, |1 X7 t6 w; r
UindB0[i]:=uk[2]+0.5*UindB0[i]*g1[0]+ y# o) }% q* {! c1 E! t
UindAD[i]:=uk[3]+(UindAD[i]*c2+UindAD[i-1]*c3)*c1
' [6 Q# h1 z& K& H( J/ f' Y& eUindBD[i]:=uk[4]+(UindBD[i]*c2+UindBD[i-1]*c3)*c1+ f& Y) E- @( z) v" ^ t
i:=i-1
( R% l9 N( _0 s1 AENDWHILE
, I! t( a @9 dTr:=trunc(th/dt)
9 Z9 g4 U3 {1 X$ U7 g
, r* n, e# L' |: y3 S" j% \% JFOR i:=Tmax TO Tr BY -1 DO* P0 N' z r! c, E' E6 D
UindA0[i]:=UindA0[i]-b1*UindA0[i-Tr]' T* i$ N2 |! O, ?2 W4 j
UindB0[i]:=UindB0[i]-b1*UindB0[i-Tr]& |- p( k8 q) T/ X% n
UindAD[i]:=UindAD[i]-b1*UindAD[i-Tr]
' D+ \/ g" N C( C, ^ G: pUindBD[i]:=UindBD[i]-b1*UindBD[i-Tr]# @0 P9 E2 I: }7 C( i
endif& V/ v1 K/ f' W" M4 v
ENDFOR
& w7 `: ^4 [) z. r9 KENDINIT, Q- B0 I4 O: A) ~) }5 L( G
EXEC
% {9 K# j4 p* Q H; G3 lFOR i:=1 to n DO2 Z& T% [8 {( i) u3 B K
UrA[i]:=60*I0*b*(z[i]*UindA0[t/dt] - UindAD[t/dt]) +2*delay(UBP[i],tau-dt,1)-delay(UrB[i],tau,1)
/ r, Z7 Y: Z4 W8 ~( ~5 ]UrB[i]:=60*I0*b*(z[i]*UindB0[t/dt] - UindBD[t/dt]) +2*delay(UAP[i],tau-dt,1)-delay(UrA[i],tau,1)
h# L% R3 C3 Q* @+ xENDFOR4 O, I% F: K3 r$ Z
ENDEXEC
$ Y6 k* w) _% |, bENDMODEL
" ~3 b$ {* K4 z3 c! s, F: Z* N7 a
程序报错如下
# r. F' G; _" t8 w- X8 t. T! CKILL = 422. The present statement is interpreted as a value assignment statement, and the preceding name is interpreted as a
- i. N5 s& z2 j5 Dvariable to which a value is being assigned. The identification of this variable is interpreted as complete, and should now be: l' R- \$ ~$ N5 A+ I3 h4 R5 f
followed by ":=", in the following format:: _) W) W% U) A. f
variable_identification := expression
2 C# i1 U& x$ v9 R% w6 t# t! k) N$ L7 K( I, ~& v
本人已经仔细检查了每个等式都加:=了,不知道为什么还是不行,有兴趣的可以仿真一下,大家交流交流。
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